bab 3 analisa data atap baja dengan metode perhitungan asd

8/16/2019 BAB 3 Analisa Data Atap Baja Dengan Metode Perhitungan ASD

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Laporan Tugas Besar Struktur Baja II

BAB III

ANALISIS DATA

3.1. Design Gambar Rangka Baja

Type Kuda – Kuda “Vault”

Gambar 1.a. Design Kuda-kuda Vault (Tampak Depan)

Gambar 1.b. Design Kuda-kuda Vault (Tampak Atas)

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41,41O

A11

B1

T1


3.2.Data yang Ditentukan

- Kemiringan Atap ( α ) = 41,41 o

- Jarak Kuda- kuda (i) = 5,800 m

- Pan ang atap miring = !0,""# m- $ebar %angka Atap = 4&,500 m

- 'inggi %angka Atap = 0,500 m

- Jarak ording (a) = 1, 00 m

- Beban *idup = 100 kg+m

- Beban Angin = !5 kg+m

- Beban *u an = 0 kg+m

3.3. Data Bahan

igunakan ba a mutu BJ-50, dengan ketentuan ebagai berikut .

- 'egangan /e/e ba a ( ie/d tre ) 2 = "0 3pa

- 'egangan tarik putu (u/timate tre ) 2u = 500 3pa

- 3odu/u e/a ti ba a (modu/u o2 e/a ti it ) = 00000 3pa

- Angka Poi on (Poi on ratio) Ʋ = 0,!

3.4. Perhitungan Panjang Batang

A6 Batang Ba7a

B1 = B = B! = B4

B = 46,2

4= 11,625 m

B6 Batang 'egak '1

'1 = tan 6 B1

= tan 41,41 9 11,& 5

= 10,250 m

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3.5. Design G"r#ing

3.5.1. Pre$iminary Design

igunakan pro2i/ anne/ “UNP 125 x 65 x 6 x 8”

- * = 1 5,00 mm- B = &5,00 mm

- t1 = &,00 mm

- t = 8,00 mm

- A = 1#,11 m

- > = 1!,40 kg+m

- I9 = 4 5,00 m 4

- I = &5,50 m4

- ?9 = &8,00 m !

- ? = 14,40 m !

3.5.2. Pembebanan G"r#ing

%. Beban &Beban 'eta( ) Beban *ati + Beban i#u(-

a. Beban *ati &D -

- Berat @endiri ording = 6 = 1!,40 kg+m

- Berat Penutup Atap = Jarak ording 9 Berat Atap

(Klipl k – !") = 1, m 9 5,& kg+m = &,#4 kg+m

#erat T tal ($1) % &' 1! kg m

- Berat A e ori = 15 9 C1

#erat T tal ($&) % 1*+ , &' 1! % '& kg m

Total Beban Mati “q(bm ” ! q1"q2 !2#$1% " &$#2 ! 2&$1' )*m

q (bm )cos

= 23,17cos 41,41

= 30,89 kg/m

b. Beban i#u( & -

/ Beban Drang = P $$ = 100,00 kg

/ Beban *u an = ( 0kg 9 $ua aera Pembebanan)

= E 0kg 9 (5,80 9 1, 0)F = 1!", 0 kg

Diambil +an) te,be-a,$ +ait. ! 1&/$2# )

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Gambar &. enampang r /il 0 1&* , "* , " , 2


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B. Gaya Da$am Pa#a G"r#ing

a. %kibat Beban *ati &D -

C(bm) = !0,8" Kg+m

C9 = C 9 :oα

= !0,8" 9 :o 41,41 = !,1# kg+mC = C 9 @inα = !0,8" 9 @in 41,41 = 0,4! kg+m

39 $ ¿18

.qx.L2 ¿ 18

. 23,17 .5,80 2 = "#,41 kgm

3 $ ¿18

.qy.L2 ¿ 18

. 20,43 . 5,80 2 = 85,"1 kgm

b. %kibat Beban i#u( & -

P = 1!", 0 kg

P9 = P 6 :o α = 1!", 0 6 :o 41,41 = 104,40 kg

P = P 6 @inα = 1!", 0 6 @in 41,41 = " ,0# kg

39 $$ ¿ 14

.Px .L ¿ 14

.104,40 . 5,80 = 151,!8 kgm

39 $$ ¿ 14 .Py.L ¿ 14

. 92,07 . 5,80 = " ,0# kgm

*aka, Gaya Da$am Pa#a G"r#ing %#a$ah

* ) * D + * ) 9!,41+151,3 ) 24 ,!9kgm ) 24. !9kg m

*y ) *y D + *y ) 5,91 +92,0! ) 219,42kgm ) 21.942kg m

. Periksa ekuatan

a. 'erha#a( entur

x= MxZx

= 24.87968,00 = !&5,8# Kg+ m

y= MyZy

= 21.94214,40 = 165 !,# Kg+ m

ekuatan %kibat Beban 'eta(

(bt )= √ x2 + y2= √ 365,87 2+1.523,72 2

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! 1056'$#& )* m 2 1/&&$&& )* m2 3 e

b. 'erha#a( 'egangan Geser

x= Lx .Zxb.Iy ,dimana b = & mm G $9 = < 6 C(bm)9 6 $ ; < P9 = 11",!8 Kg

x= 119,38 .68,006 . 65,50 % 0&,5& Kg+ m

y= Ly .Zyb.Ix ,dimana b = 1& mm G $ = < 6 C(bm)9 6 $ ; < P = 105, 8 Kg

x= 105,28.14,4016 . 425,00 = , ! Kg+ m

ekuatan %kibat 'egangan Geser

(tot )= √ x2+ y2= √ 206,56 2+2,23 2

! 2#6$5' )* m 2 116#$## )* m 2 3 e

0 'erha#a( 'egangan e ek uber enkgy

(tetap)= √ (bt )2 +3 .(tot )2 = √ 1 . 567 , 03 2+3 . 206 . 57 2

! 10685$12 )* m 2 10/&&$&& )* m2 3 e

40 Pe,i -a e a .an Len4.tan Pa4a o,4in)

H(i in) = $ + 40 = ,4 m

δ ( x)= 5 . qdlx . Lb4

384 . E . I x+ P llx . Lb

3

48 . E . I x

¿5 .(23,17100 ).(5,80 x100 )4384 .(200000 x10 ) .425

+ 104,40 .(5,80 x100 )3

48 .(200000 x10 ) .425

¿0,90 cm

δ ( y)= 5 . qdly . Lb4

384 . E . I y+ P lly . Lb

3

48 . E . I y

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¿5 .(20,43100 ).(5,80 x100 )4384 .(200000 x10 ) .65,5

