tugas 1 perencanaan trans - regresi linier
DESCRIPTION
regresi linierTRANSCRIPT
No Bangkitan/Hari (x) Total Pemilihan Kendaraan (y) xy1 4100 275 1127500 16810000 756252 1156 60 69360 1336336 36003 2565 115 294975 6579225 132254 350 100 35000 122500 100005 3500 400 1400000 12250000 1600006 1250 120 150000 1562500 144007 755 75 56625 570025 56258 800 60 48000 640000 36009 2100 215 451500 4410000 46225
10 1100 98 107800 1210000 960411 410 105 43050 168100 1102512 950 300 285000 902500 9000013 3615 450 1626750 13068225 20250014 1100 125 137500 1210000 15625
15 4500 700 3150000 20250000 49000016 520 80 41600 270400 640017 485 75 36375 235225 562518 1200 115 138000 1440000 1322519 3100 350 1085000 9610000 12250020 325 55 17875 105625 302521 550 65 35750 302500 422522 1115 200 223000 1243225 4000023 286 45 12870 81796 202524 600 112 67200 360000 1254425 2550 400 1020000 6502500 16000026 3200 415 1328000 10240000 17222527 1025 175 179375 1050625 3062528 425 85 36125 180625 722529 550 100 55000 302500 1000030 1156 120 138720 1336336 14400Σ 45338 5590 13397950 114350768 1755098
2055534244 31248100
r=
x2 y2
Σ2
𝑏=(𝑛 . (Σ𝑥𝑦)−(Σ𝑥.Σ𝑦))/(𝑛 . Σ𝑥^2−〖 (Σ𝑥)〗^2 )
𝑟=(𝑛 . (Σ𝑥𝑦)−(Σ𝑥.Σ𝑦))/(〖 [ . 𝑛 Σ𝑥^2−(Σ )^2]𝑥 〗^(1/2).〖 [ . 𝑛 Σ𝑦^2−(Σ𝑦)^2]〗^(1/2) )
Koefisien Korelasi
r= 0.8656018789
b= 0.1080002109
a= 23.116214556
Persamaan Regresi
r2=
𝑏=(𝑛 . (Σ𝑥𝑦)−(Σ𝑥.Σ𝑦))/(𝑛 . Σ𝑥^2−〖 (Σ𝑥)〗^2 )
𝑎=((Σ𝑦)−(𝑏.Σ𝑥))/(𝑛 )
𝑦=𝑎+𝑏𝑥𝑦=23.11621+0.108𝑥
𝑟=(𝑛 . (Σ𝑥𝑦)−(Σ𝑥.Σ𝑦))/(〖 [ . 𝑛 Σ𝑥^2−(Σ )^2]𝑥 〗^(1/2).〖 [ . 𝑛 Σ𝑦^2−(Σ𝑦)^2]〗^(1/2) )
0 500 1000 1500 2000 2500 3000 3500 4000 4500 50000
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f(x) = 0.108000210934082 x + 23.1162145556857R² = 0.749266612762215
0 500 1000 1500 2000 2500 3000 3500 4000 4500 50000
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f(x) = 0.108000210934082 x + 23.1162145556857R² = 0.749266612762215
50 4051 4652 4453 5554 49
260 234