model transportasi, soal.docx
TRANSCRIPT
Toko/pabrikToko 1Toko 2Toko 3Toko 4AI
A265450
B51011640
C7891030
D4128720
Dummy000010
BJ35455020
Tabel Matriks TransportasiAI = 140 + 10 = 150BJ = 150Metode NWC Toko/pabrikToko 1Toko 2Toko 3Toko 4AI
A3521565450
B530101011640
C783091030
D41210810720
Dummy00010010
BJ35455020
Distribusi Biaya :1. A Toko 1 = 35 x 2 = 702. A Toko 2 = 15 x 6 = 903. B Toko 2 = 30 x 10 = 3004. B Toko 3 = 10 x 11 = 1105. C Toko 3 = 30 x 9 = 2706. D Toko 3 = 10 x 8 = 807. D Toko 4 = 10 x 7 = 708. Dummy Toko 4 = 10 x 0Total Biaya : 990
Metode Least Cost :Toko/pabrikToko 1Toko 2Toko 3Toko 4AI
A25265520450
B515102511640
C730891030
D412208720
Dummy10000010
BJ35455020
Distribusi Biaya :1. A Toko 1 = 25 x 2 = 502. A Toko 3 = 5 x 5 = 253. A Toko 4 = 20 x 4 = 804. B Toko 2 = 15 x 10 = 1505. B Toko 3 = 25 x 11 = 2756. C Toko 2 = 30 x 8 = 2407. D Toko 3 = 20 x 8 = 1608. Dummy Toko 1 = 10 x 0Total Biaya : 980
Metode Vogel :Toko/pabrikToko 1Toko 2Toko 3Toko 4AI
A265054502 2 2
B15551011206401 1 1 1 5
C7308910301 1 1 1 1
D2041287203 3
Dummy010000100
BJ35455020
22322622222534
4224
Distribusi Biaya :1. A Toko 3 = 50 x 5 = 2502. B Toko 1 = 15 x 5 = 753. B Toko 2 = 5 x 10 = 504. B Toko 4 = 20 x 6 = 1205. C Toko 2 = 30 x 8 = 2406. D Toko 1 = 20 x 4 = 807. Dummy Toko 2 = 10 x 0Total Biaya : 815
Kesimpulan : Metode yang dipilih adalah metode Vogel Karena menghasilkan Total biaya terendah yaitu 815.