+ 92,07 .(5,80 x100 )3

48 .(200000 x10 ).65,5

¿5,15 cm

ekuatan %kibat ekakuan en#utan

δ R= √ δ x2+δ y2= √ 0,90 2 +5,15 2

! 5$2& m 2$%2 m 3 e

e0 *enggunakan 'restang

- Jarak 're tang

L= Jarak Kuda− kuda2

= 5,80 x1002

= 300,00 cm

δ ( ! ")= L240

= 5,80 x100240

= 2,42 cm

- $endutan pada ording

δ ( x)= 5 . qdlx . Lb4

384 . E . I x+ P llx . Lb

3

48 . E . I x

¿5 .(23,17100 ).(300 )4

384 .(200000 x 10 ).425+ 104,40 .(300 )

3

48 .(200000 x10 ).425

¿0,10 cm

δ ( y)= 5 . qdly . Lb4

384 . E . I y+ Plly .Lb

3

48 . E . I y

¿5 .(20,43100 ). (300 )4

384 .(200000 x 10 ).65,5+ 92,07 .(300 )

3

48 .(200000 x10 ).65,5

¿0,56 cm

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ekuatan %kibat ekakuan en#utan &menggunakan 'restang-

δ R= √ δ x2+δ y2= √ 0,10 2 +0,56 2

! #$5 m 2$%2 m 3 e

D. Beban 7ementara &Beban *ati + Beban i#u( + Beban %ngin-

a. Pa#a G"r#ing

# = (0,02 − 0,4 )= ((0,02 x41,41 )− 0,4 )= 0,43

q (ay)= $ (ay). .# = (35 x1,2 x0,43 )= 17,98 kg/m

b. %kibat emiringan %ta(

q(ay )= q(a"g " )

qay.L 2= 18

(17,98 x 5,80 2 )= 75,624 kgm= 7562,44 kgcm

M (ay )= 18

¿

q(ax )= 0

M (ax )= 0

. 'erha#a( entur %kibat Beban 7ementara

x(b . %eme"tara )= x(b.tetap )= 365,87 kg/c m2

y (b.%eme"tara )= My (bt )+ May$x

= 21.942 +7562,4468,00

= 433,88 kg /cm2

Periksa ekuatan entur

(b%)= √ x2 + y2= √ 365,87 2 +433,88 2

! 56'$55 )* m 2 1/&&$&& )* m2 3 e

#. 'erha#a( Geser

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x= Lx .Zxb.Iy ,dimana b = & mm G $9 = < 6 C(a9) 6 $ ; < P9 = 5 , 0 Kg

x= 52,20 . 68,006 . 65,50 % "0,! Kg+ m

y= Ly .Zyb.Ix ,dimana b = 1& mm G $ = < 6 C(a ) 6 $ ; < P = "8,1" Kg

x= 98,19 .14,4016 . 425,00 = ,08 Kg+ m

ekuatan %kibat 'egangan Geser

(tot )= √ x2

+ y2

= √ 90,322

+2,082

! /#$&% )* m2 116#$## )* m 2 3 e

e0 'erha#a( 'egangan e ek uber enkgy

(tetap)= √ (b%)2 +3 .(tot )2= √ 567,55 2 +90,34 2

! 628$/% )* m 2 10/&&$&& )* m2 3 e

70 Pe,i -a e a .an Len4.tan Pa4a o,4in)

H(i in) = $ + 40 = ,4 m

δ ( x)=5 . qdlx . Lb

4

384 . E . I x+ P llx . Lb

3

48 . E . I x

¿5 .( 0100 ).(300 )4

384 .(200000 x10 ).425+ 104,40 .(300 )

3

48 .(200000 x10 ).425

¿0,07 cm

δ ( y)= 5 . qdly . Lb4

384 . E . I y+ Plly .Lb

3

48 . E . I y

¿5 .

(17,98

100 ). (300 )4

384 .(200000 x 10 ).65,5 + 92,07 .(300 )

3

48 .(200000 x10 ).65,5

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¿0,54 cm

ekuatan %kibat ekakuan en#utan

δ R= √ δ x2+δ y2= √ 0,07 2 +0,54 2

! #$5% m 2$%2 m 3 e

3.6. Pembebanan Pa#a u#a u#a

3.6.1. Beban 'eta(

- C(atap) = >(atap) 9 Jarak Kuda-kuda

= 56& kg+ m 9 5,80 = ! ,&0 kg+m

- Ak e ori (15 ) = 15 9 C(atap) = 4,8" kg+m

T tal #eban Tetap % 3 !4 kg m

- C(atap)=q (bm )

cos=

37,49cos41,41

= 4","8 kg+m

- Beban Atap = C(atap) 9 < arak

Pa1 = 4","8 9 (1+ 9 11,& 5) = 290,51 kg

Pa = 4","8 9 (1+ 9 11,& 5 ;11,& 5) = 5 1,03 kg

Pa! = 4","8 9 (1+ 9 11,& 5 ;11,& 5) = 5 1,03 kg

Pa4 = 4","8 9 (1+ 9 11,& 5 ;11,& 5) = 5 1,03 kg

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esim(u$an Dari asi$ Perhitungan Design G"r#ing #a(at #isim(u$kan bah8aPr" i$ :P 125 65 6 #a(at #igunakan sebagai g"r#ing


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Pa1290, 1 kg

Pa2!1,03 kg

Pa3 " !1,03 kg

Pa4!1,03 kg

Pa290, 1 kg


Pa5 = 4","8 9 (1+ 9 11,& 5) = 290,51 kg

Gambar &. embebanan Tetap

3.6.2. Berat 7en#iri G"r#ing

= C(gording) 9 Jarak Kuda kuda = 1!,4 9 5,80 = ##,# kg

%. Reaksi Per$etakan

a.

