hitung bekisting dan scaffolding

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    Massa jenis beton: 2.4 t/m3

    Ukuran Balok

    Tinggi Lebar Bentang Beban/m P1=P2 P1'=P2'

    m! m! m! t/m! t! t!

    "## $%# 1." 1.24" 2.#22 2.&2

    "## "## 1." 1.%3$ 2.4"" 3.3%

    4## %# 1." #.12 1.4&& 1.%

    $## 14%# 1." 2.#"" 3.3"3 4.%$$

    "## %# 1." 1."24 2.%% 3."

    (eterangan:

    ) = beban merata balok t/m!

    P1= Beban *a+a ,rame -ang +iakibatkan lantai berikutn-a t!

    P2 = Beban *a+a ,rame -ang +iakibatkan lantai berikutn-a t!

    P1'= Beban total *a+a ,rame -ang +iakibatkan lantai berikutn-a t!

    setela lantai UL tela & ari

    P2' = Beban total *a+a ,rame -ang +iakibatkan lantai berikutn-a t!

    BEBAN PADA FRAME SCAFFOLDING PERANCAH BALOK LANTAIUSL

    UkuranBalok

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    BEBAN YANG DITERIMA MAINFRAME SEBAGAI SUPPORT BALOK &

    Berat 0enis Beton = 24## kg/m3

    Beban i+u* = 1## kg/m2

    Beban bekisting = &% kg/m2

    I Beban lantai USL Lb aBeban balok ukuran! = #." #.$%

    +1 = #." #.$% 24## = 124" kg/m

    b Beban *lat lantai tebal! = 1% m

    +2 = 2 3."3&343&% #.1% 24##

    "

    = 34%.3$#4 kg/m

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    Beban i+u* = 1## kg/m2

    L1 = 1## 3."3&343&% 2 = %.33% kg/m

    "

    + Berat bekisting = &% kg/m2 56!

    L2 = &% 3."3&343&% 2 !7 #." 7 2 #.$% ! " !

    "

    = 22.4%#2 kg/m

    e berat total t! = 1.2 +17+2! 7 1.$ L17L2!

    1.2 1%3.3$#4 7 1.$ 32%.3"3"

    = 2432.$4&2 kg/m

    II Beban lantai Main LEVEL Lb Penge!"an # $a"i %etela$ USL i !"a Beban balok ukuran! = #.3 #.&

    +1 = #.3 #.& 24## = %#4 kg/m

    b Beban *lat lantai tebal! = 1% m

    +2 = 2 3."3&343&% #.1% 24##

    "

    = 34%.3$#4 kg/m

    Beban i+u* = 1## kg/m2

    L1 = 1## 3."3&343&% 2 = %.33% kg/m

    "

    +Berat bekisting = #kg/m2 56 5ommitte 34&! tt*://m-blog8al,au9i.blogs*ot.om/2#11/#&/beki

    L2 = # 3."3&343&% 2 !7 #.3 7 2 #.& ! " !

    "= # kg/m

    e berat total t! = 1.2 +17+2! 7 1.$ L17L2!

    1.2 "4.3$#3" 7 1.$ %.33%

    = 11&2.&2$ kg/m

    III Beban Sa'!ling (aa lantai USL %etela$ ) $a"i= #.3% 2432.$4&1 7 #."% 11&2.&2&

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    = 1"4".2444 kg/m

    IV *a"a+ anta" Main,"a-e .ang iingin+an0arak = #.$ m

    beban/m = 1"4".2444 #.$

    = 11#".4$$ kg/m

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    PLAT

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    sting8orisontal.tml!

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    PERHITUNGAN BEBAN YANG DITERIMA MAINFRAME PERANCAH BALOK

    Berat 0enis Beton = 24## kg/m3

    Beban i+u* = 1%# kg/m2

    Beban bekisting = &% kg/m2

    L = 4.#% m

    L- = 12 m

    Lebar Main,rame L.M! = 1.2 m

    La = #;%L8#;%L.M8#;%Lb Luas tra*esium: 12 7 " 8 1.#2% ! #.%12%=

    La = 1.#2% m 2

    I Beban lantai USL Lb a Beban balok ukuran! = #." 1.%

    +1 = #." 1.% 24## = 2""# kg/m

    b Beban *lat lantai tebal! = 1%m

    +2 = 2 4."$2343&% #.1% 24##

    12

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    = 43&.$1#4 kg/m

    Beban i+u* = 1%# kg/m2

    L1 = 1%# 4."$2343&% 2 = 121.%%"$ kg/m

    12

    + Berat bekisting = &%kg/m2 56 5ommitte 34&! tt*://m-blog8al,au9i.blogs*ot.om/2#11/#&/bekisti

    L2 = &% 4."$2343&% 2 !7 #." 7 2 1.% ! 12 !

    12

    = 34%.&&3 kg/m

    e berat total t! = 1.2 +17+2! 7 1.$ L17L2!

    1.2 331&.$1#4 7 1.$ 4$&.33&

    = 4&2"."&3" kg/m

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    II Beban lantai Main LEVEL Lb Penge!"an # $a"i %etela$ USL i !"a Beban balok ukuran! = #." 1.%

    )+1 = #." 1.% 24## = 2""# kg/m

    b Beban *lat lantai tebal! = 1%m

    +2 = 2 4."$2343&% #.1% 24##

    12

    = 43&.$1#4 kg/m

    Beban i+u* = 1%# kg/m2

    L1 = 1%# 4."$2343&% 2 = 121.%%"$ kg/m

    12

    + Berat bekisting = &% kg/m2 56 5ommitte 34&! (http://myblog-alfauzi.blogspot.com/2011/07/bekisti

    L2 = &% 4."$2343&% 2 !7 #." 7 2 1.% ! 12 !

    12

    = 34%.&&3 kg/m

    e berat total t! = 1.2 +17+2! 7 1.$ L17L2!

    1.2 331&.$1#4 7 1.$ 4$&.33&

    = 4&2"."&3" kg/m

    III Beban Sa'!ling (aa lantai USL %etela$ ) $a"i= #.3% 4&2"."&3&% 7 #."% 4&2"."&4

    = %$&4.$4"% kg/m

    IV*a"a+ anta" Main,"a-e .ang iingin+an0arak = #.4% m

    beban/m = %$&4.$4"% #.4%= 2%%3.%1" kg/m

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    Berat 0enis Beton = 24## kg/m3

    Beban i+u* = 1## kg/m2

    Beban bekisting = &% kg/m2

    L = 4.#% m

    < *l-oo+ = 12

    = 1/1# 34%$.&2 #.2#2% = $."%"kg/m'

    b (ekakuan Pl-oo+ = 1/12" t L>4!/

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    II C$e+ +e+a+/an Pl.0!! t = #.#1" ma (ekuatan Pl-oo+ = 1/1# t L>2

    =1/1# &4.&$ #.3$ = 2$.13$kg/m'

    b (ekakuan Pl-oo+ = 1/12" t L>4!/

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    '

    '

    1.$ L1!

    1.$ #.4%

    #.4%> 4

    1/12 #." #.#1" >3

    OK B!11

    '

    '

    1.$ L1!

    1.$ #.$

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    #.$> 4

    1/12 #.4 #.#1" >3

    OK B!11