tugas+orkom+yoseph+ole+0843190001
DESCRIPTION
untuk pemlaTRANSCRIPT
Tabel Kebenaran Rangkaian Half Substractors
Tugas Organisasi & Arsitektur Komputer
Yoseph Ole 084319001hal. 8
Tugas Organisasi & Arsitektur Komputer
Latihan ISistem Bilangan21121029282726252423222120
204810245122561286432168421
Konversikan ke dalam binary, octal, dan hexadecimal.
1. 29(10) ( binary= 11101(2)
2. 36 (10) ( binary= 100100(2)
3. 55(10) ( binary= 110111(2)
4. 384(10) ( binary= 110000000(2)
5. 500(10) ( binary= 111110100(2)
6. 1020(10) ( binary= 1111111100(2)
Konversikan ke dalam Decimal, octal, dan hexadecimal.
1. 11110000
Ke dalam decimal= (1*27)+(1*26)+(1*25)+(1*24)+(0*23)+(0*22)+(0*21)= 240 (10)Ke dalam
Ke dalam
2. 100010101011
Ke dalam decimal= 2219 (10)Ke dalam
Ke dalam
3. 110100010110
Ke dalam decimal= 3350 (10)Ke dalam
Ke dalam
4. 10101110101010
Ke dalam decimal= 11178 (10)Ke dalam
Ke dalam
Konversikan ke dalam Decimal, binary, dan hexadecimal.
1. 13235(8)binary = 1011010011101(2)decimal = 31663(10)hexadecimal = 0001 0110 1001 1101 ( 169D(16)
2. 65454237
binary = 110101100101100010011111(2)decimal = 371540235(10)hexadecimal = 1101 0110 0101 1000 1001 1111 ( D6589F(16)
3. 741231656
binary = 111100001010011001110101110(2)decimal = 5413446050(10)hexadecimal = 0111 1000 0101 0011 0011 1010 1110 ( 78533AE(16)
Konversikan ke dalam binary, octal, dan decimal.
1. BECA
Binary = 1011111011001010 (2)Octal = 001 011 111 011 001 010 = 137312(8)Decimal = 48842(10)2. H20
Binary = 100 1000 011 0010 011 0000 (2)( BCD = 483230
Octal = 100 100 001 100 100 110 000 = 4414460(8)Decimal = 1186352(10)3. DEC1
Binary = 1101111011000001 (2)Octal = 001 101 111 011 000 001 = 157301(8)Decimal = 57025(10)4. FEBI
Binary = 100 0110 100 0101 100 0010 100 1001 (2)Octal = 001 000 110 100 010 110 000 101 001 001 = 1064260511(8)Decimal = 147939657(10)5. B2975AF
Binary = 1011001010010111010110101111 (2)Octal = 001 011 001 010 010 111 010 110 101 111 = 1312272657(8)Decimal = 187266479(10)Konversikan ke dalam binary, dan komplemen I dan komplemen II
1. 29(10)Binary =29 : 2 =14sisa 1maka 29(10)= 11101(2)
14 : 2 =7
sisa 0
7 : 2 =3
sisa 1
3 : 2 =1
sisa 1(R) Komplemen 10: (29)c,10 = 102 29 = 100 29= 71(R-1) Komplemen 9: (29)c,10-1 = 102 100 29 = 100-1-29= 702. 36(10)Binary = 100100(2)
Komplemen I =(36)c,10 = 102-36 = 64
Komplemen II =(36)c,10-1 = 102-100-36 = 63
3. 55(10)Binary = 110111(2)
Komplemen I =(55)c,10 = 102-55 = 45
Komplemen II =(55)c,10-1 = 102-100-55 = 44
4. 384(10)Binary = 110000000(2)
Komplemen I =(384)c,10 = 103-384 = 616
Komplemen II =(384)c,10-1 = 103-100-384 = 615
5. 500(10)Binary = 111110100(2)
Komplemen I =(500)c,10 = 103-500 = 500
Komplemen II =(500)c,10-1 = 103-100-500 = 499
6. 1020(20)Binary = 1111111100(2)
Komplemen I =(1020)c,10 = 104-1020 = 8980
Komplemen II =(1020)c,10-1 = 104-100-1020 = 8979
Latihan membaca Karnaugh Map
Soal 1.
