TURUNAN RUMUS UNTUK TUMPUAN :

TURUNAN RUMUS UNTUK TUMPUAN :A. Engsel-Engsel (jarak = a)

a

b

(MA= 0 ;

(Fy= 0 ;

DBB potongan x-x :

MX-X = 0 ;MX-X RAy x = 0

MX-X = RAy x =

Syarat Batas:

= 0;

Sehingga :

Untuk x = L; maka y = max

B.Engsel-Engsel (2 beban dengan jarak L dan L)

L F1 F2

L

L(MA= 0 ;

(Fy= 0 ;

DBB potongan x-x :

F1

MX-X = 0 ;

Syarat batas:

X=0 maka;y=0 dan C2=0

maka;

Sehingga:

Untuk ymax ; x= L

C. Jepit-Jepit (Jarak L)

MA = MB = 0(MA = 0 ;

(Fy = 0 ;

DBB potongan x-x :

MX =

Syarat Batas

X = 0, y = 0 ; C2 = 0

, x = 0 ; C1 = 0

ymax ; untuk x = L

EI ymax =

Ymax =

D. Jepit Jepit (Jarak L)

DBB potongan x-x :

Mx = MA - RAy

=

Syarat Batas

X = 0, y = 0 ; C2 = 0

, x = 0 ; C1 = 0

ymax ; untuk x = L

EI ymax =

Ymax

E. Jepit Jepit (Jarak & L)

DBB potongan x-x :

Syarat batas:

X=0 maka;y=0 dan C2=0

maka;

Sehingga:

Untuk ymax ; x= L

F. Jepit Engsel ~ Rumusnya sama dengan Jepit-Jepit

~ DBB berbeda

DBB potongan x-x :

G. Batang Kantilever (jarak = a)

a

b

(MA= 0 ;MA = -P.a

(Fy

= 0 ;RAy = P

MX-X = 0 ;

Mx-x = MA + RAy

= P.x - P.a

Syarat batas:

; X = 0; C1 = 0

y = 0

; C2 = 0

Sehingga:

Untuk ymax (X = L):

TUGAS PENDAHULUAN

FENOMENA DASAR MESIN 01

LENDUTAN BATANG

NAMA

: NOVA APRILLA

NRP

: 12-2002-003

KELOMPOK : 5

TGL PREKTIKUM : 07-04-2005

LABORATORIUM KONTRUKSIJURUSAN TEKNIK MESIN

FAKULTAS TEKNOLOGI INDUSTRI

INSTITUT TEKNOLOGI NASIONAL

2005

RAx

RBx

RBy

RAy

RAy

RBy

L

MX-X

x

RBy

RAx

x

RBy

MX-X

x

x

RAy

RBy

RAx

RBx

L

RBy

x

x

x

MX-X

RAy

RBy

RAx

RBx

RBx

MB

MA

x

x

3/4 F

x

MX

x

x

RBy

RAy

x

RBx

RAx

x

F

MB

MA

(MA = 0 ; EMBED Equation.3 EMBED Equation.3

(Fy = 0 ; EMBED Equation.3

RA

x

MX

RB

MA = MB = FL/8

(MA= 0 ; EMBED Equation.3

EMBED Equation.3

(Fy= 0 ; EMBED Equation.3

MX

F2

x

RAx

RBx

x

RAy

RBy

F1

EMBED Equation.3

EMBED Equation.3 EMBED Equation.3

EMBED Equation.3

x

F1

RAy

RBy

RAy

x

RBx

RAx

MA

F

x

RAy

x

MX

F

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