claves para derivar en matlab
TRANSCRIPT
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8/16/2019 Claves Para Derivar en Matlab
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=((ln(exp(g3^4)+exp(g3^2)))+(exp(2*seno(g3^2)))+(2^(exp(g3^2)))/
((g3^2)+1)+exp(2^((g3^2)+4))+(2^ln(2^(g3^4))))/(exp(cos(exp(g3^2))))+
(ln((exp(seno(g3^2)))+exp(cos(g3^2))))
=((raiz(exp(e45)-1)-(e45)*(exp(e45)))/2*(raiz(exp(e45)-1)))-
((((e45)/raiz(e45^2))-((e45)*raiz(e45^2-2))/(raiz(e45^2+4)))/
(exp(e45^2)+4))
f=x/(sqrt(exp(x)-1))-eqrt(x^2-2)/(exp(sqrt(x^2+4)))
1/(exp(x) - 1)^(1/2) - (x*exp(x))/(2*(exp(x) - 1)^(3/2)) - x/(exp((x^2
+ 4)^(1/2))*(x^2 - 2)^(1/2)) + (x*(x^2 - 2)^(1/2))/(exp((x^2 +
4)^(1/2))*(x^2 + 4)^(1/2))
F=K*(T^3+T^2+1)-LOG(T^2+5)+*LOG(2)*(T^2+3)/LOG(2)
f=si!(x)/exp(2*(x))+"#$(2*(x))/2*"#$(2)*((x)+%#s(x)/(x))-
("#$(x)/sqrt(x^2)+exp(x))*"#$(x)/(exp(x))
"! - %#s(x)/x^2 - si!(x)/x + %#s(x)/exp(2*x) - (2*si!(x))/exp(2*x)%#s(x) + "!/(x^2/exp(2*x))^(1/2) - ("!*x*((2*x)/exp(2*x) -
(2*x^2)/exp(2*x)))/(2*(x^2/exp(2*x))^(3/2))&"a'es para eri'ar
e! at"a
1,
ss x
f=%#s(x)-3*x
iff(f.x)
e'a"0a#s "a eri'aa %#! !0estr#s 'a"#res x,=,4
$=iff(f.x)s0s($.,4)
%a"%0"a#s eri'a#s $ para #te!er "a 2 eri'aa e f
iff($.x)
2,
ss x
f= exp(x^2)
iff(f.x)
e'a"0a#s "a eri'aa %#! !0estr#s 'a"#res x,=,4
$=iff(f.x)
s0s($.,4)
%a"%0"a#s eri'a#s $ para #te!er "a 2 eri'aa e f
=cos(x-3x) / (exp(x^2))+exp(sin(x^2) – ln (exp(x^2)*^0.8) + pi *
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iff($.x)
!0e'ae!te e'a"0a#s"a 2 eri'aa %#! !0estr#s 'a"#res x,=,4
!=iff($.x)
s0s(!.,4)
3,
ss x
f= exp(si!(x^2))
iff(f.x)
e'a"0a#s "a eri'aa %#! !0estr#s 'a"#res x,=,4
$=iff(f.x)
s0s($.,4)
%a"%0"a#s eri'a#s $ para #te!er "a 2 eri'aa e f
iff($.x)
!0e'ae!te e'a"0a#s"a 2 eri'aa %#! !0estr#s 'a"#res x,=,4
!=iff($.x)
s0s(!.,4)
4,
ss x "!
