model transportasi, soal.docx

Toko/pabrikToko 1Toko 2Toko 3Toko 4AI

A265450

B51011640

C7891030

D4128720

Dummy000010

BJ35455020

Tabel Matriks TransportasiAI = 140 + 10 = 150BJ = 150Metode NWC Toko/pabrikToko 1Toko 2Toko 3Toko 4AI

A3521565450

B530101011640

C783091030

D41210810720

Dummy00010010

BJ35455020

Distribusi Biaya :1. A Toko 1 = 35 x 2 = 702. A Toko 2 = 15 x 6 = 903. B Toko 2 = 30 x 10 = 3004. B Toko 3 = 10 x 11 = 1105. C Toko 3 = 30 x 9 = 2706. D Toko 3 = 10 x 8 = 807. D Toko 4 = 10 x 7 = 708. Dummy Toko 4 = 10 x 0Total Biaya : 990

Metode Least Cost :Toko/pabrikToko 1Toko 2Toko 3Toko 4AI

A25265520450

B515102511640

C730891030

D412208720

Dummy10000010

BJ35455020

Distribusi Biaya :1. A Toko 1 = 25 x 2 = 502. A Toko 3 = 5 x 5 = 253. A Toko 4 = 20 x 4 = 804. B Toko 2 = 15 x 10 = 1505. B Toko 3 = 25 x 11 = 2756. C Toko 2 = 30 x 8 = 2407. D Toko 3 = 20 x 8 = 1608. Dummy Toko 1 = 10 x 0Total Biaya : 980

Metode Vogel :Toko/pabrikToko 1Toko 2Toko 3Toko 4AI

A265054502 2 2

B15551011206401 1 1 1 5

C7308910301 1 1 1 1

D2041287203 3

Dummy010000100

BJ35455020

22322622222534

4224

Distribusi Biaya :1. A Toko 3 = 50 x 5 = 2502. B Toko 1 = 15 x 5 = 753. B Toko 2 = 5 x 10 = 504. B Toko 4 = 20 x 6 = 1205. C Toko 2 = 30 x 8 = 2406. D Toko 1 = 20 x 4 = 807. Dummy Toko 2 = 10 x 0Total Biaya : 815

Kesimpulan : Metode yang dipilih adalah metode Vogel Karena menghasilkan Total biaya terendah yaitu 815.