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CANTILEVER WALL Cantiliver wall : ADRIANI FAK. TEKNIK UNLAM

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  • CANTILEVER WALLCantiliver wall :

    ADRIANI FAK. TEKNIK UNLAM

  • CANTILEVER WALLCantiliver wall seperti gambar dibawah ini :

    Koefesien tekanan tanah :

    Untuk = 10o; = 20o ka = 0,52

    H = 3,5 + 2 tan = 3,5 + 2 tan 10 =3,85 m

    Tekanan tanah aktif :Z=0 m a1 = (1,8 x 0 +2 ) x 0,52 2x0,2

    0,52 = 0,75 t/m/m

    Z=3,85 m a1 = (1,8 x 3,85 +2 ) x 0,52 2x0,2 0,52 = 4,36 t/m/m

    ADRIANI FAK. TEKNIK UNLAM

    q = 2 t/m2

    H1)

    2

    045(tan)

    245(tan 22

    Kp

  • CANTILEVER WALLCantiliver wall seperti gambar dibawah ini :

    Koefesien tekanan tanah :

    Besar tekanan tanah aktif :

    Pa1 = 0,75 x 3,85 =2,89 t/m

    Pa2 = x3,85x(4,36-0,75) = 6,95 t/m

    Pa1v = Pa1 sin = 2,89 x sin 10 = 0,50 t/m

    Pa2v = Pa2 sin = 6,95 x sin 10 = 1,21 t/m

    Pa1h = Pa1 cos = 2,89 x cos 10 = 2,85 t/m

    Pa2h = Pa2 cos = 6,95 x cos 10 = 6,85 t/m

    Ph = Pah1 + Pah2 = 9,70 t/m

    ADRIANI FAK. TEKNIK UNLAM

    q = 2 t/m2

    H

    Pa1

    Pa2

  • CANTILEVER WALLMonen runtuh :Mg1 = Pa1h x H = 2,85 x 3,85/2 = 5,48 tm/mMg2 = Pah2 x H/3 = 6,85 x 3,85/3 = 8,79 tm/mMg = Mg1 + Mg2 = 14,27 tm/m

    Mav1 = Pav1 x B = 0,5 x 3,5 = 1,75 tm/mMav2 = Pav2 x B = 1,21 x 3,5 = 4,24 tm/mTekanan tanah Pasif :Z = 0 m a1=(1,6x0+0)x1 + 2x31 = 6 t/m/mZ = 0,5 m a2=(1,6x0,5+0)x1 + 2x0,231 = 6,8 t/m/mTekanan tanah aktif :Pp1 = 6,0 x 0,5 = 3,0 t/mPp2 = (6,8-6,0) x 0,5/2 = 0,20 t/mPp1 + Pp2 = P = 3,20 t/mMomen Pasif :Mp1 = Pai x h3 = 3 x 0,5/2 = 0,75 tm/mMp2 = Pa2 x h4 = 0,20 x 0,5/3 = 0,03 tm/mMp = Mg1 + Mg2 = 0,75 + 0,04 = 0,78 tm/m

    ADRIANI FAK. TEKNIK UNLAM

  • CANTILEVER WALLBerat cantiliver wall :

    W1 = (1-0,3)x3,0/2 x 2,4 = 2,52 t/m

    W2 = 0,3 x 3 x 2,4 = 2,16 t/m

    W3 = 2 x 3 x 2,4 = 14,40 t/m

    W4 = (3,85-3,5)x2/2x1,8 = 0,63 t/m

    W5 = 3,5x0,4 x 2,4 = 3,36 t/m

    W = W1 + W2 + W3 + W4 + W5 = 23,07 T/M

    Lengan momen thd titik guling :

    B1 = 0,5+2/3X(1-0,3) = 0,97 M

    B2 = 1,5-0,3/2 = 1,35 M

    B3 = 3,5-2/2 =2,5 M

    B4 = 3,5-2/3X2 =2,16 M

    B5 = 3,5/2 = 1,75 M

    ADRIANI FAK. TEKNIK UNLAM

    W1w2

    W3

    W4

    W5 0,4 m

    B1

    B2

    B3

    B4

    B5

  • CANTILEVER WALLMomen tahanan :