Σ 3A = 0

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( 1 9 0) ; ( 9 16 ) ; ( ! 9 64) ; ( 4 9 !6&) ; ( 5 9 468) ; ( & 9 &) ;( # 9 #6 ) ;( 8 9 864) ; ( " 9 "6&); ( 10 9 1068) = 0

( 0 0) = 0

( 1, ) = "!, &

( ! ,4) = 18&,5!

( 4 !,&) = #",#"

( 5 4,8) = !#!,0&

( & &) = 4&&,!

( # #, ) = 55",58

( 8 8,4) = &5 ,85

( " ",&) = #4&,11( 10 10,8) = 8!",!8

461"&,88 = ( b 9 11,& 5)

b = !&1,0 kgm (Pg kanan = Pg kiri)

Σ 3A = 0

0 = a ; b - 1 - - ! - 4 - 5 - & - # - 8 - " - 10

1 = a ; !&1,0 ##,# -##,# ##,# ##,# ##,# -##,# -##,###,#

##,# -##,#

0 = a ; !&1,0 -###,

a = - !&1,0 ; ###,

a = 41&,18 kgm (Pg1 kanan = Pg1 kiri)

b.

Σ 3: = 0

( 40 9 0) ; ( !" 9 16 ) ; ( !8 9 64) ; ( !# 9 !6&) ; ( !& 9 468) ; ( !5 9 &) ;( !4 9 #6 ) ; ( !! 9 864) ; ( ! 9 "6&); ( !1 9 1068) = 0

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Pg141#,1! kg

Pg2$22,04 kg

Pg3 " !32,3# kg

Pg4$22,04 kg

Pg41#,1! kg


( 40 0) = 0

( !" 1, ) = "!, &

( !8 ,4) = 18&,5!

( !# !,&) = #",#"( !& 4,8) = !#!,0&

( !5 &) = 4&&,!

( !4 #, ) = 55",58

( ! 8,4) = &5 ,85

( !! ",&) = #4&,11

( !1 10,8) = 8!",!8

461"&,88 = ( b 9 11,& 5)

b = !&1,0 kgm (Pg1 kanan = Pg1 kiri)

Σ = 0

1 = ; b !1 ! !! !4 !5 !& !# !8 !" -

40

1 = ; #& ,1& ##,# -##,# ##,# ##,# ##,# -##,# -##,#

##,#

##,# -##,#

0 = a ; !&1,0 -###,

a = - !&1,0 ; ###,

a = 41&,18 kgm (Pg! kanan = Pg! kiri)

B. Pembebanan Pa#a G"r#ing

Pg1 = a = 416,1 kg

Pg = Pg (kiri);Pg (kanan) = !22,04 kg

Pg! = Pg!(kiri);Pg!(kanan) = 32,36 kg

Pg4 = Pg = !22,04 kg

Pg5 = Pg1 = 416,1 kg

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P11%3!0,94 kg

P22%# 1, $ kg

P3 " 2%$#1,!! kg

P42%# 1, $ kg

P1%3!0,94 kg


Gambar . embebanan ada G rding

. Beban i#u( ; Beban ujan

- Beban Drang = 100 kg

- Beban *u an = 0 kg+m 9 Jarak Kuda-kuda = 0 9 5,80 = 11& kg+m

- 3aka, Beban *idup ada/a .

P*1 = 11& 9 (1+ 9 11,& 5) = , 5 kg

P* = 11& 9 (1+ 9 11,& 5;11,& 5) = 16!48,50kg

P*! = 11& 9 (1+ 9 11,& 5;11,& 5) = 16!48,50kg

P*4 = 11& 9 (1+ 9 11,& 5;11,& 5) = 16!48,50kg

P*5 = 11& 9 (1+ 9 11,& 5) = , 5kg

3aka, Beban tetap untuk diatap .

P1 = Pa1 ; Pg1 ; P*1 = 1.3 0,94 kg

P = Pa ; Pg ; P* = 2.651,5! kgP! = Pa! ; Pg! ; P*! = 2.!61, kg

P4 = Pa4 ; Pg4 ; P*4 = 2.651,5! kg

P5 = Pa5 ; Pg5 ; P*5 = 1.3 0,94 kg

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Gambar !. embebanan 5idup

3enentukan Pro2i/ A7a/

Perik a angka ke/ang ingan (i)

$ = Batang 'erpan ang %angka Ltama

I min = ipero/e dari tab/e ba a

= L

m "

m " = L & = 1.162,50

200= 5,81

i oba menggunakan pro2i/ ganda dengan iku $ 00 9 00 9 15 dengan i9 = i =

&,14 m

m "¿ x= y

5,81


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Rangka UtamaPro&' L 200 ( 200 ( 1

)* 200B* 200t * 1r1* 1$

r2 * 12

""""

"

A *- 2 " $,$.n t e g t *kg/ " 4 ,30I( " I " 21!0

( " " #,14

( " " 1 0


Gambar *. Design Kuda-kuda dengan 6angka Anak

m " = L & =

394,00

200 = 1,97

i oba menggunakan pro2i/ ganda dengan iku $ &5 9 &5 9 5 dengan i9 = i =

1,"" m

m "¿ x= y

1,97


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Rangka Anak Pro&' L # ( # (

)* #B* #t * r1* !,r2 * 3

"""""

A *- 2 " #,3#$.n t e g t *kg/ " I( " I " 2 ,3

( " " 1,99( " " ,3


D. Berat 7en#iri u#a ku#a

a. 7tuktur Rangka tama

- Pan ang 'ota/ = (11,& 5 9 );(15,4"85 9 &) ;

(10, 5);(5,1 5);( 0,5);(1 ,#05 9 ) = 1##,5! m = 1#6#5 ,&0 m

- ?1 = Pan ang 'ota/ 9

?1 = 1##,5! 9

?1 = !55,05

- A e ori = 5 9 > = 11,!!kg+m- Cb = > ; A e ori ( 5 )

= 45,! ; 11,!!

