kunci sukino 3a bab 1
DESCRIPTION
Kunci Sukino 3ATRANSCRIPT
- 1 -
A. Evaluasi Pengertian atau Ingatan
1. C. x6+c
dxx56 =66 x6+c
= x6+c
2. B.na xn+c , dengan n≠0
cxn
adxax nn 111
11
=na xn+c , dengan n≠0
3. B. cxn
an
1)1(
dxaxdxxa nn
cxn
a n
1
)1(
cxn
an
1)1(
4. A.41 z4-z3+
21 z2-3z+c
dxzzz )33( 23
=41 z4-z3+
21 z2-3z+c
5. B. cx 311
45
cxdxx 31
31 1
3435
35
cx 311
45
6. A. cxx
23
322
cxxdxxx 23
21
32
12)2( 12
cxx
23
322
7. C. 0
cxxxdxxx 5342
31)51(
A=1 B=1 → A-B=0
8. A. 0
dxxdxx
xx )12(22
23
cxx 2
A=1 B= -1 → (A+B)2=0
9. C. 0
cxxxdxxx
31
32
31
3165 35
24
A=31
B=32
D=31
→ A+B+D=0
10. A. ctt
3311
dt
ttdt
tt
424
2 111
ctt 33
11
B. Evaluasi Pemahaman dan Penguasaan Materi
1. a. cxxxx 38
38
38
35
83
83
b. xxxxx 253
22 35
35
32
cxx 253
35
c. cxxxx 10101011
101
101
d. cxxxx 5554
53
53
33
e. cxxxx
221
f. 423 3232 xxxxx
cxxxxxx 422422
41
23
41
23
g. 524 2323 xxxxx
cxxxxxx 5252
51
351
3
h. xxxxxxx 52345234 23423
cxxxxxxxx 55 234234
BAB IINTEGRAL
Latihan KompetensiSiswa 1
- 2 -
2. a.
cxdxxxx
dx2
12
3
2
cx
2
b. ctttdttt 322
31
3)23(
c.
dxxxxdxx
xx 3455
2
2525
cxxx
234
41
45
cxxx
234
131
45
d. dxxxx )1634( 23
cxxxx 234 2
e. cx
xdxx
x
1321
2 32
2
f. dxxx 1612 23
cxxx 34 23
g.
dxxxdx
xx 33
33 105
25
cxx 24 545
h.
c
xxxdx
xxx
1511
2 252
4
3. a. cxdxxdxx 49
45
944 5
b.
cxdxxdxx
313
4
313 4
c. cxxxdxxx
53532 12
23
d.
dx
xxx 2
21
cxxxx 441 2
e. dxydxy
yy 22
22
2112
cxy
x 213
f.
cxxxdx
xx 2
32
212
g. dxx
xx 5531
cxxxx 211
111022
h. cxxdxxx 3623
613
4. a. dxxxdxx 121 2422
cxxx 35
32
51
b. dxxxxdxx 323 6128)2(
cxxxx 432
41
268
c. dxxxdxx 6323 211
cxxx 74
71
21
d. dxxx 222)4(
dxxxx 642 816
cxxx 753
71
58
316
e. cxxdxxx 3623
61
)3(
f. dxxxxdxxx 7423 2)1(
cxxx 852
81
52
21
5. a. dxxxxdxxx 963323 2)1(
cxxx 1074
101
72
41
b. cxxxxdxxx 2
52
32)1(
c.
dx
xx
31
dxxxxx 2
32
12
12
3 33
cxxxx 2
12
12
32
5 26252
d. dxxxdxxx 2)1(
21
2
cxxx 23
21
3222
e. dxxx 22 1
dxxxxx 1232 234
cxxxxx 2345
21
51
f. dx
xxx )2)(1(
dxxxx 2
12
3 2
cxxx 21
23
25 4
32
52
- 3 -
A. Evaluasi Pemahaman dan PenguasaanMateri
1. a.
cxxdxx
xx 243
46
2334
b.
cx
xdxx
xx 141 4
3
6
c. dxxxxx 245327 357
cxxxxx 232
445
21
827 468
d. dxxxxx 335 232
cxxxx 3456
33
43
61
e.
dzzzzdzz
z2
12
32
7
21 22
czzz 21
25
29
254
92
f. dxxx23
cxxx 27
21
94
71
29
g. dttt2
2
cttt 23 25
524
31
h.
crrrdrr
rr2
32
52
7
32
54
721 2
i.
dx
xx
4 5
3 2 4
cxx
41
35
1653
j.
dx
xxx
12
cxx 21
25
254
2. a. dxxx
123
23
3
cxxx
25
54
23
2
b.
dx
xx 32
43
32
cxx 31
41 98
c.
dx
xx
3
3 2 64
cxx 32
35
95
12
d. dxxx 33 )1(
dxxxxx 31
34
37
310
33
cxxxx 34
37
310
313
43
79
109
133
e. dxxx 3)1(
dxxxxx 27
25
23
21 33
cxxxx 29
27
25
23
92
76
56
32
f.
dxx
xx2
34
7532
cx
xx 75
143
212 3
g.
dxx
x 2)43(
dxxxx 2
12
12
3 16249
cxxx 21
23
25
32165
18
h.
dxxx
x 3)43(
23
6414410827 23
xxxx
dxxxxx 23
21
21
23
6414410827
cxxxx
21
21
23
25
12828872554
i. dxx 4)1(
dxxxxx 1464 2234
cxxxxx 3345
34
251
j. dtt 5)119(
)119()119(91 5 tdt
ct )119(541
3. a. dxxx )3)(1(53
dxxx
59
512
53 2
cxxx 59
56
51 23
Latihan KompetensiSiswa 2
- 4 -
b.
dx
xx
32 1
dxxxx 338 33
cxxxx 249
21
343
91
c.
dt
tt
4
22 1
dttt 4221
cttt 31
31
2
d.
dxxx
xx
xx 211
dxxx
xx 2
22 1
dxxxx 234 1
cxxxx 145
41
51
4. a. dxxxx 7 5 355
cxdxx 534
529
345
b. dxxxx 10 354
cxdxx 526
521
265
c. dxxxxx 5 7 3 253
cxdxx 625
619
256
d. dxxxx 7 5 26 22
dxx 2191263
3562
dxx 79421
3562
cx 70421
356
491702
5. a. dxxxx 10 354
3
dxx15
68
3
cx 1553
5345
b. dxx
xx4
10 32 322
dxx 39
113301
1011
32
cx
83323 30
83301
1011
c.
dxxx5 3 242
dxx61
31
2
cx
673
1
726
d. dxxx 7 53 3222dxx 70
211701
3541
32 cx
79
281701
3541
7028132
B. Evaluasi Kemampuan Analisis
1. dx
xx 22 )1(11
1
= ...= ...
2. dxxx 52 1
dxx
xxxx
xxxx
1515304656
4530102346
67810
cxxxxx
xxxxx
2345
678911
25
315
430
546
656
745
830
910
11
cxxxxx
xxxxx
2345
678911
255
215
546
328
745
415
910
11
3. ...33 22 xxy dengan x≠0
...333 2244 xxxy
yxy 44 3
434
3xyyy
343 3xy
dxxydx 343 3
cx 37
7333
- 5 -
4. ...222 xxxy= ...= ...
A. Evaluasi pengertian atau Ingatan
1. D. 10
cxxxdxxx 322 23)343(
f(-3)= -9-18+27+c=10c=10
2. C. 2x3-x2+x-10
f(x)= dxxx )126( 2 = 2x3-x2+x+c
f(2)=16-4+2+c=414+c=4
c= -10f(x)= 2x3-x2+x-10
3. D. 5
cxxdxxxf 23)(
19442)4( cfc=3
32)( xxxff(1)=5
4. A. x4-x2-5
y1=f1(x)= dxx )212( 2
= 4x3-2x+c1
y=f(x)= dxcxx )24( 13
= x4-x2+c1x+c2
f(0)=c2= -5f(2)= 16-4+2c1-5=7
c1=0f(x)= x4-x2-5
5. C. x2-2xy1=f1(x)=dx2 =2x+c1
f1(x)= 2+c1=0c1= -2
f1(x)=2x-2
f(x)= dxx22
= x2-2x+c2
f(0)=02-2∙0+c2
c2=0f(x)= x2-2x
6. B. -x1 +3
f(x)= cx
dxx
112
f(1)= -1+c=2c=3
f(x)= -x1 +3
7. B. x3+2x2+x-2f1(x)= dxx 46 =3x2+4x+c1
f(x)= dxcxx )43( 12
= x3+2x2+c1x+c2
f(1)=1+2+c1+c2= 2c1+c2= -1 ... (a)
f(-2)= -8+8-2c1+c2= -4-2c1+c2= -4 ... (b)
a dan b dieliminasi, didapat:c1=1 dan c2= -2f(x)= x3+2x2+x-2
8. B.21
15
f1(x)= dxxdxxf )32()(11
=x2-3x+c1
5=0-0+c1 → c1=5f1(x)=x2-3x+5f(x)= dxxxdxxf )53()( 21
= 223 5
23
31 cxxx
5=0-0+0+c2 → c2=5
f(x)= 5523
31 23 xxx
f(3)= 5)3(5)3(23
)3(31 23
=21
15
Latihan KompetensiSiswa 3
- 6 -
9. C. 11y= dxx )14( =2x2+x+c
0=8+2+c1 → c1= -10y=2x2+x-10x=3 → y=18+3-10=11
10. D.3155 xy
cxxdxxy 32
31)1(
0=0-0+c → c=0
y=31
x3-x
m=y1(2)=22-1=3
y(2)=322
38
)2(332 xy
3153 xy
B. Evaluasi Pemahaman dan Penguasaan Materi
1. a. F(x)= dxx )46( = 3x2-4x+c
3=0-0+c → c=3Jadi F(x)= 3x2-4x+3
b. F(x)= dxxx )263( 2
= x3-3x2+2x+c7=0-0+0+c → c=7
Jadi F(x)= x3-3x2+2x+7
c. F(x)= cx
dxx
112
21
321
3 cc
Jadi F(x)=21
31
x
d. F(x)=
dxx2
41
cxx 3
31
41
c 3)1(31
)1(41
2
1211
1121
2 cc
Jadi F(x)1211
131
41 3 xx
e. F(x)= dxxx )2)(1(
= dxxx )23( 2
= cxxx 223
31 23
c 6227
923
c=0
Jadi F(x)= xxx 223
31 23
f. F(x)=
c
xxdx
xx 2
212 2
2
9=2+1+c → c=6
Jadi F(x)= 62
21 2
xx
g. cxxdxxxF32
)(
c 4432
0
316
c
Jadi, cxxxF 32
)(
h.
