10_aliran melalui sistem pipa [compatibility mode]

8/18/2019 10_Aliran Melalui Sistem Pipa [Compatibility Mode]

1/21

1

Aliran Melalui Sistem PipaAliran Melalui Sistem PipaAliran Melalui Sistem PipaAliran Melalui Sistem PipaD . E . A

2222

Pendahuluan

D

. : , .

.

.A

. : , A.

3333

Konservasi Energi

γ

γ

G

G

G

γ γ

+ + = + + + +∑ ∑

L L

4444

#1

A


2/21

2

5555

#2

( )

D :

:

,

π = = =

π =

π

= −

6666

#3

D :

( . / )

( ) ( )

γ

γ

=

=

7777

#1

A B

A B

γ

γ

G

G

8888

#2

D

B .

: Σ D


3/21

3

9999

#3

D :

/

γ η

γ η

η

=

=

=

10101010

E & ..#1

A

11111111

E & ..#2

A

12121212

E & ..#3

A


4/21

4

13131313

E & ..#3

A

14141414

H # 1

,

.

15151515

H # 2

= 1= 2 = 3 = .

E

H = 1 + 2 + 3 + .

D :

....

= + + + + + +

∑ ∑ ∑

16161616

H # 3

A

1

2

3

1

2

A

B

G

G


5/21

5

17171717

H # 4

D B :

:

:

++=

++=

. . . . . .

π π π = = =

++=

..

π ( )

18181818

E

D D

,

( ) ( )

=

..

π ( )

++=

19191919

E

D A

.

.

π

π

=+ +

=

20202020

C H AL 1 ..

, ,

, , ,

Δ ,


6/21

6

21212121

.. C H AL 1

, ,

22222222

C H AL 1 ..

E :

( )

. . . . ( , ) ( . ) ( . ) ( . )

..

.

. /

π

∆ = + +

× × ×⇔ = + + ×

⇔ =

⇔ =⇔ =

23232323

H # 1

1, 2 3 / A B.

24242424

H # 2

D :

:

( )

π

= + +

= + +

= = =

= = =

( )


7/21

7

25252525

H # 3

D :

D D :

.

.

.

π

π

π

=

=

=

.

π =

( )

( )26262626

H # 4

.( ) ( ) ( ) :

. . . .

= + +

27272727

C H AL 2 . # 1

A A B 1, 2, 3. A. B

60 A. D 300 /

28282828

C H AL 2 . # 2

:

1. 1

2. D (75%)

3. D


8/21

8

29292929

C H AL 2 # 1

:

( 2 & 3)

30303030

C H AL 2 # 2

) : ( 2 & 3) 1:

D = 1 D = D 1, :

31313131

C H AL 2 # 3

) :

) H D :

K :

32323232

C H AL 2 # 4

) H D :

:

D :


9/21

9

33333333

C H AL 2 # 5

) D 2 3:

2 & 3 , = 300 / .

K :

34343434

C H AL 2 # 6

D 2:

35353535

C H AL 2 # 6

D 3:

36363636

B

D /

/ .

B :

: , ,

: ,

: ?


10/21

10

37373737

D

I:

( )

II: ,

III: ,

38383838

B : 3 #1

A

B

39393939

B : 3 # 2

I D G E G :

G E (EG ) G (HG ) :

EG B HG

γ

γ

= + +

= +

40404040

B : 3 # 3

, :

1. , /

( ) .

2. H ( ) 1,2, 3 .

3. H 1, 2, 3 .


11/21

11

41414141

B : 3 # 4

4. ( 1 ≠ 2 + 3),

( ) ( 1 > 2 + 3,

).

5. 2 ,

( ) ( )

42424242

B : 3 # 5

A :

43434343

B : 3 # 6

D A , A, B ( , , D) ,

.

44444444

C H AL 3 # 1

A

B

+196.7

+190.0

+162.6


12/21

12

45454545

C H AL 3 # 2

D :

1 = 2440 , D 1 = 610

2 = 1200 , D 2 = 406

3 = 1220 , D 3 = 305

= 0.029

H .

46464646

C H AL 3 # 1

A B C:

A = A D

= 196.7 162.6 = 34.1

B = B D

= 190.0 162.6 = 27.4

.

47474747

C H AL 3 # 2

=π

⇒ =

⇒ =

. .

. ( . ) ( . )

. .

. ( . ) ( . )

. .

. ( . ) ( . )

× ×= =× ×

× ×= =× ×

× ×= =× ×

48484848

C H AL 3 # 2

1:

D B

B (2 = 0)

2: =


13/21

13

49494949

C H AL 3 # 3

3:

. .

. /

=

⇔ =

⇔ =

. = =

50505050

C H AL 3 # 4

1:

. .

. /

=⇔ =⇔ =

. . . = − = − =

51515151

C H AL 3 # 5

C :

( ) . ( . )

. /

− + = − +

=

A ,

52525252

C H AL 3 # 5

2:

E +193.0( )

:

1 = 196.7 193.0 = 3.7

2 = 193.0 190.0 = 3.0

3 = 193.0 162.6 = 30.4


14/21

14

53535353

C H AL 3 # 6

D 1: 1 = 3.7

D 2: 2 = 3.0

. .

. /

=⇔ =⇔ =

. .

. /

=⇔ =⇔ =

54545454

C H AL 3 # 8

D 3: 3 = 30.4

. .

