lampiran b.docx
TRANSCRIPT
LAMPIRAN B
PERHITUNGAN
B.1 Massa Fenol (C6H5OH) Teori
Asam Salisilat Massa Fenol (C6H5OH) = 6 gram
Mr Fenol (C6H5OH) = 94 gram/mol
Mol Fenol (C6H5OH) = 6 gram94 gram/mol
= 0,064 mol
Asam Nitrat Volume asam nitrat = 21 ml
Massa jenis asam nitrat = 1,39 gram/ml
Massa asam nitrat = 21 ml x 1,39 gram/ml = 29,19 gram
Mr asam nitrat = 63 gram/mol
Mol asam nitrat = 29, 19 gram63 gram/mol
= 0,463 mol
Reaksi : fenol + asam nitrat asam pikrat + air
Mula-mula 0,064 0,463 0 0
Bereaksi 0,064 0,064 0,064 0,064 -
Sisa 0 0,386 0,064 0,064
Jadi, mol fenol sama dengan mol asam pikrat
Mol fenol = 0,064 mol
Mr fenol = 229 gram/mol
Massa fenol teori = 0,064 mol x 229 gram/mol = 14,656 gram
B.2 Massa Fenol (C6H5OH) Praktek
Massa fenol kristalisasi = 23,96 - 3,90 – 2,65 = 17,41 gram
Massa fenol rekristalisasi = 8,15 - 4,59 – 1,98 = 1,58 gram
Massa total fenol praktek = 27,82 + 1,34 = 18,99 gram
B.3 Perhitungan Persen Ralat
% Ralat = |14,656 – 18,9914,656 | x 100 %
= 29,57 %