perhitungan masjen 2011
TRANSCRIPT
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LAMPIRAN
7.1. Perhitungan Data
7.1.1. Penentuan Volume Piknometer
Vp =(mp + a ) - (mp) . a
Vp =21,42 - 11,87
1
Vp = 9,55 cm3
7.1.2. Penentuan Massa Jenis Bahan Pangan Cair
7.1.2.1. Larutan ula 1! "
7.1.2.1.1. #uhu Ruang
b =(mp + b )- (mp)Vp
b =(22,5 ) - (11,87 )9,55
b =1,113
gr/cm
3
7.1.2.1.2. #uhu $inggi
b =22,6 - 11,87
9,55 = 1,124
7.1.2.1.%. #uhu #e&ang
b =22,55 - 11,87
9,55= 1,118
7.1.2.2. Larutan ula 2! "
7.1.2.2.1. #uhu Ruang
b =23,5 - 11,87
9,55 = 1,218
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7.1.2.2.2. #uhu $inggi
b =22 ,78 - 11,87
9,55= 1,142
7.1.2.2.%. #uhu #e&ang
b =22,93 - 11,87
9,55= 1,158
7.1.2.%. Larutan aram 1! "
7.1.2.%.1. #uhu Ruang
b =22,78 - 11,87
9,55= 1,142
7.1.2.%.2. #uhu $inggi
b =22,5 - 11,87
9,55= 1,113
7.1.2.%.%. #uhu #e&ang
b =22 ,66 - 11,87
9,55= 1 ,130
7.1.2.'. Larutan aram 2! "
7.1.2.'.1. #uhu Ruang
b =23,3 - 11,87
9,55 = 1,197
7.1.2.'.2. #uhu $inggi
b =23 - 11,87
9,55= 1,165
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7.1.2.'.%. #uhu #e&ang
b =23,35 - 11,87
9,55= 1,202
7.1.%. Bulk DensityBahan Pangan
Volume Balok = p x l x t
= 11,5 x 4,5 x 8,6
= 445,05 cm3
Volume Silinder = x r2 x t
= 3,14 x 3,692 x 11,16
= 46,920 cm3
Volume !an"kuk #$idak Beraturan%
Berat !an"kuk = 1,5 "ram
Berat !an"kuk & 'ir = 406,43 "ram
ma((a air = 406,43 ) 1,5
= 388,93 "ram
* = m + atau = m + *
= 388,93 + 1
= 388,93 cm3
7.1.%.1. Beras
7.1.%.1.1. Balok
bulk dens!" =447,72
445,05 = 1,006
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7.1.%.1.2. #ilin&er
bulk dens!" =387,92
344,218 = 1,127
7.1.%.1.%. Mangkuk ($i&ak Beraturan)
bulk dens!" =373,99
388,93 = 0,962
7.1.%.2. *a+ang ,i-au
7.1.%.2.1. Balok
bulk dens!" =447,39
445,05 = 1,005
7.1.%.2.2. #ilin&er
bulk dens!" =370,51
344,218 = 1,076
7.1.%.2.%. Mangkuk ($i&ak Beraturan)
bulk dens!" =366,17
388,93 = 0,941
7.1.%.%. *a+ang $anah
7.1.%.%.1. Balok
bulk dens!" =346,97
445,05= 0,780
7.1.%.%.2. #ilin&er
bulk dens!" =296,84
344,218= 0,862
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7.1.%.%.%. Mangkuk ($i&ak Beraturan)
bulk dens!" =295,64
388,93 = 0,760
7.2. Laoran #ementara