. /

=⇔ =⇔ =

55555555

C H AL 3 # 9

C :

( ) . ( . . )

. /

− + = − += −

A

56565656

C H AL 3 # 10

3: 1 2

0.0417

E

ΣΣΣΣ0.1537

+190.0

+193.0

= ?

E = +190.0 +

. ( )

. ( . )

.

= −− −

=

.

.

= += +


15/21

15

57575757

C H AL 3 # 11

3:

E +192.3598 (D 1 & 2)

:

1 = 196.7 192.3598 = 4.3402

2 = 192.3598 190.0 = 2.3598

3 = 192.3598 162.6 = 29.7598

58585858

C H AL 3 # 12

D 1: 1 = 4.3402

D 2: 2 = 2.3598

. .

. /

=⇔ =⇔ =

. .

. /

=⇔ =⇔ =

59595959

C H AL 3 # 14

D 3: 3 = 29.7598

. .

. /

=⇔ =⇔ =

60606060

C H AL 3 # 15

C :

( ) . ( . . )

. /

− + = − += −

A


16/21

16

61616161

H E 2

1, 2, 3,

H D 2 1, 2, 3,

CK

A

H

2

C

B K G ,

G F F

62626262

F F .

= =

).

./

(

+−=

/ . .

ν= − +

C :

. D :

= υ

63636363

J

C : D A.

D :

H C

H HC

64646464

J

H K E

K :

D A = D AK ΣΣΣΣ = 0

J K = 0 ΣΣΣΣ = 0

= =

π


17/21

17

J

65656565

=

π

= 1 = 4

= 5

= 4 = 2

= 3

100

25

25

50 66666666

K E K G( L )

K E K G :

= : D , = 2 ;H , = 1,85

= &K

D D:

=

=

=

π

67676767

H C #1

:

1. 2 0 K .

2. H K

: = 2

3. J .

4. H ΣΣΣΣ , ΣΣΣΣ = 0

68686868

H C #2

.. ( ):

5. H ΣΣΣΣ 2 2 .

6. :

(A)

7. D = 0 + ∆∆∆∆ , 1 6 ∆∆∆∆ = 0

∆ = − ∑∑


18/21

18

69696969

H C #2

(A) :

1. K :

2. ∆∆∆∆


19/21

19

73737373

H C #2

K E :

L K :

= 02 2 0

1 60 2 = 3600 2 1 60 = 120

4 10 2 = 400 2 4 10 = 80

3 40 2 = 4800 2 3 40 = 240

ΣΣΣΣ = 800 ΣΣΣΣ 2 0 = 440

= 1

= 3

60

4010

−∆ = − =

= 4

74747474

H C #3

K E :

L K :

= 02 2 0

4 50 2 = 10000 2 4 50 = 400

2 25 2 = 1250 2 2 25 = 100

5 25 2 = 3125 2 5 25 = 250

4 10 2 = 400 2 4 10 = 80ΣΣΣΣ = 7725 ΣΣΣΣ 2 0 = 830

∆ = − = −

= 4

= 5

= 4 = 210

25

25

50

75757575

= 1 = 4

= 5

= 4 = 2

= 3

100

25

25

50

60

4010

25

25

50

= 1 = 4

= 5

= 4 = 2

= 3

100

25

25

50

62

3821

16

34

41

∆ =∆ = −

76767676

H C #4

2: D

= 1 = 4

= 5

= 4 = 2

= 3

100

25

25

50

62

3821

16

34

41


20/21

20

77777777

H C #5

K E :

L K :

= 02 2 0

1 62 2 = 3844 2 1 62 = 124

4 21 2 = 1764 2 4 21 = 168

3 38 2 = 4332 2 3 38 = 228

ΣΣΣΣ = 1276 ΣΣΣΣ 2 0 = 520

= 1

= 3

62

3821

.∆ = − = −

= 4

78787878

H C #6

K E :

L K :

= 02 2 0

4 41 2 = 6724 2 4 41 = 328

2 16 2 = 512 2 2 16 = 64

5 34 2 = 5780 2 5 34 = 340

4 21 2 = 1764 2 4 21 = 268ΣΣΣΣ = 308 ΣΣΣΣ 2 0 = 900

. −∆ = − = −

= 4

= 5

= 4 = 221

16

34

41

79797979

H C #7

3: D

= 1 = 4

= 5

= 4 = 2

= 3

100

25

25

50

59.5

40.518.8 15.7

34.3

40.7

80808080

H C #5

K E :

L K :

= 02 2 0

1 (59.5) 2 = 3540.25 2 1 59.5 = 119

4 (18.8) 2 = 1413.76 2 4 18.8 = 150.4

3 (40.5) 2 = 4920.75 2 3 40.5 = 243

ΣΣΣΣ = 33.26 ΣΣΣΣ 2 0 = 512.4

= 1

= 3

59.5

40.518.8

..

.∆ = − = −

= 4


21/21

21

81818181

H C #6

K E :

L K :

= 02 2 0

4 (40.7) 2 = 6625.96 2 4 40.7 = 325.6

2 (16.7) 2 = 557.78 2 2 16.7 = 66.8

5 (34.3) 2 = 5882.45 2 5 34.3 = 343

4 (18.8)2

= 1413.76 2 4 18.8 = 150.4ΣΣΣΣ = 112.47 ΣΣΣΣ 2 0 = 885.8

..

.

−∆ = − = −

= 4

= 5

= 4 = 218.8

16. 7

34.3

40.7

82828282

H C #4

A ∆ ≈ 0

10_aliran melalui sistem pipa [compatibility mode]

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