dx
xxxF 2
3 23)(
cx
x 2
43 4
41
2243
1 c
Jadi,41
22
43
)( 4 x
xxf
i.
dx
xxxxF 3
4 33)(
cx
xx 225
23
23
51
c23
23
51
1
54
1c
Jadi,54
123
23
51
)( 225
xxxxF
j. dxxxF 3)2()(
dxxxx )8126( 23
cxxxx 86241 234
c 162416415c
Jadi, 586241
)( 234 xxxxxF
- 7 -
2. a. cxxdxxxg 21
23
)13()(
b. cxxdxxxg32
)(1
c.
dx
xxdx
xx
xg 33
41 11
)(
cx 21
21 2
d. dxxxg )32()(1
cxx 32
e. cxxg 34
)(1
cxx 32
73
f. cxxdxxxxg 2321
21
31
)()(
3. a. cxxdxy 22
213 2 cc22 xy
b. cxxdxxy 2
21)1(
2131
213 cc
213
21 2 xxy
c. cxxdxxy 2
21)1(
2111
213 cc
211
21 2 xxy
d. cxxdxxy 2
23)13(
2121
233 cc
212
23 2 xxy
e. cxxdxxy 32
311
3231
313 cc
323
31 3 xxy
f. cx
dxx
y 112
110 cc
11 x
y
g. cxxdxxy32
c 4432
5
31
c
31
32
xxy
h. dxxxy 123 2
cxxx 23
11110 cc123 xxxy
i. dxxxy 164 23
cxxx 34 26216168 cc
62 34 xxx
j. cx
dxx
y21
21
2
341
43
2 cc
321
x
y
4. a. dxxxF )14()(
cxx 22131820 cc
12)( 2 xxxF9128)2( F
b. dxxxxF 126)( 2
cxxx 23250005 cc
52)( 23 xxxxF1952416)2( F
c.
c
xxdx
xxF 111)( 2
3113 cc
31)( x
xxF
2143
212)2( F
- 8 -
d. xdxdx
xdF6
)(
123 cx
000 11 cc
23)(
xdx
xdF
2323)( cxdxxxF
880 22 cc
16)2(8)( 3 FxxF
e. 122)(
cxdxdx
xdF
3023 1 cc
32)(
xdx
xdF
dxxxF )32()(
22 3 cxx
7315 22 cc
73)( 2 xxxF17764)2( F
f. cx
dxx
xF21
21
)( 2
31
161
67
cc
31
121
)( x
xF
121
131
141
)2( F
g. dxxxxF )204)(1()(
dxxx )20164( 2
cxxx 20834 23
32
3620834
10 cc
32
3620834
)( 23 xxxxF
32
364032332
)2( F
31
25
h. dxxdx
xdF)16(2
)( 2
dxx )212( 2
13 24 cxx
5005 11 cc
524)( 3 xx
dxxdF
dxxxxF 524)( 3
224 5 cxxx
35112 22 cc
35)( 24 xxxxF19310416)2( f
Soal Aplikasi Bidang Geometri
5. cxxdxxy 3)32( 2
2992 ccPersamaan kurva:
232 xxy
6. dxxxxdxxxy 23422 2
cxxx 345
31
21
51
00000 ccPersamaan kurva:
345
31
21
51 xxxy
7. dtkttF )25()(
cktt 2500050 2 cck
01151 k4k
245)( tttF
8. cxxdxxxF 23)(
509924 cc
502)( xxxF
9. a. dxxxy 583 2
cxxx 54 23
c 15362742c
254 23 xxxy
- 9 -
b. Akan dibuktikan (2,0) memenuhi persamaankuva tersebut.
2252420 23 2101680
00 (terbukti)Jadi, (2,0) melalui persamaan kurva
254 23 xxxy
10 . cxbaxdxbxay 2
2)(
0000 cc2
2xbaxy
1)0( ba1a
22 )1(2
)1(1)1(2
)1(3 bba
42
13 bb
22xxy
11 . 1236 cxxdx
dxdy
01212 11 cc
23xdxdy
2323 cxdxxy
484 22 cc
43 xy
12 . 21 3145)( tttF
cttttF 3275)(
Sumbu simetri37
614 t
c
27343
949
737
525
732675)(
27326 32 ttttFc
13. dxxxf )34()(
cxx 32 2
0)(1 xf034 x
43
x
c
43
343
281 2
c818
89
81
45
810
c
45
32)( 2 xxxf
Soal Aplikasi Bidang Mekanika
14. dttadttv )210()(
1210 ctt
12001000)0( cv
01 c210)( tttv
dtttts )10()( 2
232
31
5 ctt
0)0( s
232 0
31
050 c
02 c
32
31
5)( ttts
Benda akan berhenti ketika 0)( ts
031
5 32 tt
0151
15 2
tt
t=0 t=15Benda itu akan berhenti ketika 15t
15. dtttv )218()(
1218 ctt
20)0( v
10020 c201 c
2018)( 2 tttv2036108)6( v
sm92
- 10 -
2018)( 2 ttts
223 209
31
cttt
81)3( s
26081981 c512 c
5120931
)( 23 tttts
16 . a. dtts 3
1
)36(
3063633 31
2 tt
b. 4
2
2 23 dttts
68128042
23 tt
c. 9
4
5 dtts
3135635
32 9
4
ttt
3227
d. 5
0
)22( dtts
152 50
2 tt
e. 4
0
2 23 dttts
4
0
23 223
31
ttt
315824
364
17 . Total biaya = xdx)005,0064,1(
cxx 20025,0064,1biaya awal = 16,3
Total biaya = c 200025,00064,13,16c
Total biaya = 3,160025,0064,1 2 xxRata-rata biaya
xx 3,160025,0064,1
18. Total biaya )(xf
dxxx 26602
cxxx 32 2302Rata-rata biaya
xcxx 22302
19. Fungsi pendapatan total )(xR
dxxx 2268
cxxx 32
32
38
Fungsi Demand:
xcxx 2
3238
20. Fungsi pendapatan total
cxx
dxxx
ln23232
Fungsi Demand
xc
xxx
ln23
2
C. Evaluasi Kemampuan Analisis
1. a. cbxaxy 2
cba 0)0,1( ... (1)cba 390)0,3( ... (2)048 bacba 12)12,1( ... (3)
(1) dieliminasi dengan (3), diperoleh:6b
Subsitusi 6b ke 048 ba248 a3a
96312 ccJadi, persamaan kurva adalah:
963 2 xxy
b. Sketsa grafik kurva.
8
10
12
2
2
4
4
6
6
-2-4 x
- 11 -
2. 12 xa
dxdy
31 dxdy
x
211
3 2 aa
122
xdxdy
dx
xy 1
22
cxx
2
31 yx
c
112
3
4c
42
xx
y
3. ))(( qxpxadxdy
apqxqpaaxdxdy )(2
apqxqpaaxy )(2
capqxxqpaxa 23
2)(
3
axcapqqpaa 12)(2
380
axcapqqpaa 2
2)(
31
pqqp 222
...
4. baxxdxdy
23
330 baba5332732 baba
84 a2a1b
dxxxy 123 2
cxxx 23
5.
...
6. ctdtv 3232
5003250)0( cv50c
50432)4( v178 kaki/detik
dtts 5032
ktt 5016 2
10000500161000)0( 2 ks1000k
10005016)( 2 ttts1000200256)4( s
1456 m
A. Evaluasi Pemahaman dan PenguasaanMateri
1. a. duuu cos36 2
cuu sin32 3
b. d1tan2
cd tansec2
c. dd sectan
cossinsec
c sec
d. d)cos3sin2(
c sin3cos2
e.
