tikungan husnul
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Perencanaan Jalan
1. Trase (garis arah)2. Menetukan koordinat
Langkah - langkah pencarian koordinat
1. Titik A : = 59 ! 1"#9 (25) atau
= $% - "9 (25) =
: = $1 - "9 (25) =
= $5 ! "$ (25) =
: = $% ! 1 (25) =
= $$ - "95 (25) =
: = $5 ! 1"$# (25) =
= $& - 1 (25) =
: = $& ! 1"&' (25) =
= $' ! "& (25) =
%. Menetukan arak
=
= 19$& . $ ! 5$# $.25= 2&5.'2
=
= %9 $.25 ! 11'2$.5$25= 225.#$
=
= & &5$ ! 2$2$.5$25= 2& .'9
=
= #1#12.25 ! 2 % $.25= 2#'.#%
* A+ A
2. Titik , 1 * 1+ 1
%. Titik , 2 * 2+ 2
#. Titik , % * %+ %
5. Titik , *
+
d A / , 1
d , 1 / , 2
d , 2 / , %
d , % /
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Tc = 5$"& 2 )c = #"
c = 11T 2
3a)4ar Lengkun
Ls6 = 5 )
7u)4u8alan
en= -29
%:# Ls6
T 2
1 :# Ls6
-29 -29
-29%"559
Lengku ng pe ralihan
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1'0Tc = 5$"& 2 )c = #" #$% )
c = 112"##' ) T 2
3a)4ar Lengkung ull ircle , 2
Ls6 = 5 )
Lc = 112.##' )
4un
= -29
%:# Ls6 %:# Ls6
Ls6 = 5 )
1:# Ls6
T 2 T 2
1 :# Ls6
-29
-29%"559
Lengku ng peralihan Lengkung peralihanagian Lengkung
5"#9
;iagra) super ele
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4.
= arc tan-
± arc tan-
- -
= arc tan6077.5 - 5937.25
± arc tan6275 -
6515 - 6277.5 6623.75 -
= arc tan 0.5905263 ± arc tan 1.8161
= 30.5630 ± 61.1614
= 91.7243 ° (+)= -30.5984 ° (-)
= arc tan - ± arc tan -- -
= arc tan6275 - 6077.5
± arc tan6541 -
6623.75 - 6515 6675 -
= arc tan 1.816092 ± arc tan 5.1902= 61.1614 ± 79.0945
= 140.256 ° (+)= -17.9331 ° (-)
= arc tan-
± arc tan-
- -
= arc tan6541 - 6275
± arc tan6744.5 -
6675 - 6623.75 6817.5 -
= arc tan 5.1902439 ± arc tan 1.4281= 79.0945 ± 54.9985
= 134.093 ° (+)= 24.0960 ° (-)
Menentukan Sudut Putar ( )
P! 1" 1 " # " 2$ 1 $ # $ 2
P! 2 "2 " 1 " 3
$ 2 $ 1 $ 3
P! 3" 3 " 2 " %$ 3 $ 2 $ %
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6077.56515
62756623.75
65416675
" 1$ 1
" 2$ 2
" 3$ 3
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;irencanakan Lengkungan ull ircle ( )
;ata-data perencanaanlasi>ikasi alan = olektor
? = 1' ⁰
ecepatan rencana (@ ) = $ k aLe4ar alan = &.Le4ar 4ahu = 1.5
in = %5 rencana = %5'
B aC = . 5# Ta4el #.&Ls = 5 Ta4el #.&
Tc = c D tan D? 2 == 5$.& 2
c = Tc D tan (? #)= 5$"& 2 C tan #"5= #.#$%
Lc == . 1 C 1' C %5'
= 112.##'
7Earat untuk lengkungan ontrol =
= 112.##' F 11%.# %259 Gke
Lengkungan Horizontal II (PI 2)
%5' & tan 9
. 1 C ' C c
Lc F 2 & c
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Menggunakan lengkung 4usur lingkaran d
;ata-data perencanaanlasi>ikasi alan =
? =ecepatan rencana (@ ) =
Le4ar alan =Le4ar 4ahu =
in = rencana =
B aC =Ls =
H esar sudut spiral* == 5 C 9 %.1# C 2 5= $.991
H esar sudut pusar lingkaran== % "$ - 2($"991)= 1$.$1' ⁰
H,an ang Lengkung ircleLc =
= 1$"5$' %$ C 2 C%.1= 59.#29
L = Lc ! 2 Ls= 59"25 ! 2 C 5= 159.#29
, === 2. %252 %252 -= .5 '
k = Ls - (LsI% # C cI= 5 -= 2#.9&5
Lengkungan Horizontal I (PI 1)
Ls C 9 , C c
' c ' - 2 Js
?c %$ C 2, c
Ls $ C c - c(1-5 $C2 5 -2 5 (1-
