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Soal :

Dari gambar dan name plate beban yang sudah disediakan, tentukan :

1. Pengaman yang digunakan

2. Nilai penghantar utama dan cabang

3. Nilai Isc masing masing motor

4. Perbaikan faktor daya sistem sebelum dan sesudah

Jawab

Perhitungan Pengaman Yang Digunakan

Group 1

Motor M31 Bail Press

Diketauhi : IMCCB : 800 A

Starter : Y/∆

Jawab :

IMCCB = 800 A

In = IMCCB

250 %

= 800

250 %

= 320 A

Ist = 13

x I DOL

= 13

x 6x∈¿

= 2 x In

= 2 x 320

= 640 A

(Maka digunakan MCCB hager H1000 50kA 800 A)

TOR = 1

√3xIn

=1

√3x320

= 184,7 A

Kontaktor = 115% x In

= 115% x 320

= 368 A

(Digunakan Kontaktor Eaton DILM400 400A)

Group 2

Bagian MCC SPINDEM

Motor M11 Pompa Hidrolik Bending 1 15 kW / 380 V

Diketauhi : In : 30 A

Starter : Y/∆

Jawab :

IMCB = 250% x In

= 250% x 30

= 75 A

Ist = 13

x I DOL

= 13

x 6x∈¿

= 2 x In

= 2 x 30

= 60 A

(Maka digunakan MCB Moeler FAZ-D63/3 15kA 63 A)

TOR = 1

√3xIn

=1

√3x30

= 17,3 A


= 115% x 30

= 34,5 A




Starter : Y/∆

Jawab :

IMCB = 250% x In

= 250% x 30

= 75 A

Ist = 13

x I DOL

= 13

x 6x∈¿

= 2 x In

= 2 x 30

= 60 A


TOR = 1

√3xIn

=1

√3x30

= 17,3 A


= 115% x 30

= 34,5 A


Motor M13 Pompa Hidrolik Bending Sirkulasi 1,5 kW / 380 V

Diketauhi : In : 3,5 A

Starter : DOL Y

Jawab :

IMCB = 250% x In

= 250% x 3,5

= 8,75 A

Ist = I DOL

= 6 x∈¿

= 6 x 3,5

= 21 A


TOR = 100% x∈¿

= 100% x3,5

= 3,5 A


= 115% x 3,5

= 4,02 A


Motor M14 Leteral Unwind 3 kW / 380 V


Starter : DOL Y

Jawab :

IMCB = 250% x In

= 250% x 11,6

= 29 A

Ist = I DOL

= 6 x∈¿

= 6 x 11,6

= 69,6 A


TOR = 100 % x∈¿

=100 % x 11,6

= 11,6 A


= 115% x 3,5

= 4,02 A


Motor M15 Central Blower 11 kW / 380 V


Starter : Y/∆

Jawab :

IMCB = 250% x In

= 250% x 23

= 57,5 A

Ist = 13

x I DOL

= 13

x 6x∈¿

= 2 x In

= 2 x 23

= 46 A


TOR = 1

√3x∈¿

=1

√3x23

= 13,28 A


= 115% x 23

= 26,45 A


Motor M16 Pompa Auxiliary sirkulasi 2 kW / 380 V


Starter : DOL Y

Jawab :

IMCB = 250% x In

= 250% x 6,62

= 16,55 A

Ist = I DOL

= 6 x∈¿

= 6 x 6,62

= 39,72 A


TOR = 100 % x∈¿

=100 % x 11,6

= 11,6 A


= 115% x 11,6

= 13,34 A

(Digunakan Kontaktor Eaton DILM15 15,5A)

Motor M17 Pompa Hidrolik Auxiliary1 11 kW / 380 V


Starter : Y/∆

Jawab :

IMCB = 250% x In

= 250% x 23

= 57,5 A

Ist = 13

x I DOL

= 13

x 6x∈¿

= 2 x In

= 2 x 23

= 46 A


TOR = 1

√3x∈¿

=1

√3x23

= 13,28 A


= 115% x 23

= 26,45 A




Starter : Y/∆

Jawab :

