perhitungan keb luas gudang

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  • 7/25/2019 Perhitungan Keb Luas Gudang

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    PERHITUNGAN K

    Kebutuhan Luas Gudang = (A) + (B) + ( ) !"# S$%

    (A) S&a'e Ra' ng untu &* du't M e InstanEst %as Sa,es 2

    - Pa,,et 1,198 Pallet- Pa,,et . Ra' 10 Pallet / Rack- Ra' 120 UnitRa' ng S&a'e 264 SqmTta, (A) /0! S$%

    P* du't de Des'* &t n1 ,u%e Ke%asan

    Pan2ang Leba*K-001 Mie Instan "Enak Mie" 40 20K-002 Mie Instan " intan! Mie" 40 20K-00 Mie Instan "Enaaak Mie" 40 20K-004 Mie Instan "#$mi Mie" 40 20K-00% Mie Instan "Ra&a Mie" 40 20K-006 Mie Instan "'(() Mie" 40 20K-00* Mie Instan "Rat+ Mie" 40 20K-008 Mie Instan " ice Mie" 40 20K-009 Mie Instan " +lan Mie" 40 20K-110 Mie Instan " (sa Mie" 40 20

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    BUTUHAN LUAS GUDANG MIE INSTAN

    (B) S&a'e Rea'h T*u' 3 4 * , 5t3 MHE (B) S&a'e 67'eS&a'e Anta* Ra' 86 Sqm 67'e Inb und

    S&a'e In86ut 48 Sqm 67'e 6*de* P ' ngL ad ng D ' 1% Sqm Manage* . Su&e*9 s *Meet ng R %

    Tta, ( ) :!; S$% Tta, (B)

    ('%) H st * 'a, In9ent *< . Daan8:/ 4eb8:/ Ma*8:/ Ma?

    2% 20,000 40 %,000 %,200 %,100 %,2002% 20,000 40 ,0%0 2,600 2,*00 ,0%02% 20,000 40 2,600 1,*%0 1,%00 2,6002% 20,000 40 ,460 , %0 ,400 ,4602% 20,000 40 8,24% 8,% 0 *,*00 8,% 02% 20,000 40 %,280 6,000 6,%00 6,%002% 20,000 40 4,080 4,6%0 ,460 4,6%02% 20,000 40 %,040 4,800 4,%00 %,0402% 20,000 40 ,120 ,0%0 ,460 ,4602% 20,000 40 4,6%0 4,080 %,280 %,280

    @t< . Pa,,et( tn)

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    #.e a!eMa

    9Sqm

    12 Sqm9Sqm1% Sqm

    !" S$%

    Keb Pa,,etA9e*age

    %,100 1 0 2,*8 ** 1,9%0 6% ,40 8* 8,1%8 214 %,92* 16 4,06 11* 4,*80 126 ,210 8* 4,6*0 1 2

    :3:;#