WRITE(*,*)'PROGRAM INI AKAN MENGHITUNG NILAI DARI'

WRITE(*,*)'AKAR-AKAR PERSAMAAN KUADRAT:'

WRITE(*,*)' 2 '

WRITE(*,*)'AX +BX+C=0'

WRITE(*,*)

1 WRITE(*,'(1X,A,\)')'NILAI KOEFISIEN A?'

READ (*,'(F7.2)')A

! seleksi nilai A tidak boleh = 0

IF(A.EQ.0.0)GOTO 1

WRITE(*,'(1X,A,\)')'NILAI KOEFISIEN B?'

READ (*,'(F7.2)')B

WRITE(*,'(1X,A,\)')'NILAI KOEFISIEN C?'

READ (*,'(F7.2)')C

WRITE(*,*)

! hitung nilai dari determinan

D=B**2-4*A*C

! seleksi nilai dari determinan

IF(D.LT.0.)THEN

! nilai determinan negatif -> ada 2 angka kompleks berlainan

Z1=(-B)/(2*A)

Z2=SQRT (-D)/(2*A)

WRITE(*,'(1X,A,F7.2,A,F7.2,A)')'X1=',Z1,'+',Z2,'i'

WRITE(*,'(1X,A,F7.2,A,F7.2,A)')'X2=',Z1,'-',Z2,'i'

END IF

IF(D.EQ.0)THEN

! nilai determinan nol, berarti ada dua akar real kembar

X1=(-B)/(2*A)

WRITE(*,*)'ADA DUA AKAR REAL KEMBAR:'

WRITE(*,*)'-------------------------'

WRITE(*,'(1X,A,F7.2)')'X1=X2=',X1

END IF

IF(D.GT.0.)THEN

! nilai determinan positif, berarti ada 2 akar real berlaninan

X1=(-B+SQRT (D))/(2*A)

X2=(-B-SQRT (D))/(2*A)

WRITE(*,*)'ADA DUA AKAR REAL BERLAINAN:'

WRITE(*,*)'----------------------------'

WRITE(*,'(1X,A,F7.2)')'X1=',X1

WRITE(*,'(1X,A,F7.2)')'X2=',X2

END IF

! selesai

END