tugas 5 geo analitik bangun dan ruang

7/29/2019 Tugas 5 Geo Analitik Bangun Dan Ruang

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Tugas 5 Geometri Analitik Bangun Dan Ruang

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NAMA : PHELIPUS MERE

NIM : 1001036019

PRODI : P. MATEMATIKA

SEMESTER : V

1. Find the equation of the line passing thorough the point of intersection ofthe line + 2 6 = 0 5 2 6 = 0 and containing the point (3,4)

Answer:

+ 2 6 + (5 2 6) = 0

Substitusing the containing point:

3 + 2(4) 6 + (5(3) 2(4) 6) = 0

5 + (1) = 0

= 5

Substituting the value of k:

+ 2 6 + 5(5 2 6) = 0

24 + 12 + 24 = 0

2 + + 2 = 0

2. Find the equations of the line passing thorough the point of intersection

of the line + 2 4 = 3 4 12 = 0 and containing the point

(2,1)

Answer:

+ 2 4 + (3(2) 4(1) 12) = 0

(6 4 12 = 0

= 0


+ 2 4 + 0(3 4 12) = 0

+ 2 4 = 0

3. Find the equation of the line passing thorough the point of intersection of

the line 2 3 + 7 = 0 + 7 = 0 and contains the origin.

Answer:


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2 3 + 7 + ( + 7 7) = 0

Substituting the containing point ( 0,0)

2(0) 3(0) + 7 + (0 + 0 7) = 0

7 = 7

= 1


2 3 + 7 + 1( + 7) = 0

2 3 + 7 + + 7 = 0

3 2 = 0


the line + 6 = 0 2 + = 0 and having a y- intercept of 2.

Answer:

Having a y- intercept of 2, it means the containing point is (0.2).

+ 6 + (2 + ) = 0

4 + 2 = 0

= 2


+ 6(2(2 + ) = 0

+ 6 + (4 2 ) = 0

3 3 + 6 = 0

x-y+2=0


the line + 8 = 0 + 2 = 0 and having a x- intercept of -4.

Answer:having a x- intercept of -4, it line means the containing points is (-4,0).

+ 8 + ( + 2 ) = 0

Substituting the containing points:

4 0 + 8 + 4 + 2(0) = 0


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8 + (4 ) = 0

= 2


+ 8 + (2( + 2 ) = 0

+ 8 + (2 4 ) = 0

5 + 8 = 0

Soal diatas di ambil dari buku PLANE ANALYTIC GEOMETRY halaman

49 no 4, 5, 7, 8 dan 12 sebagai no 1 s/d 5 dalam posting saya

tugas 5 geo analitik bangun dan ruang

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