analisis penamp-tul-rangkap.xls

Tugas 2 fix (4)PERHITUNGAN DIMENSI & TULANGAN RANGKAP PADA BALOK0.85Fc'ec' = 0.003Sces'As'-aubCc5551CubAs+es4ST30dia edia sMu =39.8Tm}d =0.5Fc' =250kg/cm2Fy =3200kg/cm2Keadaan BalancePersamaan Deformasi/Kompatibilitas :1.ec'=Cubesd - Cub0.003=Cub0.001651-Cub0.153 = 0.0016 Cub + 0.003 CubCub =33.26cmaub = 0.85 x 33.26 =28.272cmPersamaan statika : bajaSc = As'.Fs' = 0.5 As . Fy =1600AsCc =0.85 Fc'. Aub . B =180234St = As. Fy =3200As1.S H = 0Sc + Cc = ST1600 As + 180234 = 3200 As180234.0=1600AsAsb =112.65cm2As'b =56.33cm2Jadi ,Sc = 56.33 x 3200 =180256.0kgCc =0.85 x 250 x 28.272 x 30 =180234.0kgSt = 112.65 x 3200 =360480.0kg2.S M = 0Sc (d - d') + Cc (d - 0.5au) = MnbMnb = (180256 x (51 - 4)) + (180234 x (51 - (0.5 x28.272)))Mnb =15116178.176kgcmMub = 0.8 x 15116178.176 kgcm=120.929Tm> ... Mu, dimensi balok kuatDesign Tulangan (Under-reinforced)Cu =10cmAu = 0.85Cu = 0.85 x 10 =8.5cmPersamaan Deformasi/Kompatibilitas :1.ec'=Cuec'=10es'Cu - d'es'10 - 40.003=10es'60.018 = 10es'es' =0.0018> 0.0016kg/cm2tulangan tekan sudah leleh,maka Fs' = Fy =3200kg/cm2Persamaan statika : bajaSc = As'.Fs' = 0.5 As x =1600AsCc = 0.85 Fc'. Au . B =54187.5St = As. Fy =3200As1.S H = 0Sc + Cc = ST1600 As + 54187.5 = 3200 As54187.5=1600AsAs =33.87cm2As' =16.94cm2Jadi ,Sc = 16.94 x 3200 =54208.0kgCc = 0.85 x 250 x 8.5 x 30 =54187.5kgSt = 33.87 x 3200 =108384.0kg2.S M = 0Sc (d - d') + Cc (d - 0.5au) = MnbMn = (54208 x (51 - 4)) + (54187.5 x (51 - (0.5 x8.5)))2547776Mn =5081041.63kgcmMu = 0.8 x 5081041.63 kgcm=40.65Tm> Mu, dimensi balok kuatKeadaan Under Reinforce = 0.7 x Asb (max).84.4875diambilAs =33.87cm2As' =16.935cm2Perhitungan tulangan di bawah ini tidak terpakai.Sc =16.9 x 3200 =54192.00kgCc =0.85 x 250 x 8.5 x 30 =54187.50kgSt =33.9 x 3200 =108384.00kgPERSAMAAN :1.S M = 0Sc (d - d') + Cc (d - 0.5au) = MnMn =5080289.63kg cmMu = f MnMu =4064231.70kg cm=40.64Tm > M = 39.8 TmOK, dimensi & tulangan cukupTulangan diameter25, Luas =4.91cm2Tulangan tarik7buahTulangan tekan4buahJadi DipakaiAs =34.37cm2As' =19.64cm2r =0.02246OK, r min < rOK, r < r maxr ' =0.0128366013OK, r min < rOK, r < r maxr tulangan min =0.00455= As min =6.96cm2r tulangan max =0.03035= As max =46.44cm2Dimensi & tulangan terpasang4d257d2555557d254d253030TumpuanLapangan

Tugas 2 fix (3)PERHITUNGAN DIMENSI & TULANGAN RANGKAP PADA BALOK0.85Fc'ec' = 0.003Sces'As'-aubCc5046CubAs+es4ST25dia edia sMu =39.8Tm}d =0.5Fc' =250kg/cm2Fy =3200kg/cm2Keadaan BalancePersamaan Deformasi/Kompatibilitas :1.ec'=Cubesd - Cub0.003=Cub0.001646-Cub0.138 = 0.0016 Cub + 0.003 CubCub =30cmaub = 0.85 x 30 =25.500cmPersamaan statika : bajaSc = As'.Fs' = 0.5 As . Fy =1600AsCc =0.85 Fc'. Aub . B =135468.75St = As. Fy =3200As1.S H = 0Sc + Cc = ST1600 As + 135468.75 = 3200 As135468.8=1600AsAsb =84.67cm2As'b =42.34cm2Jadi ,Sc = 42.34 x 3200 =135488.0kgCc =0.85 x 250 x 