LAMPIRAN B

PERHITUNGAN

B.1 Massa Fenol (C6H5OH) Teori

Asam Salisilat Massa Fenol (C6H5OH) = 6 gram

Mr Fenol (C6H5OH) = 94 gram/mol

Mol Fenol (C6H5OH) = 6 gram94 gram/mol

= 0,064 mol

Asam Nitrat Volume asam nitrat = 21 ml

Massa jenis asam nitrat = 1,39 gram/ml

Massa asam nitrat = 21 ml x 1,39 gram/ml = 29,19 gram

Mr asam nitrat = 63 gram/mol

Mol asam nitrat = 29, 19 gram63 gram/mol

= 0,463 mol

Reaksi : fenol + asam nitrat asam pikrat + air

Mula-mula 0,064 0,463 0 0

Bereaksi 0,064 0,064 0,064 0,064 -

Sisa 0 0,386 0,064 0,064

Jadi, mol fenol sama dengan mol asam pikrat

Mol fenol = 0,064 mol

Mr fenol = 229 gram/mol

Massa fenol teori = 0,064 mol x 229 gram/mol = 14,656 gram

B.2 Massa Fenol (C6H5OH) Praktek

Massa fenol kristalisasi = 23,96 - 3,90 – 2,65 = 17,41 gram

Massa fenol rekristalisasi = 8,15 - 4,59 – 1,98 = 1,58 gram

Massa total fenol praktek = 27,82 + 1,34 = 18,99 gram

B.3 Perhitungan Persen Ralat

% Ralat = |14,656 – 18,9914,656 | x 100 %

= 29,57 %