d
2cos1cos
deccoscos
cec cos
f. dxx )1(cot2
xdxec2cos
cx cot
Latihan KompetensiSiswa 4
- 12 -
g. dx
xx2sin1
sin
xdxx sectan
cxsec
h. dxxxx sin2
cxxxx 32cos
31 3
2. a. dxxx 24cos6
cxx 3
34
sin6
b. dxxx sin6cos8
cxx cos6sin8
c. dxx
x2cos
sin
cxsec
d. dxxx
2sincos
cecx cos
e. xdxxxx 2244 cossin2cossin
dxxx222 cossin
cxdx21
f. d 2cos1
c cos2sin2
g. d 2cos1
c sin2cos2
h. dxxx 1secsec 2
xdxx tansec
cxsec
3. a. xdxxF sin23)(
cxx cos23csc 002031
1c
b. xdxxF cos23)(
cxx sin23c 0sin2035
5c5sin23)( xxxF
c. dxxxF 3sec)( 2
cxx 3tan
c4
34
tan43
2
1c13tan)( xxxF
4. a. xxxF sincos)(
cxx cossin
c2
cos2
sin5
4c
44
cos4
sin4
F
24
b. xdxxxF cossin)(
cxx sincos
c3
sin3
cos321
21
c 321
21
321
21
1c
14
sin4
cos4
F
12
c. cxdxx
xxF sec
cossin
)( 2
c3
sec7
5c
54
sec4
F
25
5. a. dxxx 22 sec2cos4
xdxx 2sec22cos
21
214
cxxx tan22sin2
b. dxxxecxx sectancoscos
cxecx seccos
c. dxxecx 0cossec 2
cecxx costan
d. dxxxxecxx tanseccoscos2sin4 2
xdxxxx seccotsin2cos4
e. dxx 5tan2
dx61tan 2
dxx 6sec2
cxx 6tan
f. dxx 7cot2
dxx 61cot2
dxxec 6cos 2
cxx 6cot
- 13 -
B. Evaluasi Kemampuan Analisis
1.a. dx
xx
xx 22
sin1sin2
sectan
= xdxxxxxx sectan2sectan2sectan 22
dxxx 1sec1tan 22
dxx 1sec2 2
cxx tan
b. dxxx
xx 22
secsin2
sectan
xdxxxxxx 222 cossin2sectan2sectan
xxxx sectan21sec1tan 22
)(coscos2 2 xxd
cxxxx 3cos32sectan2
c. dxxxecxx 2
2
sincos2coscot
ecxxxecx coscot2coscot 22
ecxdxx coscot2
dxxecx 1cos1cot 22
cxx cot2
2. a.
dxxx
xx2
33
cossincossin
...
b.
dxxx
xx2
33
cossinsincos
...
c.
dxxxxx
42
33
coscoscossin
...
d.
dxxxxx
42
33
sinsinsincos
...
A. Evaluasi Pengertian atau Ingatan
1. B. aabb 32
b
a
b
a
xxdxx 3
2
aabb 32
2. C. babababa )(32
ab
ba
ab
ba
xxdxx
3
2
= babababa )(32
3. C.31
2
1
22
121)2(
21 dxxxdxxx
2
1
32
61
21
xx
61
21
342
31
4. 104
919
1
46 xxdxx 1044108
Latihan KompetensiSiswa 5
- 14 -
5. D.21
26
2
6
sincos
xxdx
21
21
1
6. C. 5
123)32( 12
1
n
n
xxdxx
12)31(32 nn
01032 nn0)2)(5( nn
5n
7. C. -1
63)23(22
2
aa
xxdxx
6)3(46 2 aa
0432 aa0)1)(4( aa
1a
8. E. 4
2
0
)(9 dtt
2
1
1
0
)(9)(9 tdtt
1
2
1
0
)(9)(9 dttdtt
4)2(2
9. D. 23
263 13
1
2 t
t
xdxx
261tt22
33t
33 32t
10 . C. 388
7
3
3 210 dxxx
7
3
24 2541
xxx
=388
11. B. -13,5
4
1
2 12153 dxxx
5,13122
15 4
1
23 xxx
12. A. 2
xdxx cos3sin0
0sin3cos xx
2)01(01
13. A. 4
2
0
cos)tan5(
xdxx 2
0
sincos5
xdxx
20cossin5
xx4)10(05
14. A. -6
0
sin)3(cot xdxx
0
sin3cos xdxx
0cos3sin xx 6)30(30
15. A. -2, 0 dan 3
n
dxxx1
2 623
46 123
nxxx
4611623 nnn0623 nnn
0)2)(3( nnnn= -2 n=0 n=3
B. Evaluasi Pemahaman dan Penguasaan Materi
1. a.5
0
25
021
cxxdx
)0(225
cc
225
b.3
1
43
1
3
41
cxdxx
2041
481
cc
- 15 -
c.5
0
35
0
2
35
5 cxdxx
)0(3
625cc
3625
d.3
2
3
22
1 c
xxdx
cc
21
31
61
e.2
1
34
2
1
3
43
cxdxx
cc
43
1643 3
14,111643 3
f.3
1
23
1
223
23 cxxdxx
cc 2
23
62
27
8
g.4
12
4
13
1632 c
xdx
x
15)16(1 cc
h.
2
1
23 234 xdxxx
2134 2 cxxx)211(4816 cc
30
i.
1
1
42 42 dxxx
1
1
53
54
32
cxx
54
32
54
32
c
51
31548
152420
58
34
j.3
23
32 21111
c
xxdx
xx
cc
181
31
21
1
92
11822
1816918
2. a. 22424
1
4
1
xx
dx
b. 621
2)2(2
0
22
0
xxdxx
c. 2
0
22
0
2 44)2( dxxxdxx
38
31
242
0
32 xxx
d. 3
0
223 dxxx
931
33
0
32 xxx
e.
2
1
32
1
21 dttttdtt
2
1
42
41
21
tt
41
241
21
42
f. 4
1
)1( duuu
4
1
duuuu
4
1
2
52
32
uuuu
52
32
564
316
1518670
562
314
1511
715116
g. 2
0
252
0
32 1 dxxxdxxx
2
0
36
31
61
xx
340
38
332
h.
1
0
21 dxxx
1
0
2dxxx
61
31
21 1
0
32 xx
- 16 -
i.8
1
3 28
1
32
53
xxdxx
593
53
596
j.
2
1
)12)(5( dxxx
2
1
2 592 dxxx
2
1
23 529
32
xxx
5
29
32
10183
16
29
3. a. 5
1
5
1
)(2)(2 dxxhdxxh
842
b. 5
1
3)( dxxh
5
1
5
1
3)( dxdxxh
16)15(34
c. 1
5
)( dxxh
4)(5
1
dxxh
d. 5
1
)( dxkxxh
28)(5
1
kxdxdxxh
28152
4 22 k
2k
4. a. 3
0
)( dxxf
3
2
2
0
)()( dxxfdxxf
1055
b. 2
3
2
0
)()( dxxfdxxf
3
2
2
0
)()( dxxfdxxf
055
c. 2
0
2)(4 dxxf
2
0
2
0
2)(4 dxdxxf
22)02(254
d.
0
2
)( dxxf
5)(2
0
dxxf
5. a. 2
0
)1(cos
dxx
20sin
xx
21
b. 4
0
2tan1
dxx
1tan 40
x
c.
00
cossin xxdx 211
d. 2
0
)sin(
dxxx
2
0
2 cos21
xx
)10(08
2
18
2
e.
4
4
)(cos
dxxx
4
4
2
21sin
xx
322
21
322
21 22
2
f. 4
0
2cot1
xdx
1cot 40
x
- 17 -
g.
4
4
sincot2
xdxx
2sincos2 4
4
xx
h.
3
4
2tan1
xdx
3
4tan
x
31)1(3
i. 4
3
2cot1
xdx
4
3cot
x
1331
311
j.
2
4
costan2
xdxx
2
4
sincos2
xdxx
2
4cossin2
xx
2
21202
223
2
6. a. 4)12( 12
1
a
a
xxdxx
062 aa0)2)(3( aa
a= -3 a=2HP={-3,2}
b. 462)32(2 12
1
a
a
xxdxx
0862 2 aa0432 aa
0)1)(4( aaa=4 a= -1HP={-8,3}
c. 185)52( 12
1
a
a
xxdxx
02452 aa0)3)(8( aa
a= -8 a=3HP={-8,3}
d. 2421
)13(3
1
233
2 xxdxx
a
2421
29
27 23
aa
48954 23 aa0323 aa
1321
21
21211
2,1
a
HP=
2131
,2
131
7. a. 5
2
228 dttts
5
2
32
318
ttt
38416
31252540
63
11745
b. 3
12
82 dtt
ts
3
1
2 8
tt
38)81(
389
c. dttt 3
0
2 2
3
0
23 221
31
ttt
21106
299
8. a. 3
1
)2)(1( dxxxx
dxxxx 3
1
23 2
3
1
234
31
41
xxx
1
31
41
994
81
3220
- 18 -
b.
dxx
xxx2
2
dxxxx
212
xx41
1
c. dxxxx
3
12
32 1
3
1211dxx
x
3
1
2 121
xxx
1
211
31
291
326
d. 3
22
234
)1(22 dx
xxxxx
3
22
22
1)2)(1( dx
xxxx
3
2
23
31
xx
43899
3111
e.
2
1
23 5438 dxxxx
21234 522 xxxx525212208832
f. 33
223 2
3 2 125 dxx
x
23
23
3
2
33 2 363 xxx
236223336393
242363
223321
9.21
)2(1
n
dxx
21
221 1
2
n
xx
21
22
12
nn
142 2 nn0342 nn
0)3)(1( nnn=1 n=3(tm)
a. 1232 nb. 49)12( 2 n
c. 1)2( 2 n
d. 25)2( 2 n
10. a
dxx1
10)52(
105 12
axx
0452 aa0)1)(4( aa
a= -4 (tm) a= -1
1
0)12(b
dxx
012 bxx
02 2 bb022 bb0)1)(2( bb
b=2 b= -1(tm)
a. 9)21()( 22 ba
b. 1)21()( 22 ba
c. 34122 bad. 31422 ab
- 19 -
C. Evaluasi Kemampuan Analisis
1. a.
23
23
2 76 dxxx
23
23
23 7331
xxx
2721218332329
15
272121832
319
5
2620
b.
dxcbxax2
cxx
bx
a 23
23
cba 2233
23
c.
a
a
dttt22 2
a
a
dttttt 4452 234
a
a
ttttt 42
35
21
51 2345
334455
35
21
51
aaaaaa
aaaa 42 22
aaa 83
1052 35
d. 12
2x
x
dtt
123
31
x
x
t
xxxx 11212831 23
31
311
438 23 xxx
2. dcxbxaxxf 23)(00)0( df
00)1( cbaf
cbxaxxf 23)( 21
3636)0(1 cfsehingga 36ba
36 ab
1
0
23 5ddxcxbxax
1
0
23 36)( xdxxaax
5183
364
1
0
234
xx
ax
a
5181234
aa
112
a
12a483612 b
3. 1
0
2 dxmlxbaxx
1
0
23 )()( bmdxxblamxalmlx
0234
1
0
234 bmxxblamxalmxl
= ...
