bab 3 ( melintang )

8/10/2019 Bab 3 ( Melintang )

1/27

IKATAN MAH ASISWA SIPIL

FAKULTASTEKNIK JURUSAN TEKNIKSIPIL

DESMAWATI

03101001011

PERHITUNGAN PASAK GELAGAR MELINTANG

P1 P1

P3 p4 p2 p2 p2 p2 p2 p2 p2 p4 p3

1 m 0.5 0.5 0.5 0.5 0.5 0.5 0.5 0.5 1 m

6 m

Diketahui : Jarak gelagar memanjang = 0,5 m

Jumlah gelagar memanjang = 13 buah

Jarak gelagar melintang = 3 m

Lebar Jembatan = 6 m

CivilEngineering ofSriwijaya University


2/27



DESMAWATI

03101001011

Pembebanan

1. Akibat Lantai Kendaraan

eban P1

erat gelagar memanjang = 0,2 ! 0,25 ! "50 = 4#.5 kg$m

erat papan lantai tr%t%ar = 0,0# ! 0,2 ! "50 = 13.3 kg$m

erat air hujan = 0,05 & 0,5 & 1000 = 25 kg$m

erat bal%k 'an(aran = 0,25 & 0,2 & "50 kg$m = 4#,5 kg$m

) = 133.3 kg$m

*%e'lag 10 + = 13.33 kg$m

) 1 = 146.63 kg$m

Jarak gelagar melintang 3 meterP1 = ) 1. L

= 146.63 kg$m ! 3

= 43"." kg

eban P!

erat gelagar memanjang tr%t%ar -20$25 = 0,2 ! 0,25 ! "50 = 4#.5 kg$m

erat papan Lantai ata' -5$25 = 0.05 ! 0,25 ! "50 = 11,#5 kg$m

erat papan lantai ba/ah -15$25 = 0,15 ! 0,25 ! "50 = 35.625 kg$m

erat a'pal = 0,0# ! 0,25 ! 1000 = 1#.5 kg$m

erat air ujan =0,05 ! 0,25 ! 1000 = 12.5 kg$m

= 125kg$m


+

+


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DESMAWATI

03101001011

*%e'lag 10+ = 12,5kg$m

) = 13#.5 kg$m

Dengan jarak gelagar melintang a(alah 3 m, maka

P2 = )2 ! L

= 13#.5 kg$m ! 3 m

= 412.5 kg

eban P3

erat gelagar memanjang tr%t%ar -20$25 = 0,2 ! 0,25 ! "50 = 4#.5 kg$m

erat papan Lantai ata' -5$25 = 0.05 ! 0,5 ! "50 = 23.#5 kg$m

erat papan lantai ba/ah -15$25 = 0,15 ! 0,5 ! "50 = #1.25 kg$m

erat a'pal = 0,0# ! 0,5 ! 1000 = 35 kg$m

erat air ujan =0,05 ! 0,5 ! 1000 = 25 kg$m

= 202.5 kg$m

*%e'lag 10+ = 20.25kg$m

) = 222.#5 kg$m

aka, P3 = ) 3! L

= 222.#5 kg$m ! 3 m

= 66.25 kg



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DESMAWATI

03101001011

eban P"

erat gelagar memanjang tr%t%ar = 0,2 ! 0,25 ! "50 = 4#.5 kg$m

erat papan lantai tr%t%ar = 0,0# ! 0,2 ! "50 = 13.3 kg$m

erat air hujan = 0,05 ! 0,5 ! 1000 = 25 kg$m

) = 5. kg$m

*%e'lag 10+ = .5 kg$m

) = "4.3 kg$m

Jarak gelagar melintang 3 meter

P4 = ) 4. L

"4.3 kg$m ! 3 m

= 23.14 kg

eak'i Perletakan

= 0- . 6 -P3 . 6 7 -P1 . 4 7 -P4 . 4 7 P2 - 3,5 3 2,5 2 1,5 7 -P 1 . 2 7 -P4 . 2 =0

6 = -66.25 ! 6 -43"." ! 4 -23.14 ! 4 -412.5 ! 12,5 -43"."! 2

-23.14 ! 2

6 = 13503."3 kg

= 2250.655 kg.

