tugas lendutan beton prategang

7/26/2019 TUGAS LENDUTAN BETON PRATEGANG

1/33

TUGAS BETON PRATEGANGNAMA : ACHMAD SUKUR

KELAS : 3MRK 1

NIM : 1341320014

ql = 1700

A

A

22 m

35

20

5!135

55

15

525

53!"7

25

35

POTONGAN A#A

NO

PENAMPANG

DIMENSI $%m& LUAS '% $'%! A(&

PENAMPANG )( *( $%m&

1 S+,( Em-./ 20 35 700 100!00 70000!00

$%m&

2

3

1

4 5

6 7


2/33

S+,( T(,. 5 10 25!00 2!7 !7

7 S+,( T(,. 5 10 25!00 2!7 !7

UMLAH 250 142750

A) DATA PERENCANAAN :

T(/( B+./ $'*& = 53!"72453 %m

Mm+ I+6(. = 350""7!11

P.., B+/., $L& = 22 m

= 2200 %m

G!P+66/+66+8 $P& = 0 /

0000 ,

E6+/(6(/.6 $ + & = 25 %m

B+*. H(89- $ql& = 1700 ,m;

= 17 ,%m;

= 2400

= 0!0024 ,%m

B+*. M./( $q8& =

= !3 ,%m;

M9/9 B+/ = 40 M-.

400

K+)(l.,. P./+,., 15.l

= #72!712544

= 32!133001

2& K8(6( A)(

= #270!1242

= 221!47012

E) Kontrol Tengangan

S../ : T+,.,. '., /+.8( ? M9/9 B+/

270!1242 ? 400

F) Jarak ert!kal t!t!k e "an T!t!k P

,%m

,%m

,%m

,%m

,%m

,%m

,%m

,%m

,%m

,%m ,%m

_ ) 3 )=(85% . . .( (_ )" /

_ ) 3 )=(85% .( (_. . ) " /

_ ) 4 )=(( (_ _( .) )_ /

_ ) 4 )= _( . )( (_ ( )_ /

_ ) 1 2 3( #_ $_ $_

_ ) 1 2 3( #_ $_ $_

_ ) 1 2 3 4( #_ $_ $_ $_

_ ) 1 2 3+ 4( #_ $_ $_ _

_ )=(

=tan /2


4/33

F) Ga#$ar Tegangan

#73!"7 #1!20 20

5!13

53!"7

70!" #1!20

#73!"7 #1!20 20

( - )

( + )

+


5/33

53!"7

70!" #1!20

( + )


6/33

,m;

110

8(

$%m&

23333!33 4!13 1513051!20

IO I//.l

$IO A( !8(&( 4)

( 4

)


7/33

34!72 #27!20 1"532!43

34!72 #27!20 1"532!43

350""7!11


8/33

%OK)

=


9/33

#72!72

#1!53 32!1

#17!45 #270!1242

( -

)

( + )

( - )

+ =

( -

)

( + )

( + ) ( ( )


10/33

#1!53 1"!4" 221!47012

( - )

( + )

( +

)


11/33

TUGAS BETON PRATEGANGNAMA : ACHMAD SUKUR

KELAS : 3MRK 1

NIM : 1341320014

ql = 1"50

A

A

25 m

30

27

1!"10

45

15

1550

3!11

2"

2"

POTONGAN A#A

NOPENAMPANG

DIMENSI $%m& LUAS '% $'%! A(&

PENAMPANG )( *( $%m&

1 S+,( Em-./ 27 30 "10 111!50 0315!00

$%m&

2

3

1

4 5

6 7

( 4)


12/33

S+,( T(,. 15 !5 4"!75 33!00 10"!75

7 S+,( T(,. 15 !5 4"!75 33!00 10"!75

UMLAH 2"17 17775"

A) DATA PERENCANAAN :

T(/( B+./ $'*& = 3!1132114 %m

Mm+ I+6(. = 44"1442!5

P.., B+/., $L& = 25 m

= 2500 %m

G!P+66/+66+8 $P& = 20 /

20000 ,

E6+/(6(/.6 $ + & = 30 %m

B+*. H(89- $ql& = 1"50 ,m;

= 1"!5 ,%m;

= 2400

= 0!0024 ,%m

B+*. M./( $q8& =

= !75 ,%m;

M9/9 B+/ = 3 M-.

30

K+)(l.,. P./+,., 12!500

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