4. 1
0
221
0
)66(6612 xabaxadxax
0)6( bdxxab
3310
2 )22(266 xabaxaxax
02
31
0
2
bxxab
02
322212 bababaa
0621
16 ba
ab1233
1
0
2221
0
2 2 dxbabxxadxa
13
1
0
2232
2
xbabxxaxa
13
22
2 babaa
11441089
1233
32
22
aaaaa
- 20 -
1144
108939648144 2222
aaaa
144885 2 a
8851442 a
885
12a
ab1233
885
396
885
12 ba
885
396
885
12
ba
a. 22 334 baba
12,51688512492
b. ba 38
885
3963
885
96
885
1096
885
1096atau
5. a. x
dtttxf1
2 43)(
x
ttt1
23 423
31
4
23
314
23
31 23 xxx
6524
23
31 23 xxx
43)( 21 xxxf
b.
15
1
2 43x
dttt
223 1)15(231)15(
31 xx
1154 x
xxxxxx 2015275525
3125 223
xxx 102
153
125 23
1015125)( 21 xxxf
c.
x
x
dttt 12 2
x
x
ttt 23
21
32
xxxxxx 2233
21
32
xx 234 3
24)( 21 xxf
d.
3
1
22 dtxxtt
3
1
223
231
txt
xt
)13()19(2
)127(31 2 x
x
328
44 2 xx
48)(1 xxf
e. x
dxxxt3
2
x
xtx
3
23
21
3
29
921
33
4
xxx
923
34
)( 231 xxxf
f. x
dttxt3
2
x
ttx
3
23
3
993
24
xxx
9234)( 231 xxxf
6. a. 2
0
12 )()( dttfxxf
)0()2()( 2 ffxxf
b. x
a
xxdttf 23)( 21
23)()( 2 xxafxf
)(23)( 2 afxxxf
c. x
axxdttf1
21 2)(
axxfxf 2)1()( 2
)1(2)( 2 faxxxf
- 21 -
d. x
xxxfdttf1
21 7)()(
7)()1()( 2 xxxffxf)1(f
...
e.
1
1
1 2)( dxxf
2)1()1( ff
x
fxfdttf0
1 )0()()(
3
9x
k
7. a
dttfxxaf0
)(4)(
a
xxafdttf0
4)()(
a
xxafdtxf0
4)()(
8. x a
dttfaxxdttf0 0
2 )()(
...
A. Evaluasi Pengertian atau Ingatan
1. C. 1,0;)1(
1 1
nacbaxna
n
dxbax n
)()(1 baxdbaxa
n cbax
nan
1)(
)1(1
Penyebut tidak boleh nol, sehingga a≠0 dan n≠ -1
2. A. 1;0;)()1(2
1 12
nacbaxna
n
baxdbaxa
dxbaxxnn 222
21
)(
cbaxna
n
12
)1(21
a≠0 dan n≠ -1
3. E. 2
cxaxdx 3
3
cxxdx 32
3Jadi, a=2
4. C. 56 x
)65(6561
65 xdxdxx
cxx 65)65(32
61
cxxcxxf 65)65(91
65)(91
56)65()( xxxf
5. A. x59
)59()59(51)59( 66 xdxdxx
cx 7)59(351
xxf 59)(
6. B. cx 5)37(151
)37()37(31)37( 44 xdxdxx
cx 5)37(151
Latihan KompetensiSiswa 6
- 22 -
7. C. 0;)cos(1
2 acbaxa
dxbaxa
)sin(1
0;)cos(12 acbax
a
8. D. 0);sin( abax
dxbaxa )cos(
0);sin( abax
9. E. cx
31
4sin41
dxx
31
4cos
= cx
31
4sin41
10 . D. cx
415tan
51
dxx
415sec2
cx
415tan
51
11 . B.97
1
0
231 dxxx
1
0
22 313161
xdx
1
0
22 313191
xx
97
91
98
12 . D. 12232
dtan1sec45
0
2
= )(tantan145
0
d
=
45
0
tan1)tan1(32
=322
24
= 12232
13. D. c2sec21
dd 23 sectan
cossin
)(secsec d
c 2sec21
14. A. ctt 3331 22
dtttdttt 33 224
)3(321 22 tdt
ctt 3331 22
15. D.31
1
0
21
0
42 1 dxxxdxxx
1
0
22 )1(121
xdx
1
0
22 1)1(31
xx
31
16. C.8
17
1
1
3
141 dxx
1
1
3
1411
414 xdx
1
1
4
141
x
25681
256635
817
1634
256544
17. E. cxx 552 33
dxxx 59 32
553 33 xdx
cxx 552 33
- 23 -
18 . C. cx 14 3
dx
x
x
1
63
2
1
123
3
x
xd
cx 14 3
19 . B. 2881
4
0
4 sincos5
xdxx
4
0
4 )(coscos5
xxd
40
5cos
x
1281
2881
20 . A. cxxxx 41782142 22
dxxxx 417216 2
4174173 22 xxdxx
cxxxx 4174172 22
B. Evaluasi Pemahaman dan Penguasaan Materi
1. a. dxx 23
)2(
cx 25
)2(52
b.
)1()1(
1)1( 33 xd
xxdx
cx
2)1(21
c.
3
33 x
xdxdx
cx 32
d. )13(133113 xdxdxx
cxx 13)13(92
e. xdxx 31
2 32
323241 23
12 xdx
cxx 3 22 3232163
f. dyyy 341
44 1141
ydy
cyy 44 1161
g. dxxx 24
22 4421
xdx
cxx 22 4431
h. dxx4
)4(4 xdx
cxx 4432
i. du
u
u52sin1
2sin
)sin1(sin1
1 252
udu
cu
42sin14
1
cu 8sec41
j. 32 4x
xdx
32
2
4
421
x
xd
cx
22 44
1
2. a.
3
222 1
2 dxx
x
3
222
2
1
1
x
xd
3
22 11
x
31
81
245
2483
- 24 -
b. 1
0
21 dxxx
1
0
22 )1(121
xdx
1
0
22 1131
xx
31
31
0
c. 2
0
2cos
xdxx
2
0
)2(2cos21
xxd
2
0
2sin21
x
0
d.
3
0
3
02
2
2 9
)9(21
9 x
xd
x
xdx
3
0
29 x
329
e. 4
0
4
0
)42()42(21
)42( tdtdtt
4
0
2)42(41
t
31436
f. 4
0
21
4
0
21
)42()42(21)42( tdtdtt
4042 t
232
g.
0
2cos dttt
0
22 )(cos21
tdt
0sin21
0
2
t
h. 2
0
2
0
22sin21
2sin
dd
2
0
2cos21
121
21
i. 2
0
3 2 32)1( dxxxx
2
0
23 2 323221
xxdxx
2
0
3 22 323283
xxxx
0389
389 33
j. 2
0
5cos5sin xdxx
2
0
10sin21
xdx
2
0
10cos201
x
0201
201
3. a. dxxx 3cos2
cxx 3sin31
31 3
b.
tdtt
32
35
55
32 2
332
3tdt
ctt 4
561
c.
dxx 54
211
xdx 21121121
54
cx 51
21125
d.
32
2
32 53
53
53
)96(
xx
xxd
xx
dxx
cxx
22 532
3
e. dxxx 21
32 9
9931 32
13 xdx
f. dxxx 23sin
22 33sin21 xdx
cx 23cos21
- 25 -
g. tdttcossin 3
ttd sinsin 3
ct 4sin41
h. dxxx 2132 4
4431 32
13 xdx
cxx 4492 33
i. dxxx 2143 9
994 4214 xdx
cxx 9938 44
j. dxxx 12
)12()12(21
xdx
2)12(41
x
4. a. dxxx 65 sin12
66sin2 xdx
cx 6cos2
b. xdxx cossin8
xxd sinsin 8
cx 9sin91
c. xdxx 38 cossin
)(sinsin 8 xxd
cx 9sin91
d. dxx
x2
1sin4
xd
x11sin4
cx 1cos4
e. xdxx 3sin
xxd 33sin31
cx 3cos91
f. xdxxsincos10
xxd coscos10
cx 11cos111
g. xdxx 212 sectan
)(tantan12 xxd
cx 3tan131
h. dxxx 2sin42cos
)2sin4(2sin421
xdx
cxx 2sin42sin431
i. dsincos1 10
)cos1()cos1( 10 d
c 11cos1111
j. dx
xx
2)cos2(sin
2)cos2()cos2(
xxd
cx
)cos2(
1
5. a. dxxx 134
31
11
43 3
43
4xdx
cxx
11
21 3
43
4
b.
dxxx
105
1
105
52x
xd
cx
9
59
2
c. dxxxx 22 sincos
22 coscos21 xdx
cxx 22 coscos31
d. dxxxx 225 cossin
225 sinsin21 xdx
cx 26sin121
- 26 -
e.
dx
xx 2
10 111
xd
x1
11
110
cx 11)1(111
f. dxxx )12(sec)12(tan 26
)12tan()12(tan6 xdx
cx )12(tan71 7
g. dxxecxx 23cos23cot 2227
)23cot(23cot61 227 xdx
cx 23cot481 28
h. dxxax 322
3232
31
xadxa
cxaxa 3232
92
6. a. dx
xx
1
2
...
b. dx
x
x
1...
c. dt
tt
236
...
d. dttt 453
...
e. dxxx 12
...
f.
dxxx
xx432
2
2
3
432
32
2
221
xx
xxd
cxx
332 26
1
g. dxxx
10011
xdx 112100
cx 101
11012
h.
dttt
3
2
tan1sec
3)tan1(
)tan1(ttd
ct
2)tan1(21
i. xdxxx sincoscos3 2
)(coscos)(coscos3 2 xxdxxd
cxx 32 cos31cos
23
j. xxddx
xx
55 sin)(sin
sincos
cx
4sin31
7. a. 2
0
)( dxxf
2
1
41
0
3 dxxdxx
2
1
51
0
4
51
41
xx
209
651
532
41
- 27 -
b.