IMCB = 250% x In

= 250% x 23

= 57,5 A

Ist = 13

x I DOL

= 13

x 6x∈¿

= 2 x In

= 2 x 23

= 46 A


TOR = 1

√3x∈¿

=1

√3x23

= 13,28 A


= 115% x 23

= 26,45 A


Motor M19 Fume Exhaust 24 kW / 40 V


Starter : Y/∆

Jawab :

IMCB = 250% x In

= 250% x 43

= 107,5 A

Ist = 13

x I DOL

= 13

x 6x∈¿

= 2 x In

= 2 x 43

= 86 A


TOR = 1

√3x∈¿

=1

√3x 43

= 24,83 A


= 115% x 43

= 49,43 A


Motor M20 Motor Blower 5,5 kW / 380 V


Starter : Y/∆

Jawab :

IMCB = 250% x In

= 250% x 11,1

= 27,75 A

Ist = 13

x I DOL

= 13

x 6x∈¿

= 2 x In

= 2 x 11,1

= 22,2 A


TOR = 1

√3x∈¿

=1

√3x11,1

= 6,4 A


= 115% x 11,1

= 12,76 A


MCCB Utama MCC SPIDEM

IMCCB = Rating Pengaman Terbesar + ∑In Yang Lain

= 63 + 30 + 30 + 3,5 + 11,6 + 23 + 6,62 + 23 + 23 + 11,1

= 225 A

(Diambil MCCB Hager 40 kA 200A)

Bagian Cooling Tower

Motor M21 Pompa Cooling Tower 1 22 kW / 380 V


Starter : Y/∆

Jawab :

IMCB = 250% x In

= 250% x 40

= 100 A

Ist = 13

x I DOL

= 13

x 6x∈¿

= 2 x In

= 2 x 40

= 80 A


TOR = 1

√3x∈¿

=1

√3x 40

= 23,1 A


= 115% x 40

= 46 A

(Digunakan Kontaktor Eaton DILM50 50 A)



Starter : Y/∆

Jawab :

IMCB = 250% x In

= 250% x 40

= 100 A

Ist = 13

x I DOL

= 13

x 6x∈¿

= 2 x In

= 2 x 40

= 80 A


TOR = 1

√3x∈¿

=1

√3x 40

= 23,1 A


= 115% x 40

= 46 A


Motor M23 Water Pump 1 1,1 kW / 380 V


Starter : DOL Y

Jawab :

IMCB = 250% x In

= 250% x 2,7

= 6,75 A

Ist = I DOL

= 6 x∈¿

= 6 x 2,7

= 16,2 A


TOR = 100 % x∈¿

=100 % x 2,7

= 2,7 A


= 115% x 2,7

= 3,1 A




Starter : DOL Y

Jawab :

IMCB = 250% x In

= 250% x 2,7

= 6,75 A

Ist = I DOL

= 6 x∈¿

= 6 x 2,7

= 16,2 A


TOR = 100 % x∈¿

=100 % x 2,7

= 2,7 A


= 115% x 2,7

= 3,1 A


Motor M26 Cooling Tower 5HP / 380 V


Starter : DOL Y

Jawab :

IMCB = 250% x In

= 250% x 4,2

= 10,5 A

Ist = I DOL

= 6 x∈¿

= 6 x 4,2

= 25,2 A


TOR = 100 % x∈¿

=100 % x 4,2

= 4,2 A


= 115% x 4,2

= 4,83 A


Motor M27 Main Fire Hydrant Pump1 75 kW / 380 V


Starter : Y/∆

Jawab :

IMCB = 250% x In

= 250% x 140

= 350 A

Ist = 13

x I DOL

= 13

x 6x∈¿

= 2 x In

= 2 x 140

= 280 A

(Maka digunakan MCCB Hager 50kA 200 A)

TOR = 1

√3x∈¿

=1

√3x140

= 80,1 A


= 115% x 140

= 161 A

(Digunakan Kontaktor Eaton DILM170 170 A)

Motor M28 Jockie Fire Hidrant Pump 1 5 kW / 380 V


Starter : Y/∆

Jawab :

