tegangan tali (mekanika bahan)
Post on 10-Oct-2015
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IVAN KRISSANDY HIDAYATD3 TSB 2013B / 130522506275MEKANIKA BAHAN A CP = 200 kg B AB = 15 mm 1,5 cm
200 kg BC = 10 mm 1,0 cm = 60 = 70 = = P1 = P2 = P1 = 245,3 kg P2 = 226,1 kgAB = = = 138,8 BC = = = 287
CARA GRAFISSkala 1 cm = 100 kg
P1 = 2,45 cmP2 = 2,25 cmP1 = 245 kgP2 = 225 kgAB = = = 138,7 BC = = = 286,6
P = 100 kg q = 50 kg/m
B A B 5,00 m10,00 mBalok berpenampang segiempat b = 10 cmh = 2 cmA = 2. 10-3 m2RAV ?MB = 0-P1.CB + RAV.AB q.AB2 = 0 RAV = = = 400 kgMmax D = 0M(x) = - P(5+x) + RAV.x q.x2 = -5P Px + RAV.x q.x2M(x)dx = D D = 0-P + RAV q.x = 0 x = x = = 6 mMmax = -5P Px + RAV.x q.x2 = -500 600 + 2400 900 = 400 kgmMmin = MA = -P.CA = -100.5 = -500 kgmMAX = = = = 200.103 MIN = = = = -250.103
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