0
)( df
2
2
0
cos dd
2
220 2
1sin
821
22
83
12
8. a. xdxx sincos100
xxd coscos100
cx 101cos101
1
b. dec270 coscot
cotcot70 d
c 71cot711
c. dtansec10
secsec9 d
c 10sec101
d. d220 sectan
tantan20 d
c 21tan211
e. d3cos3sin4
3sin3sin31 4 d
c 3sin151 5
f. dxxx 3cot3cot 810
dxxx 3cot13cot 28
xdx 3cot3cot31 8
cx 3cot271 9
g. dttt 4tan4tan 68
dttt 4tan14tan 26
)4(tan4tan41 6 tdt
ct 4tan281 7
h. xdxecx 2coscot1
xdx cot1cot1
cxx cot1cot132
i. dxxx tan2tan122
...
j. dcossinsin2 2
dd cossincossin2 2
)(sinsin)(sinsin2 2 dd
c 32 sin31
sin
C. Evaluasi Kemampuan Analisis
1.
dxxx 322 11
...
2. a.
a
a
dxxf )(
aa
a
dxxfdxxf0
)()(
Karena f fungsi ganjil)()( xfxf , maka
aa
dxxfdxxf00
)()(
0 (terbukti)
- 28 -
b.
a
a
dxxf )(
aa
a
dxxfdxxf0
)()(
Karena f fungsi genap, maka
aa
dxxfdxxf00
)()(
a
dxxf0
)(2
atau
00
)()(aa
dxxfdxxf
0
)(2a
dxxf
3. a. a
dxxf0
)(
...
b.
2
0cossin
sin
dxxx
x
...
4. a. 2
0
)(sin
dxxf
...
b.
0
)(sin dxxxf
...
5. a. 2
0
cos)(3sin)(
xdxxfxxf
...
b. 2
0
cos)(sin)(
tdttfxxf
...
6. a.
x
dtt
txx
0cos1
cos10
lim
...
b.
x
dtx
tx
0
2)sin1(0
lim
x
tdttxx
0
2sinsin2110
lim
x
tdttxx
0
2cos21
21
sin211
0lim
x
tttxx 0
2sin41
cos2231
0lim
22sin
41cos2
231
0lim xxx
xx
xxx
xx
x2
42sin1cos2
23
0lim
c.
x
dtx
tx
0
2coslim
x
dtx
tx
0
21
21 2coslim
x
xtt
x0
41
21 2sinlim
- 29 -
xxx
x2sinlim 4
121
xxx
2sin41
21lim
21
A. Evaluasi Pemahaman dan PenguasaanMateri
1. a. xdxx 32 sincos
xdxxx sin)cos1(cos 22
xdxxxdxx sincossincos 42
)(coscos)(coscos 42 xxdxxd
cxx 53 cos51cos
31
b. xdxx 34 cossin
xdxxx cos)sin1(sin 24
xdxxxdxx cossincossin 64
)(sinsin)(sinsin 64 xxdxxd
cxx 75 sin71sin
51
c. xdxx 2cos2sin 52
...
d. xdxx 33 cossin
xdxxx cos)sin1(sin 23
)(sinsin)(sinsin 53 xxdxxd
cxx 64 sin61
sin41
e. tdtt 2sincos
)(sinsin 2 ttd
ct 3sin31
f. xdx2sin
dxx
2cos
21
21
cxx 2sin41
21
g. dxx )2(cos4
dxx
2
)42cos(21
21
dxxx )42(cos41
)42cos(21
41 2
dxxx )84cos(81
81)42cos(
21
41
cxxx )84sin(321)42sin(
41
83
h. xdx5sin 3
xdxx 5sin5cos1 2
)5(cos5cos515sin 2 xxdxdx
cxx 5cos1515cos
51 3
i. xdx2cot3
xdxxec 2cot2cos1 2
)2(cot2cot21
2cot xxdxdx
cxx 2cot41
2sinln21 2
j. xdx2cot
dxxec 2cos1
cxx cot
2. a. 3
6
42 sincos
d
3
6
2
2cos21
212cos
21
21
d
3
6
4cos21
21
41
2cos21
21
2cos21
21
d
3
6
4cos812cos
21
832cos
21
21
d
Latihan KompetensiSiswa 7
- 30 -
b. 3
0
3 3cos
d
3
0
2 3cos3sin1
d
3
0
23
0
)3(sin3sin31
3cos
dd
3
0
33
0
3sin91
3sin31
0
c.
0
5sin tdt
0
2
sin2cos21
21
tdtt
0
2
sin4cos21
21
41
2cos21
41
tdttt
0
sin4cos81sin2cos
21sin
83 tdtttdtttdt
ttt coscos31
cos83 3
d. 3
6
2tan
d
3
6
2 1sec
d
3
6tan
63
31
33
63
32
e. 2
4
6cos
dec
...
f.
0
2 3sin xdx
0
6cos21
21
dxx
0
6sin121
21
xx
)00(02
2
g.
22 2sin
xdx
24sin
81
21
xx
0
20
4
43
h. 2
4
cossin
xdxx
2
4
2sin21
x
41
21
41
i. 4
0
22 sectan
xdxx
4
0
3tan31
x
31
j.
dxxx
4sincot1
dxxx
xdxec 54
sincos
cos
...
- 31 -
3. a. xdx3tan5
dxxx )1(sectan 23
dxxxd 33 tan)(tantan
dxxxxxd )1(sectan)(tantan 23 xdxxdxxxd tan)(tantan)(tantan 3
cxxx coslntan21tan
41 24
b. xdx4sec
dxxx )tan1(sec 22
)(tantansec 22 xxdxdx
cxx 3tan31
tan
c. xdxx sectan3
xdxxx sectan)1(sec 2
xdxxxxd sectan)(secsec2
cxx secsec31 3
d. tdt3cot
tdttec cot)1(cos 2
tdtttd
cot)(cotcot1
ctt
sinln1
cot1 2
2
e. xdxx 2sec2tan 33
...
f. xdxecx 2cos2cot 33
...
g. xdx7tan
dxxx )1(sectan 25
dxxxd 55 tan)(tantan
dxxxxxd )1(sectan)(tantan 235
dxxxdxxd 335 tan)(tantan)(tantan
)(tantan)(tantan 35 xxdxxd
dxxx )1(sectan 2
)(tantan)(tantan 35 xxdxxd
dxxxxd tan)(tantan
cxxxx coslntan21
tan41
tan61 246
h. xdx
3cot
xdx3tan
cxx coslntan21 2
i. xdx5cos
dxxx )sin1(cos 23
xdxxdx 233 sincoscos
xdxxxdxxx sin)sin1(cos)sin1(cos 22
)(sinsin)(sinsincos 2 xxdxxdxdx
)(sinsin3 xxd
cxxxx 423 sin41sin
21sin
31sin
j.
dxxx
4sincot1
- 32 -
A. Evaluasi Pemahaman dan PenguasaanMateri
1. a. 24 x
dx
sin2xddx cos2
2arcsin
x
x
d2sin44
cos2
2sin12
cos2 d
cd
cx
2arcsin
b. 236 y
dy
6arcsin
cos6sin6
yddy
y
22 sin16
cos6
sin3636
cos6 dd
cd
cy 6
arcsin
c. 494 2tdt
72arctan
sec27
tan27
2
t
ddt
t
49tan4sec
2449
227
d
2
227
tan149sec d
ct
c 72
arctan141
141
d.
c
x
x
dx
2arcsin
2 2
e.
cx
xdx
5arctan
51
25 2
f.
cy
ydy
43
arctan121
169 2
g. 281 x
dx
ddx
x
cos22
1
sin22
1
cos
cos22
1 d
cx 22arcsin22
1
h.
dxx
x249
2
dxx
xdxx 22 4949
2
ddx
x
sin23
cos23
2
2
2 49
)49(81
cos13
sin3
x
xdd
cxx 24941
32arccos
i. dx
x
x24
2
ddxx
cos2sin2
2sin44
cossin d
cd cos4sin4
cx
2
44
2
cx 242
j.
dxx
x2916
3
cx 4
916122
cx 29163
Latihan KompetensiSiswa 8
- 33 -
2. a.
2x
4-x² 22 4 xx
dx
ddxx
cos2sin2
22 sin44sin4
cos2 d
dec 2cos41
c cot41
cx
x 24
41
cx
x 44 2
b.
2
x x²+4
42xx
dx
ddx
x2sec2
tan2
4tan4tan2
sec22
2
d
dcot21
c sinln21
cx
x
4
ln21
2
c.
dxx
x2
24
ddxx
cos2sin2
2
2
sin4cos2sin44 d
d2cot4
...
d.
6
x x²+6
62
2
x
dxx
ddx
x2sec6
tan6
6tan6
sec6tan62
22
d
d2tan6
d)1(sec6 2
dd 6sec6 2
c 6tan6
cxx 6
arctan66
6
cxx 66arctan66
e. 225 xx
dx
ddxx
cos5sin5
2sin2525sin5
cos5 d
sin51 d
...
f.