= 5&,&! kg+m

- B6@ %angka Ltama = ?1 9 Cb

= 4&,5 m 9 5&,&! kg+m

= 06104,8 kg

b. 7truktur Rangka %nak - Pan ang 'ota/ = ( 6 9 1&);(1 9 8 );( 60 1 9 4);(16#5& 9 4);(!6"4 9

);( 65#1 9 &);(1655! 91 );(1684#91 );( 64#"94);( 6 #498) ;( 604 9 8) ;(16"4 9 1&);(16 9 8);(16! 9 8)= !#",05 m = !#6"04,&0 m

- ?1 = Pan ang 'ota/ 9

?1 = !#",05 9

?1 = #58,0" m

- A e ori = 5 9 > = 1, 5 kg+m

- Cb = > ; A e ori ( 5 )

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P s13%10 ,3# kg

P s2#%210,$2 kg

P 53 " #%210,$2 kg

P 54#%210,$2 kg

P s3%10 ,3# kg


= 5 ; 1, 5

= &, 5 kg+m

- B6@ %angka anak = ?1 9 Cb

= 1615",&4 m 9 &, 5 kg+m= 46#!8,08 kg

Cb ('ota/) =B . ' Ra"gka(tama +B . ' Ra"gka )"ak

Pa"!a"g Be"ta"g Kuda − kuda

=20.104,82 +4.738,08

46,50

= 534,26 kg /m

3aka, Berat @endiri ada/a .

Pb 1 = 5!4, & 9 (1+ 9 11,& 5) = 3.105,36 kg

Pb = 5!4, & 9 1+ (11,& 5;11,& 5) = 6.210,!2 kg

Pb ! = 5!4, & 9 1+ (11,& 5;11,& 5) = 6.210,!2 kg

Pb 4 = 5!4, & 9 1+ (11,& 5;11,& 5) = 6.210,!2 kg

Pb 5 = 5!4, & 9 (1+ 9 11,& 5) = 3.105,36 kg

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Gambar ". #erat 7endiri Kuda - kuda

>. Beban 7ementara

Beban mati ; Beban *idup ; Beban Angin

a. Pembebanan %ngin iri

- 3uka Angin

α = 41,41 o

: (koe26 Angin 'ekan = 0,0 α - 0,4 = 0,4!

C(angin) =$ (a"g " ) x # x Jarak Kuda − kuda

cos

=45 x0,43 x5,8

cos 41,41

=111,76

0,75= 149,01 kg/m

Pa 1 = C(angin) 91+ m = 14",01 9 (1+ 9 15,4"8) = 1.154,!5 kg

Pa = C(angin) 91+ (m;n) = 14",019 1+ (15,4"8;15,4"8) = 2.309,50 kg

Pa ! = C(angin) 91+ n = 14",01 9 (1+ 9 15,4"8) = 1.154,!5 kg

- Be/akang Angin

α = 41,41 o

: (koe26 Angin 'ekan = - 0,4 = -0,4


cos

=45 x(− 0,4 ) x5,8

cos41,41

=− 104,40

0,75= − 139,201 kg/m

Pa ! = C(angin) 91+ o = − 139,201 9 (1+ 9 15,4"8) =/1.0! ,!0 kg

Pa 4 = C(angin) 91+ (o;p) = − 139,201 9 1+ (15,4"8;15,4"8) =/2.15!,40 kg

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Pa 11%1 4,$ kg

Pa 22%309, 0 kg

Pa 31%1 4,$ kg

Pa 361%0$!,$0 kg

Pa 462%1 $,40 kg

Pa61%0$!,$0 kg


Pa 5 = C(angin) 91+ p = − 139,201 9 (1+ 9 15,4"8) =/1.0! ,!0 kg

Gambar 3. embebanan Angin Kiri

b. Pembebanan %ngin anan

- 3uka Angin

α = 41,41 o

: (koe26 Angin 'ekan = 0,0 α - 0,4 = 0,4!


cos

=45 x0,43 x5,8

cos 41,41

=111,76

0,75= 149,01 kg/m

Pa 1 = C(angin) 91+ m = 14",01 9 (1+ 9 15,4"8) = 1.154,!5 kg

Pa = C(angin) 91+ (m;n) = 14",019 1+ (15,4"8;15,4"8) = 2.309,50 kg

Pa ! = C(angin) 91+ n = 14",01 9 (1+ 9 15,4"8) = 1.154,!5 kg

- Be/akang Angin

α = 41,41 o

: (koe26 Angin 'ekan = - 0,4 = -0,4

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Pa 11%1 4,$ kg

Pa 22%309, 0 kg

Pa 31%1 4,$ kg

Pa 361%0$!,$0 kg

Pa 462%1 $,40 kg

Pa61%0$!,$0 kg


C(angin) =$ (a"g " ) x# x Jarak Kuda − kuda

cos

=45 x(− 0,4 ) x5,8

cos41,41

= − 104,400,75

= − 139,201 kg /m

Pa ! = C(angin) 91+ o = − 139,201 9 (1+ 9 15,4"8) =-1.0! ,!0 kg

Pa 4 = C(angin) 91+ (o;p) = − 139,201 9 1+ (15,4"8;15,4"8) =-2.15!,40 kg

Pa 5 = C(angin) 91+ p = − 139,201 9 (1+ 9 15,4"8) =

/1.0! ,!0 kg

Gambar 2. embebanan Angin Kanan

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3.!. %:% =7% 7'R R

Ana/i a @truktur pada Peren anaan e ign %angka Kuda kuda Atap Ba a ini menggunakan Program @o2t7are @AP 000 6146 Berikut ini