BC
AB'B
A'
A11
C'CC'
Minterm (m) ( F = ACSoal 2.
BC
AB'B
A'
A
C'CC'
Minterm (m) ( F = ABC + ABC
F = C (AB + AB)
F = C
Soal 3.
BC
AB'B
A'111
A
C'CC'
Minterm (m) ( F = AC
Maxterm (M) (F = A(BC)
Soal 4.
BC
AC'C
A'B
111B
A11
B
D'DD
Minterm (m) ( F = ABC + BD
Soal 5.
BC
AC'C
A'11B
1B
A1
11B
D'DD
Minterm (m) ( F = BD + CD
Soal 6. BC
AC'C
A'111B
B
A
111B
D'DD
Minterm (m) ( F = ABC + ABC + D
Soal 7.
BC
AC'C
A'B
111B
A111
B
D'DD
Minterm (m) ( F = ABC + BD + ABC
Soal 8.
BC
AC'C
A'B
B
A1111
B
D'DD
Minterm (m) ( F = AB
Tabel Kebenaran Rangkaian Half Substractors
XYDBm
00000
01111
10102
11003
Keterangan tabel:
X dan Y = variabel
D= Different
B= borrow
m =position in K-Map
K-Map for Different
Y'Y
X'01
m0m1
X10
m3m4
Persamaan:D = XY + XY
K-Map for Borrow
Y'Y
X'01
m0m1
X00
m3m4
Persamaan:
B=XY
Rangkaian Kombinasional Half Sustractor
Tabel Kebenaran Rangkaian Full Substractors
XYZDBm
000000
001111
010112
011013
100104
101005
110006
111117
Keterangan tabel
X, Y, Z = variabel
D= Different
B= borrow
m =position in K-Map
K-Map for Different
Y'Y
X'0101
m0m1m3m2
X1010
m4m5m7m6
Z'ZZ'
Persamaan:
D = X'YZ + X'YZ' + XY'Z' + XYZ
K-Map for Borrow
Y'Y
X'0111
m0m1m3m2
X0010
m4m5m7m6
Z'ZZ'
Persamaan:
B = X'Z + X'Y +YZ
Rangkaian Kombinasional Full Substractor
Diagram keadaan
Tabel eksitasi Tongle Flip-flopPresent State ()Next State ()
m
00000(0001100010
10001(0010200111
20010(0011300012
30011(0100401113
40100(0101500014
50101(0110600115
60110(0111700016
70111(1000811117
81000(1001900018
91001(0000010019
1010(1011
1011(11004 buah flip-flop T
1100(1101diisi berdasarkan
1101(1110table eksitasi
1110(1111no. 10-15 tidak
1111(0000digunakan
ABCD
Menurunkan fungsi flip-flop
CC
CDCDCDCD
AAB0000B
M0M1M3M2
AB0010B
M4M5M7M6
AAB0000
M12M13M15M14
AB0100B
M8M9M11M10
DDD
Fungsi: T0 = ABCD + ABCDMenurunkan fungsi flip-flop
CC
CDCDCDCD
AAB0010B
M0M1M3M2
AB0010B
M4M5M7M6
AAB0000
M12M13M15M14
AB0000B
M8M9M11M10
DDD
Fungsi:
T1= ACDMenurunkan fungsi flip-flop
CC
CDCDCDCD
AAB0110B
M0M1M3M2
AB0110B
M4M5M7M6
AAB0000
M12M13M15M14
AB0000B
M8M9M11M10
DDD
Fungsi:
T2 = AD
Menurunkan fungsi flip-flop
CC
CDCDCDCD
AAB1111B
M0M1M3M2
AB1111B
M4M5M7M6
AAB1111
M12M13M15M14
AB1111B
M8M9M11M10
DDD
Fungsi:
T3 = 1
Gambar rangkaian counter 4 bit T Flip-flop
Tabel eksitasi Set Reset Flip-flopPresent State ()Next State ()
