tugas 2 masalah nilai awal

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  • 7/28/2019 Tugas 2 Masalah Nilai Awal

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    TUGAS 2 MNA

    http://www.usmcr010.blogspot.com

    http://www.ataromba.blogspot.com Page 1

    NAMA : PHELIPUS MERE

    NIM : 1001036019

    PRODI : P. MATEMATIKA

    SEMESTER: VI

    1. a. 10 + 20 + 20 = 50 cos

    = 1

    = 1 10 .

    = 10 20 = 10

    =

    +=

    50 (10)

    20 + (10)= 1

    =

    +=

    50 (20)

    20 + (10)= 2

    ( ) = cos + sin= cos 2 sin

    b. 40 + 240 + 1000 = 369(10) cos(10 ):

    ( ) = cos 10 + sin 10

    =(369)(300)

    240 + 300= 0,75

    =(369)(240)

    240 + 300= 0,6

    ( )= 0,70cos 10 0,6sin

    c. 10 + 40 + 150 = 800 c os 5

    = 5 10 =1

    5 0,02= 40

    :( ) = cos 5 + sin 5

    =160 40

    40 + 40= 2

    =160 40

    40 + 40= 2

    = 2 cos 5 2 sin 52. a. :

    = 40 = 10 = 0,02= 300 = 300 cos

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    TUGAS 2 MNA

    http://www.usmcr010.blogspot.com

    http://www.ataromba.blogspot.com Page 2

    + +1

    = cos

    = 10 + 40 + 50 = 300 1 cos= = 1 10

    ,= 40

    = =( )

    ( )=

    .= 3, 75

    = =( )

    ( )=

    .= 3,75

    :10 + 40 + 50 = 0

    =2

    =40

    2 1040

    4 10

    0,02

    = 400

    = 20 =

    :1 = + = 2 +2 = = 2

    :( ) = 1 ( ) + 2 ( ) + 3,75 cos 3,75 sin . (1)

    1 2 (0) = 0 cos = 0:

    (0) = 1 + 2 + 3,75(0) = (2 + ) 1 + (2 ) 2 3,75 . (2)

    1 + 2 = 3,75

    1 +1,875(1 )

    = 3,75

    1 +1,875(1 )

    = 3,75

    1 + 1,875(1 ) = 3,751 = 3,75 + 1,875 1,8751 = 1,875 1,875

    1 = 1,875( 1) :

    ( ) =(1,875(1 ) ( ) +

    (1,875(1 ) ( ) + 3,75 cos 3,75 sin

    10( ) = +

    = (3,75) + (3,75)= 14,0625 + 14,0625

    = 28,125= 5,3033

    tan = = 40

    40= 1

    = (1)

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    TUGAS 2 MNA

    http://www.usmcr010.blogspot.com

    http://www.ataromba.blogspot.com Page 3

    = 135 315:

    ( ) = 5,3033 sin( 135)

    b. = 160

    = 20 = 0,002= 481 sin(10)

    20 + 160 + 500 = 481(10) cos

    = 10 20 1

    10 0,002= 150

    :( ) = cos 10 + sin 10

    =481 150

    160 + 150= 1,5

    =481(160)

    160 + (150)= 1,6

    :20 + 160 + 500 = 0

    + 8 + 25 = 0 :

    =2

    =160

    40= 4

    =1

    212

    4

    =

    1

    40 160 40.000=

    1

    401201

    = 311 = + = 4 + 311 = = 4 31

    = 1 + 2 + cos + sin= 1 + 2 + (1,5) cos 481 + (1,6)

    (0) = 1 + 2 1,5 cos 481 0 1,6 sin 48 0 1 + 2 = 1,5 0

    1 + 2 = 1,5o (0) = 4 + 31 1 4 + 31 2 1,6cos 481 0

    = 4 + 31 1 4 + 31 2 1,6 = 0 = 4 + 31 1 4 + 31 2 1,6 = 4 1 + 31 1 4 33 2 = 1,6

    1 + 2 = 1,5

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    TUGAS 2 MNA

    http://www.usmcr010.blogspot.com

    http://www.ataromba.blogspot.com Page 4

    4 + 31 1 4 + 31 2 = 1,6

    4 + 31 1 4 + 31 2 = 4 + 31 1,5

    4 + 31 1 4 + 31 2 = 1,6

    61 2 = 7,6 + 4,5

    2 =, ,

    1 +, ,

    = 1,5

    1 = 1,5 , ,

    =, ,

    ( ) =13,5 61,6

    6 +

    61,6 + 4,56

    = 1,5cos(3776) 1,6 sin(3776) :

    ( ) = sin( )

    = + = 48148100 = 481219,31722 = 2,19

    tan = =150

    160 = 43,15

    ( ) = 2,19sin(10 ) 43,15