RA # R # !!$0.%$$ k&

%men ak'imum 8ang terja(i (itengah bentang

ma! = - 3 P3 - 3 P1 - 1 7 P4 - 1 7 P2 - 1.5 7 P2 - 0,5

= - 3 P3 - 3 - P1 P4 1 P2 - 1.5 0,5



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DESMAWATI

03101001011

= 2250.655 - 3 66.25 - 3 -43"." 23.14 1 412.5 -

1.5 0,5

= 6#51."65 2004.#5 #23.03 25

= 31"".15 kg.m

9ma! = 7 P3 = 2250.655 7 66.25 = 152.405

!. Akibat M'atan L(adin&

Dari '%al (iketahui :

uatan gari' P = 5 t%n

uatan merata ) = 1,25 t$m

ntuk jembatan kela' ;;; , (iambil #0+

uatan gari' P = 5 t%n ! #0 + = 3.5 t%n uatan merata ) = 1,25 t$m ! 30 + = 0.#5 t$m

Jarak gelagar melintang 3 m


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DESMAWATI

03101001011

9ma! = 21 ) ! L

= 21 ! 201 kg$m ! 3 m

= 301.5 kg

aka be'arn8a ga8a :

P2 = P 9

= 05 kg 301.5 kg

= 1106.5 kg

P1 = 21 ! P2

= 21 ! 1106.5 kg

= 553.25 kg

= = P1 3,5 P2 .

= 553.25 kg -3.5 ! 1106.5 kg = 4426 kg

ma! = - 3 P1- 2 P2-1.50,5

=4426 -3 553.25 -2 1106.5 -2

= 132# 1106.5 2213

= ""5.5 kg.m

9ma! =

= 4426 kg

3. Akibat berat )endiri &e*a&ar me*intan&

elagar melintang (iren>anakan 30$0



7/27



DESMAWATI

03101001011

) = 0,3 ! 0, ! "50

= 22 kg$m

ma! = 1$ ! ) ! L

= 1$ ! 22 ! 62

= 1026 kgm

9ma! = ? ! ) ! L

= ? ! 22 ! 6

= 64 kg

ma! t%tal = -31"".15 kgm ""5.5 kgm 1026 kgm

= 1413.65 kgm

9ma! t%tal = -301.5 kg 4426 kg 64 kg

= 5411.5 kg

/ =6

1 ! b ! h2

=6

1 ! 30 >m ! -0 >m2

= 32000 >m3

1. K(ntr(* Tek'k

tk #

W

M totalmax#

32000

1418368.5= 44.32 kg$>m2

S+arat aman



8/27



DESMAWATI

03101001011

lltk

@lltk

44.32 kg$>m2 @ 46.#5 kg$>m2 . . . . . . . AMAN

!. K(ntr(* Te&an&an Ge)er

=hb2

Qx3 total

= 80302

5411.53

xx

x

= 3.32 kg$>m

S+arat Aman

@

ll

3.32 kg$>m2 @ 5 kg$>m2 . . . . . . . AMAN , ,

3. K(ntr(* Lend'tan

) = 22 kg$m

; = 3hb12

1

= 38x3x12

1

= 120000 >m4

". Lend'tan mak)im'm ter-adi di ten&a bentan&

kibat P3 (i titik 1

a = 1 meter

b = 6 m 1 m = 5 meter



9/27



DESMAWATI

03101001011

#LxEI3

bxaxP 22

= ( ) ( ) ( )

( )( )( )600101281250003500100668.254

22

x

= 0,005 >m

kibat P2(i titik 2

a = 1 meterb = 5 m 1 m = 4 meter

#LxEI3

bxaxP 22

= ( ) ( ) ( )

( )( )( )5001012812500034001003633,65

4

22

x

= 0,024 >m

kibat P2(i titik 3

a = 1,5 meter

b = 5 m 1,5 m = 3,5 meter

#LxEI3

bxaxP 22

= ( ) ( ) ( )

( )( )( )5001012812500033501503633,654

22

x

= 0,041 >m

kibat P2(i titik 4

a = 2 meter



10/27



DESMAWATI

03101001011

b = 5 m 2 m = 3 meter

#LxEI3

bxaxP 22

= ( ) ( ) ( )