25.5 x 25 =135468.8kgSt = 84.67 x 3200 =270944.0kg2.S M = 0Sc (d - d') + Cc (d - 0.5au) = MnbMnb = (135488 x (46 - 4)) + (135468.75 x (46 - (0.5 x25.5)))Mnb =10194831.938kgcmMub = 0.8 x 10194831.938 kgcm=81.559Tm> ... Mu, dimensi balok kuatDesign Tulangan (Under-reinforced)Cu =12cmAu = 0.85Cu = 0.85 x 12 =10.2cmPersamaan Deformasi/Kompatibilitas :1.ec'=Cuec'=12es'Cu - d'es'12 - 40.003=12es'80.024 = 12es'es' =0.0020> 0.0016kg/cm2tulangan tekan sudah leleh,maka Fs' = Fy =3200kg/cm2Persamaan statika : bajaSc = As'.Fs' = 0.5 As x =1600AsCc = 0.85 Fc'. Au . B =54187.5St = As. Fy =3200As1.S H = 0Sc + Cc = ST1600 As + 54187.5 = 3200 As54187.5=1600AsAs =33.87cm2As' =16.94cm2Jadi ,Sc = 16.94 x 3200 =54208.0kgCc = 0.85 x 250 x 10.2 x 25 =54187.5kgSt = 33.87 x 3200 =108384.0kg2.S M = 0Sc (d - d') + Cc (d - 0.5au) = MnbMn = (54208 x (46 - 4)) + (54187.5 x (46 - (0.5 x10.2)))2276736Mn =4493004.75kgcmMu = 0.8 x 4493004.75 kgcm=35.94TmNOT OKKeadaan Under Reinforce = 0.7 x Asb (max).63.5025diambilAs =33.87cm2As' =16.935cm2Perhitungan tulangan di bawah ini tidak terpakai.Sc =16.9 x 3200 =54192.00kgCc =0.85 x 250 x 10.2 x 25 =54187.50kgSt =33.9 x 3200 =108384.00kgPERSAMAAN :1.S M = 0Sc (d - d') + Cc (d - 0.5au) = MnMn =4492332.75kg cmMu = f MnMu =3593866.20kg cm=35.94Tm > M = 39.8 TmNOT OK, As diperbesar, tp max 0.7 AsbTulangan diameter25, Luas =4.91cm2Tulangan tarik7buahTulangan tekan4buahJadi DipakaiAs =34.37cm2As' =19.64cm2r =0.02989OK, r min < rOK, r < r maxr ' =0.0170782609OK, r min < rOK, r < r maxr tulangan min =0.00455= As min =5.23cm2r tulangan max =0.03035= As max =34.90cm2Dimensi & tulangan terpasang4d257d2550507d254d252525TumpuanLapangan

Tugas 2 fix (2)PERHITUNGAN DIMENSI & TULANGAN RANGKAP PADA BALOK0.85Fc'ec' = 0.003Sces'As'-aubCc6056CubAs+es4ST30dia edia sMu =39.8Tm}d =0.5Fc' =250kg/cm2Fy =3200kg/cm2Keadaan BalancePersamaan Deformasi/Kompatibilitas :1.ec'=Cubesd - Cub0.003=Cub0.001656-Cub0.168 = 0.0016 Cub + 0.003 CubCub =36.52cmaub = 0.85 x 36.52 =31.043cmPersamaan statika : bajaSc = As'.Fs' = 0.5 As . Fy =1600AsCc =0.85 Fc'. Aub . B =197899.125St = As. Fy =3200As1.S H = 0Sc + Cc = ST1600 As + 197899.125 = 3200 As197899.1=1600AsAsb =123.69cm2As'b =61.85cm2Jadi ,Sc = 61.85 x 3200 =197920.0kgCc =0.85 x 250 x 31.043 x 30 =197899.1kgSt = 123.69 x 3200 =395808.0kg2.S M = 0Sc (d - d') + Cc (d - 0.5au) = MnbMnb = (197920 x (56 - 4)) + (197899.125 x (56 - (0.5 x31.043)))Mnb =18302499.731kgcmMub = 0.8 x 18302499.731 kgcm=146.420Tm> ... Mu, dimensi balok kuatDesign Tulangan (Under-reinforced)Cu =9cmAu = 0.85Cu = 0.85 x 9 =7.65cmPersamaan Deformasi/Kompatibilitas :1.ec'=Cuec'=9es'Cu - d'es'9 - 40.003=9es'50.015 = 9es'es' =0.0017> 0.0016kg/cm2tulangan tekan sudah leleh,maka Fs' = Fy =3200kg/cm2Persamaan statika : bajaSc = As'.Fs' = 0.5 As x =1600AsCc = 0.85 Fc'. Au . B =48768.75St = As. Fy =3200As1.S H = 0Sc + Cc = ST1600 As + 48768.75 = 3200 As48768.75=1600AsAs =30.48cm2As' =15.24cm2Jadi ,Sc = 15.24 x 3200 =48768.0kgCc = 0.85 x 250 x 7.65 x 30 =48768.8kgSt = 30.48 x 3200 =97536.0kg2.S M = 0Sc (d - d') + Cc (d - 0.5au) = MnbMn = (48768 x (56 - 4)) + (48768.75 x (56 - (0.5 x7.65)))2535936Mn =5080445.53kgcmMu = 0.8 x 5080445.53 kgcm=40.64Tm> Mu, dimensi balok kuatKeadaan Under Reinforce = 0.7 x Asb (max).92.7675diambilAs =30.48cm2As' =15.24cm2Perhitungan tulangan di bawah ini tidak terpakai.Sc =15.2 x 3200 =48768.00kgCc =0.85 x 250 x 7.65 x 30 =48768.75kgSt =30.5 x 3200 =97536.00kgPERSAMAAN :1.S M = 0Sc (d - d') + Cc (d - 0.5au) = MnMn =5080445.53kg cmMu = f MnMu =4064356.43kg cm=40.64Tm > M = 39.8 TmOK, dimensi & tulangan cukupTulangan diameter25, Luas =4.91cm2Tulangan tarik7buahTulangan tekan4buahJadi DipakaiAs =34.37cm2As' =19.64cm2r =0.02046OK, r min < rOK, r < r maxr ' =0.0116904762OK, r min < rOK, r < r maxr tulangan min =0.00455= As min =7.64cm2r tulangan max =0.03035= As max =50.99cm2Dimensi & tulangan terpasang4d257d2560607d254d253030TumpuanLapangan

Balok 25x50PERHITUNGAN DIMENSI & TULANGAN RANGKAP PADA BALOKNama :SHOLIK KRISTIANTONIM :411071200460.85Fc'ec' = 0.003Sces'As'-aubCc4035CubAs+es5ST30dia edia sMu =34.56Tm}d =0.5Fc' =250kg/cm2Fy =2400kg/cm2Keadaan BalancePersamaan Deformasi/Kompatibilitas :1.ec'=Cubesd - Cub0.003=Cub0.001235-Cub0.105 = 0.0012 Cub + 0.003 CubCub =25cmaub = 0.85 x 25 =21.250cmPersamaan statika : bajaSc = As'.Fs' = 0.5 As . Fy =1200AsCc =0.85 Fc'. Aub . B =135468.75St = As. Fy =2400As1.S H = 0Sc + Cc = ST1200 As + 135468.75 = 2400 As135468.8=1200AsAsb =112.89cm2As'b =56.45cm2Jadi ,Sc = 56.45 x 2400 =135480.0kgCc =0.85 x 250 x 21.25 x 30 =135468.8kgSt = 112.89 x 2400 =270936.0kg2.S M = 0Sc (d - d') + Cc (d - 0.5au) = MnbMnb = (135480 x (35 - 5)) + (135468.75 x (35 - (0.5 x21.25)))Mnb =7366450.781kgcmMub = 0.8 x 7366450.781 kgcm=58.932Tm> ... Mu, dimensi balok kuatDesign Tulangan (Under-reinforced)Cu =8cmAu = 0.85Cu = 0.85 x 8 =6.8cmPersamaan Deformasi/Kompatibilitas :1.ec'=Cuec'=8es'Cu - d'es'8 - 50.003=8es'30.009 = 8es'es' =0.0011> 0.0012kg/cm2karena tulangan tekan belum leleh,maka Fs'=4000kg/cm2Persamaan statika : bajaSc = As'.Fs' = 0.5 As x =2000AsCc = 0.85 Fc'. Au . B =43350St = As. Fy =2400As1.S H = 0Sc + Cc = ST2000 As + 43350 = 2400 As43350=400AsAs =108.38cm2As' =54.19cm2Jadi ,Sc = 54.19 x 4000 =216760.0kgCc = 0.85 x 250 x 6.8 x 30 =43350.0kgSt = 108.38 x 2400 =260112.0kg2.S M = 0Sc (d - d') + Cc (d - 0.5au) = MnbMn = (216760 x (35 - 5)) + (43350 x (35 - (0.5 x6.8)))6502800Mn =7872660kgcmMu = 0.8 x 7872660 kgcm=62.98Tm> Mu, dimensi balok kuatKeadaan Under Reinforce : As.maks < 0.7 x Asb (max).84.6675diambilAs =108.38cm2As' =54.19cm2Perhitungan tulangan di bawah ini tidak terpakai.Sc =54.2 x 4000 =216760.00kgCc =0.85 x 250 x 6.8 x 30 =43350.00kgSt =108.4 x 2400 =260112.00kgPERSAMAAN :1.S M = 0Sc (d - d') + Cc (d - 0.5au) = MnMn =7872660.00kg cmMu = f MnMu =6298128.00kg cm=62.98Tm > M = 34.56 TmOK, dimensi & tulangan cukupTulangan diameter25, Luas =4.91cm2Tulangan tarik23buahTulangan tekan12buahJadi DipakaiAs =112.93cm2As' =58.92cm2r =0.10755OK, r min < rNOT OKr ' =0.0561142857OK, r min < r 'NOT OKr tulangan min =0.00210r tulangan max =0.02440Dimensi & tulangan terpasang12d254023d2530LapanganTumpuan

&L&F&CPage &P Of &N&R&A

Balok 30x55PERHITUNGAN DIMENSI & TULANGAN RANGKAP PADA BALOKNama :SHOLIK KRISTIANTONIM :411071200460.85Fc'ec' = 0.003Sces'As'-aubCc5551CubAs+es4ST30dia edia sMu =39.8Tm}d =0.5Fc' =250kg/cm2Fy =3200kg/cm2Keadaan BalancePersamaan Deformasi/Kompatibilitas :1.ec'=Cubesd - Cub0.003=Cub0.001651-Cub0.153 = 0.0016 Cub + 0.003 CubCub =33.26cmaub = 0.85 x 33.26 =28.272cmPersamaan statika : bajaSc = As'.Fs' = 0.5 As . Fy =1600AsCc =0.85 Fc'. Aub . B =180234St = As. Fy =3200As1.S H = 0Sc + Cc = ST1600 As + 180234 = 3200 As180234.0=1600AsAsb =112.65cm2As'b =56.33cm2Jadi ,Sc = 56.33 x 3200 =180256.0kgCc =0.85 x 250 x 28.272 x 30 =180234.0kgSt = 112.65 x 3200 =360480.0kg2.S M = 0Sc (d - d') + Cc (d - 0.5au) = MnbMnb = (180256 x (51 - 4)) + (180234 x (51 - (0.5 x28.272)))Mnb =15116178.176kgcmMub = 0.8 x 15116178.176 kgcm=120.929Tm> ... Mu, dimensi balok kuatDesign Tulangan (Under-reinforced)Cu =10cmAu = 0.85Cu = 0.85 x 10 =8.5cmPersamaan Deformasi/Kompatibilitas :1.ec'=Cuec'=10es'Cu - d'es'10 - 40.003=10es'60.018 = 10es'es' =0.0018> 0.0016kg/cm2tulangan tekan sudah leleh,maka Fs' = Fy =3200kg/cm2Persamaan statika : bajaSc = As'.Fs' = 0.5 As x =1600AsCc = 0.85 Fc'. Au . B =54187.5St = As. Fy =3200As1.S H = 0Sc + Cc = ST1600 As + 54187.5 = 3200 As54187.5=1600AsAs =33.87cm2As' =16.94cm2Jadi ,Sc = 16.94 x 3200 =54208.0kgCc = 0.85 x 250 x 8.5 x 30 =54187.5kgSt = 33.87 x 3200 =108384.0kg2.S M = 0Sc (d - d') + Cc (d - 0.5au) = MnbMn = (54208 x (51 - 4)) + (54187.5 x (51 - (0.5 x8.5)))2547776Mn =5081041.63kgcmMu = 0.8 x 5081041.63 kgcm=40.65Tm> Mu, dimensi balok kuatKeadaan Under Reinforce = 0.7 x Asb (max).84.4875diambilAs =33.87cm2As' =16.935cm2Perhitungan tulangan di bawah ini tidak terpakai.Sc =16.9 x 3200 =54192.00kgCc =0.85 x 250 x 8.5 x 30 =54187.50kgSt =33.9 x 3200 =108384.00kgPERSAMAAN :1.S M = 0Sc (d - d') + Cc (d - 0.5au) = MnMn =5080289.63kg cmMu = f MnMu =4064231.70kg cm=40.64Tm > M = 39.8 TmOK, dimensi & tulangan cukupTulangan diameter25, Luas =4.91cm2Tulangan tarik7buahTulangan tekan4buahJadi DipakaiAs =34.37cm2As' =19.64cm2r =0.02246OK, r min < rOK, r < r maxr ' =0.0128366013OK, r min < r 'OK, r '< r maxr tulangan min =0.00455r tulangan max =0.03035Dimensi & tulangan terpasang4d25557d2530TumpuanLapangan