m
00000(000110X0X0X100
10001(001020X0X10011
20010(001130X0XX0102
30011(010040X1001013
40100(010150XX00X104
50101(011060XX010015
60110(011170XX0X0106
70111(10008100101017
81000(10019X00X0X108
91001(00000010X0X019
1010(1011
1011(1100
1100(1101
1101(1110
1110(1111
1111(0000
ABCDABCD
Menurunkan fungsi flip-flop S0
CC
CDCDCDCD
AAB0000B
M0M1M3M2
AB000B
M4M5M7M6
AAB----
M12M13M15M14
ABX0--B
M8M9M11M10
DDD
Fungsi S0 = ABCDMenurunkan fungsi flip-flop S1
CC
CDCDCDCD
AAB000B
M0M1M3M2
ABXX0XB
M4M5M7M6
AAB----
M12M13M15M14
AB00--B
M8M9M11M10
DDD
Fungsi S1 = ABCDMenurunkan fungsi flip-flop S2
CC
CDCDCDCD
AAB010XB
M0M1M3M2
AB010XB
M4M5M7M6
AAB----
M12M13M15M14
AB00--B
M8M9M11M10
DDD
Fungsi S2 = ACDMenurunkan fungsi flip-flop S3
CC
CDCDCDCD
AAB1001B
M0M1M3M2
AB1001B
M4M5M7M6
AAB----
M12M13M15M14
AB10--B
M8M9M11M10
DDD
Fungsi S3 = AD + BCDMenurunkan fungsi flip-flop R0
CC
CDCDCDCD
AABXXXXB
M0M1M3M2
ABXX0XB
M4M5M7M6
AAB----
M12M13M15M14
AB0--B
M8M9M11M10
DDD
Fungsi R0 = ABCDMenurunkan fungsi flip-flop R1
CC
CDCDCDCD
AABXX0XB
M0M1M3M2
AB000B
M4M5M7M6
AAB----
M12M13M15M14
ABXX--B
M8M9M11M10
DDD
Fungsi R1 = ABCDMenurunkan fungsi flip-flop R2
CC
CDCDCDCD
AABX010B
M0M1M3M2
ABX010B
M4M5M7M6
AAB----
M12M13M15M14
ABXX--B
M8M9M11M10
DDD
Fungsi R2 = ACDMenurunkan fungsi flip-flop R3
CC
CDCDCDCD
AAB0110B
M0M1M3M2
AB0110B
M4M5M7M6
AAB----
M12M13M15M14
AB01--B
M8M9M11M10
DDD
Fungsi R3 = AD + BCD
Gambar rangkaian counter 4 bit Set Reset Flip-flop
Tabel eksitasi JK Flip-flopPresent State ()Next State ()
m
00000(000110X0X0X1X0
10001(001020X0X1XX11
20010(001130X0XX01X2
30011(010040X1XX1X13
40100(010150XX00X1X4
50101(011060XX01XX15
60110(011170XX0X01X6
70111(100081XX1X1X17
81000(10019X00X0X1X8
91001(00000X10X0XX19
1010(1011
1011(1100
1100(1101
1101(1110
1110(1111
1111(0000
ABCD
Menurunkan fungsi flip-flop J0
CC
CDCDCDCD
AAB0000B
M0M1M3M2
AB000B
M4M5M7M6
AAB----
M12M13M15M14
ABXX--B
M8M9M11M10
DDD
Persamaan J0 = ABCD + ABCMenurunkan fungsi flip-flop J1
CC
CDCDCDCD
AAB0010B
M0M1M3M2
ABXXXXB
M4M5M7M6
AAB----
M12M13M15M14
AB00--B
M8M9M11M10
DDD
Persamaan J1 = ACD + ABMenurunkan fungsi flip-flop J2
CC
CDCDCDCD
AAB01XXB
M0M1M3M2
AB01XXB
M4M5M7M6
AAB----
M12M13M15M14
AB00--B
M8M9M11M10
DDD
Persamaan J2 = AD + ACMenurunkan fungsi flip-flop J3
CC
CDCDCDCD
AAB1XX1B
