BAB IIIDATA PERENCANAAN

PEMBEBANAN

Bentang Jembatan = 14 m

A Beban Mati2 Pelat = 2 x 0.2 x 2400 = 960 kg/m

Aspal = 2 x 0.05 x 2200 = 220 kg/mKerb = 2 x 0.05 x 1000 = 100 kg/mBeban Sendiri = 1 x 0.4 x 2400 = 960 kg/m +

2240 kg/m

Mn = = 3920 kg.m

B Beban Hidupq = 2.2 t/m = 2200 kg/mp = 12 t = 12000 kgq' = = 0.800 t/m = 800.00 kg/m

k = 1 + 20/(50+16) = 1.313

p' = = 5.727 t = 5727.27 kg/m

Mu = = 73945.45 kg.m

C Beban Trotoirq = = 300 kg/m

Mu = = 7350 kg.m

D AnginP = 150 kg/m

= = 300 kg/m= = 165 kg/m= = 82.5 kg/m= = 1.1 kg/m= = 3.1 kg/m= = 1.1 kg/m

q = = 795.62 kg/m

Mu = = 19492.66 kg.m

E Beban Rem

1/8 x 2240 x 162

1/8*2200*162 + 1/4*5685.95*16

1/8*2200*162

q1

q2

q3

l2

l1

l3

1/8*795.62*162

H = = 1700 kgZ = = 2.9 mMu = H.Z = 4930 kg.m

F DiafragmaP = = 270 kgRa = Rb = = 675 kg

Mmax = (675 x (0.5 x 10)) – (270 x (2.5 x 2.5 + 2.5 x 1.5 + 2.5 x 0.5))

= 1687.5 kg.m

= 111325.61392 kg.m= 1,113,256,139 N.mm

Mtotal

PERHITUNGAN DIAFRAGMA

DATA :

qu = 2200 kg Mu= 111325.6139 kgm1113256139 Nmm

fc' 25 Mpal = 2 m fy 400 Mpa

b = 450 mm2 D 16

d2' = 30mm

d = 1050 mm

d1' = 30mm

6 D 32

As = 4825.4863159 -352263042

As' perlu = -863a = 201.850 mm

Dicoba :Ts x Z As' pakai = 2D16

1,465,519,181

Cek : As' pakai = 402.1As' pakai > As' perlu

> Mu OkOk

f Mn perlu = Mu - f Mn

mm2 f Mn perlu = Nmm2

mm2

f Mn =

Nmm2

mm2

f Mn

Ts = CcAs x fy = 0.85 x fc' x a x b

d - d2'

Ts = As x fy

a

Z = d - 1/2 a

Cs' = As' x fy

Cc = 0.85 x fc' x a x b

BALOK T PERSEGI

Mu = 1,113,256,139

fc' 20 Mpafy 400 Mpa

b eff = 4000 mm

hf =200 mm

850 mm

d' = 30 mm6 D 32

bw = 450 mm

As = 4825.49

a = 28.385 mma < hf

Tinggi balok tekan masuk plat

Ts x Z1599447809 Nmm

Cek :

> MuOk

mm2

f Mn =

f Mn

4.00

Cc = 0.85 x fc' x a x b eff

Ts = As x fy

a

Z = d - 1/2 a

Ts = CcAs x fy = 0.85 x fc' x a x b eff

BALOK T MURNI

Mu = 1113256139 Nmm

fc' 20 Mpafy 400 Mpa

b eff = 4000 mm

hf =200 mm

850 mm

d' = 30 mm6 D 32

bw = 300

Cc1 (d-1/2hf) + Cc2 (d-hf-1/2 (a-hf))

As = 4825.49 13055471773 Nmm

Cek :> Mu

a = 28.385 mm Oka < hf

Tinggi balok tekan masuk plat

Cc1 = 13600000 Nmm

Cc2 = 144764.6 Nmm

f Mn =

mm2

f Mn

1.85

Ts = CcAs x fy = 0.85 x fc' x a x b eff

Cc1 = 0.85 x fc' x hf x b eff

Ts = As x fy

Z1 = d - 1/2 hf

Cc2 = 0.85 x fc' x a x bw

Z2 = d - hf-1/2 (a-hf)

Cc1 = 0.85 x fc' x hf x b eff

Cc2 = 0.85 x fc' x a x bw

PELAT

fc' = 30 Mpafy = 240 Mpa

d = 200d' = 30 mm

mm

b = 5420 mm

Mu = 111325.61392 kgm1113256139 Nmm

Rn = 6.4186816144

m = 9.4117647059

0.0313777433

As =

34013.473757

As pakai = 40 D 1280 D 1260 D 1220 D 12

As pakai = 38453.09408As pakai > As perlu

Ok

Jarak :12 - 135.5 mm

ρ =

ρ* b*d

mm2

mm2