- 34 -
W²-7 W
7 722 ww
dw
ddw
dw
sectan7
sec7
7sec7sec7
sectan722
d
tan7sec7sectan7
2
d
cd sin71cos
71
cw
w 771 2
g. dxxx 22 16
ddxx
cos4sin4
dcos4sin1616sin16 22
d22 cossin256
d2cos12cos14
256
d2cos164 2
d4cos
21
21164
d4cos21
21
64
c 4sin832
cxx
4arcsin4sin8
4arcsin32
h.
6
x 4+x²
2
324 x
dx
ddx
x2sec2
tan2
22
2
tan44tan44
sec2 d
sec2sec4sec2 2 d
cd sin41cos
41
cx
x
244
1
i.
3
2x4x²-9
2
32 94x
dx
ddx
x
sectan23
sec23
9sec99sec9
sectan22
23
d
tan3tan9sectan
223 d
dseccot181 2
2sin18
)(sind
csin18
1
cx
x
9418
22
cx
x
949 2
j. 24 16 xx
dx
ddx
x2sec4
tan4
24
2
tan1616tan64
sec4 d
sec4tan64
sec44
2 d
dseccot641 4
- 35 -
xx
4
3
sincos
641
3.
4x
16-x²a.
2
02
3
16 x
dxx
sin4xddx cos4
6
02
3
sin1616
cos4sin64
d
6
0
3sin64
d
6
0
2 sincos164
d
dd sincos64sin64 26
0
6
0
3cos364
cos64
6
0
222
641616
364
41664
xxx
3646438332
3128324
b.
4
x 16+x²
4
0 23
216 x
dx
ddx
x2sec4
tan4
4
022
2
tan1616tan1616
sec4
d
4
02sec16
sec
d
4
0
cos161
d
4
0
sin161
4
021616
1
x
x
5401
581
c.
3
x x²+9
33
322 9xx
dx
ddx
x2sec3
tan3
3
6
22
2
9tan9tan9
sec3
d
3
6
2tan9sec
d
d3
6
2sin9cos
3
6sin91
33
3
2
99
x
x
3932
3276
3816
92
3272
92
d.
- 36 -
2x
4-x²
1
02
2
4 x
dxx
ddxx
cos2sin2
6
02
2
sin44
cos2sin4
d
6
0
2cos21
214
d
6
0
2cos22
d
602sin2
1
0
2
442
2arcsin2
xxx
1
0
2
24
2arcsin2
xxx
)00(13
13
e.
6
42 4xx
dx
ddxx
sectan2sec2
31
arccos
32 4sec4sec2
sectan2
d
31
arccos
321
d
31arccos
321
6
42sec
21
xarc
63sec
21 arc
f.
2
ww²-4
8
4 232 4w
dw
ddww
sectan2sec2
4sec
4
22 4sec44sec4
sectan2arc d
4sec
4
2tan2secarc d
darc
4sec
4
2sin2cos
4sec
3sin21 arc
8
42 42
w
w
2
g. 5
0
22 25 dxxx
5
05
arcsin4sin32625
5arcsin
8625
xx
16625
)00(016
625
h.
3
124 3xx
dx
...
i.
6 x
6-x²
- 37 -
2
12
326 x
dx
ddx
x
cos6
sin6
6
2arcsin
61
arcsin22 sin66sin66
cos6
d
6
2arcsin
61
arcsin
2cos6 d
6
2arcsin
61
arcsin
2sec6 d
62
arcsin
61
arcsintan6
2
126
66
x
56663
305663
j.
3
0216 x
dx
ddx
x2sec
tan4
43arctan
02
2
tan1616sec4
d
4
3arctan
041
d
41
3
04arctan
41
x
43
arctan41
4. a.
02 2sin1
2cos dxx
x
...
b.
4
02 2cos1
2sin
dxx
x
...
5. a. 24 xx
dx
....
6. dt
tt
2
2
41
ddt
t2sec
tan
2
22
tan4sectan1 d
dec4
cossec 2
...
- 38 -
1. a. xdxsin53
...
b. 1tan xdx
112 zzdz
...
A. Eavaluasi Pemahaman dan PenguasaanMateri
1. a. x
xdx
3
dxxdz
xz3
4
4
zz
dzz
32
2
dz
zz
)3(2
23
...
A. Evaluasi Pemahaman dan PenguasaanMateri
1. a. dyyy 33
Cara Tabulasiy 33 y1 43
41
y
0 53201
y
cyyy 54 32013
41
b. dx
x
x
1x 2
11 x
1 2112 x
0 cx 23
134
cxxxx 1134
12
c. dxxx 233
dxxxx 6369
x 6369 xx 1 74
71
23
9 xxx
0 852
561
103
29
xxx
cxxxxxx 852852
561
103
29
71
23
9
d. dxxx 12
2x 211 x
x2 231
32 x
2 251
154 x
0 27
11058 x
cx
xxxx
27
25
232
110516
1158
132
Latihan KompetensiSiswa 9
Latihan KompetensiSiswa 10
Latihan KompetensiSiswa 11
- 39 -
e. dyyy 28
y 28y1 38
31 y
0 48121 y
cyyy 43 8121
831
f. dxxx 242
2x 21
24 xx2 2
324
31
x
2 25
24151
x
0 27
24105
1x
25
232 24
15224
31 xxxx
cx 27
24105
2
g. dx
x
x3
5
21
...
h. dxxax 222
...
i. dxxx 62
2x 21
6xx2 2
36
32
x
2 25
6154
x
0 27
6105
8x
25
23
2
61586
32 xxxx
cx 27
610516
j. dttt 24 1
...
2. a. cxxxxx cossincos
x xcos1 xsin0 xcos
b. xxxxxx cos2sincos 22
cx sin22x xcosx2 xsin
2 xcos0 xsin
c. cbxba
bxbax
bxax cossincos 2
ax bxcosa
bxb
sin1
0bx
bcos1
2
d.
dxxxxdxx 2cos
21
21cos2
xx2cos
21
21
1xx 2sin
41
21
0xx 2cos
81
41 2
xxxxx 2cos81
412sin
41
21 22
e. xdxxxdxxx 2sin21
cossin
xx2sin
21
1 x2cos41
0x2sin
81
- 40 -
cxx 2sin812cos
41
f. xdxxx 3cos3sin8
xdxx 6sin4
x4 x6sin4
x6cos61
0x6sin
61
cxxx 6sin326cos
32
g. dxxx )12cos(
x )12cos( x1
)12sin(21 x
0)12cos(
41 x
cxxx )12cos(41
)12sin(21
h. xdxx 3sin2
2x x3sinx2
x3cos31
2x3sin
91
0x3cos
271
xxxxx 3cos2723sin
923cos
31 2
3. a. 2
0
23 1 dttt
...
b.
0
2 cos xdxx
2x xcos
x2 xsin2 xcos0 xsin
02 sin2cos2sin xxxxx 202
c.
xdxx 2cos2
2x x2cosx2
x2sin21
2x2cos
41
0x2sin
81
xx
xxx 2sin
41
2cos2
2sin21 2
22
d. 3
0
cos3sin
xdxx
...
e. 2
0
2
2cos
dxx
...
f. 4
3
4
coscot
ecxdxxx
x ecxx coscot1 xcot0 xsinln
43
4sinlncot
xxx
2
21ln
42
21ln
43
- 41 -
g. 2
0
sin
xdxx
x xsin1 xcos0 xsin
20sincos
xxx 1
h. 8
12
3 2cot
ydy
...
i. 4
0
2 sin
xdxx
2x xsinx2 xcos
2 xsin0 xcos
40
2 cos2sin2cos
xxxxx
)200(24
232
22
2232
)8(2
j.
0
3 332 sincos dxxxx
0
2 sincos xdxxx
0
2 2sin21
xdxx
2x x2sin21
x2x2cos
41
2 x2sin81
0x2cos
161
0
2
2cos81
2sin4
2cos4
xx
xx
x
481
81
4
22
4. a. xdxln
...
b. xdxx ln2
...
c. dxex x23
3xu dxxdu 23
2xedv 2
21 xex
v
...
5. a. dxxe x3
x xe3
1 xe3
31
0 xe3
91
ceex xx 33
91
3
b. dxex x3
3x xe
23x xex6 xe
- 42 -
6 xe0 xe
xxxx exeexex 663 23
cxxxe x 663 23
c. dxex x3
3x xe23x xe
x6 xe6 xe0 xe
xxxx exeexex 663 23 cxxxex 663 23
d. xdxx sin4
xxxxxx cos12sin4cos 234 cxx cos24sin24
e. xdxx cos4
xxxxxx sin12cos4sin 234 cxx sin24cos24
f. dxxt )52sin(3
3t )52sin( x23t )52cos(
21
x
t6)52sin(
41 x
6)52cos(
81
x
0)52sin(
161 x
)52sin(4
3)52cos(
21 2
3 xt
xt
cxxt )52sin(83
)52cos(31
6. a. 2
0
2 dxxe x
2
0
22
21
21
xx exe
210
21 44 ee
21
21 4 e
b. 4
0
3 4sin
xdxe x
...
c. 4
1
sec dxxarc
...
d. 1
0
arcsin xdxx
...
A. Evaluasi Pemahaman dan PenguasaanMateri
1. a. 3
0
2 2dxxL
3
0
3 231
xx
1569
b. 4
0
24 dyyyL
Latihan KompetensiSiswa 12
- 43 -
4
0
32
312
yy
332
36432
c. dxxL 9
09
032
xx
18
d.
1
0
230
3
23 3232 xdxxxxxxL
0
3
234 332
41
xxx
1
0
234 323
41
xxx
323
41
27184
81
2124
2. a. 4
1
2xdxL
1541
2 x
b. 5
1
)12( dxxL
512 xx 20020
c. 7
4
62xL
742 6xx 1587
d. 1
0
1 xdxL
1
0
2
21
xx
21
3. a.