f= "!*(exp(x^2)̂ ,)
iff(f.x)
e'a"0a#s "a eri'aa %#! !0estr#s 'a"#res x,=,4
$=iff(f.x)
s0s($.,4)
%a"%0"a#s eri'a#s $ para #te!er "a 2 eri'aa e f
iff($.x)
!0e'ae!te e'a"0a#s"a 2 eri'aa %#! !0estr#s 'a"#res x,=,4
!=iff($.x)s0s(!.,4)
5,
ss x pi
f= pi*%#s(x)-3*x
iff(f.x)
e'a"0a#s "a eri'aa %#! !0estr#s 'a"#res x,=,4
$=iff(f.x)
s0s($.,4)
%a"%0"a#s eri'a#s $ para #te!er "a 2 eri'aa e f
iff($.x) !0e'ae!te e'a"0a#s"a 2 eri'aa %#! !0estr#s 'a"#res x,=,4
!=iff($.x)
s0s(!.,4)
>> syms x pi
>> f= pi*cos(x)-3*x
f = pi*cos(x) - 3*x
>> diff(f,x)
ans = - pi*sin(x) - 3
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>> % evaluamos la derivada con nuestros valores x0=0.4.
>> =diff(f,x)
= - pi*sin(x) - 3
>> su!s(,0.4)
ans = -4.""34
>> % calculamos derivamos para o!tener la "# derivada de f.
>> diff(,x)
ans = -pi*cos(x)
>> % nuevamente evaluamosla "# derivada con nuestros valores x0=0.4.
>> n=diff(,x)
n = -pi*cos(x)
>> su!s(n,0.4)
>> syms x ln i!%"0e "a raiz
f=sin(x)$exp("*x)(ln*"*x)$("*x)cos(x)$x-ln*x$s&rt(x'")(exp(x)$exp(x))sin(x)
f=3-exp(x)*cos(x)"*x*y-("*x'"-)$3
f=((-0.*x)'")3."*x-(ln*")$(0.3+*x)-(s&rt()$((0.*x)'")-(".$(0.3*x))-(0.4$0.3))'0.($
(0.*x))
f="#$(x^2+3)/"#$(2) para e" "#$ !at0ra"
f=y*sin(ln*x'"4)exp(s&rt(x'"3))*y$ln*x'y - 4-cos(exp(x-
))$y*exp(sin(y)*(s&rt(y'"4)))
(,/)
"*ln*x*y*cos(ln*x'" 4)(x*y*exp((x'" 3)'($")))$(x'" 3)'($")$exp(x - )*sin(exp(x -
)) ln*x'(y - )*y
syms x
f= exp(x'")
diff(f,x)
=diff(f,x)
su!s(,0.4)
diff(,x)
n=diff(,x)
su!s(n,0.4)
syms x
f= exp(sin(x'"))
diff(f,x)
=diff(f,x)
su!s(,0.4)
diff(,x)n=diff(,x)
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su!s(n,0.4)
syms x ln
f= ln*(exp(x'")'0.)
diff(f,x)
=diff(f,x)
su!s(,0.4)
diff(,x)
n=diff(,x)
su!s(n,0.4)
syms x pif= pi*cos(x)-3*x
diff(f,x)
=diff(f,x)
su!s(,0.4)
diff(,x)
n=diff(,x)
su!s(n,0.4)
syms x
f=cos(x)-3*x
diff(f,x)=diff(f,x)
su!s(,0.4)
diff(,x)
n=diff(,x)
su!s(n,0.4)
,1 f1=%#s(x-3*(x))/(exp(x^2)) + exp(se!#(x)^2)/(exp(x^2))-se!#(x) -
("!((exp(x^2))^,)/%#s(x-2) + pi()*%#s(x)-3*(x))/se!# (x) + ,32
syms x
f=cos(x)-3*x
=diff(f,x)
syms x
f= exp(x'")
diff(f,x)
syms x
f= exp(sin(x'"))
diff(f,x)
syms xf= exp(x'") - sin(x)
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diff(f,x)
syms x ln
f= ln*(exp(x'")'0.)
diff(f,x)
syms x
f=cos(x-")
diff(f,x)
syms x pi
f= pi*cos(x)-3*x
diff(f,x)syms x
f= sin(x0.3")
diff(f,x)
syms x
f=cos(x)-3*x
diff(f,x)