M0M1M3M2
AB1XX1B
M4M5M7M6
AAB----
M12M13M15M14
AB1X--B
M8M9M11M10
DDD
Persamaan J3 = A + BC
Menurunkan fungsi flip-flop K0
CC
CDCDCDCD
AABXXXXB
M0M1M3M2
ABXXXXB
M4M5M7M6
AAB----
M12M13M15M14
AB01--B
M8M9M11M10
DDD
Persamaan K0 = A + CDMenurunkan fungsi flip-flop K1
CC
CDCDCDCD
AABXXXXB
M0M1M3M2
AB0010B
M4M5M7M6
AAB----
M12M13M15M14
ABXX--B
M8M9M11M10
DDD
Persamaan K1 = AB + ACD + BCMenurunkan fungsi flip-flop K2
CC
CDCDCDCD
AABXX10B
M0M1M3M2
ABXX10B
M4M5M7M6
AAB----
M12M13M15M14
ABXX--B
M8M9M11M10
DDD
Persamaan K2 = AC + AD + BCMenurunkan fungsi flip-flop K3
CC
CDCDCDCD
AABX11XB
M0M1M3M2
ABX11XB
M4M5M7M6
AAB----
M12M13M15M14
ABX1--B
M8M9M11M10
DDD
Persamaan K3 = AD + BC
Gambar rangkaian counter 4 bit JK Flip-flop
1
1
1
1
1
1
1
Dosen: Bpk. Anwar
Teknik Informatika D3 UPI-YAI
_1300133902.unknown
_1301175375.unknown
_1301259467.vsdA
B
C
D
A
B
C
D
_1301295600.unknown
_1301295775.unknown
_1301296152.unknown
_1301382333.vsdA
B
C
D
A
B
C
D
J0 = ABCD + ABC
AC
AD
BC
K1 = AB+ACD+BC
J2 = AD + AC
K2 = AC+AD+BC
J3 = A + BC
AD
K3 = AD + BC
AC
ABCD
ABC
CD
K0= A + CD
ACD
AB
J1 = ACD + AB
AB
ACD
BC
BC
BC
AD
_1301295980.unknown
_1301295688.unknown
_1301295341.unknown
_1301295424.unknown
_1301295248.unknown
_1301293651.vsdA
B
C
D
A
B
C
D
S0 = ABCD
R0 = ABCD
S1 = ABCD
R1 = ABCD
S2 = ACD
R2 = ACD
S3 = AD + BCD
AD
BCD
R3 = AD + BCD
AD
BCD
_1301175517.unknown
_1301176852.unknown
_1301176869.unknown
_1301176893.unknown
_1301176901.unknown
_1301176872.unknown
_1301176864.unknown
_1301176831.unknown
_1301176840.unknown
_1301175518.unknown
_1301175515.unknown
_1301175516.unknown
_1301175397.unknown
_1301175514.unknown
_1301175395.unknown
_1300857626.unknown
_1300861313.unknown
_1300861393.unknown
_1300861674.unknown
_1300859002.unknown
_1300859025.unknown
_1300859053.unknown
_1300859015.unknown
_1300857746.unknown
_1300857744.unknown
_1300857745.unknown
_1300134331.unknown
_1300274024.unknown
_1300857437.unknown
_1300857462.unknown
_1300653429.vsd0000
0001
0001
0010
0011
0100
0101
0110
0111
1000
1001
_1300272328.vsd1
X
Y
D
B
_1300273913.unknown
_1300270016.vsd1
X
Y
Z
D
B
_1300134140.unknown
_1300134237.unknown
_1300134075.unknown
_1300133577.unknown
_1300133701.unknown
_1300133815.unknown
_1300133698.unknown
_1300133306.unknown
_1300133347.unknown
_1300133286.unknown