-2 1 2
4
x
y
2
1
24 dxxL
2
1
3
314
xx
311
388
314
377
b.
-2 1 2
4
x
y
dxxL
1
2
24
1
2
3
31
4 xx
388
314
343
37
12
c.
- 44 -
x
y
-3
9
0
3
2)3( dxxL
0
3
3)3(31
x
9
d.
x
y
-3 2-4
1114
3
2
3
212 xxL
2
3
32
31
2112
xxx
)278(31)94(
21)5(12
335
25
60
3211
21260
6550
e.
1
4
x
y
3 4
3
1
24 dxxxL
3
1
32
312
xx
326
16
322
4. a.
1 x
y
-1
1
1
1
21 dyyL
1
1
3
31
yy
34
32
32
b.
- 45 -
x
y
1
-9
3
3
1
0
2 93 dyyL
103 9yy 8
c.
4
x
y
2-2
2
2
24 dxxL
2
2
3
314
xx
388
388
332
31616
d.
x
y
2-3
514
2
3
26 dxxxL
2
3
32
31
216
xxx
9
2918
38212
214
32219
6520
e.
1 x
y1
1
0
2 122 dxxxL
1
0
23 131
2
xx
32
4
f.
1 x
y
-1
10
-10
1
0
3 92 xdxxL
219
29
412
1
0
24
xx
- 46 -
5. a.
2
0
242 dxxL
336
3142
2
0
3
xx
b.
8
131
dyyL
8134
43 y
4111
4312
c.
dyyL 5
11
3
161132
5
1
yy
d.
dxxxL .40
2
2 0
2
23 231
xx
32108
38
e.
dyyL 2
0
2
38
31 2
0
3 y
f.
dyyL 5
112
2
321134 5
1
yy
- 47 -
A. Evaluasi Pemahaman dan PenguasaanMateri
1. a.
dxxxL 392
3
2 dxxx
2
3
262
3
32
31
216
xxx
3531
521
5.6
335
2530
6520
3211
21230
b.
dxxxL 2
1
22
2
1
22 xx dx2
1
23
21
31
2 xxx
3.21
9.31
3.2
21
423
36
c.
dxxxL 1
0
2
61
31
21 1
0
32 xx
d.
dxxxL 1
0
32
21
41
212 42
xx
e.
dxxxL 4444
0
2
4
0
2 4xx dx
4
0
23 231
xx
332
36432
Latihan KompetensiSiswa 13
39 2 xx062 xx
023 xx3x ; 2x
xx 22022 xx
012 xx2x ; 1x
xx 44 2
042 xx 04 xx
0x ; 4x
- 48 -
f.
2
0 222 dx
xL
0
2
3
6122
xx
316
3442
g.
dxxxxL 2
0
2
dxxx 2
0
2 .2
2
0
23
31
xx
34
384
h.
1
2
22 xxL dx1
2
23
21
312
xxx
214
2336
i.
2
1
22 dxxxL2
1
32
312
21
xxx
21436
23
j.
56 2 xx0562 xx
051 xx1x ; 5x
Jika digeser menjadi
5
1
2 56 dxxxL5
1
23 5331
xxx
20723
12 y
321052
3141
xxx 2
022 xx 02 xx
0x ; 2x
xx 22022 xx
012 xx2x ; 1x
xx 22022 xx
012 xx2x ; 1x
- 49 -
2. a.
10
112 dxxL
361134 10
1
xx
b.
0
4
2 4yyL dy0
4
23 231
yy
332
323
64
c.
4
2
2
42
21 dxyyL
4
2
32
1212
41
yyy
176203
d.
42
2
yy
822 yy
0822 yy 024 yy
4y ; 2y
4
2
2
24 dx
yyL
4
2
32
61
421
yyy
121224
3. a.
dxxxxxL 26 24
0
2
4
0
2 82 xx dx
4
0
23 432
xx
36464
3128
- 50 -
b.
1
0
32 dxxxL
121
41
31 1
0
43 xx
c.
dxxxxL 25
0
210 dxxx
5
0
2210
5
0
32
325
xx
3125
3250125
4. a. 22 xx022 xx
012 xx2x ; 1x
b. 22 yy
022 yy 012 yy
2y ; 1y
c.
4
cossin xxL dx
4
sincos xx
21221
221
01
d. 1
0
3
41
2 xxL dx
1
0
24
81
41
2
xx
41
81
.2
e. 3
2
2 62 dxxxxL
3
282 dxxx
3
2
23 831
xxx
31
334053
35
f.
0sinsin22 xxL dx
0sin2 x dx
4cos2 0 x
g. 2
0coscos24
xxL dx
4sin4 20
x
h. 56,206
56,26cossin22 xxL dx
360
56,206sin2cos xx dx
56,20656,26sincos2 xx
36056,206cos2sin xx
45,079,145,079,1 79,145,020
45,079,145,079,1 82,779,145,020
5. a. xxx 5
xxx 52
042 xx 04 xx
0x ; 4xxy 44
Koordinat titik 4,4A
dxxxL 2
1
222
1
32
312
21
xxx
2143
32
dyyyL 2
1
222
1
32
312
21
yyy
214
- 51 -
b.
4
5
2 5xxL 0
4
2 5 dxxxxdx0
4
234
5
23 231
25
31
xxxx
323
642
45361
65
1221
5432
41
6.
Persamaan garis lurus PQ
232
212
21
91
21
xy
21835
25 xy
18115
1835 xy
3
2 210
18115
1835 dx
xxL
3
2
2 1018115
3635
xxx
210
310
18115
37175
365
36180120230175
7. a. 011 2 xx1x ; 1x
jadi 0,1A dan 0,1B
11010 2 yjadi 1,0C
012.111 21 xxxym
0212 22 xxx0123 2 xx
0113 xx
31
x ; 1x
2
131
131
y
2716
94
.34
y
Jadi
2716
,31
M
b. Luas LuasAMCO : OCB
1
0
20
1
2 11:11 dxxxdxxx
1
0
230
1
23 1:1 dxxxxdxxxx
1
0
2340
1
234
234:
234
xxxxxxxx
1
21
31
41
:121
31
41
1212643
:12
12643
5:11125
:1211
8. Misal mxy
xxm 22
022 xxm 012 xmx
0x ;2
1m
x m
y 1
ym 1
dymytL
t0
- 52 -
9.
Luas 2
0
38 dxxA
2
0
4
418
xx
12416
Luas 2
0
3dxxB
441 2
0
4 x
Luas LuasB : 12:4A3:1
10. a. 34 043
042 0 ; 2 ; 2
ambil 2 0karena2.44 x
8Jadi 2 dan 8
b.
2
0
34 dxxxL
2
0
42
412
xx
448
B. Evaluasi Kemampuan Analisis1. a. xxxx 5456 22
01010 2 xx02 xx
01 xx0x ; 1x0y ; 1y
gbr tidak jelas,tolong gbr ulang!!!
1
0
22 5654 dxxxxxL
1
0
2 1010 xx dx
1023 53
10 xx
355
310
b. 1
0
2 54 xxxLI dx
1
0
2 44 xx dx
1023 234 xx
322
34
1
0
2 56 dxxxxLII
1
0
266 dxxx
123 10
32 xx
32:1: LILII
2:3
2. a.
- 53 -
3. L 2
2
24 dxxAEB2
2
3
34
xx
38
838
8
316
16
31
113
64
panjang persegi panjangpanjang AB 422
lebar persegi3
1643
64
panjang
4. gambar & tulisan yang jelas doong!!!
1
0
22 21
22 dxxxL
arc1
3
31
2sin
xx
114
5.
6.
A. Evaluasi Pemahaman dan PenguasaanMateri
1. a. 3
0
22 dxxV
3
0
24 dxx
3634 3
0
3 x
b.
6
0
2
2dyyV
6
0
2
4dyy
1812
6
0
3
y
2. a. 2
0
22 2 dxxV
3
0
23 44 dxxx2
0
34 434
41
xxx
32
2283
324
b. 2.2.32
22 2V
832
22
32
14
c. 2
0
22 42 dxxV
2023 4xx 2424
Latihan KompetensiSiswa 14
- 54 -
3. a. 1
08xV dx
4410
2 x
b. 2
08xV dx
16420
2 x
c. 2
18xV dx
28421
2 x
d. 882
1 xV dx
212 84 xx 4812
e. 2
0816 xV dx
1641620
2 xx
f. 2
1816 xV dx
212416 x 41216
4. a.
2
1
22 dxxV dx2
0
23 4231
xxx
3888
38
b.
1
0
2dxxV
31
31 1
0
3
x
c.
2
2
4dxxV 2
2
5
51
x
564
532
532
d.
1
1
22 316 dxxV
1
1
24 9616 dxxx1
1
35 251
7
xxx
53
9452
14
e.
1
0
432 2 dxxxxV
301
51
21
31 1
0
543
xxx
- 55 -
f.
5
0
44 dxxV
250054 5
0
5
x
g.
1
04xV dx
2210
2 xh.
4
04 xV dx
8214
4
0
2
xx
i.
6
0
4
16dxxV
80
7776801 6
0
5
x
j.
2
0
416256 dxxV
5
20485
162562
0
5
xx
5. a.
2
0
4dxxV
532
51 2
0
5
x
b.
- 56 -
2
0
24 12 dxxxV
15206
32
51 2
0
35
xxx
c.
2
0
6dxxV
7
12871 2
0
7
x
d.
2
1 21 dxx
V
21
2
1
xe.
1
2
4dxxV
531
51 1
2
5
x
f.
