tugas 2 masalah nilai awal
TRANSCRIPT
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7/28/2019 Tugas 2 Masalah Nilai Awal
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TUGAS 2 MNA
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NAMA : PHELIPUS MERE
NIM : 1001036019
PRODI : P. MATEMATIKA
SEMESTER: VI
1. a. 10 + 20 + 20 = 50 cos
= 1
= 1 10 .
= 10 20 = 10
=
+=
50 (10)
20 + (10)= 1
=
+=
50 (20)
20 + (10)= 2
( ) = cos + sin= cos 2 sin
b. 40 + 240 + 1000 = 369(10) cos(10 ):
( ) = cos 10 + sin 10
=(369)(300)
240 + 300= 0,75
=(369)(240)
240 + 300= 0,6
( )= 0,70cos 10 0,6sin
c. 10 + 40 + 150 = 800 c os 5
= 5 10 =1
5 0,02= 40
:( ) = cos 5 + sin 5
=160 40
40 + 40= 2
=160 40
40 + 40= 2
= 2 cos 5 2 sin 52. a. :
= 40 = 10 = 0,02= 300 = 300 cos
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+ +1
= cos
= 10 + 40 + 50 = 300 1 cos= = 1 10
,= 40
= =( )
( )=
.= 3, 75
= =( )
( )=
.= 3,75
:10 + 40 + 50 = 0
=2
=40
2 1040
4 10
0,02
= 400
= 20 =
:1 = + = 2 +2 = = 2
:( ) = 1 ( ) + 2 ( ) + 3,75 cos 3,75 sin . (1)
1 2 (0) = 0 cos = 0:
(0) = 1 + 2 + 3,75(0) = (2 + ) 1 + (2 ) 2 3,75 . (2)
1 + 2 = 3,75
1 +1,875(1 )
= 3,75
1 +1,875(1 )
= 3,75
1 + 1,875(1 ) = 3,751 = 3,75 + 1,875 1,8751 = 1,875 1,875
1 = 1,875( 1) :
( ) =(1,875(1 ) ( ) +
(1,875(1 ) ( ) + 3,75 cos 3,75 sin
10( ) = +
= (3,75) + (3,75)= 14,0625 + 14,0625
= 28,125= 5,3033
tan = = 40
40= 1
= (1)
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= 135 315:
( ) = 5,3033 sin( 135)
b. = 160
= 20 = 0,002= 481 sin(10)
20 + 160 + 500 = 481(10) cos
= 10 20 1
10 0,002= 150
:( ) = cos 10 + sin 10
=481 150
160 + 150= 1,5
=481(160)
160 + (150)= 1,6
:20 + 160 + 500 = 0
+ 8 + 25 = 0 :
=2
=160
40= 4
=1
212
4
=
1
40 160 40.000=
1
401201
= 311 = + = 4 + 311 = = 4 31
= 1 + 2 + cos + sin= 1 + 2 + (1,5) cos 481 + (1,6)
(0) = 1 + 2 1,5 cos 481 0 1,6 sin 48 0 1 + 2 = 1,5 0
1 + 2 = 1,5o (0) = 4 + 31 1 4 + 31 2 1,6cos 481 0
= 4 + 31 1 4 + 31 2 1,6 = 0 = 4 + 31 1 4 + 31 2 1,6 = 4 1 + 31 1 4 33 2 = 1,6
1 + 2 = 1,5
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4 + 31 1 4 + 31 2 = 1,6
4 + 31 1 4 + 31 2 = 4 + 31 1,5
4 + 31 1 4 + 31 2 = 1,6
61 2 = 7,6 + 4,5
2 =, ,
1 +, ,
= 1,5
1 = 1,5 , ,
=, ,
( ) =13,5 61,6
6 +
61,6 + 4,56
= 1,5cos(3776) 1,6 sin(3776) :
( ) = sin( )
= + = 48148100 = 481219,31722 = 2,19
tan = =150
160 = 43,15
( ) = 2,19sin(10 ) 43,15