tugas hcm gue
TRANSCRIPT
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TH RT1 TH RT1 LT TH RT1
633 33 383 33 53 523 63
5 5 8 8 8 8 8
0.9 0.9 0.9
P P P
4 3 3
D
I
A
G
R
A
M 1
Timing G = 26.0
Y = 4.0
G = Y =
Protected turns Permitted turns Cycle length, C = 70.0 s
Notes1. RT volumes, as shown, exclude RTOR.
2. Approach pedestrian and bicycle volumes are those that conflict with right turns from the subject approach.
3. Refer to Equation 16-2.
G = 36.0
Y = 4.0
G = Y = G = Y = G = Y = G = Y = G = Y =
Signal Phasing Plan
2 3 4 5 6 7 8
Bus stopping, NB (buses/h) 0 0 0 0
Min. timing for pedestrians,3 Gp (s) 14.26 14.26 10.76 10.76
Parking (Y or N) N N N N
Parking maneuvers, Nm (maneuvers/h) 0 0 0 0
Approach pedestrian volume,2 vped (p/h) 11 11 11 11
Approach bicycle volume,2 vbic (bicycles/h) 20 20 20 20
Arrival type, AT 2
Extension of effective green time, e (s)
Start-up lost time, l1 (s)
Pretimed (P) or actuated (A) P
Peak-hour factor, PHF 0.9
% heavy vehicles, % HV 5 5 5 5 8
INPUT WORKSHEET
General InformationSite Information
Analyst WLL
Agency or Company eCEI
Date Performed e4/12/99
Intersection Third Avenue/Main Street Area Type X CBD Oth
Intersection Geometry
grade= 0% 15 ft
= Pedestrian Button
= Lane Width
Show North Arrow
grade= 0%= Through
100(20)
11 ft = Right
11 ft = Left
11 ft
11 ft = Through + Right
100 20
LT
Volume, V (veh/h) 78 48 43 713 43
Volume and Timing Input
EB WB NB SB
LT RT1 LT TH
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LT TH RT LT TH RT LT TH RT
Volume, V (veh/h) 78 633 48 43 713 33 43 383 33
Peak-hour factor, PHF 0.9 0.9 0.9
Adjusted flow rate, vp = V/PHF (veh/h) 86.6667 703 53 48 792 36.6667 48 426 36.66
Lane group
Adjusted flow rate in lane group, v (veh/h) 843 877 510
Proportion1 of LT or RT (PLT or PRT) 0.10277 - 0.06324 0.0545 - 0.04183 0.09368 - 0.071
Base saturation flow, so (pc/h/ln) 1900 1900 1900
Number of lanes, N 2 2 1
Lane width adjustment factor, fw 0.96667 0.96667 1.1
Heavy-vehicle adjustment factor, fHV 0.95238 0.95238 0.92593
Grade adjustment factor, fg 1 1 1
Parking adjustment factor, fp 1 1 1
Bus blockage adjustment factor, fbb 1 1 1
Area type adjustment factor, fa 0.9 0.9 0.9
Lane utilization adjustment factor, fLU 0.95 0.95 1
Left-turn adjustment factor, fLT 0.99489 0.99728 0.99534
Right-turn adjustment factor, fRT 0.99051 0.99373 0.98922
Left-turn ped/bike adjustment factor, fLpb 0.997 0.997 0.999
Right-turn ped/bike adjustment factor, fRpb 0.992 0.995 0.996
Adjusted saturation flow, s (veh/h)
s = so N fw fHV fg fp fbb fa fLU fLT fRT fLpb fRpb2915 2941 1706
Saturation Flow Rate (see Exhibit 16-7 to determine adjustment factors)
Notes
VOLUME ADJUSTMENT AND SATURATION FLOW RATE WORKSHEET
General Information
Project Description Example Problem 1
Volume Adjustment
EB WB NB
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1. PLT = 1.000 for exclusive left-turn lanes, and PRT = 1.000 for exclusive right-turn lanes. Otherwise, they are equal to the proportions of tu
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EB WB NB SB
36 36
36 36
36 36
1 1
48 59
0.094 0.083
0.083 0.094
710 510
4 4
0.929 1.145
13.806 9.917
1 1
10.544 12.589
0.486 0.486
12.981 9.197
23.019 23.411
0 0
0.917 0.906
2.7 2.2
1 1
0.0608 0.0602
0 0
1. Refer to Exhibits C16-4, C16-5, C16-6, C16-7, and C16-8 for case-specific parameters and adjustment factors.
2. For exclusive left-turn lanes, N is equal to the number of exclusive left-turn lanes. For shared left-turn lanes, N is equal to
the sum of the shared left-turn, through, and shared right-turn (if one exists) lanes in that approach.