ada/a a i/ per itungan menggunakan o2t7are ter ebut6

3.!.1. Gambar Perm"#e$an 7%P 2000 ?.14

A6 Ke P/an @truktur

Gambar 4. Key lan 7truktur

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B6 Input Beban 'etap

Gambar 1'. 8nput #eban Tetap

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:6 Input Beban ording

Gambar 11. 8nput #eban G rding

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6 Input Berat @endiri Kuda kuda

Gambar 1 . 8nput #eban 7endiri Kuda – kuda

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6 Input Beban Angin Kiri

Gambar 1!. 8nput #eban Angin Kiri

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6 Input Beban Angin Kanan

Gambar 1*. 8nput #eban Angin Kanan

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*6 A9ia/ or e Akibat Kombina i 1 (B6 3ati ; B6 *idup ; B6 @ Kuda-kuda)

Gambar 1". A,ial : r;e Akibat K mbinasi 1 (#.


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I6 A9ia/ or e Akibat Kombina i (Kombina i 1 ; B6 Angin Kiri)

Gambar 13. A,ial : r;e Akibat K mbinasi & (K mbinasi 1 = #. Angin Kiri)

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J6 A9ia/ or e Akibat Kombina i ! (Kombina i 1 ; B6 Angin Kanan)

Gambar 12. A,ial : r;e Akibat K mbinasi (K mbinasi 1 = #. Angin Kanan)

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3.!.2. asi$ Perhitungan Gaya Batang #engan 7%P 2000 ?.14

TABLE 1 : Perhitungan GayaBatang

Frame Station OutputCase CaseType PTe t m Te t Te t !g"

22 $,2# #3 7O8BI ASI 2 :o nat on 23242,!922 $,$ 7O8BI ASI 2 :o nat on 23242,!922 !,2343! 7O8BI ASI 2 :o nat on 23242,!922 !,$1!$ 7O8BI ASI 2 :o nat on 23242,!922 9,20313 7O8BI ASI 2 :o nat on 23242,!922 9,#!$ 7O8BI ASI 2 :o nat on 23242,!922 10,1$1!! 7O8BI ASI 2 :o nat on 23242,!922 10,# #2 7O8BI ASI 2 :o nat on 23242,!922 11,140#3 7O8BI ASI 2 :o nat on 23242,!922 11,#2 7O8BI ASI 2 :o nat on 23242,!922 0 7O8BI ASI 3 :o nat on 11423,1!22 0,4!43! 7O8BI ASI 3 :o nat on 11423,1!22 0,9#!$ 7O8BI ASI 3 :o nat on 11423,1!22 1,4 313 7O8BI ASI 3 :o nat on 11423,1!22 1,93$ 7O8BI ASI 3 :o nat on 11423,1!22 2,421!! 7O8BI ASI 3 :o nat on 11423,1!

22 2,90#2 7O8BI ASI 3 :o nat on 11423,1!22 3,390#3 7O8BI ASI 3 :o nat on 11423,1!22 3,!$ 7O8BI ASI 3 :o nat on 11423,1!22 4,3 93! 7O8BI ASI 3 :o nat on 11423,1!22 4,!43$ 7O8BI ASI 3 :o nat on 11423,1!22 ,32!13 7O8BI ASI 3 :o nat on 11423,1!22 ,!12 7O8BI ASI 3 :o nat on 11423,1!22 #,29#!! 7O8BI ASI 3 :o nat on 11423,1!22 #,$!12 7O8BI ASI 3 :o nat on 11423,1!

22 $,2# #3 7O8BI ASI 3 :o nat on 11423,1!22 $,$ 7O8BI ASI 3 :o nat on 11423,1!22 !,2343! 7O8BI ASI 3 :o nat on 11423,1!22 !,$1!$ 7O8BI ASI 3 :o nat on 11423,1!22 9,20313 7O8BI ASI 3 :o nat on 11423,1!22 9,#!$ 7O8BI ASI 3 :o nat on 11423,1!22 10,1$1!! 7O8BI ASI 3 :o nat on 11423,1!22 10,# #2 7O8BI ASI 3 :o nat on 11423,1!22 11,140#3 7O8BI ASI 3 :o nat on 11423,1!22 11,#2 7O8BI ASI 3 :o nat on 11423,1!23 0 7O8BI ASI 1 :o nat on 1 991,4923 0,4!43! 7O8BI ASI 1 :o nat on 1 991,49

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23 0,9#!$ 7O8BI ASI 1 :o nat on 1 991,49

TABLE 1 : Perhitungan Gaya

BatangFrame Station OutputCase CaseType P

Te t m Te t Te t !g" 23 1,4 313 7O8BI ASI 1 :o nat on 1 991,4923 1,93$ 7O8BI ASI 1 :o nat on 1 991,4923 2,421!! 7O8BI ASI 1 :o nat on 1 991,4923 2,90#2 7O8BI ASI 1 :o nat on 1 991,4923 3,390#3 7O8BI ASI 1 :o nat on 1 991,49

