kuliah 6 future ipr
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FUTURE IPR FOR VERTICAL WELL
Dengan bertambahnya waktu produksi (Np), maka tekanan reservoir berkurang (p ) perubahan pada sifak fisik reservoir seperti: , Rs, Bo. Menyebabkan perubahan kurva IPR
METODE IPR DI MASA MENDATANG1. Metode Fetkovich Harga eksponen (n) tetap selama masa produksi Konstanta aliran (Jo) berubah.
PRESENT IPR
FUTURE IPR
Example # 1Given data: four-point oil well test, Pr = 2500 psia dan Pb = 3000 psia
Calculate:a. Value of exponent nb. Value of Jo
c. PRESENT IPR EQUATIONd. Absolute open flow potential (AOFP) or q omaxe. qo for Pwf = 2200 psia
f. FUTURE IPR EQUATIONg. qo,max when Pr lowers to 1800 psia
h. qo for Pwf = 800 psia when Pr = 1800 psia
i. Construct IPR @ Pr = 2500 psia and IPR @ Pr = 1800 psia.
Test qo Pwf1 880 20002 1320 15003 1595 10004 1752 500
Solution of Example # 1a. Prepare a table as follows:
b. Construct a graph on log-log paper based on paper:
Test qo Pwf (Pr2-Pwf2)x103
1 880 2000 22502 1320 1500 40003 1595 1000 52504 1752 500 6000
100 1000 10000100
1000
10000
100000
1000000
10000000f(x) = 143.568000957193 x^1.42465205322171R² = 0.999993310787062
q (bpd)
(Pr2
-Pw
f2) p
si2
c. Find the exponent, n,n = 1/Slope = 1/1.4247 = 0.7019
d. Find, Jo,
e. PRESENT IPR
f. Find AOFP
Solution of Example # 1
g. Find qo for Pwf = 2200 psia
h. FUTURE IPR
i. qo,max when Pr lowers to 1800 psia
Solution of Example # 1
g. Find qo for Pwf = 800 psia when Pr = 1800 psia
i. Construct IPR @ Pr = 2500 psia and IPR @ Pr = 1800 psia.
PRESENT IPR FUTURE IPR
Solution of Example # 1
Pwf, psia q, bpd0 1805.51
200 1797.39400 1772.94600 1731.87800 1673.67
1000 1597.541200 1502.351400 1386.421600 1247.291800 1081.132000 881.392200 634.912400 302.362500 0.00
Pwf, psia q, bpd0 819.73
200 812.62400 791.11600 754.69800 702.41
1000 632.641200 542.621400 427.141600 274.001800 0 0 500 1000 1500 2000
0
500
1000
1500
2000
2500PresentFuture
q, bpd
Pwf,
psia
METODE IPR DI MASA MENDATANG2. Metode Eickmer Menggabungkan Future IPR Fetkovich dan Vogel. Harga eksponen aliran sama dengan 1, maka laju alir maksimum
pada kondisi awal dapat dibandingkan dengan laju alir maksimum di masa mendatang.