2
1 22 1
1 dxx
xV
2
1
3 131
xxx
651
211
31
g.
1
0
41 dxxV
32
31 1
0
3
xx
6. a.
1
0 211 dxx
V
211
1
0
x
b. 1
021 xxV dx
1
0
2
21
34
xxxx
621
341
c. 65
6
2sin4
xV dx
65
6
2cos22
x dx
65
62sin2
xx
3
21
623
21
610
33
4 2
- 57 -
A. Evaluasi Pemahaman dan PenguasaanMateri
1. a. 3
0
2
91 dyyV
3
0
3
27
yy
213
b. 3
0
2
9dyyV
3
0
3
27y
2. a. 1
0
5
1144 dyydyV
5
1
210 2
144
yyy
1212204
b. 5
114 dyyV
8215
5
1
2
yy
c. 5
11dyyV
821 5
1
2
yy
3. a. 22
0
4
641 dyyV
22
0
5
320
yy
2582
5222
b. 22
0
4
644 dyyV
25
38320
422
0
5
yy
c. 22
0
4
64dyyV
25
2320
22
0
5
y
d. 4
0
4
64dyyV
5
16320
4
0
5
y
e. 4
0
4
644 dy
yV
4
0
5
3204
yy
5
645
1616
4. a. 4
0yV dy
821 4
0
2
y
b. dyyV 5
0
2
3
1253
5
0
3
y
c. dyyV 16
0 4
328
16
0
2
y
d. dyyyV 4
1
2 124
1
23
31
yyy
931521
e. dyyV 50
0 2
6254
50
0
2
y
f. dyyV 0
55
0
5
2 521
yy
2
75252
25
g. 1
0
2
111 dydyyV
102
1
2
212 yyy
23
2
h. dyyV 4
0
4
5
10245
4
0
5
y
Latihan KompetensiSiswa 15
- 58 -
5.
a. 4
0
2
169 dxxV
12489
4
0
3
x
b. 3
0
2
91616 dyyV
3
0
3
271616
yx
321648
c.
3
0
2
434 xdyV
322716 3
0
3
y
d.
4
03
43
ydxV
12489 4
0
3
x
6. a. 1
032
dyyV
1
032 yy
b. 2
0
4 dyyV
5
3251 2
0
5
y
c. 2
0yV dy
221 2
0
2
y
d. 1
01dyyV
221 1
0
2
yy
A. Evaluasi Pemahaman dan PenguasaanMateri
1.
5
2
22 107 dx
xxV
5
2 22 1001449 dx
xxx
5
2
32 10031749
xxxx
9502039147147
2.
1
0
2
1
22
122
dxxxdxxV
2
1
231
0
3
21
1212
xxxx
61
23
127
12
3.
2
1
4
2
2
2
2 14
1 dxx
dxxV
4
23
2
1
23
31
41
41
121
xxxx
19223
1927
12
4. 23
0
246 dxxxV
23
0
32
34
3
xx
29
427
49
41827
5.
1
0
2
1
2
22 4113 dx
xdxxV
1
0
2 69 xx dxx
dx
2
1 416
2
13
10
23
31633
xxx
3
323
146
Latihan KompetensiSiswa 16
- 59 -
6. 3
04 yV dy
3
0
2
21
4
yy
215
29
12
7. 2
0
22 410 dxxxxV
2
0
32
355
xx
320
34020
8. a. 2
0
2222 1352 dxxxV
2
0
2424 16925204 dxxxxx
2
0
24 24145 dxxx
3
16024
314 2
0
35
xxx
b.
6
2
22 128 dx
xxV
6
2 22 144
6416 dxx
xx
6
2
23 14464831
xxxx
31217224256256
3208
c. 4
0
2 1684 xxV dx
4
0
2 16646416 xxx dx
4
0
2 643216 dxxx
3
160064163
16 4
0
23
xxx
d. 1
0
2
1
22222 dxxxdxxV
2
1
2310
2 4534
xxxx
3
324153
28
9. 1
0
4 dxxxV
103
51
21
1
0
52
xx
10. 2
2
42 124 dxxxV
2
2
53 351
32
xxx
1574
26528
238
11. 2
0
224 dxxxV
2
0
32
34
xxx
3
203848
12. a
ady
ay
aV2
2
4
22
16
a
aa
yya
2
22
52
80
333
516
54
4 aaa
13. 5
1 2100 dxx
V
80100 5
1
x
14. 2
1
42 44 dxxxxV 2
1
523
51
4231
xxxx
15
182531
4637
15. 4
1
432 12284816 dxyyyyV 4
1
5432
513
3282416
yyyyy
32486205765
3182036080
B. Evaluasi Kemampuan Analisis
1. a. 4
0
364 xV 8yd
19241
644
0
4
xx
b. 8
034
16 yV 4xd
7
51273164
8
0
37
yy
- 60 -
c. 8
034
yV 4xd
7
38473 8
0
37
y
d. 4
0
3xV 8yd
6441 4
0
4
y
2.
0
2
2
0
22
24
24 dxxxdxxxV
0
2
22 444
xdx
444
22
0
2 xdx
2
0
220
2
22 421
44
21
4
xx
484
84
3.
4. 2
0
2 64162 dxxxV
4
2
22 1616464162 dxxxxx
4232
0
23 322648312 xxxxx
312136456212832
382
5. 3
4
2sec
xV dx
13tan 3
4
x
6. 4
0
2sec
xV dx
40tan x
7. a. 4
0
22 sincos
xxV dx
22sin
21 4
0
x
b. 4
0
22 cossin2sincos
xxxxV dx
21
42cos
21 4
0
xx
A. Pilihan Ganda
1. C. 0
221 dxxxx
2. A.421
30
1
4560
1
5 101051 xxxxdxxx
xx 25 dx0
1
234567
21
35
25
265
71
xxxxxx
421
21
35
25
265
71
3.
5
5 2
5
14x
x
4. E.5
5y
2
2
434sin dxxxxx
2
2
432
2cos21
21
dxxxxx
xxxx 4cos
21
21
41
2cos21
412
2
dxxx 43
xxxx 4cos81
81
2cos21
412
2
dxxx 43
Uji Kompetensi AkhirBAB I
- 61 -
xxxxx81
2cos81
2sin41
81 2
2
2
54
51
41
4sin321
xxx
554
564
21
000
5. A. cxxx 21cos8
21sin4
xx21cos2 cxxxdx
21cos8
21sin4
x2 x21cos
2 x21sin2
0 x21cos4
6. C.38
2
0
2 2xxL 2
3
2 2xxdx dx2
3
232
0
23
31
31
xxxx
38
53
194
38
7. B. 5210 satuan volume
2
1
42 44 dxxxxV 2
1
523
5142
31
xxxx
5210
5331263
8. C. 0
2
0
22 cossin
xx dx
2
02cos
x 02sin21 2
0
xdx
9. D. xx 4sin812sin
41
xx 3sinsin xxdx 4cos21
2cos21
dx
cxx 4sin81
2sin41
10.
7363 2712 xxdxxx
982 250462
563 xxxx
1025040
6 x
6
43
223
22
040.56
2504
6
2563
271
xxxx
xxxx
62040.51
x
lanjutannya manaa !!!
3x 62 x23x 77
1 2 x
x6 8561 2 x
6 95041 2 x
0 10040.51 2 x
11. A. cxxxx 753 sin71
sin53
sinsin
x7cos xxdx cossin132 dx
xxxx cossinsin3sin31 642 dx
xcos xdx 2sin3 xd sin
x4sin3 xxd 6sinsin xd sin
cxxxx 753 sin71
sin53
sinsin
12. D.651
3
2
2 312 dxxxxL3
2
23 221
31
xxx
6512
25
319
- 62 -
13. C. 1,2
k
odxxkxL 288,02
288,031
232
k
o
xxk
2888,0632
333
kkk
2,1k
14. E. 61
dxxx
dxx
V 144
2
1
21
0
2
2
1
231
0
3
21
121
121
xxxx
61
23
127
2
15. lanjutannya manaaa!!!
xxdx
3
16. lanjutannya manaaa!!!
3
0sincos
ttfxxf dt
3
0sin
ttf xxfdt cos
17. C.21
1
1
1
1
32
31
21
1
axxx
adxxax
1231
232
aa
21
a
18. lanjutannya manaaa!!!
dxx
xxx 23
231
2233
231
2222
33
2231
31
2233
2233
6
3322 2233
19. B. 238
21
21
2 12 dxxx
21
21
23
3
xxx
3
226231226231
212122212221
23822242
310
20. D.1221
0
1
23 2xxxL dx xxx 222
1
3 dx2
0
2240
1
234
31
41
31
41
xxxxxx
1221
434
4131
41
- 63 -
21. B. satuan6
343 luas
8
1
2 89 dyyyL8
1
23
829
3
yyy
634356
2567
3511
22. B. satuan3548
volume
3
3
4269 dxxxV
3
3
53
51
29
xxx
5
3483
518
312318
23. Lanjutannya manaaa!!!
dx
xx
x3
3 1
24. Lanjutannya manaaa!!!
dxxx
x3
3 1
25. Lanjutannya manaaa!!!
dx
xx
2
tan1tan
xx 22 cos2tan dx
B. Evaluasi Kemampuan Analisis1.
2. 1
0
2 0cdxcbxax
1
0
23 0cexbecdxaebdadx
0234
1
0
23
cexx
becdx
aebdad
0234
cebecdaebdad
012
1266443
cebecdaebdad
01266443 cebecdaebdad
- 64 -
3.
4. a. xx cossin dx
lanjutannya mana booo!!!
b. xx cos
1
sin
1dx
5. 2
1
4
2 2
141
41
dxx
dxxL
4
2
2
1
2 141
81
x
xx
satuan83
21
41
41
83
luas