aplikasi_pembezaan.ppt
TRANSCRIPT
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The Derivative-Instantaneous rate of change
0
( ) ( )( ) lim
h
dy f a h f af a
dx h
0
( ) ( )( ) limh
dy f x h f xf x
dx h
The derivative of a function,fat a specific
value ofx, say a is a value given by:
The derivative of a function,fas a function of
x, is calledf(x) and is given by:
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Related problems 2( ) 3 4 7f x x x
1) Find the slope off(x) atx = 3,x = -2
3) Find the point onf(x) for which the slope is 2
4) Find the point for whichf(x) has a
horizontal tangent line
2) Write the equation of the tangent line at x = -2
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Solutions2( ) 3 4 7f x x x
1) Find the slope off(x) atx = 3,x = -2
2) Write the equation of the tangent line at x = -2
( ) 6 4f x x so
( 2) 6( 2) 4 16f
(3) 6(3) 4 14f
1 1( )y y m x x
2( 2) 3( 2) 4( 2) 7 27f
27 16( 2)y x
27 16( 2)y x 16 5y x
use the point-slope formula
Find the value of y
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Solutions 2( ) 3 4 7f x x x
3) Find the point onf(x) for which the slope is 2
4) Find the point for whichf(x) has a horizontal
tangent line
( ) 6 4f x x 6 4 2
1
x
x
2
3x
2
(1) 3(1) 4(1) 7 6f The point is (1, 6)
6 4 0x
22 2 2 17( ) 3( ) 4( ) 7
3 3 3 3
f
The point is (2/3, 17/3)
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Figure 2.7: Derivatives at endpoints are one-sided limits.
Derivatives at Endpoints are one-sided limits.
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How a derivative can fail to exist
A cornerA vertical
tangentA discontinuity
Which of the three examples are the functions
continuous?
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The graph of a function
The graph of the derivative (slope) of the function
Where f(x) is increasing
(slope is positive)
Where f(x) is decreasing
(Slope is negative)
Horizontal tangent
(slope =0)
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3.3 Differentiation formulas
Simple Power rule 1n nd
x nxdx
Sum and difference rule ( ) ( )d d d
u v u vdx dx dx
Constant multiple rule ( )d d
cu c udx dx
Constant ( ) 0d
cdx
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Find the derivative function for:
21
( ) 175 3
xf x
x
2( ) (3 2)f x x
12 2
1 1( ) 17
5 3
f x x x
3
2
2 1( )
5
6
f x x
x
2( ) 9 12 4f x x x
( ) 18 12f x x
rewrite
rewrite
3
21 1 1
( ) 2 * ( )( ) 05 3 2f x x x
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Rules for Finding Derivatives
u and v are functions of x.
Simple Power rule 1n nd x nxdx
Sum and difference rule ( ) ( )d d du v u vdx dx dx
Constant multiple rule ( )d d
cu c udx dx
Product rule ( ) ( )d d d
uv u v v udx dx dx
Quotient rule2
( ) ( )d d
v u u vd u dx dx
dx v v
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Differentiate
2 1 3
(3 2 )(4 5)y x x x
( ) ( )
d d duv u v v u
dx dx dx
2 1 3 3 2 1
(3 2 ) (4 5) (4 5) (3 2 )
dy d d
x x x x x xdx dx dx
2 1 2 3 2(3 2 )(12 ) (4 5)(6 2 )dy
x x x x x xdx
4 4 2
4 2
36 24 24 8 30 10
60 14 10
dyx x x x x x
dx
dyx x x
dx
Product rule
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Differentiate 25 2
1
xy
x
2 2
2 2
( 1) (5 2) (5 2) ( 1)
( 1)
d dx x x x
dy dx dx
dx x
2
( ) ( )d d
v u u vd u
dx dxdx v v
2
2 2
( 1)(5) (5 2)(2 )
( 1)
dy x x x
dx x
2 2
2 2
(5 5) (10 4 )
( 1)
dy x x x
dx x
2
2 2
5 4 5
( 1)
dy x x
dx x
Quotient rule
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Find the derivative function for:
2( ) (3 2 )(5 4 )f x x x x
2
5 2( )
1
xf x
x
2 2( ) (3 2 ) (5 4 ) (5 4 ) (3 2 )d df x x x x x x xdx dx
2(3 2 )4 (5 4 )(3 4 )x x x x 224 4 15x x
2 2
2 2
( 1) (5 2) (5 2) ( 1)( )
( 1)
d dx x x x
dx dxf xx
2 2 2
2 2 2 2
2
2 2
( 1)5 (5 2)2 (5 5) (10 4 )
( 1) ( 1)
5 4 5
( 1)
x x x x x x
x
x x
xx
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Velocity. The particle is moving forward for the
first 3 seconds and backwards the next 2 sec,
stands still for a second and then moves forward.
forward
motion
means
velocity is
positive
backward
motion
means
velocity is
negative
If velocity = 0, object is standing still.
