5/19/2018 PERHITUNGANGAN ALINYEMEN HORIZONTAL

1/4

1.FC

di = 225 m

R = 573

=

TC = TC tg

= 573. 0,267

= 153,53

EC = TC tg

= 153,53_ x 0,131

= 20,21

LC = 0,01745 x x R

= 0,01745 x 30 x 573

= 299,96

2.SCS

V = 90

R = 477

=

Ljln = 2 x 4

s = Ls x

= 75 x

= 4,506

c = - 2 x s

= 25 (2 x 4, )

= 15,988

5/19/2018 PERHITUNGANGAN ALINYEMEN HORIZONTAL

2/4

Lc =

x 2

=

x 2 . 3,14 . 477

= 133,036 m

L = Lc + Ls + Ls

= 133,036 + 75 + 75

= 283, 036 m

P =

Rc ( 1 cos s)

=

477 ( 1 cos 4,)

= - ( 0,004)

= 1,965 -

= 0,057

K = Ls -

- Rc sin

= 75 -

- 477. 0,078

= 75 0,04637,47

= 37,484

ES = (Rc + P) Sec

- R

= (477 + 0,057) Sec 12,5 477

= 1,024 477

= 488,639 477

= 11,639

TC = (Rc + P) tg

+ K

= (477 + 0,057) 0,221 + 37,484

= 105,429 + 37,484

= 142,91

5/19/2018 PERHITUNGANGAN ALINYEMEN HORIZONTAL

3/4

3.SS

SS =

=

R = 573, LS = 75 C = 0,072

=

LS =

=

= 249,891 m

m = 150 . e =

Ls = m ( e+ en) . B

= 150 ( 0,072 + 0,02 ) 4

= 150 ( 0,092 ) 4

= 55,2 m

Ls > Ls mm , tetapi terlalu besar, karena itu di coba dengan mempergunakan

R = 289, e= 0,1

Ls =

=

= 124,72 m

1) Ls mm = 150 ( 0,1 + 0,02 ) 4

= 72 m

Ls > Ls mm, maka R untuk lengkung berbentuk S S dapat di pergunakan

R = 289 m

Jadi P = . Ls

= 0,0185025 . 249,891

= 4,623 m

K = . Ls

= 0,4991966 . 249,891

= 124,745

L = 215 = 249,44 m

5/19/2018 PERHITUNGANGAN ALINYEMEN HORIZONTAL

4/4

Ls = ( R + P ) tg

+ K

= ( 289 + 4,623 ) 0,222 + 124,745

= 189,93 m

Es = (R + P ) Sec

- R

= ( 289 + 4,623 ) Sec - 289

= ( 293,623 ) 1,024 - 289

= 11,752 m