IMCB = 250% x In

= 250% x 11,4

= 28,5 A

Ist = 13

x I DOL

= 13

x 6x∈¿

= 2 x In

= 2 x 11,4

= 22,8 A


TOR = 1

√3x∈¿

=1

√3x 40

= 23,1 A


= 115% x 40

= 46 A


MCCB Utama Cooling Tower


= 200 + 40 + 40 + 2,7 + 2,7 + 2,7 + 4,2 + 11,4

= 303,7 A

(Diambil MCCB Hager 50 kA 250 A)

MCCB Utama Group 2


= 250 + 30 + 30 + 3,5 + 11,6 + 23 + 6,62 + 23 + 23 + 43 + 11,1

= 454,8 A

(Diambil MCCB Hager 50 kA 630 A)

Group 3

Bagian Bailing Press

Motor M31 Bail Press 1Diketauhi : IMCCB : 30 A

Starter : Y/∆

Jawab :

IMCB = 250 % x In

In = IMCCB

250 %

= 30

250 % = 12 A

Ist = 13

x I DOL

= 13

x 6x∈¿

= 2 x In

= 2 x 12

= 24 A

(Maka digunakan MCB Moeler FAZ-D10 15kA 10A)

TOR = 1

√3xIn

=1

√3x12

= 6,9 A


= 115% x 12

= 13,8 A



Starter : Y/∆

Jawab :

IMCCB = 250 % x In

In = IMCCB

250 %

= 40

250 % = 16 A

Ist = 13

x I DOL

= 13

x 6x∈¿

= 2 x In

= 2 x 16

= 32 A (Maka digunakan MCB Moeler FAZ-D25 15kA 25A)

TOR = 1

√3xIn

=1

√3x16

= 9,23 A


= 115% x 16

= 18,4 A


Motor M33 Cyclone Motor 1


Starter : Y/∆

Jawab :

IMCCB = 250 % x In

In = IMCCB

250 %

= 60

250 %

= 24 A

Ist = 13

x I DOL

= 13

x 6x∈¿

= 2 x In

= 2 x 24


TOR = 1

√3xIn

=1

√3x24

= 13,85 A


= 115% x 24

= 27,6 A




Starter : Y/∆

Jawab :

IMCCB = 250 % x In

In = IMCCB

250 %

= 40

250 %

= 16 A

Ist = 13

x I DOL

= 13

x 6x∈¿

= 2 x In

= 2 x 16


TOR = 1

√3xIn

=1

√3x24

= 13,85 A


= 115% x 16

= 18,4 A


MCCB Utama Group 3


= 60 + 16 + 16 + 12

= 104 A

(Diambil MCCB Hager 18kA 160 A)

MCCB Utama Sistem

Diketauhi : Trafo : 1000kVA

In : 1443,4 A

Dibebani Maksimum 65%

Jawab : Maka In Maksimal Sistem

Insistem = 65% x In

= 65% x 1443,4

= 938,21 A

Digunakan MCCB Hager 50kA 1000A

Perhitungan Penghantar Utama Dan Cabang

Diketauhi ∆V yang diijinkan adalah 3% x 380 V = 11,4 V

Group 1

Motor M31 Bail Press


l : 100 meter

Starter : Y/∆

Jawab :

IMCCB = 250 % x In

In = IMCCB

250 %

= 800

250 %

= 320 A

A = √3 x∈x l∆V x XCu

= √3 x 320x 10011,4 x56 x106

= 86,8 mm2 (Diambil NYY 4 x (1 x 400 mm2)dengan KHA 855 A)

Group 2

Bagian MCC SPINDEM



l : 100 meter

XCu : 56 x 106

Jawab :


= √3 x30 x10011,4 x 56x 106

= 8,14 mm2 (Diambil NYY 4 x 10 mm2 dengan KHA 69 A)



l : 90 meter

XCu : 56 x 106

Jawab :


= √3 x30 x 90

11,4 x 56x 106


Motor M13 Pompa Hidrolik Bending Sirkulasi 1,5 kW / 380 V


l : 80 meter

XCu : 56 x 106

Jawab :


= √3 x3,5 x80

11,4 x 56x 106

= 0,76 mm2 (Diambil NYY 4 x 2,5 mm2 dengan KHA 32 A)

Motor M14 Leteral Unwind 3 kW / 380 V


l : 70 meter

XCu : 56 x 106

Jawab :