3. For exclusive left-turn lanes, gf = 0, and skip the next step. Lost time, tL, may not be applicable for protected-permitted
PTHo = 1 PLTo
EL1 (refer to Exhibit C16-3)
EL2 = max*(1 PTHon)/PLTo, 1.0+
fmin = 2(1 + PLT)/g
gdiff = max*gq gf, 0+ (except when left-turn volume is 0)4
0.844 0.941(fmin fm 1.00)
Notes
fLT = fm = [gf/g] +
n = max*(gq gf)/2, 0+
Proportion of LT volume in opposing flow, PLTo
Adjusted flow rate for opposing approach, vo (veh/h)
Lost time for LT lane group, tL
Computation
LT volume per cycle, LTC = vLTC/3600Opposing flow per lane, per cycle,
Opposing platoon ratio, Rpo (refer to Exhibit 16-11)
0.629
gf = G*e0.860(LTC )+ tL gf g (except exclusive
Opposing queue ratio, qro = max*1 Rpo(go/C), 0+
gq = 4.943volc^0.762qro^1.061 tL gq g
gu = g gq if gq gf, or gu = g gf if gq < gf
Proportion of LT volume in LT lane group, PLT
SUPPLEMENTAL WORKSHEET FOR PERMITTED LEFT TURNS OPPOSED BY SINGLE-LANE APPROACH
General Information
Project Description Example Problem 1
Input
Cycle length, C (s) 70
Total actual green time for LT lane group,1 G (s)
Effective permitted green time for LT lane group,1 g (s)
Opposing effective green time, go (s)
Number of lanes in LT lane group,2 N
Adjusted LT flow rate, vLT (veh/h)
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EB WB NB SB
Cycle length, C (s)
Total actual green time for LT lane group,1
G (s) 26 26
Effective permited green time for LT lane group,1g (s) 26 26
Opposing effective green time, g0(s) 26 26
Number of lanes in LT lane group,2N 2 2
Number of lanes in opposing approach, N0 2 2
Adjusted LT flow rate, VLT(veh/h) 86.67 48
Proportion of LT volume in LT lane group,3P LT 0.103 0.054
Adjusted flow rate for opposing aproach, Vo(veh/h) 877 843
Lost time for LT lane group, tL 4 4
LT volume per cycle, LTC = vLTC/3600 1.685 0.929
opposing lane untilization factor, fLUo (refer to volume adjustment
and saturation flow rate worksheet)0.950 0.950
Opposinf flow rate per lane, per cycle
8.972 8.631
gf = G[e-0,860(LTC^0,629)
]- tL gfgf
gu= g-g f if gq
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EB WB NB SB
Effective pedestrian green time,1,2 gp (s) 26 26 36 36
Conflicting pedestrian volume,1 vped (p/h) 11 11 11 11
vpedg = vped (C/gp) 26.9 26.9 19.4 19.4
OCCpedg = vpedg/2000 if (vpedg 1000) or
OCCpedg = 0.4 vpedg/10,000 if (1000 < vpedg 5000) 0.0135 0.0135 0.0097 0.0097
Opposing queue clearing green,3,4 gq (s) 15.928 12.341 12.981 9.197
Effective pedestrian green consumed by opposing
vehicle queue, gq/gp; if gq gp then fLpb = 1.00.613 0.475 0.361 0.255
OCCpedu = OCCpedg *1 0.5(gq/gp)+ 0.0093 0.0103 0.0080 0.0085
Opposing flow rate,3 vo (veh/h) 877 843 710 510
OCCr = OCCpedu *e(5/3600)vo+ 0.014 0.016 0.014 0.017
Number of cross-street receiving lanes,1 Nrec 1 1 2 2
Number of turning lanes,1 Nturn 1 1 1 1
ApbT = 1 OCCr if Nrec = Nturn
ApbT = 1 0.6(OCCr) if Nrec > Nturn0.986 0.984 0.992 0.990
Proportion of left turns,5 PLT 0.103 0.054 0.094 0.083
Proportion of left turns using protected phase,6 PLTA 0 0 0 0
fLpb = 1.0 PLT(1 ApbT)(1 PLTA) 0.9986 0.9991 0.9992 0.9992
Effective pedestrian green time,1,2 gp (s) 26 26 36 36
Conflicting pedestrian volume,1 vped (p/h) 10 10 10 10
Conflicting bicycle volume,1,7 vbic (bicycles/h) 20 20 20 20
vpedg = vped(C/gp) 26.9 26.9 19.4 19.4
OCCpedg = vpedg/2000 if (vpedg 1000), or
OCCpedg = 0.4 vpedg/10,000 if (1000 < vpedg 5000) 0.0135 0.0135 0.0097 0.0097
Effective green,1 g (s) 26 26 36 36vbicg = vbic(C/g) 54 54 39 39
OCCbicg = 0.02 + vbicg/2700 0.040 0.040 0.034 0.034
OCCr = OCCpedg OCCbicg (OCCpedg)(OCCbicg) 0.053 0.053 0.044 0.044
Number of cross-street receiving lanes,1 Nrec 1 1 2 2
Number of turning lanes,1 Nturn 1 1 1 1
ApbT = 1 OCCr if Nrec = Nturn
ApbT = 1 0.6(OCCr) if Nrec > Nturn0.947 0.947 0.974 0.974
Proportion of right turns,5 PRT 0.0632 0.0418 0.0719 0.0986
Proportion of right turns using protected phase,8 PRTA 0 0 0 0
fRpb = 1.0 PRT(1 ApbT)(1 PRTA) 0.997 0.998 0.998 0.997
Notes
1. Refer to Input Worksheet. 5. Refer to Volume Adjustment and Saturation Flow Rate Worksheet.2. If intersection signal timing is given, use Walk + flashing Don't Walk (use G + Y if 6. Ideally determined from field data;
alternatively, assume it equal to no pedestrian signals). If signal timing must be estimated, use (Green Time Lost(1 permitted
phase fLT)/0.95.