Balok 30x60PERHITUNGAN DIMENSI & TULANGAN RANGKAP PADA BALOKNama :SHOLIK KRISTIANTONIM :411071200460.85Fc'ec' = 0.003Sces'As'-aubCc6056CubAs+es4ST30dia edia sMu =39.8Tm}d =0.5Fc' =250kg/cm2Fy =3200kg/cm2Keadaan BalancePersamaan Deformasi/Kompatibilitas :1.ec'=Cubesd - Cub0.003=Cub0.001656-Cub0.168 = 0.0016 Cub + 0.003 CubCub =36.52cmaub = 0.85 x 36.52 =31.043cmPersamaan statika : bajaSc = As'.Fs' = 0.5 As . Fy =1600AsCc =0.85 Fc'. Aub . B =197899.125St = As. Fy =3200As1.S H = 0Sc + Cc = ST1600 As + 197899.125 = 3200 As197899.1=1600AsAsb =123.69cm2As'b =61.85cm2Jadi ,Sc = 61.85 x 3200 =197920.0kgCc =0.85 x 250 x 31.043 x 30 =197899.1kgSt = 123.69 x 3200 =395808.0kg2.S M = 0Sc (d - d') + Cc (d - 0.5au) = MnbMnb = (197920 x (56 - 4)) + (197899.125 x (56 - (0.5 x31.043)))Mnb =18302499.731kgcmMub = 0.8 x 18302499.731 kgcm=146.420Tm> ... Mu, dimensi balok kuatDesign Tulangan (Under-reinforced)Cu =9cmAu = 0.85Cu = 0.85 x 9 =7.65cmPersamaan Deformasi/Kompatibilitas :1.ec'=Cuec'=9es'Cu - d'es'9 - 40.003=9es'50.015 = 9es'es' =0.0017> 0.0016kg/cm2tulangan tekan sudah leleh,maka Fs' = Fy =3200kg/cm2Persamaan statika : bajaSc = As'.Fs' = 0.5 As x =1600AsCc = 0.85 Fc'. Au . B =48768.75St = As. Fy =3200As1.S H = 0Sc + Cc = ST1600 As + 48768.75 = 3200 As48768.75=1600AsAs =30.48cm2As' =15.24cm2Jadi ,Sc = 15.24 x 3200 =48768.0kgCc = 0.85 x 250 x 7.65 x 30 =48768.8kgSt = 30.48 x 3200 =97536.0kg2.S M = 0Sc (d - d') + Cc (d - 0.5au) = MnbMn = (48768 x (56 - 4)) + (48768.75 x (56 - (0.5 x7.65)))2535936Mn =5080445.53kgcmMu = 0.8 x 5080445.53 kgcm=40.64Tm> Mu, dimensi balok kuatKeadaan Under Reinforce = 0.7 x Asb (max).92.7675diambilAs =30.48cm2As' =15.24cm2Perhitungan tulangan di bawah ini tidak terpakai.Sc =15.2 x 3200 =48768.00kgCc =0.85 x 250 x 7.65 x 30 =48768.75kgSt =30.5 x 3200 =97536.00kgPERSAMAAN :1.S M = 0Sc (d - d') + Cc (d - 0.5au) = MnMn =5080445.53kg cmMu = f MnMu =4064356.43kg cm=40.64Tm > M = 39.8 TmOK, dimensi & tulangan cukupTulangan diameter25, Luas =4.91cm2Tulangan tarik7buahTulangan tekan4buahJadi DipakaiAs =34.37cm2As' =19.64cm2r =0.02046OK, r min < rOK, r < r maxr ' =0.0116904762OK, r min < r 'OK, r '< r maxr tulangan min =0.00455r tulangan max =0.03035Dimensi & tulangan terpasang4d25607d2530TumpuanLapangan


Balok 35x70PERHITUNGAN DIMENSI & TULANGAN RANGKAP PADA BALOKNama :SHOLIK KRISTIANTONIM :411071200460.85Fc'ec' = 0.003Sces'As'-aubCc5045CubAs+es5ST25dia edia sMu =34.56Tm}d =0.5Fc' =300kg/cm2Fy =4000kg/cm2Keadaan BalancePersamaan Deformasi/Kompatibilitas :1.ec'=Cubesd - Cub0.003=Cub0.002045-Cub0.135 = 0.002 Cub + 0.003 CubCub =27cmaub = 0.85 x 27 =22.950cmPersamaan statika : bajaSc = As'.Fs' = 0.5 As . Fy =2000AsCc =0.85 Fc'. Aub . B =146306.25St = As. Fy =4000As1.S H = 0Sc + Cc = ST2000 As + 146306.25 = 4000 As146306.3=2000AsAsb =73.15cm2As'b =36.58cm2Jadi ,Sc = 36.58 x 4000 =146320.0kgCc =0.85 x 300 x 22.95 x 25 =146306.3kgSt = 73.15 x 4000 =292600.0kg2.S M = 0Sc (d - d') + Cc (d - 0.5au) = MnbMnb = (146320 x (45 - 5)) + (146306.25 x (45 - (0.5 x22.95)))Mnb =10757717.031kgcmMub = 0.8 x 10757717.031 kgcm=86.062Tm> ... Mu, dimensi balok kuatDesign Tulangan (Under-reinforced)Cu =20cmAu = 0.85Cu = 0.85 x 20 =17cmPersamaan Deformasi/Kompatibilitas :1.ec'=Cuec'=20es'Cu - d'es'20 - 50.003=20es'150.045 = 20es'es' =0.0023> 0.002kg/cm2tulangan tekan sudah leleh,maka Fs' = Fy =2600kg/cm2Persamaan statika : bajaSc = As'.Fs' = 0.5 As x =1300AsCc = 0.85 Fc'. Au . B =108375St = As. Fy =4000As1.S H = 0Sc + Cc = ST1300 As + 108375 = 4000 As108375=2700AsAs =40.14cm2As' =20.07cm2Jadi ,Sc = 20.07 x 2600 =52182.0kgCc = 0.85 x 300 x 17 x 25 =108375.0kgSt = 40.14 x 4000 =160560.0kg2.S M = 0Sc (d - d') + Cc (d - 0.5au) = MnbMn = (52182 x (45 - 5)) + (108375 x (45 - (0.5 x17)))2087280Mn =6042967.5kgcmMu = 0.8 x 6042967.5 kgcm=48.34Tm> Mu, dimensi balok kuatKeadaan Under Reinforce = 0.7 x Asb (max).54.8625diambilAs =40.14cm2As' =20.07cm2Perhitungan tulangan di bawah ini tidak terpakai.Sc =20.1 x 2600 =52182.00kgCc =0.85 x 300 x 17 x 25 =108375.00kgSt =40.1 x 4000 =160560.00kgPERSAMAAN :1.S M = 0Sc (d - d') + Cc (d - 0.5au) = MnMn =6042967.50kg cmMu = f MnMu =4834374.00kg cm=48.34Tm > M = 34.56 TmOK, dimensi & tulangan cukupTulangan diameter22, Luas =3.8cm2Tulangan tarik11buahTulangan tekan6buahJadi DipakaiAs =41.8cm2As' =22.8cm2r =0.03716OK, r min < rNOT OKr ' =0.0202666667OK, r min < r 'OK, r '< r maxr tulangan min =0.00210r tulangan max =0.02440Dimensi & tulangan terpasang6d225011d2225TumpuanLapangan


balok tul rangkap2 (Tugas 2)PERHITUNGAN DIMENSI & TULANGAN RANGKAP PADA BALOK0.85Fc'ec' = 0.003Sces'As'-aubCc6056CubAs+es4ST30dia edia sMu =39.8Tm}d =0.5Fc' =250kg/cm2Fy =3200kg/cm2Keadaan BalancePersamaan Deformasi/Kompatibilitas :1.ec'=Cubesd - Cub0.003=Cub0.001656-Cub0.168 = 0.0016 Cub + 0.003 CubCub =36.52cmaub = 0.85 x 36.52 =31.043cmPersamaan statika : bajaSc = As'.Fs' = 0.5 As . Fy =1600AsCc =0.85 Fc'. Aub . B =197899.125St = As. Fy =3200As1.S H = 0Sc + Cc = ST1600 As + 197899.125 = 3200 As197899.125=1600AsAsb =123.69cm2As'b =61.85cm2Jadi ,Sc = 61.85 x 3200 =197920.0kgCc =0.85 x 250 x 31.043 x 30 =197899.1kgSt = 123.69 x 3200 =395808.0kg2.S M = 0Sc (d - d') + Cc (d - 0.5au) = MnbMnb = (197920 x (56 - 4)) + (197899.125 x (56 - (0.5 x31.043)))Mnb =18302499.731kgcmMub = 0.8 x 18302499.731 kgcm=146.420Tm> ... Mu, dimensi balok kuatDesign Tulangan (Under-reinforced)Cu =9cmAu = 0.85Cu = 0.85 x 9 =7.65cmPersamaan Deformasi/Kompatibilitas :1.ec'=Cuec'=9es'Cu - d'es'9 - 40.003=9es'50.015 = 9es'es' =0.0017> 0.0016kg/cm2tulangan tekan sudah leleh,maka Fs' = Fy =3200kg/cm2Persamaan statika : bajaSc = As'.Fs' = 0.5 As x =1600AsCc = 0.85 Fc'. Au . B =48768.75St = As. Fy =3200As1.S H = 0Sc + Cc = ST1600 As + 48768.75 = 3200 As48768.75=1600AsAs =30.48cm2As' =15.24cm2Jadi ,Sc = 15.24 x 3200 =48768.0kgCc = 0.85 x 250 x 7.65 x 30 =48768.8kgSt = 30.48 x 3200 =97536.0kg2.S M = 0Sc (d - d') + Cc (d - 0.5au) = MnbMn = (48768 x (56 - 4)) + (48768.75 x (56 - (0.5 x7.65)))2535936Mn =5080445.53kgcmMu = 0.8 x 5080445.53 kgcm=40.64Tm> Mu, dimensi balok kuatKeadaan Under Reinforce = 0.7 x Asb (max).92.7675diambilAs =30.48cm2As' =15.24cm2Perhitungan tulangan di bawah ini tidak terpakai.Sc =15.2 x 3200 =48768.00kgCc =0.85 x 250 x 7.65 x 30 =48768.75kgSt =30.5 x 3200 =97536.00kgPERSAMAAN :1.S M = 0Sc (d - d') + Cc (d - 0.5au) = MnMn =5080445.53kg cmMu = f MnMu =4064356.43kg cm=40.64Tm > M = 39.8 TmOK, dimensi & tulangan cukupTulangan diameter25, Luas =4.91cm2Tulangan tarik7buahTulangan tekan4buahJadi DipakaiAs =34.37cm2As' =19.64cm2r =0.02046NOT OKr ' =0.0116904762NOT OKr tulangan min =0.00455= As min =7.64cm2r tulangan max =0.03035= As max =50.99cm2Dimensi & tulangan terpasang4d257d2560607d254d253030TumpuanLapangan

balok tul rangkap2PERHITUNGAN DIMENSI & TULANGAN RANGKAP PADA BALOK0.85Fc'ec' = 0.003Sces'As'-aubCc4035CubAs+Mnbes5ST30dia edia sMu =6.48Tm}d =0.5Fc' =300kg/cm2Fy =2400kg/cm2Keadaan BalancePersamaan Deformasi/Kompatibilitas :1.ec'=Cubesd - Cub0.003=Cub0.001235-Cub0.105 = 0.0012 Cub + 0.003 CubCub =25cmaub = 0.85 x 25 =21.250cmPersamaan statika :Sc = As'.Fs' = 0.5 As . Fy =1200As(tul. Tekan sudah leleh)Cc =0.85 Fc'. Aub . B =162562.5St = As. Fy =2400As1.S H = 0Sc + Cc = ST1200 As + 162562.5 = 2400 As162562.5=1200AsAsb =135.47cm2As'b =67.74cm2Jadi ,Sc = 67.74 x 2400 =162576.0kgCc =0.85 x 300 x 21.25 x 30 =162562.5kgSt = 135.47 x 2400 =325128.0kg2.S M 2= 0Sc (d - d') + Cc (d - 0.5au) = MnbMnb = (162576 x (35 - 5)) + (162562.5 x (35 - (0.5 x21.25)))Mnb =8839740.938kgcmMub = 0.8 x 8839740.938 kgcm=70.718Tm> ... Mu, dimensi balok kuatDesign Tulangan (Under-reinforced)COBA 1:Cu =9cmAu = 0.85Cu = 0.85 x 9 =7.65cmPersamaan Deformasi/Kompatibilitas :1.ec'=Cuec'=9es'Cu - d'es'9 - 50.003=9es'40.012 = 9es'es' =0.0013> 0.0012kg/cm2tulangan tekan sudah leleh,maka Fs' = Fy =2400kg/cm2Persamaan statika :Sc = As'.Fs' = 0.5 As x fy =1200AsCc = 0.85 Fc'. Au . B =58522.5St = As. Fy =2400As1.S H = 0Sc + Cc = ST1200 As + 58522.5 = 2400 As58522.5=1200AsAs =48.77cm2As' =24.39cm2Jadi ,Sc = 24.39 x 2400 =58536.0kgCc = 0.85 x 300 x 7.65 x 30 =58522.5kgSt = 48.77 x 2400 =117048.0kg2.S M = 0Sc (d - d') + Cc (d - 0.5au) = MnMn = (58536 x (35 - 5)) + (58522.5 x (35 - (0.5 x7.65)))1756080Mn =3580518.94kgcmMu = 0.8 x 3580518.94 kgcm=28.64Tm> Mu, dimensi balok kuatKeadaan Under Reinforce = 0.7 x Asb (max).101.6025diambilAs =48.77cm20As' =24.385cm2Perhitungan tulangan di bawah ini tidak terpakai.Sc =24.4 x 2400 =58524.00kgCc =0.85 x 300 x 7.65 x 30 =58522.50kgSt =48.8 x 2400 =117048.00kgPERSAMAAN :1.S M = 0Sc (d - d') + Cc (d - 0.5au) = MnMn =3580158.94kg cmMu = f MnMu =2864127.15kg cm=28.64Tm > M = 6.48 TmOK, dimensi & tulangan cukupTulangan diameter28, Luas =6.15cm2Tulangan tarik8buah49.248.77Tulangan tekan4buah24.6r =0.046447619r tulangan min =0,0058= As min =0.00cm2dilihat tabel pmin dan pmaks di fcr tulangan max =0.04840= As max =58.08cm2Dimensi & tulangan terpasang4d288d2840408d284d283030TumpuanLapangan