= √3 x11,6 x7011,4 x 56x 106


Motor M15 Central Blower 11 kW / 380 V


l : 60 meter

XCu : 56 x 106

Jawab :


= √3 x23 x60

11,4 x 56x 106


Motor M16 Pompa Auxiliary sirkulasi 2 kW / 380 V


l : 80 meter

XCu : 56 x 106

Jawab :


= √3 x6,62 x8011,4 x 56x 106




l : 100 meter

XCu : 56 x 106

Jawab :


= √3 x23 x10011,4 x 56x 106




l : 90 meter

XCu : 56 x 106

Jawab :


= √3 x23 x 90

11,4 x 56x 106


Motor M19 Fume Exhaust 24 kW / 40 V


l : 70 meter

XCu : 56 x 106

Jawab :


= √3x 43 x 70

11,4 x 56x 106


Motor M20 Motor Blower 5,5 kW / 380 V


l : 60 meter

XCu : 56 x 106

Jawab :


= √3 x11,1 x 6011,4 x 56x 106


KHA Busbar MCC SPIDEM

KHA = Rating Pengaman Terbesar + ∑In Yang Lain

= 63 + 30 + 30 + 3,5 + 11,6 + 23 + 6,62 + 23 + 23 + 11,1

= 225 A

(Diambil busbar dengan penampang 74,4 mm2 dengan KHA 252 A)

Bagian Cooling Tower



l : 90 meter

XCu : 56 x 106

Jawab :


= √3x 40 x 90

11,4 x 56x 106




l : 80 meter

XCu : 56 x 106

Jawab :


= √3x 40 x 80

11,4 x 56x 106




l : 105 meter

XCu : 56 x 106

Jawab :


= √3 x2,7 x10511,4 x 56x 106




l : 100 meter

XCu : 56 x 106

Jawab :


= √3 x2,7 x10011,4 x 56x 106




l : 95 meter

XCu : 56 x 106

Jawab :


= √3x 2,7 x 95

11,4 x 56x 106


Motor M26 Cooling Tower 5HP / 380 V


l : 100 meter

XCu : 56 x 106

Jawab :


= √3 x4,2 x10011,4 x 56x 106


Motor M27 Main Fire Hydrant Pump1 75 kW / 380 V


l : 60 meter

XCu : 56 x 106

Jawab :


= √3 x140 x6011,4 x 56x 106

= 22,7 mm2 (Diambil NYY 4 x (1 x 35 mm2) dengan KHA 210 A)

Motor M28 Jockie Fire Hidrant Pump 1 5 kW / 380 V


l : 70 meter

XCu : 56 x 106

Jawab :


= √3 x11,4 x7011,4 x 56x 106


KHA Busbar Cooling Tower


= 200 + 40 + 40 + 2,7 + 2,7 + 2,7 + 4,2 + 11,4

= 303,7 A

(Diambil busbar dengan penampang 124 mm2 dengan KHA 330 A)

KHA Busbar Utama Group 2


= 250 + 30 + 30 + 3,5 + 11,6 + 23 + 6,62 + 23 + 23 + 43 + 11,1

= 454,8 A

(Diambil busbar dengan penampang 320 mm2 dengan KHA 721 A)

KHA Utama Kabel Group 2

Diketauhi : ∑In : 448,5 A

l : 200 meter

XCu : 56 x 106

Jawab :


= √3 x 448,5 x20011,4 x56 x 106

= 243,4 mm2 (Diambil NYY 4 x(1 x 300 mm2 )dengan KHA 730 A)

Group 3

Bagian Bailing Press


l : 75 meterStarter : Y/∆

Jawab : IMCCB = 250 % x In

In = IMCCB

250 %

= 30

250 % = 12 A


= √3 x12 x75

11,4 x 56 x 106



l : 75 meterStarter : Y/∆


In = IMCCB

250 %

= 40

250 % = 16 A


= √3 x16 x75

11,4 x 56 x 106




l : 100 meter

Starter : Y/∆


In = IMCCB

250 %

= 60

250 %

= 24 A


= √3 x24 x 10011,4 x 56x 106




l : 100 meter

Starter : Y/∆


In = IMCCB

250 %

= 40

250 %

= 16 A


= √3 x16 x10011,4 x 56x 106


KHA Busbar Utama Group 3


= 60 + 16 + 16 + 12

= 104 A

(Diambil busbar dengan penampang 64,8 mm2 dengan KHA 179 A)