23 3,!$ 7O8BI ASI 1 :o nat on 1 991,4923 4,3 93! 7O8BI ASI 1 :o nat on 1 991,4923 4,!43$ 7O8BI ASI 1 :o nat on 1 991,4923 ,32!13 7O8BI ASI 1 :o nat on 1 991,4923 ,!12 7O8BI ASI 1 :o nat on 1 991,4923 #,29#!! 7O8BI ASI 1 :o nat on 1 991,4923 #,$!12 7O8BI ASI 1 :o nat on 1 991,4923 $,2# #3 7O8BI ASI 1 :o nat on 1 991,4923 $,$ 7O8BI ASI 1 :o nat on 1 991,4923 !,2343! 7O8BI ASI 1 :o nat on 1 991,4923 !,$1!$ 7O8BI ASI 1 :o nat on 1 991,4923 9,20313 7O8BI ASI 1 :o nat on 1 991,4923 9,#!$ 7O8BI ASI 1 :o nat on 1 991,4923 10,1$1!! 7O8BI ASI 1 :o nat on 1 991,4923 10,# #2 7O8BI ASI 1 :o nat on 1 991,4923 11,140#3 7O8BI ASI 1 :o nat on 1 991,4923 11,#2 7O8BI ASI 1 :o nat on 1 991,4923 0 7O8BI ASI 2 :o nat on 2321#,4223 0,4!43! 7O8BI ASI 2 :o nat on 2321#,42

23 0,9#!$ 7O8BI ASI 2 :o nat on 2321#,4223 1,4 313 7O8BI ASI 2 :o nat on 2321#,4223 1,93$ 7O8BI ASI 2 :o nat on 2321#,4223 2,421!! 7O8BI ASI 2 :o nat on 2321#,4223 2,90#2 7O8BI ASI 2 :o nat on 2321#,4223 3,390#3 7O8BI ASI 2 :o nat on 2321#,4223 3,!$ 7O8BI ASI 2 :o nat on 2321#,4223 4,3 93! 7O8BI ASI 2 :o nat on 2321#,4223 4,!43$ 7O8BI ASI 2 :o nat on 2321#,4223 ,32!13 7O8BI ASI 2 :o nat on 2321#,4223 ,!12 7O8BI ASI 2 :o nat on 2321#,4223 #,29#!! 7O8BI ASI 2 :o nat on 2321#,42

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23 #,$!12 7O8BI ASI 2 :o nat on 2321#,4223 $,2# #3 7O8BI ASI 2 :o nat on 2321#,42

TABLE 1 : Perhitungan GayaBatangFram

e Station OutputCase CaseType PTe t m Te t Te t !g"

23 $,$ 7O8BI ASI 2 :o nat on 2321#,4223 !,2343! 7O8BI ASI 2 :o nat on 2321#,4223 !,$1!$ 7O8BI ASI 2 :o nat on 2321#,4223 9,20313 7O8BI ASI 2 :o nat on 2321#,42

23 9,#!$ 7O8BI ASI 2 :o nat on 2321#,4223 10,1$1!! 7O8BI ASI 2 :o nat on 2321#,4223 10,# #2 7O8BI ASI 2 :o nat on 2321#,4223 11,140#3 7O8BI ASI 2 :o nat on 2321#,4223 11,#2 7O8BI ASI 2 :o nat on 2321#,4223 0 7O8BI ASI 3 :o nat on 11410, 123 0,4!43! 7O8BI ASI 3 :o nat on 11410, 123 0,9#!$ 7O8BI ASI 3 :o nat on 11410, 123 1,4 313 7O8BI ASI 3 :o nat on 11410, 123 1,93$ 7O8BI ASI 3 :o nat on 11410, 123 2,421!! 7O8BI ASI 3 :o nat on 11410, 123 2,90#2 7O8BI ASI 3 :o nat on 11410, 123 3,390#3 7O8BI ASI 3 :o nat on 11410, 123 3,!$ 7O8BI ASI 3 :o nat on 11410, 123 4,3 93! 7O8BI ASI 3 :o nat on 11410, 123 4,!43$ 7O8BI ASI 3 :o nat on 11410, 123 ,32!13 7O8BI ASI 3 :o nat on 11410, 123 ,!12 7O8BI ASI 3 :o nat on 11410, 123 #,29#!! 7O8BI ASI 3 :o nat on 11410, 1

23 #,$!12 7O8BI ASI 3 :o nat on 11410, 123 $,2# #3 7O8BI ASI 3 :o nat on 11410, 123 $,$ 7O8BI ASI 3 :o nat on 11410, 123 !,2343! 7O8BI ASI 3 :o nat on 11410, 123 !,$1!$ 7O8BI ASI 3 :o nat on 11410, 123 9,20313 7O8BI ASI 3 :o nat on 11410, 123 9,#!$ 7O8BI ASI 3 :o nat on 11410, 123 10,1$1!! 7O8BI ASI 3 :o nat on 11410, 123 10,# #2 7O8BI ASI 3 :o nat on 11410, 123 11,140#3 7O8BI ASI 3 :o nat on 11410, 123 11,#2 7O8BI ASI 3 :o nat on 11410, 12# 0 7O8BI ASI 1 :o nat on 1#221,09

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2# 10,2 7O8BI ASI 1 :o nat on 1# #4,1!2# 20, 7O8BI ASI 1 :o nat on 1#90$,2$2# 0 7O8BI ASI 2 :o nat on 1$!3#,1!



