asam kuat vs basa kuat
DESCRIPTION
asam Vs basaTRANSCRIPT
ASAM KUAT VS BASA KUAT
ASAM KUAT VS BASA KUAT
50 ml HCl 0,1 M
HCl + NaOH NaCl + H2O
NaOH 0 ml
HCl + NaOH NaCl + H2OM 5 0
R 00
S 500
(HCl) =
PH = - log 10 1 = 1NaOH 10 ml
HCl + NaOH NaCl + H2OM 5 1
R 11
S 401
(HCl) =
PH = - log 6 . 10 2 = 1,2
NaOH 20 ml
HCl + NaOH NaCl + H2OM 5 2
R 22
S 302
(HCl) =
PH = - log 4 . 10 2 = 1,4NaOH 30 ml
HCl + NaOH NaCl + H2OM 5 3
R 33
S 203
(HCl) =
PH = - log 2,5 . 10 2 = 1,6
NaOH 40 ml
HCl + NaOH NaCl + H2OM 5 4
R 44
S 104
(HCl) =
PH = - log 1 . 10 2 = 1,9NaOH 50 ml
HCl + NaOH NaCl + H2OM 5 5
R 55
S 005
PH = 7
NaOH 60 ml
HCl + NaOH NaCl + H2OM 5 6
R 55
S 15
(OH) =
POH = - log
PH = 14 2 = 12
ASAM LEMAH VS BASA KUAT50 ml CH3COOH 0,1 M
Ka = 1,8 . 10 -5
NaOH 0 ml
CH3COOH+NaOH CH3COOH Na +H2OM 5 0
R 00
S 500
(CH3COOH) =
PH = - log 10 1 = 1NaOH 10 ml
CH3COOH+NaOH CH3COOH Na +H2OM 5 1R 11
S 401(CH3COOH) =
PH = - log 7,2 . 10 5 = 4,1
NaOH 20 ml
CH3COOH+NaOH CH3COOH Na +H2OM 5 2
R 22
S 302
(CH3COOH) =
PH = - log 2,7 . 10 5 = 4,5NaOH 30 ml
CH3COOH+NaOH CH3COOH Na +H2OM 5 3
R 33
S 203
(CH3COOH) =
PH = - log 1,2 . 10 5 = 4,9
NaOH 40 ml
CH3COOH+NaOH CH3COOH Na +H2OM 5 4
R 44
S 104
(CH3COOH) =
PH = - log 4,5 . 10 6 = 5,3NaOH 50 ml
CH3COOH+NaOH CH3COOH Na +H2OM 5 5
R 55
S 005
PH = 7
NaOH 60 ml
CH3COOH+NaOH CH3COOH Na +H2OM 5 6
R 55
S 015
(OH) =
POH = - log
PH = 14 2 = 12
ASAM KUAT VS BASA LEMAH
50 ml NH 4OH 0,1M
Kb = 1,8 . 10 -5NaOH 10 ml
NH4OH + HCl NH4Cl + H2OM 5 1R 11
S 401(0H-) =
POH = - log 7,2 . 10 5 = 4,1PH = 14 4,1 = 9,9NaOH 20 ml
NH4OH + HCl NH4Cl + H2OM 5 2
R 22
S 302
(0H-) =
POH = - log 2,7 . 10 5 = 4,6
PH = 14 4,6 = 9,4
NaOH 30 ml
NH4OH + HCl NH4Cl + H2OM 5 3
R 33
S 203
(0H-) =
POH = - log 1,2 . 10 5 = 4,9
PH = 14 4,9 = 9,1NaOH 40 ml
NH4OH + HCl NH4Cl + H2OM 5 4
R 44
S 104
(0H-) =
POH = - log 0,45 . 10 5 = 5,3
PH = 14 5,3 = 8,7
NaOH 50 ml
NH4OH + HCl NH4Cl + H2OM 5 5
R 55
S 005(H+) =
PH = - log =5,3NaOH 60 ml
NH4OH + HCl NH4Cl + H2OM 5 6R 55
S 015M =
PH = - log
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