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Ts == (2 5! "5 ') tan 15"= '1.19$
s = ( c!,) sec ? 2 - c= 21%. 59'$&1$ -= '. $
ontrolL F 2 Ts
159.#29 F 1$2.%91#$2&
( c!,) tan ' 2 ! k
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engan lengkung peralihan (spiral - lingkaran - spiral )
olektor % "$⁰
$ k a&.1.51152 5
. ' Ta4el #.&5 Ta4el #.&
C 2 5
1.52# ##''
) - ( c sin Js). %$ 5 - 2#.95 $$51199
os Js)os $"991)
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! 2#"9&5
2 5
Gke
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Menggunakan lengkung 4usur lingkaran dengan lengkung peralihan (spiral - ling
;ata-data perencanaanlasi>ikasi alan = olektor
? = 2#"512 ⁰
ecepatan rencana (@ ) = $ k aLe4ar alan = &.Le4ar 4ahu = 1.5
in = 115 rencana = %1'
B aC = . 59 Ta4el #.&Ls = 5 Ta4el #.&
H esar sudut spiral* == 5 C 9 %.1# C %1'= #.5 &
H esar sudut pusar lingkaran== 2#"512 - 2(#.5 &)= 15.#99 ⁰
H,an ang Lengkung ircleLc =
= 15"#99 %$ C 2 C%.1# C %1'= '5.9&$
L = Lc ! 2 Ls= '5"9&$ ! 2 C 5= 1'5.9&$
, === 1.%1 2&25%$& - .9'%19##'= .%2&
k == 5 - . % 9 2$5 - 2#.9'$'9$9= 2#.9'2
Lengkungan Horizontal III (PI 3)
Ls C 9 , C c
' c ' - 2 Js
?c %$ C 2, c
Ls $ C c - c(1- os Js)5 $C%1' -%1' (1- os #.5 &)
Ls - (Ls % # C cI2) - ( c sin Js)
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Ts == (%1'! . .%2&) tan 12"25$ ! 2#.9'2= 9#.1%%
s = ( c!,) sec ? 2 - c= %25.&51%1#&%'' - %1'= &.&51
ontrolL F 2 Ts
1'5.9&$ F 1''.2$5%'%19'
( c!,) tan ' 2 ! k
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Jarak Pandang Henti
= 60 k / a
n = 75 (ta e )t = 2.5 det k
= -0.000625 + 0 192= 0.1542
= 0 278 + t= 41.7
=
= 91.91
d == 133.61
:ntr:d ; n
133.61 ; 75
Jarak Pandang Menyiap
= 60 k / a
= 15 k / a (k:n*tantan)
ar atan ( )
t 1
d 1 0 278 t 1 ( - + (a t 1 /2))
t2
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== 157.4592
= 80 (keteta>an)
== 104.9728
d == 392.7381
d 2 0 278 t 2
d 3
d 4 2/3 d 2
d 1 + d 2 + d 3 + d 4
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Perhitungan Diagram uperele!a"i
= 60 k / a
< rencana = 205e n:r a = 2 ?e ak* = 8 ?@e ar a an = 7A eBa* #* a an = 1365
Ak a a = A eBa* #* Ca an - 1/2 % e ak*= 1365 - 1/2 7 0 08= 1364.72
Ak enDaE = A eBa* #* Ca an - e n:r a= 1365 - 0 02= 1364.98
Ak @uar = A eBa* #* Ca an + 1/2 % e ak*= 1365 + 1/2 7 08= 1365.28
= 60 k / a< rencana = 358e n:r a = 2 ?e ak* = 5.4 ?@e ar a an = 7A eBa* #* a an = 1373
Ak a a = A eBa* #* Ca an - 1/2 % e ak*= 1373 - 1/2 7 0 054= 1372.811
Ak enDaE = A eBa* #* Ca an - e n:r a= 1373 - 0 02= 1372.98
Ak @uar = A eBa* #* Ca an + 1/2 % e ak*= 1373 + 1/2 7 0 054= 1373.189
= 60 k / a
Tikungan PI 1 (S-C-S)
<
Tikungan PI 2 (FC)
<
Tikungan PI 3 (S-C-S)
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< rencana = 115e n:r a = 2 ?e ak* = 5.9 ?@e ar a an = 7A eBa* #* a an = 1368
Ak a a = A eBa* #* Ca an - 1/2 % e ak*= 1368 - 1/2 7 0 059= 1367.794
Ak enDaE = A eBa* #* Ca an - e n:r a= 1368 - 0 02= 1367.98
Ak @uar = A eBa* #* Ca an + 1/2 % e ak*= 1368 + 1/2 7 0 059= 1368.207
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