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The graphs ofs and v as functions of time;s islargest when v = ds/dt= 0. The graph ofs isnotthe path of the rock: It is a plot of heightversus time. The slope of the plot is the rocks
velocity graphed here as a straight line.
a) How high does the rock go?b) What is the velocity when the rock is 256 ft.
above the ground on the way up? On the way
down?
c) What is the acceleration of the rock at any time?
d) When does the rock hit the ground? At what velocity?
3.4 applications
A dynamite blast blows a heavy rock straight up with a launch
velocity of 160 ft/sec. Its height is given by s = -16t2 +160t.
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A dynamite blast blows a heavy rock straight up with a launch
velocity of 160 ft/sec. Its height is given by s = -16t2 +160t.
a) How high does the rock go?Maximum height occurs when v =0.
-32t+ 160 = 0v = s= -32t+ 160
t= 5 sec.
s = -16t2 +160t
At t = 5,
s = -16(5)2 +160(5)
= 400 feet.
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A dynamite blast blows a heavy rock straight up with a launch
velocity of 160 ft/sec. Its height is given by s = -16t2 +160t.
b) What is the velocity when the rock is 256 ft. above theground on the way up? On the way down?
v =-32t+ 160
at t= 2v=-32(2)+160 = 96 ft/sec.
at t = 8
v=-32(8)+160 = -96 ft/sec
-16t2 +160t = 256
-16t2 +160t256=0
-16(t2 - 10t + 16)=0-16(t2) (t- 8) = 0
t = 2 or t = 8
Find the times
Substitute the timesinto the velocity
function
Set position = 256
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A dynamite blast blows a heavy rock straight up with a launch
velocity of 160 ft/sec. Its height is given by s = -16t2 +160t.
c) What is the acceleration of the rock at any time?
d) When does the rock hit the ground? At what velocity?
s = -16t2 +160t
v = s= -32t+ 160
a = v = s= -32ft/sec2
s = -16t2 +160t = 0
t = 0 and t = 10
v =-32t+ 160
v = -32(10)+ 160 = -160 ft/sec.
Set position = 0
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3.5 Derivatives of trig functions-formulas needed
sin(x+h) = sin x*cos h+cos x*sin h
0
sinhlim 1h h
cos(x+h) = cos x*cos h- sin x*sin h
0
cos 1lim 0h
h
h
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Derivative of y = sin x0
( ) ( )( ) limh
dy f x h f xf x
dx h
0
sin( ) sin( )
( ) limh
x h x
f x h
0
sin( )cos( ) cos( )sin( ) sin( )limh
x h x h x
h
0
sin( )cos( ) sin( ) cos( )sin( )limh
x h x x h
h
0
sin( )(cos( ) 1) cos( )sin( )
limhx h x h
h h
0
sin( )(cos( ) 1) cos( )sin( )
limhx h x h
h h
0 +cos(x)*1 = cos (x)
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3.5 Derivatives of Trigonometric Functions
sin cosd
x xdx
cos sind
x xdx
2tan secd x xdx
2cot cscd x xdx
sec sec tand
x x xdx csc csc cotd
x x xdx
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Figure 25: The curvey = sinx as the graph of the slopes of
the tangents to the curvey = cosx.
Slope of y = cos x
Fi d h d i i
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Find the derivatives
21( ) 5sin sec tan 7 32
f x x x x x x
21( ) 5 cos sec tan sec tan (1) 142f x x x x x x x x
1 sin( )
cos
xf x
x x
2
( cos ) (1 sin ) (1 sin ) ( cos )
( )
( cos )
d dx x x x x x
dx dxf x
x x
2
( cos )(cos ) (1 sin )(1 sin )( )
( cos )
x x x x xf x
x x
2 2 2 2
2 2
( cos cos ) (1 sin ) cos cos 1 sin( )
( cos ) ( cos )
x x x x x x x xf x
x x x x
2
cos( )
( cos )
x xf x
x x