praktis math tahun 6

8/18/2019 Praktis Math Tahun 6

1/20

Kemahiran Asas Matematik 21


1 2 jam 45 min = min

6 1 3

1— - — =

3 5

2 3. 05 m = cm 7 Isipad k!s "an# sisin"a

$ cm =

3 0.15k# % $50# = # $ &as se#iti#a !ersdt te#ak "an#

tin##in"a 17 cm dan tapakn"a

6 cm =

4 25 ' dpd (M 320 = ) 6 jam 4$min

% 1$ jam 3) min

5 *am 1525 = pk+ 10 3 1

— - — =

4 3


2/20


1 10 , 0.75 = 6 &as se#iempat sama "an# sisin"a

30 cm=

2 0.75 4$0 = 7 ar#a 3 nit = (M 24

ar#a ) nit=

3 4

11 - — =

7

$ 2 3

1 — - — =

5 4

4 2.75 k# , 1550 # = k# # ) Isipad k!/id "an# !erkran

$cm12cm dan 20 cm=

5 1254 sen= (M 10 Masa !er+epas = jam 01 30

erja+anan = 20jam 15min

Masa ti!a=


3/20


1 3 7

— m % — m = cm

4 10

6 5 3

— - — =

6 $

2 *ika 100' = 60 /ran#.

15 ' =

7 1356 m+ % 0. 53 +iter = m+

3 *ika har#a asa+n"a (M 1$.00

iskan 10 ' !erapa har#a

ja+n"a

$ 750cm - 4. 05 m = m

4 *ika +as se#iempatsama ia+ah

144 cm perse#i !erapakah

perimetern"a

) 3 5

1—jam % — jam= min

4 6

5 3 )

— k# % — k# = #

5 10

10 24 1)36 11 dan 27

ratan"a =


4/20


1 0.04 % 3.26 - 1.75 =2 jam 45 min =

min

6 1 5

1— - — =

$ 6

2 Masa ti!a = jam 10 20

erja+anan = $jam 30min

Masa !ert/+ak =

7 Isipad k!s "an# sisin"a

) cm =

3 1 3

2— %1— =

6 4

$ &as se#iti#a !ersdt te#ak "an#

tin##in"a 1$ cm dan tapakn"a

) cm =

4 2 km , 14 )5 m = m ) $ jam 45min

% 10 jam 5) min

5 500 – 480 ÷ 8 = 10 5 3

— - — =

6 4


5/20


1 12 , 0.4$5 = 6 35 ' dpd 120 =

2 0.45 200 = 7 2. 5 % 0. 6 5 =

3 5

5 - — =

6

$ 1000 0.125 =

4 2 k# , 1050 # = k# # ) 3 1

— % — =

5 2

5 10 000 sen= (M 10 3 jam 05 min = min


6/20


1 2 . 55 m = cm 6 &as se#iempat sama "an# sisin"a

40 cm=

2 2.05k# % 754# = # 7 ar#a 5 nit = (M 4 5

ar#a ) nit=

3 45 ' dpd (M 5000 = $ 1 3

1 — - — =

5 4

4 *am 0025 = pk+ ) Isipad k!/id "an# !erkran

10cm12cm dan $ cm=

5 $ 5

— - — =

) 6

10 Masa !er+epas = jam 20 30

erja+anan = 4jam 15min

Masa ti!a=


7/20

Kemahiran Asas Matematik 2$

1 1 3

— m % — m = cm

4 10

6 1$00 m+ - 0. )$ +iter = m+

2 *ika 30' = 6 /ran#.

100 ' =

7 )00cm - 4. 5 m = m

3 *ika har#a asa+n"a (M 240 .00


ja+n"a

$ 1 5

1—jam - — jam= min

4 6


4) cm perse#i !erapakah

perimetern"a

) 25 1535 40 dan 20

ratan"a =

5 1 1

— k# - — k# = #

5 10

10 0.25 % 3. 5 - 1. 415 =


8/20

Kemahiran Asas Matematik 2)

1 Masa ti!a = jam 10 20pm

erja+anan = $jam 30min

Masa !ert/+ak =

6 1 3

1— - — =

2 5

2 5 5

3— %1— =

$ 6

7 Isipad k!s "an# sisin"a

10 cm =

3 2.15 km , 1$)5 m = m $ &as se#iti#a !ersdt te#ak "an#


14 cm =

4 1000 + 96 ÷ 12 = ) 14 jam 55 min

%12 jam 45 min

5 40 ' dpd 120 = 10 4 2

— - — =

5 3


9/20


10/20

1 7$0 # % )50 # = k# 6 &as se#iempat sama "an# sisin"a 50

cm=

2 35 ' dpd (M 300 = 7 ar#a 10 nit = (M 24

ar#a 5 nit=

3 *am 0245 = pk+ $ 1 3

2 — - — =

5 4

4 2 2

— - — =

3 5

) Isipad k!/id "an# !erkran

$cm10cm dan 20 cm=

5 1. 2 + - 0. 53 + = m+ 10 Masa !er+epas = jam 1$ 30

erja+anan = 6 jam 15min

Masa ti!a=


11/20



1 3 3

— m - — m = cm

4 10

6 1750cm - $. 75m = m

2 *ika 25 ' = 60 /ran#.