Hubungan q dan pwf di masa mendatang menggunakan persamaan Vogel
PRESENT IPR
FUTURE IPR
PRESENT-FUTURE CORR
Given data:Pr = 3000 psia (Pb = 3000 psia)A test shows q = 200 bpd at a flowing pressure of 2500 psia.Calculate:(1). qomax at 3000 psia
(2). qomax when the static pressure drops to 2000 psia
(3). Construct PRESENT IPR Curve (@2500 psia) and FUTURE IPR Curve (@2000 psia)
(4). Qo for Pr = 2000 psia and Pwf = 1000 psia
Example # 2
(1). qomax at 3000 psia (Eq.4a)
(2). qomax when the static pressure drops to 2000 psia (Eq. 5)
Solution of Example # 2
(3). Construct PRESENT IPR Curve (@2500 psia) and FUTURE IPR Curve (@2000 psia)
Present (Eq. 4a) Present (Eq. 4b)
Solution of Example # 2
Pwf, psia q, bpd Pwf, psia q, bpd0 720 1600 479.36
200 707.84 1800 426.24400 690.56 2000 368600 668.16 2200 304.64800 640.64 2400 236.16
1000 608 2600 162.561200 570.24 2800 83.841400 527.36 3000 0
Pwf, psia q, bpd Pwf, psia q, bpd0 213 1200 126.10
200 207.04 1400 99.68400 197.66 1600 69.86600 184.88 1800 36.64800 168.70 2000 0
1000 149.1
(4). Qo for Pr = 2000 psia and Pwf = 1000 psia (Eq. 4b)
Solution of Example # 2
0 100 200 300 400 500 600 700 8000
500100015002000250030003500
PresentFuture
q, bpd
Pwf,
psia
METODE IPR DI MASA MENDATANG3. Metode Pudjo Sukarno
METODE IPR DI MASA MENDATANG
• If API 40
• If API < 40
Given data:Pr = 1345 psia (Pb = 3000 psia)A test shows q = 321 bpd at a flowing pressure of 719
psia.API > 40 and S = 0Calculate:(1). qomax at 1345 psia
(2). qomax when the static pressure drops to 1000 psia
(3). Construct PRESENT IPR Curve (@1345 psia) and FUTURE IPR Curve (@719 psia)
Example # 3
(1). qomax at 1345 psiaSolution of Example # 3
(2). qomax when the static pressure drops to 1000 psia (Eq. 6)
(3). Construct PRESENT IPR Curve (@1345 psia) and FUTURE IPR Curve (@719 psia)
Present (Eq.5) Future (Eq.5)
Solution of Example # 3
Pwf, psia q, bpd0 432.43
200 422.57400 396.85800 294.08
1000 211.751200 102.171345 0.85
Pwf, psia q, bpd0 183.95
200 176.74400 157.21800 73.89
1000 0.36
0 100 200 300 400 5000
200400600800
1000120014001600
PresentFuture
q, bpd
Pwf,
psia
METODE IPR DI MASA MENDATANG4. Metode Sukarno-Ariadji-Regina Menggabungkan Asumsi IPR Vogel, Sukarno, Klins,
dan Wiggins.PRESENT IPR (depletion Np/N = 1%-4%)
FUTURE IPR (depletion Np/N = 6%-8%)
PRESENT-FUTURE correlation
Given data:Pr = 1345 psia (Pb = 3000 psia)A test shows q = 321 bpd at a flowing pressure of 719
psia.API > 40 and S = 0Calculate:(1). qomax at 1345 psia
(2). qomax when the static pressure drops to 1000 psia
(3). Construct PRESENT IPR Curve (@1345 psia) and FUTURE IPR Curve (@719 psia)
Example # 4
(1). qomax at 1345 psia (Eq. 8)
(2). qomax when the static pressure drops to 1000 psia (Eq.10)
Solution of Example # 4
(3). Construct PRESENT IPR Curve (@1345 psia) and FUTURE IPR Curve (@719 psia)
Present (Eq.8) Future (Eq.9)
Solution of Example # 4
Pwf, psia q, bpd0 501
200 471.19400 425.78600 364.74800 288.10
1000 195.841200 87.971345 0
Pwf, psia q, bpd0 196.6
200 172.84400 141.29600 101.97800 54.87
1000 0
0 100 200 300 400 500 6000
200400600800
1000120014001600
PresentFuture
q, bpd
Pwf,
psia
ASSIGNMENTObtained isochronal test data: Pr = 1350 psi.
Apply Fetkovich, Eickmer, Sukarno, Sukarno-Ariadji-Regina Methods to a. Calculate qo max at present.b. Draw Present IPR Curves @ Pr = 1350 psia.
c. Calculate qo max at future when reservoir pressure (Pr) drop to 1000 psia and 800 psia.
d. Draw Future IPR Curves @ Pr = 1000 psia and Pr = 800 psia.
e. Calculate qo if pwf = 400 psia and Pr = 800 psia.
Flow Test Qo , bpd Pwf, psia
1 134 1142
2 229 921
3 321 719