2# 10,2 7O8BI ASI 2 :o nat on 1!1$9,2$2# 20, 7O8BI ASI 2 :o nat on 1! 22,3#2# 0 7O8BI ASI 3 :o nat on 1#323,1!2# 10,2 7O8BI ASI 3 :o nat on 1####,2$2# 20, 7O8BI ASI 3 :o nat on 1$009,3#2$ 0 7O8BI ASI 1 :o nat on 62$#!0,0#2$ $,$4924 7O8BI ASI 1 :o nat on 62$ 0!, 22$ 1 ,49!49 7O8BI ASI 1 :o nat on 62$33#,9$2$ 0 7O8BI ASI 2 :o nat on 62!33!,122$ $,$4924 7O8BI ASI 2 :o nat on 62!1##, $2$ 1 ,49!49 7O8BI ASI 2 :o nat on 62$99 ,032$ 0 7O8BI ASI 3 :o nat on 62!3#3,!2$ $,$4924 7O8BI ASI 3 :o nat on 62!192,2#2$ 1 ,49!49 7O8BI ASI 3 :o nat on 62!020,$12! 0 7O8BI ASI 1 :o nat on 342 1,!32! #,3 229 7O8BI ASI 1 :o nat on 3433$,#2! 12,$04 ! 7O8BI ASI 1 :o nat on 34423,3$2! 0 7O8BI ASI 2 :o nat on 3!919,1$2! #,3 229 7O8BI ASI 2 :o nat on 39004,942! 12,$04 ! 7O8BI ASI 2 :o nat on 39090,$12! 0 7O8BI ASI 3 :o nat on 31 ##, #2! #,3 229 7O8BI ASI 3 :o nat on 31# 2,33

2! 12,$04 ! 7O8BI ASI 3 :o nat on 31$3!,129 0 7O8BI ASI 1 :o nat on 34 !2,3929 #,3 229 7O8BI ASI 1 :o nat on 3449#,#229 12,$04 ! 7O8BI ASI 1 :o nat on 34410,!29 0 7O8BI ASI 2 :o nat on 392 3,2429 #,3 229 7O8BI ASI 2 :o nat on 391#$,4$29 12,$04 ! 7O8BI ASI 2 :o nat on 390!1,$29 0 7O8BI ASI 3 :o nat on 31900,9429 #,3 229 7O8BI ASI 3 :o nat on 31!1 ,1$29 12,$04 ! 7O8BI ASI 3 :o nat on 31$29,430 0 7O8BI ASI 1 :o nat on 3423!,0#30 2, #2 7O8BI ASI 1 :o nat on 34323,!3

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30 ,12 7O8BI ASI 1 :o nat on 34409,#30 0 7O8BI ASI 2 :o nat on 3$9!1,9130 2, #2 7O8BI ASI 2 :o nat on 3!0#$,#930 ,12 7O8BI ASI 2 :o nat on 3!1 3,4#



30 0 7O8BI ASI 3 :o nat on 320!4,430 2, #2 7O8BI ASI 3 :o nat on 321$0,1$30 ,12 7O8BI ASI 3 :o nat on 322 ,9431 0 7O8BI ASI 1 :o nat on 6#$0 ,!931 $,$4924 7O8BI ASI 1 :o nat on 6#!$$,4431 1 ,49!49 7O8BI ASI 1 :o nat on 6$04!,9!31 0 7O8BI ASI 2 :o nat on 611294,31 $,$4924 7O8BI ASI 2 :o nat on 6114##,0431 1 ,49!49 7O8BI ASI 2 :o nat on 611#3$, 931 0 7O8BI ASI 3 :o nat on 64 #1,!431 $,$4924 7O8BI ASI 3 :o nat on 64$33,3!31 1 ,49!49 7O8BI ASI 3 :o nat on 64904,9332 0 7O8BI ASI 1 :o nat on #929,032 ,12 7O8BI ASI 1 :o nat on #$ $,32 10,2 7O8BI ASI 1 :o nat on # ! ,9#32 0 7O8BI ASI 2 :o nat on #91 , !32 ,12 7O8BI ASI 2 :o nat on #$44,0332 10,2 7O8BI ASI 2 :o nat on # $2,4932 0 7O8BI ASI 3 :o nat on #93$,3!32 ,12 7O8BI ASI 3 :o nat on #$# ,!432 10,2 7O8BI ASI 3 :o nat on # 94,29

eterangan

KD3BIMA@I 1 Beban 3ati ; Beban *idup ; Beban @endiri Kuda - Kuda KD3BIMA@I Kombina i 1 ; Beban Angin Kiri KD3BIMA@I ! Kombina i 1 ; Beban Angin Kiri

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RE!AP#TULAS# GA$A PA%A BATA&G

TABLE ' : Rekapitu(asi Gaya Pa)a Batang

&amaBatan

g

Pan*angBatang

+m,

!om-inasi Be-an Gaya

Batang.aksima(+!g",

!eteranganCO.BO1

CO.BO'

CO.BO/

1! 1 ,49!496

214!2,31

619!2 ,!

4

62213 ,$

30''1/ 23/ T;7A *6

19 1 ,49!49 614 !!,3

61 241,#

#

61 239,3

!01 '41255 T;7A *6

20 1 ,49!49

6

14 $0,4 9

61#3$#,

6

140#!,4 ! 015/352 T;7A *6

21 1 ,49!496

422$$,2

64#90$,1

2

6401 #,1

204567321' T;7A *6

22 11,#2 1#00!, 323242,!

911423,1

! '/'4'286 TA


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Rangka UtamaPro&' L 200 ( 200 ( 1

)* 200B* 200t * 1

r1* 1$r2 * 12I n *- ,!1e /e(t ,4#

"""

""""

A *- 2 " $,$.n t e g t *kg/ " 4 ,30I( " I " 21!0

( " " #,14( " " 1 0


32 10,2 #929,0 #91 , ! #93$,3! 56/32/8 TA


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Batang 'arik terpan ang ada/a = 1 ,#0458 m

i9 = i9o = &,14 m4

O =lk m " =

1270,458

6,14 = 206,9149 @ 240 &7:=- < >

B6 $ua Penampang 2ekti2 Pro2i/

Anetto = A (@ambungan $a )