Sheet1TUGAS ; TULANGAN LENTUR DAN SENGKANGPLDiketahui ;qDfc'=300Kg/cm2fy =400Kg/cm2PL=1.2tABqd =1.2t/m'qL =0.8t/m'8Ditanya :Desain Balok Optimum (Dimensi Balok dan Tulangan) !PENYELESAIAN ;0.85Fc'ec' = 0.003Sces'As'-aubCc0.350.3CubAs+Mnbes0.05ST0.2dia edia sBeban diatas dua tumpuan h min =L=81616=0.5mambil H =3.5mmb = 0,5 x hb = 0.5 x 0.35 =1.75mBerat Balok Sendiri =h x b x bj beton=0.350.224=1.68Kn/mqu =1,2 x qd + 1,6 qd=4.736t/m'Pu =1,6 x PL=1.92Mu =4.48tonHitung luas tulangan yang dibutuhkan :# asumsi tulangan 2 lapisd = h + 90d = 0.35 + 0.9 =1.25mMu=4.48b x d0.2 x 0.3=2.4888888889

balok tul rangkap2 (2)PERHITUNGAN DIMENSI & TULANGAN RANGKAP PADA BALOK0.85Fc'ec' = 0.003Sces'As'-aubCc8075CubAs+Mnbes5ST40dia edia sMu =26.5464Tm}d =0.5Fc' =300kg/cm2Fy =3200kg/cm2Keadaan BalancePersamaan Deformasi/Kompatibilitas :1.ec'=Cubesd - Cub0.003=Cub0.001675-Cub0.225 = 0.0016 Cub + 0.003 CubCub =48.91cmaub = 0.85 x 48.91 =41.576cmPersamaan statika :Sc = As'.Fs' = 0.5 As . Fy =1600As(tul. Tekan sudah leleh)Cc =0.85 Fc'. Aub . B =424075.2St = As. Fy =3200As1.S H = 0Sc + Cc = ST1600 As + 424075.2 = 3200 As424075.2=1600AsAsb =265.05cm2As'b =132.53cm2Jadi ,Sc = 132.53 x 3200 =424096.0kgCc =0.85 x 300 x 41.576 x 40 =424075.2kgSt = 265.05 x 3200 =848160.0kg2.S M 2= 0Sc (d - d') + Cc (d - 0.5au) = MnbMnb = (424096 x (75 - 5)) + (424075.2 x (75 - (0.5 x41.576)))Mnb =52676684.742kgcmMub = 0.8 x 52676684.742 kgcm=421.413Tm> ... Mu, dimensi balok kuatDesign Tulangan (Under-reinforced)COBA 1:Cu =20cmAu = 0.85Cu = 0.85 x 20 =17cmPersamaan Deformasi/Kompatibilitas :1.ec'=Cuec'=20es'Cu - d'es'20 - 50.003=20es'150.045 = 20es'es' =0.0023> 0.0016kg/cm2tulangan tekan sudah leleh,maka Fs' = Fy =3200kg/cm2Persamaan statika :Sc = As'.Fs' = 0.5 As x fy =1600AsCc = 0.85 Fc'. Au . B =173400St = As. Fy =3200As1.S H = 0Sc + Cc = ST1600 As + 173400 = 3200 As173400=1600AsAs =108.38cm2As' =54.19cm2Jadi ,Sc = 54.19 x 3200 =173408.0kgCc = 0.85 x 300 x 17 x 40 =173400.0kgSt = 108.38 x 3200 =346816.0kg2.S M = 0Sc (d - d') + Cc (d - 0.5au) = MnMn = (173408 x (75 - 5)) + (173400 x (75 - (0.5 x17)))12138560Mn =23669660kgcmMu = 0.8 x 23669660 kgcm=189.36Tm> Mu, dimensi balok kuatKeadaan Under Reinforce = 0.7 x Asb (max).198.7875diambilAs =108.38cm2OK, As max < As < As min0.4089039804 M = 26.5464 TmOK, dimensi & tulangan cukupTulangan diameter36, Luas =10.17cm2Tulangan tarik11buah111.87108.38Tulangan tekan6buah61.02r =0.0361266667r tulangan min =0.0028= As min =8.96cm2dilihat tabel pmin dan pmaks di fcr tulangan max =0.03640= As max =116.48cm2Dimensi & tulangan terpasang6d3611d36808011d366d364040TumpuanLapangan

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