( )( )( )5001012812500033002003633,65

4

22

x

= 0,054 >m

kibat P2(i titik 5

a = 2.5 meter

b = 6 m 2.5 m = 3.5 meter

#LxEI3

bxaxP 22

=

( ) ( ) ( )

( )( )( )6001012812500033502503633,65

4

22

x

= 0,0"# >m

kibat P2(i titik 6

a = 3 meter

b = 6 m 3 m = 3 meter

#LxEI3bxaxP 22

= ( ) ( ) ( )

( )( )( )6001012812500033003003633,65

4

22

x

= 0,102 >m



11/27



DESMAWATI

03101001011

kibat )

! =

IE38"

Lx!x# "=

( ) ( )

)1280000)(125000(384

60028.254

= 0.024 >m

max = 2 1 2 2 2 3 2 " 2 " 2 q

= 2 -0,005 2 -0,024 2 -0,041 2 -0,054 2 -0,102 2 -0.024

= 0,5016 >m

="

L=

400

600= 1,5 >m

A8arat :

@

0,5016 >m @ 1,5 >m . . . . . . . AMAN , ,

PERHITUNGAN PASAK GELA/AR MELINTANG

ntuk gelagar melintang (igunakan bal%k 30$0 (i'u'un ter'u'un 3 lapi' :



12/27



DESMAWATI

03101001011

30

i(ang Lintang gelagar ter'ebut :

P1 P1

P3 p4 p2 p2 p2 p2 p2 p2 p2 p4 p3

1 m 0.5 0.5 0.5 0.5 0.5 0.5 0.5 0.5 1 m

6 m

i(ang Lintang


1

1

6


13/27



DESMAWATI

03101001011

Diketahui :

P1 = 43"." kg

P2 = 412.5 kg

P3 = 66.25 kg

P4 = 23.14 kg

) = 22 kg$m

= = ? )L P1 P2 P3 P4= ? ! 22 kg$m ! 6 m 43"." kg 412.5 kg 66.25 kg 23.14 kg= 24#.# kg

Barena batang 'imetri' maka (itinjau 'etengah 'aja :

9 =

= 24#.# kg

9 kanan = 97 P3= 24#.# kg 66.25 kg= 11".53 kg

o 9 kiri = 9 kanan 7 )= 11".53 kg 7 - 22 kg

= 15"1.53 kg9 kanan = 9 kiri -P4P1

= 15"1.53 kg -23.14 kg 43"."

= 6.5 kg

o 9C kiri = 9 kanan 7 ) 0,5



14/27



DESMAWATI

03101001011

= 6.5 kg 7 - 22 ! 0.5 kg

= #54.5 kg

9C kanan = 9C kiri P2

= #54.5 kg 412.5 kg

= 342 kg

o 9D kiri = 9C kanan 7 ? )= 342 kg 7 - 0,5 . 22kg

= 22 kg9D kanan = 9D kiri ? )

= 22 kg kg

= 10 kg

o 9 kiri = 9D kanan 7 ? )= 114 kg 7 - 0,5 . 22 kg

=0kg



15/27



DESMAWATI

03101001011

a8a e'er Per Aatuan Panjang

=b =

I

S$%

Dengan >atatan E;F (apat (iambl tanpa re(uk'i - Geli! 8ap hal #1 . ma! (apat (i>ari

(engan menggunakan 'iGat7'iGat titik parab%la.

maka : =max = h2Q3

Ga+a &e)er +an& ter-adi 'nt'k 1 ba*(k

A =( )

( )cm

kg

802

78,24873= 46.65 kg$>m

ka&a&A =( )

( )cm

kg

802

1819.533= 34.12 kg$>m

30 kanan = 34.1240

1034.12

2

= 31."" kg$>m



16/27



DESMAWATI

03101001011

k'(') =( )

( )cm802

1591.533= 2".4 kg$>m

30 kiri = 29.8440

1029.84

2

= 2#." kg$>m

ka&a&) =( )

( )cm

kg

802

868.53= 16.2 kg$>m

30 kanan = 16.2840

1016.28

2

= 15.26 kg$>m

k'('* =( )

( )cm

kg

802

754.53 = 14.15 kg$>m

30 kiri C = 15.1540

1014.15

2

= 13.26kg$>m

ka&a&* =( )