Anetto = 115,5 m

:6 Ana/i a Kekuatan Batang 'arik

Batang tarik dengan ga a terbe ar ada/a = !" 5!, 4 kg

Ntr = P 1 ) " =

39253,24115,5 =339, 5 @ 1.933,33 < >

3.9. Design Batang 'ekan

A6 Ana/i a Ke/ang ingan Batang 'ekan 3a emuk

Batang tekan ang terpan ang ada/a = !,811 m (Batang Ltama 'erpan angete/a menggunakan Batang Anak)

a a Batang 'ekan 'erbe ar = 4&6"0#,1 kg

B6 e ign 'ekuk 'er adap @umbu Ba an

i9 = i9o = &,14 m4

O =lk

m "

=381,16,14 = 62,0! @ 200 &7:=- < >

:6 'egangan Kriti 'ekuk $entur

O = *c+

x√,y E = 62,07+ x√ 290200000 = 0,#53aka, dipero/e ni/ai 9 =

1,421,6 − 0,6 *c

= 1,421,6 − 0,6 x 0,75 = 1,!1

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Perik a Kekuatan

N tr = P 2 x -x

) =612719,263

115,5 = 530,04 @ 1.933,33 < >

6 e ign 'ekuk 'er adap @umbu Beba Ba an

i 0 = &,14 m

e = 5,4& m

t = 1,"1 m = QRa = e ; t = 9 5,4& ; 1,"1 = 1 ,8! m

i = √( y2

+(12 a))

2

= √(6,142

+(12 12,83 ))

2

= 8,8" m 4

O =lk

y=

381,18,88 = 42,92 @ 200 &7:=- < >

6 e ign Dptimum ( O7 S O9)

O 9 =O ; O 1

O 1 =O 9 ; O

O 1 =& ,0# ; 4 ,"

O 1 = 6010,5"

O 1 = √ 2.010,59

O 1 =44,84

i1 = 5,81 m

$1 = O 1 9 i1

= 44,84 9 5,81

= &0,&! m

Jum/a 3edan

m =lk L1

= 381,1260,63

=1,4& T!

/1 =lk m =

381,13

=1 #,0! m

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O =l 1

"=

127,035,81 = 21, 6 @ 200 &7:=- < >

6 Perik a 'egangan 'er adap @umbu Beba Ba anO 9 = √ * y2+ *1 2 S O 9

O 9 = √ 42,92 2 +21,86 2 S & ,0#

A ) 4 ,16 62,0! < >

6 Perik a Kekuatan Batang 'ekan

Batang tekan dengan ga a tekan mak imum = 4&"0#,1 kg

O = *+ √ /y E = 48,16+ √ 29002000000 = 0,5 @ 1,2 "ke

=1,42

1,6 − 0,6 *c =1,42

1,6 − 0,6 x0,58 = 1,18

N tekan = P x -2 . ) =

46907,12 x 1,18115,5 = 240,20@ 1.933,33 < >

3.10. Design P$at "(e$

Batang tekan dengan ga a tekan mak imum = 4&"0#,1 kg

Pro2i/ ang digunakan ada/a $ 00 9 00 9 15

a = 1 ,8! m

$1 = 1 #,0! m

I1 = IU = 180 m 4

A6 @ arat Kekakuan P/at Koppe/

I koppela V

10 L1 I 1

Ikoppe/ = 10 112

t 03

Jadi,

112 t 0

3

V 10l 1= I1

L1 a

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t 03 V 10 2180127,03

12,83 x12

t 03 V 26.420,84

i oba p/at kope/ dengan teba/ = 1, # mm T


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= 9 (&,14) ; 1,27 x(12 12,83 )2

= 1 #,&& m!

$ = 2 x 'y Iy $1 = 938,14 x8,15127,66 9 1 #,0! = 56& ,85 kg

N XN in2t 9

'y Iy X 0,& 9N in

693,591,27 9

8,15127,66 X 161&0,00

34, 5 @ 1.160,00 < >

3.11. Perhitungan 7ambungan as

iketa ui .

Ni in = 16"!!,!! kg+ mt = 1,"1 m

P =

' "2 +3sin 2❑3 ¿ )

¿A = α = 0 o

P0,58

= α = 45 o P

0,707

a =t

√ 2

$n =t

√ 2$br = $n ;!a

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44/45

A

B

D

;

=

>

):


Gambar 14. letak sambungan rangka ba9a

A6 'abe/ Pan ang %igi rigi $a %angka Ltama

Per itungan Pan ang %igi rigi $a %angka Ltama ada/a ebagai berikut

'%B > 3 Panjang Rigi rigi as Rangka tama

:< :"Batang

GayaBatang

% a n br br

&kg- & m2- & m- & m- & m- & m-

1 A1 61!5,#!1",#

41,!

514,& 18,&

#5,0

0

A 156 41,&&1!,5

"1,!

510,0

&14,1 4,0

0

! A! 1&6!#&,5014,&

01,!

510,8

114,8

#4,0

0

4 A4 4&6"0#,1 41,8!1,!

5!0,"

#!5,0 ",0

0

5 B1 !6 4 ,8"0,#

!1,!

515,!

51",4

05,0

0

& B!6 1&,4 0,#

01,!

515,!

!1",!

85,0

0# '1 1865 ,!&

1&,5 1,!5

1 ,!

1&,8

5,00

Bab III Page44


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8 ' 86!&!,80

5,"

1,!5

18,#!

,#8

&,00

" '! !"60"0,#1!4,8

&1,!

55,8

1",8

&8,0

0

10 1 !"6 5!,

4

!5,0

1

1,!

5

5," ","

#

8,0

011 !8615!,4

&!4,0

!1,!

55,1

"",

48,0

0

1 ! 116&!#,5"10,!

81,!

5#,&

811,#

4!,0

0

1! 4 &6"!#,!8

&,1"

1,!5

4,58

8,&!

!,00

B6 Pan ang %igi rigi $a %angka Anak

Pan ang %igi rigi $a %angka Anak mengambi/ pan ang tandard aitu 0 m

t pi a/ untuk emua rangka anak

bab 3 analisa data atap baja dengan metode perhitungan asd

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