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7/29/2019 Tugas 5 Geo Analitik Bangun Dan Ruang
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Tugas 5 Geometri Analitik Bangun Dan Ruang
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NAMA : PHELIPUS MERE
NIM : 1001036019
PRODI : P. MATEMATIKA
SEMESTER : V
1. Find the equation of the line passing thorough the point of intersection ofthe line + 2 6 = 0 5 2 6 = 0 and containing the point (3,4)
Answer:
+ 2 6 + (5 2 6) = 0
Substitusing the containing point:
3 + 2(4) 6 + (5(3) 2(4) 6) = 0
5 + (1) = 0
= 5
Substituting the value of k:
+ 2 6 + 5(5 2 6) = 0
24 + 12 + 24 = 0
2 + + 2 = 0
2. Find the equations of the line passing thorough the point of intersection
of the line + 2 4 = 3 4 12 = 0 and containing the point
(2,1)
Answer:
+ 2 4 + (3(2) 4(1) 12) = 0
(6 4 12 = 0
= 0
Substituting the value of k:
+ 2 4 + 0(3 4 12) = 0
+ 2 4 = 0
3. Find the equation of the line passing thorough the point of intersection of
the line 2 3 + 7 = 0 + 7 = 0 and contains the origin.
Answer:
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2 3 + 7 + ( + 7 7) = 0
Substituting the containing point ( 0,0)
2(0) 3(0) + 7 + (0 + 0 7) = 0
7 = 7
= 1
Substituting the value of k:
2 3 + 7 + 1( + 7) = 0
2 3 + 7 + + 7 = 0
3 2 = 0
4. Find the equation of the line passing thorough the point of intersection of
the line + 6 = 0 2 + = 0 and having a y- intercept of 2.
Answer:
Having a y- intercept of 2, it means the containing point is (0.2).
+ 6 + (2 + ) = 0
4 + 2 = 0
= 2
Substituting the value of k:
+ 6(2(2 + ) = 0
+ 6 + (4 2 ) = 0
3 3 + 6 = 0
x-y+2=0
5. Find the equation of the line passing thorough the point of intersection of
the line + 8 = 0 + 2 = 0 and having a x- intercept of -4.
Answer:having a x- intercept of -4, it line means the containing points is (-4,0).
+ 8 + ( + 2 ) = 0
Substituting the containing points:
4 0 + 8 + 4 + 2(0) = 0
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8 + (4 ) = 0
= 2
Substituting the value of k:
+ 8 + (2( + 2 ) = 0
+ 8 + (2 4 ) = 0
5 + 8 = 0
Soal diatas di ambil dari buku PLANE ANALYTIC GEOMETRY halaman
49 no 4, 5, 7, 8 dan 12 sebagai no 1 s/d 5 dalam posting saya