( )cm

kg

802

3423 = 6.412 kg$>m

30 kanan C = 174,3740

10174,37

2

= #6,2 kg$>m

k'('% =( )

( )cm

kg

802

2283 = 4.2#5 kg$>m

30 kiri D = 4.27540

104.275

2

= 4.01 kg$>m

ka&a&% =( )

( )cm

kg

802

1083 = 2.025 kg$>m

30 kanan D = 025.240

102.025

2

= 1."0 kg$>m

k'('E =( )

( )cm

kg

802

03 = 0 kg$>m

30 kiri = 040

100

2

= 0 kg$>m



17/27



DESMAWATI

03101001011

Ga+a Ge)er +an& Har') Diik'* Pa)ak

L =2

3030 BkiriAkanan +

! 100 >m

=2

/98.27/31.99 cmkgcmkg +! 100 >m

= 2"".5 kg

LC =2

3030 CkiriBkanan +! 50 >m

=2

/26.13/15.26 cmkgcmkg +! 50 >m

= #13 kg

LCD =2

3030 DkiriCkanan +

! 50 >m

=2

/01.4/28,76 cmkgcmkg +! 50 >m

= 200#.25 kg

LD =2

3030 EkiriDkanan + ! 50 >m

=2

/0/90.1 cmkgcmkg +

! 50 >m

= 4#.5 kg

Lt(ta* = 5#66.25 kg



18/27



DESMAWATI

03101001011

Kek'atan Pa)ak

ll ka8u kela' ;;; mutu = 5 kg$>m2

(ipakai pa'ak ka8u (engan '8arat :

u H 5 t

t H 1,5 >m

u H 15 >m

Dipakai pa'ak :

u = 15 >m

t = 3 >m

b = 30 >m

aka kekuatan pa'ak

A1 = u . b . ll pa'ak

= 15 >m ! 30 >m ! 5 kg$>m2

= 2250 kg

A2 = b . t . tk bal%k


diambil t > 3 cm

sehingga ! 5 t ! 5 " 3 ! 15 cm


19/27



DESMAWATI

03101001011

= 30 >m ! 3 >m ! 33,33 kg$>m2

= 2""",# kg

Diambil nilai A minimum 8aitu A = 2250 kg

/'m*a Pa)ak 'nt'k Seten&a entan&

=kg2250

#g5766.25= 2.56 = 3 buah

/'m*a Pa)ak +an& Dier*'kan Per Sat' ari)

=S

L A) =kg

kg

2250

2998.5= 1,54 2 pa'ak

C =S

L)* =kg2250

#g713= 0.32 1 pa'ak

CD =S

L*% =kg

kg

2250

25.2007= 0." 1 pa'ak

D =S

L%E =kg

kg

2250

5.47 = 0.021 0 pa'ak

PERHITUNGAN IKATAN ANGIN

Dalam memperhitungkan jumlah bagian7bagian jembatan pa(a 'etiap 'i'i (apat (igunakan

ketentuan menurut PJ ina arga I%.12 $ 1"#0 :

Jembatan rangka (iambil 30 + terha(ap lua' bi(ang 'i'i jembatan 8ang

ber'angkutan.



20/27



DESMAWATI

03101001011

Pengaruh tekanan angin 'ebe'ar "0 kg$>m2pa(a jembatan (itinjau ber(a'arkan

bekerjan8a angin h%ri%ntal terbagi rata pa(a bi(ang Kertikal jembatan (alam

arah tegak luru' 'umbu memanjang jembatan

Jumlah lua' bi(ang Kertikal jembatan 8ang (ianggap terkena angin, (itetapkan

'ebe'ar 1,5 kali jumlah lua' bagian 'i'i jembatan.

ila a(a muatan hi(up (i jembatan, maka lua' ter'ebut (itambah (engan lua'

bi(ang Kertikal muatan hi(up 8ang ti(ak terlin(ungi %leh bagian 'i'i jembatan.

i(ang Kertikal muatan hi(up ter'ebut (itetapkan 'ebagai 'uatu permukaan

bi(ang Kertikal 8ang mempun8ai tinggi teru' meneru' 'ebe'ar 2m (i lantai

ken(araan.