Time per Phase) from Quick Estimation Control Delay and LOS Worksheet.7. If vbic = 0 then vbicg = 0, OCCbicg = 0, and OCCr =
OCCpedg.
3. Refer to supplemental worksheets for left turns. 8. PRTA is the proportion of protected green over the total green,
gprot/(gprot
4. If unopposed left turn, then gq = 0, vo = 0, and OCCr = OCCpedu = OCCpedg.+ gperm). If only permitted right-turn phase exists,
then PRTA = 0.
Permitted Right Turns
SUPPLEMENTAL WORKSHEET FOR PEDESTRIAN-BICYCLE EFFECTS ON PERMITTED LEFT TURNS AND RIGHT TURNS
General Information
Project Description Example Problem 1
Permitted Left Turns
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Phase number 1 1 2 2
Phase type P P P P
Lane group
Adjusted flow rate, v (veh/h) 843 877 510 710
Saturation flow rate, s (veh/h) 2915 2941 1706 1695
Lost time, tL (s), tL = l1 Y e 4 4 4 4Effective green time, g (s), g = G Y tL 26 26 36 36
Green ratio, g/C 0.371 0.371 0.514 0.514
Lane group capacity,1 c = s(g/C), (veh/h) 1082 1091 877 871.3
v/c ratio, X 0.78 0.8036 0.582 0.815
Flow ratio, v/s 0.289 0.419
Critical lane group/phase ()
Sum of flow ratios for critical lane groups, Yc
Yc = (critical lane groups, v/s)
Total lost time per cycle, L (s)
Critical flow rate to capacity ratio, Xc
Xc = (Yc)(C)/(C L)
EB WB NB SB
Lane group
Adjusted flow rate,2 v (veh/h) 843 877 510 710
Lane group capacity,2 c (veh/h) 1081.6 1091 877 871.3
v/c ratio,2 X = v/c 0.7797 0.80 0.582 0.815
Total green ratio,2 g/C 0.371 0.37 0.514 0.514
2
Uniform delay, d1 = 0.50 C *1 (g/C)+ (s/veh)
1 *min(1, X)g/C+
19.48 19.73 11.79 14.22
Incremental delay calibration,3 k 0.5 0.5 0.5 0.5
Incremental delay,4 d2
d2 = 900T*(X 1) (X 1)2 e8kIX ](s/veh)
cT
-49.065 -43.72 -93.5 -41.19
Initial queue delay, d3 (s/veh) (Appendix F) 0 0 0 0
Uniform delay, d1 (s/veh) (Appendix F)
Progression adjustment factor, PF 0.926 1.111 1 1
Delay, d = d1(PF) + d2 + d3 (s/veh) -31.02 -21.81 -81.71 -26.96
LOS by lane group (Exhibit 16-2) C C F C
Delay by approach, dA = e(d)(v) (s/veh)
v
LOS by approach (Exhibit 16-2)
Approach flow rate, vA (veh/h)
Intersection delay, dI = (dA)(vA) (s/veh)
vA
Notes
1. For permitted left turns, the minimum capacity is (1 + PL)(3600/C).
2. Primary and secondary phase parameters are summed to obtain lane group parameters.
3. For pretimed or nonactuated signals, k = 0.5. Otherwise, refer to Exhibit 16-13.
4. T = analysis duration (h); typically T = 0.25, which is for the analysis duration of 15 min.
I = upstream filtering metering adjustment factor; I = 1 for isolated intersections.
843 877 510 710
-36.09 Intersection LOS (Exhibit 16-2) D
-81.71 -26.96
C C F C
-31.02 -21.81
0.78
Lane Group Capacity, Control Delay, and LOS Determination
8
CAPACITY AND LOS WORKSHEET
General information
Project DescriptionExample Problem 1
Capacity Analysis
0.69