rumus 1

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Rumus 1 Rumus 2 a. Fase Stabilisasi Kebutuhan Energi Basal Formula Harris Benedict ( Pria ) KEB=66,5+13,7 BB+5,0 TB - 6,8U =66,5+13,7 ( 50 ) + 5,0 ( 170 ) – 6,8 (50) =66,5 + 685 + 850 – 340 =1261,5 kkal =1300 kkal b. Fase Pemulihan BB Ideal= Tinggi Badan ( TB ) – 100 = 170 cm – 100 = 70 kg Kebutuhan Energi Basal Formula Harris Benedict ( Pria ) KEB= 66,5+13,7 BB+5,0 TB - 6,8U =66,5+13,7 ( 70 ) + 5,0 ( 170 ) – 6,8 ( 50 ) =66,5 + 959 + 850 – 340 =1535,5 kkal a. Fase Stablisasi Kondisi stabil: 20-25 kkal/KgBB/hr KEB = 25 x BB = 25 x 50 Kg = 1250 kkal b. Fase Akut Fase Akut: 25-35 kkal/KgBB/hr KEB = 35 x BB = 35 x 50 Kg = 1750 kkal c. Fase Pemulihan Fase Pemulihan : 35-50 kkal/KgBB/hr KEB = 50 x BB = 50 x 50 = 2500 kkal a. Fase Stabilisasi Kebutuhan Kalori (dalam keadaan sakit) KET = KEB + FS + AF = 1300 + 40%KEB + 10%KEB = 1300 + 40%(1300) + 10%(1300) = 1300 + 520 + 130 a. Fase Stabilisasi KET = KEB + FS + AF = 1250 + 40%KEB + 10%KEB = 1250 + 40%(1250) + 10%(1300) = 1250 + 500 + 130 = 1880 kkal b. Fase Akut KET = KEB + FS + AF = 1750 + 40%KEB + 10% KEB = 1750 + 40%(1750) +

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Page 1: Rumus 1

Rumus 1 Rumus 2a. Fase StabilisasiKebutuhan Energi BasalFormula Harris Benedict ( Pria )KEB=66,5+13,7 BB+5,0 TB - 6,8U

=66,5+13,7 ( 50 ) + 5,0 ( 170 ) – 6,8 (50)=66,5 + 685 + 850 – 340=1261,5 kkal=1300 kkal

b. Fase PemulihanBB Ideal= Tinggi Badan ( TB ) – 100

= 170 cm – 100= 70 kg

Kebutuhan Energi BasalFormula Harris Benedict ( Pria )KEB= 66,5+13,7 BB+5,0 TB - 6,8U

=66,5+13,7 ( 70 ) + 5,0 ( 170 ) – 6,8 ( 50 )=66,5 + 959 + 850 – 340 =1535,5 kkal

a. Fase StablisasiKondisi stabil: 20-25 kkal/KgBB/hrKEB = 25 x BB = 25 x 50 Kg = 1250 kkal b. Fase AkutFase Akut: 25-35 kkal/KgBB/hrKEB = 35 x BB = 35 x 50 Kg = 1750 kkal

c. Fase PemulihanFase Pemulihan : 35-50 kkal/KgBB/hrKEB = 50 x BB = 50 x 50 = 2500 kkal

a. Fase Stabilisasi

Kebutuhan Kalori (dalam keadaan sakit)

KET = KEB + FS + AF

= 1300 + 40%KEB + 10%KEB

= 1300 + 40%(1300) + 10%(1300)

= 1300 + 520 + 130

= 1950 kkal

b. Fase Pemulihan

KET = KEB + FS + AF

= 1535,5 + 20%KEB + 20%KEB

= 1535,5 + 20%(1535,5) + 20%(1535,5)

