tugas rumah

4
Tugas Rumah SOAL 1 : 192.168.98.0 / 29 Jawab: Biner : 11111111.11111111.11111111.11111000 SubnetMask : 255.255.255.248 Jumlah Subnet = 2 x = 2 5 = 32 Subnet Jumlah Host per Subnet = 2 y – 2 = 2 3 – 2 = 8 – 2 = 6 Host Blok Subnet = 256 – nilai octet terakhir subnetmask = 256 – 248 = 8 0, 8, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88, 96, 104, 112, 120, 128, 136, 144, 152, 160, 168, 176, 184, 192, 200, 208, 216, 224, 232, 240, 248

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Page 1: Tugas Rumah

Tugas Rumah

SOAL 1 :

192.168.98.0 / 29

Jawab:

Biner : 11111111.11111111.11111111.11111000

SubnetMask : 255.255.255.248

Jumlah Subnet = 2x

= 25

= 32 Subnet

Jumlah Host per Subnet = 2y – 2

= 23 – 2

= 8 – 2

= 6 Host

Blok Subnet = 256 – nilai octet terakhir subnetmask

= 256 – 248

= 8

0, 8, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88, 96, 104, 112, 120, 128, 136, 144, 152, 160, 168, 176, 184, 192, 200, 208, 216, 224, 232, 240, 248

Page 2: Tugas Rumah

SOAL 2

192.162.77.0 / 30

Jawab:

Biner : 11111111.11111111.11111111.11111100

SubnetMask : 255.255.255.252

Jumlah Subnet = 2x

= 26

= 64 Subnet

Jumlah Host per Subnet = 2y – 2

= 22 – 2

= 4 – 2

= 2 Host

Blok Subnet = 256 – nilai octet terakhir subnetmask

= 256 – 252

= 4

0, 4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, 64, 68, 72, 76, 80, 84, 88, 92, 96, 100, 104, 108, 112, 116, 120, 124, 128, 132, 136, 140, 144, 148, 152, 156, 160, 164, 168, 172, 176, 180, 184, 188, 192, 196, 200, 204, 208, 212, 216, 220, 224, 228, 232, 236, 240, 244, 248, 252

Page 3: Tugas Rumah

SOAL 3

192.170.6.7 / 27

Jawab:

Biner : 11111111.11111111.11111111.11100000

SubnetMask : 255.255.255.224

Jumlah Subnet = 2x

= 23

= 8 Subnet

Jumlah Host per Subnet = 2y – 2

= 25 – 2

= 32 – 2

= 30 Host

Blok Subnet = 256 – nilai octet terakhir subnetmask

= 256 – 224

= 32

7, 39, 71, 103, 135, 167, 199, 231

Page 4: Tugas Rumah

SOAL 4

192.88.55.15 / 28

Jawab:

Biner : 11111111.11111111.11111111.11110000

SubnetMask : 255.255.255.240

Jumlah Subnet = 2x

= 24

= 16 Subnet

Jumlah Host per Subnet = 2y – 2

= 24 – 2

= 16 – 2

= 14 Host

Blok Subnet = 256 – nilai octet terakhir subnetmask

= 256 – 240

= 16

15, 31, 47, 63, 79, 95, 111, 127, 143, 159, 175, 191, 207, 223, 239, 255