    Mt1 = W1 x B1 = 2,52 x 0,97 = 2,44TM/M

    MT2 = W2 x B2 = 2,16 x 1,35 = 2,92 TM/M

    MT3 = W3 x B3 = 14,40 x 2,5 = 36,00 TM/M

    MT4 = w4 x B4 = 0,63 x 2,16 = 1,36 TM/M

    MT5 = w5 x B5 = 3,36 x 1,75 = 5,88 TM/M

    Mav1 = 1,75 tm/m

    Mav2 = 4,24 tm/m

    MT = MT1 + MT2 + MT3 + MT4 + MT5 + Mav1 + Mav2 = 54,59 TM/M

    Kontrol stabilitas :

    a. Guling :

    SF = (MT+Mp)/Mg = (54,59+0,78)/14,27 =

    b. Geser : Aman

    ADRIANI FAK. TEKNIK UNLAM

    40,370,9

    20,3103/25,3)203/2tan(07,23'tan

    x

    P

    PLWS

    a

    p

    f

  • CANTILEVER WALLKontrol stabilitas :

    c. Eksentrisitas :

    4. Daya dukung tanah :Tergangan yang terjadi maks = W/B + 6M/B

    2

    maks = 23,07/3,5 x(1+6x-0,03/3,5) = 24,26 ton/m2

    min = 23,07/3,5 x(1-6x-0,03/3,5) = 21,88 ton/m2

    Daya dukung = qu =

    Untuk q = 0o maka Nc = 5,6 ; Nq = 1 ; N = 0

    qizin = qu/SF =57,80/2 = 28,90 ton/m2> maks = 24,26 ton/m

    2 Aman

    ADRIANI FAK. TEKNIK UNLAM

    62

    L

    W

    MgMtLe

    6

    5,303,0

    07,23

    78,027,1459,54

    2

    5,3

    e

    NBqNNcq qcu2

    1'

    2/80,5706,15,32

    116,15,07,510 mtonqu

  • CANTILEVER WALLKontrl potongan titik kritis :

    Potongan 1-1 :

    1 = 21,88 +(24,26-21,88)/3,5x1,5=22,90 t/m2

    M1-1 = 22,90x2x2/2+x(24,26-22,90)x2x2x2/3-W3 x 2/2 W4 x 2/3 x 2 2 x 2,4 x 2/2 = 22,90x2x2/2+x(24,26-22,90)x2x2x2/3-14,4x2/20,63x 2/3x22x0,4x2,4x2/2 = 30,45 tm/m

    M2-2 = 21,88x0,5x0,5/2+x0,5x(22,90-21,88)x1/3x0,50,5x0,4x2,4x0,5/2 = 2,66 tm/m

    ADRIANI FAK. TEKNIK UNLAM

    1

    12

    2

    33

    21,88

    24,26

  • CANTILEVER WALLKontrl potongan titik kritis :

    Potongan 3-3 :Tekanan tanah aktif :

    Z=0 m a1 = (1,8 x 0 +2 ) x 0,52 2x0,2 0,52 = 0,75 t/m/m

    Z=3,0 m a1 = (1,8 x 3,0 +2 ) x 0,52 2x0,2 0,52 = 3,56 t/m/m

    Besar tekanan tanah aktif :

    Pa1 = 0,75 x 3,0 =2,25 t/m

    Pa2 = x3,0x(3,56-0,75) = 4,22 t/m

    Pa1v = Pa1 sin = 2,25 x sin 10 = 0,39 t/m

    Pa2v = Pa2 sin = 4,22 x sin 10 = 0,73 t/m

    Pa1h = Pa1 cos = 2,25 x cos 10 = 2,22 t/m

    Pa2h = Pa2 cos = 4,22 x cos 10 = 4,16 t/m

    Ph = Pah1 + Pah2 = 6,38 t/m

    Pv = Pav1 + Pav2 = 1,12 t/m

    M3-3 = Pav x 1 + Pah1 x x3 + Pah2 x 1/3 x 3 = 1,12 x 1 + 2,22 x 3/2 + 4,16 x 3/3 = 8,61 tm/m

    ADRIANI FAK. TEKNIK UNLAM

    1

    12

    2

    33

    21,8824,26

    0,75

    3,56

  • CANTILEVER WALLTugas :

    a. Tentukan diagraam tekanantanah

    b. Tentukan besar tekanan tanah

    c. Tentukan besar momen guling

    d. Tentukan besar momen tahanan

    e. Cek Stabilitas terbadap :

    f. Cek Stabilitas terbadap Guling

    g. Cek Stabilitas terbadap Geser

    h. Cek Stabilitas terbadapEksentrisitas

    i. Cek Stabilitas terbadap Dayadukung

    j. Hitung momen pada titik kritis

    ADRIANI FAK. TEKNIK UNLAM

    = 0o