100 ' =

7 3 5


4 6

3 *ika har#a asa+n"a (M 1 . 00


ja+n"a

$ 20 1030 40 dan 50

ratan"a =


16) cm perse#i !erapakah

perimetern"a

) 0. 45 % 3.2 X 4 =

5 4 3

— k# - — k# = #

5 10

10 Masa ti!a = jam 0) 20

erja+anan = 6jam 30 min

Masa !ert/+ak


12/20


1 1 1

4 — % 2 — =

6 2

6 1 3

1— - — =

2 4

2 1. 02 km , $ )5 m = m 7 Isipad k!s "an# sisin"a

15 cm =

3 1 000 – 500 ÷ 5 = $ &as se#iti#a !ersdt te#ak "an#


15 cm =

4 40 ' dpd $0 = ) 3 jam 05 min

- 1 jam 35 min

5 200 % 6 5 = 10 1 2

1— - — =

4 3


13/20


1 10 , 5.225 = 6 1000 0.245 =

2 1. 5 4$0 = 7 4 1

— - — =

5 4

3 5

5 - — =

6

$ 1 jam 25 min = min

4 2. 5 k# , 355 # = k# # ) 0. 45 m = cm

5 2020 sen= (M 10 0.75 k# % 550 # = #


14/20


1 &as se#iempat sama "an# sisin"a

50 cm=

6 1 )

— m % — m = cm

4 10

2 ar#a 4 nit = (M 24

ar#a 10 nit=

7 *ika 40 ' = 60 /ran#.

100 ' =

3 1 3

1 — - — =

6 4

$ *ika har#a asa+n"a (M 120 .00


ja+n"a

4 Isipad k!/id "an# !erkran

$cm10cm dan 20 cm=

) *ika +as se#iempatsama ia+ah


perimetern"a

5 Masa !er+epas = jam 21 30


Masa ti!a=

10 4 3

— k# % — k# = #

5 10


15/20


1 15 ' dpd (M 32 = 6 1 5


4 6

2 *am 2325 = pk+ 7 12 1)16 15 dan 13

ratan"a =

3 5 3

— - — =

6 4

$ 1.25 % 3. 3 X 3 =

4 1600m+ % 0. $5 +iter = m+ ) Masa ti!a = jam 04 20

erja+anan = $jam

Masa !ert/+ak =

5 )00cm - 4. 5 m = m 10 1 3

4— % 3— =

6 $


16/20


1 1.4 km , )5 m = m 6 1 3

1— - — =

2 4

2 10 % 0.054 + 0.25 = 7 Isipad k!s "an# sisin"a

10 cm =

3 20 ' dpd (M 100 = $ &as se#iti#a !ersdt te#ak "an#


15 cm =

4 450 % )0 3 = ) 4 jam 05 min

- 1 jam 45 min

5 100 0.45 = 10 1 )

10 — - 1 — =

100 10

perp+han


17/20

Kemahiran Asas Matematik 3$

1 10 , 4. $5 = 6 3 7

2 % — % — =

100 10 perp+han

2 1. 2 400 = 7 2 jam 15 min = min

3 3

2 - — =

$

$ 0. 4 m = cm

4 2. 5 k# , 355 # = k# # ) 0.)5 k# % 75 # = #

5 8erapakah !akin"a jika (M 20

dit/+ak den#an 1050 sen

10 10 ' dpd (M 55 =


18/20

Kemahiran Asas Matematik 3)

1 &as se#iempat sama "an# sisin"a

)0 cm=

6 1 3

— m - — m = cm

2 10

2 ar#a 6 nit = (M 4$

ar#a 12 nit=

7 *ika 4 ' = 4 /ran#.

100 ' =

3 1 4

1 — - — =

3 5

$ *ika har#a asa+n"a (M 1250 .00


ja+n"a

4 Isipad k!/id "an# !erkran

5 cm 10cm dan 30cm=

) *ika +as se#iempatsama ia+ah


perimetern"a

5 Masa !er+epas = 10.30 am


Masa ti!a= jam

10 3 )

— k# % — k# = #

5 100


19/20


1 k+ 6.45 pa#i = jam 6 120 1)0160150 dan 130

ratan"a =

2 2 4

1 — - — =

3 5

7 1.25 % 0. 3 X 3 =

3 160m+ % 0. 5 +iter = m+ $ Masa ti!a = jam 10 20

erja+anan = 5 jam

Masa !ert/+ak =

4 1$00cm - 4. 5 m = m ) 1 3

4— % 3— =

6 $

5 1 5


10 6

10 1.2 km , 250 m = m


20/20

1 10 % 2.45 +1.078 = 6 1 5

2— - — =

2 6

2 120 ' dpd (M 200 = 7 Isipad k!s "an# sisin"a

14 cm =

3 63 ) X 100 = $ &as se#iti#a !ersdt te#ak "an#


12 cm =

4 1000 0. 035 = ) $ jam 24 min

- 5 jam 45 min

5 12 3

5 % — % — =

100 10 perp+han

10 3 )

4 — - 2 — =

100 10

perp+han

praktis math tahun 6

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