KHA Kabel Utama Group 3

Diketauhi : ∑In : 68 A

l : 200 meter

XCu : 56 x 106

Jawab : A = √3 x∈x l∆V x XCu

= √3 x68 x20011,4 x 56x 106

= 36,9 mm2 (Diambil NYY 4 x(1 x 50 mm2 )dengan KHA 250 A)

Perhitungan Isc

Jaringan sisi atas trafo R1 X1

Diketauhi :

Uo : 400V

Vp : 20 kV

Usc :5%

In : 1443,4 A

S : 1000 kVA

Digunakan maksimum 65% maka

In = 65% x 1443,4 = 938 A

S = 65% x 1000 = 650 kVA

Jawab

I sc=I n ×100

U sc

I sc=938× 100

5=18760 A=18,76 kA

Psc=√3 .V L . I sc

¿√320 .103 .18,76 .103

¿650 MVA

Z1=Uo2

Psc

¿ 4002

650¿246,15 mΩ

R1=Z1 x cosθ .10−3

¿246,15 x0,15 .10−3

¿0,037mΩ

X1=Z 1x sin θ .10−3

¿246,15 x0,98 .10−3

¿0,24 mΩ

Transformator (R2, X2)

R2 = Wc x Uo2 x10−3

S2

= 12100x 4002 x10−3

10002

= 1,936 mΩ

Z2 = Usc100

xUo2

S

= 5100

x4002

1000

= 8 mΩ

X2 = √Z 22−R 22

= √(8¿¿2)−(1,936¿¿2)¿¿

= √60,25 = 7,76 mΩ

Kabel 1 (R3, X3)

KHA= 125% x In

= 125% x 938

= 1172,5 A

Diambil NYY 4 x (1 x 630 mm2) dengan KHA 1195 A

R3 = ρlA

= 22,5x 100

4 x630

= 0,89 mΩ

X3 = 0,08 x l

= 0,08 x 100

= 8 mΩ

Pemutus Daya M1 (R4 X4 diabaikan)

Rt1 = R1 + R2 + R3 + R4

= 0,037 + 1,936 + 0,89

= 2,863 mΩ

Xt1 = X1 + X2 + X3 + X4

= 0,24 + 7,76 + 8

= 16 mΩ

Isc = Uo

√3 x √Rt 12+Xt 12

= 400

√3 x √2,8632+162

= 400

√3 x √264,2

= 14,2 kA (Digunakan MCCB Hager H1000 50kA 1000A)

Busbar 1 (R5 X5)

Diketauhi : ρ : 22,5

L : 10 m

KHA Busbar = KHA Kabel

= 1172,5A

(Digunakan Busbar 630 mm2 dengan KHA 1180A)

R5 = ρlA

= 22,5x 105x 630

= 0,07 mΩ

X3 = 0,08 x l

= 0,08 x 10

= 0,8 mΩ

Group 1

Pemutus Daya Group 1 (R61, X61 diabaikan)

RtG1 = Rt1 + R5 + R61

= 2,863 + 0,07 + 0

= 2,933 mΩ

XtG1 = Xt1 + X5 + X61

= 16 + 0,8

= 16,8 mΩ

Isc = Uo

√3 x √RT G12+ XTG1

2

= 400

√3 x √2,9332+16,82

= 400

√3 x √290,8

= 13,5 kA (digunakan MCCB hager H1000 50kA 800 A)

Isc M31 (R71 X71)

Digunakan NYY 4 x 1 x 400mm2 100m

Maka :

R Kabel M31 = ρlA

= 22,5x 100

4 x400

= 1,4 mΩ

X Kabel M31 = 0,08 x l

= 0,08 x 100

= 8 mΩ

Rt M31 = RtG1 + R71

= 2,933 + 1,4

= 4,333 mΩ

Xt M31 = XtG1 + X71

= 16,8 + 8

= 24,8 mΩ

o Isc = Uo

√3 x √RT M 312+ XT M 31

2

= 400

√3 x √4,3332+24,82

= 400

√3 x √633,8

= 9,1 kA

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