24 m



21/27



DESMAWATI

03101001011

< rangka =2

624 +m ! 4 m = 60 m2

Jumlah lua' bagan Kertikal jembatan 8ang (ianggap terkena angin a(alah

1,5 ! Lua' t%tal = 1,5 ! 60 m2= "0 m2

ntuk jembatan rangka lua'n8a 30 +

L = 0,3 ! "0 m2 = 2# m2

*ekanan angin - / = "50 kg$m2

e'ar ga8a angin pa(a rangkan8a :

= 2# m2 ! 60 kg$m2

= 1620 kg

a8a angin pa(a muatan hi(up 'etinggi 2 m

= 2 m ! 24 m ! 60 kg$m2= 20 kg

*%tal ga8a akibat angin pa(a jembatan rangka

= 1620 kg 20 kg

= 4500 kg

Jumlah me(an pa(a jembatan rangka =

*iap 'impul = = 562.5

P$2 = = 21.25

= = 4P= 4 -562.5 kg= 2250 kg

Ikatan An&in di ba2a Lantai



22/27



DESMAWATI

03101001011

PP+2 P P P P P P+2P

rem(na Ikatan An&in



23/27



DESMAWATI

03101001011

Tabe* Ga+a atan&

atan&

Ga+a atan&

Pan-an&Sebenarn+a 4 k& 5

tarik 4 6 5 tekan 4 7 5



24/27



DESMAWATI

03101001011

1=2 = #3= 64=5

1= 2= #3= 64= 5

D1= D16D2= D15D3= D13D4= D15D5= D12D6= D11D#= D10

D= D"

*1= *16*2= *1#

*3 = *14*4= *15*5= *12*6= *13*#= *10*= *11

*"

01,512,63,2

01,512,63,2

2,361,#1

0,350,35

11,#

2,36

0,5

40,251,#50,251,250,250,#50,5

7777

7211,3

364,#4644,"1

723,4#

74",1

7140,2#

7331,0#

7

735,0#17

35,0#17777

7211,3

364,#4644,"1

7777

331,0#7

140,2#7

4",157

23,4#7

#0,14

561,147245,5

71#5,3535,0#1105,215#0,14

DIMENSI ATANG IKATAN ANGIN

o atang ata' (an batang ba/ah merupakan gelagar memanjang.

o atang tegak merupakan gelagar melintang jembatan.

Ja(i, han8a men(imen'i batang (iag%nal - D pa(a ikatan angin



25/27



DESMAWATI

03101001011

Perhitungan ubungan elagar elintang (engan ;katan ngin

Akibat Ga+a Tarik

Di>%ba ukuran bal%k 15$20

Pma! batang D = 331,0# kg

Panjang batang mak'imum

Lk = ( ) ( ) 22 5,275,0 mm +

= 2,610 m = 261 >m

;! = 1$12 . b . h3


4 m

4 m

3 m

T1

T2

T3

T4

T6 T8

T9

T7T5

2

1 3 5 7

4 6 8

3 m 3 m 3 m


26/27



DESMAWATI

03101001011

= 1$12 . 15 . 203

= 10000 >m4

m2

m2

t( =

(F

P =

240

07,331 = 1,3 kg$>m2

'8arat :

t( @ lltr

1,3 kg$>m2 @ 10,33 kg$>m2. . . . . . . . . AMAN , ,

Akibat Ga+a Tekan

Di>%ba ukuran bal%k 15$20

Pma! batang D = 331,0# kg

Panjang batang mak'imum

Lk = ( ) ( ) 22 5,275,0 mm +

= 2,610 m = 261 >m

;! = 1$12 . b . h3

= 1$12 . 15 . 203

= 10000 >m4

m2



27/27



DESMAWATI

03101001011

m2

ima! =F

Ix =3

1= 5,##4 >m

=mini

Lk =

774,5

261 = 45,2 45

Dari tabel tekuk = 45 (i(apat / = 1,45 - PPB;, hal 12

'8arat :

@ 150

45 @ 150 . . . . . . . . . . . . AMAN , ,

tr =brF

wxP =

300

45,107,331 x = 1,6 kg$>m2

'8arat :

tr @ lltr

1,6 kg$>m2 @ 10,33 kg$>m2.........................I


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