= 1535,5 + 307,1 + 307,1

= 2149,7 kkal

a. Fase StabilisasiKET = KEB + FS + AF = 1250 + 40%KEB + 10%KEB = 1250 + 40%(1250) + 10%(1300) = 1250 + 500 + 130 = 1880 kkal

b. Fase AkutKET = KEB + FS + AF = 1750 + 40%KEB + 10% KEB = 1750 + 40%(1750) + 10%(1750) = 1750 + 700 + 175 = 2625 kkal

c. Fase PemulihanKET = KEB + FS + AF = KEB + 20%KEB + 20%KEB = 2500 + 20%(2500) + 20%(2500) = 2500 + 500 + 500 = 3500 kkal

a. Fase Stabilisasi- MakronutrienDengan Variasi :

a. Fase Stabilisasi- MakronutrienDengan Variasi :

Page 2: Rumus 1

Karbohidrat :40 %Protein :20 %Lemak :40 %

1. Karbohidrat ( 40 % )Kebutuhan Karbohidrat = 40% . KET

= 40% . 1950 kkal= 780 kkal

Konversi (dalam gram ) = 780 : 4= 195 gram

2. Protein (20%)Kebutuhan Protein= 20% . KET

= 20% . 1950 kkal= 390 kkal

Konversi (dalam gram ) = 390 : 4= 97,5 gram

3.Lemak Kebutuhan Lemak= 40% . KET

= 40% . 1950 kkal= 780 kkal

Konversi (dalam gram ) = 780 : 9= 86,67 gram

b. Fase Pemulihan - Makronutrien

Dengan Variasi :Karbohidrat :55 %Protein :20 %Lemak :25 %

1. Karbohidrat ( 40 % )Kebutuhan Karbohidrat = 55% . KET

= 55% . 2149,7 kkal= 1182,34 kkal

Konversi (dalam gram ) = 1182,34 : 4= 295,59 gram

2. Protein (20%)Kebutuhan Protein= 20% . KET

= 20% . 2149,7kkal = 429,94 kkal

Konversi (dalam gram ) = 429,94 : 4 = 107,49 gram

3. Lemak (25%)Kebutuhan Lemak= 25% . KET

= 25% . 2149,7kkal= 537,42 kkal

Karbohidrat : 40%Protein : 20%Lemak : 40%

1. Karbohidrat (40%)Kebutuhan Karbohidrat = 40%.KET = 40%.1885 kkal = 754 kkalKonversi (dalam gram) = 754 : 4 = 188,5 kkal

2. Protein (20%)Kebutuhan Protein = 20%.KET = 20% . 1885 kkal = 377 kkalKonversi (dalam gram) = 377 : 4 = 94,25 gram

3. Lemak (40%)Kebutuhan Lemak = 40%.KET = 20% . 1885 kkal = 377Konversi (dalam gram) = 377 : 9 = 41,89 gram

b. Fase Akut -Makronutrien1. Karbohidrat (40%)Kebutuhan Karbohidrat = 40%.KET = 40% . 2625 kkal = 1050 kkalKonversi (dalam gram)=1050 : 4 =262,5 gram

2. Protein (20%)Kebutuhan Karbohidrat = 20%.KET = 20% . 2625 kkal = 525 kkalKonversi (dalam gram)= 525 : 4 =131,25 gram

3. Lemak (40%)Kebutuhan Lemak= 40%.KET = 40% . 2625 = 1050 kkalKonversi (dalam gram) = 1050 : 9

Page 3: Rumus 1

Konversi (dalam gram ) = 537,42 : 9 = 59,71 gram

=116,67 gram

c. Fase Pemulihan-MakronutrienDengan variasi:Karbohidrat (55%)Protein(20%)Lemak(25%)

1. KarbohidratKebutuhan Karbohidrat= 55%.KET = 55% . 2500 kkal = 1375 kkalKonversi (dalam gram)= 1375 : 4 =343,75 gram

2. ProteinKebutuhan Protein = 20%.KET = 0% . 2500 = 500 kkal

Konversi (dalam gram) = 500 : 4 =125 gram

3. LemakKebutuhan Lemak= 25%.KET =25% . 2500Konversi (dalam gram)= 625 gram