pola sebaran hama
DESCRIPTION
Menentukan Pola Sebaran Hama dengan Metode Iwao dan Metode Taylor melalui RumusTRANSCRIPT
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CONTOH PENERAPAN RUMUS
POLA SEBARAN HAMA
DENGAN METODE IWAO DAN METODE TAYLOR
Oleh
ANDI AMAL HAYAT MAKMUR
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SOAL :
Tabel 1. Kepadatan Populasi Wereng Hijau (Ekor / Rumpun)
NO PETAK KE -
1 2 3 4 5
1 9 0 27 23 18
2 1 11 0 2 12
3 25 2 1 1 2
4 1 3 2 2 3
5 0 1 19 0 0
6 2 16 1 13 1
7 3 1 0 11 5
8 1 2 2 2 9
9 18 0 13 4 1
10 0 8 2 1 4
JAWABAN :
METODE IWAO
NO PETAK KE -
1 2 3 4 5
1 9 0 27 23 18
2 1 11 0 2 12
3 25 2 1 1 2
4 1 3 2 2 3
5 0 1 19 0 0
6 2 16 1 13 1
7 3 1 0 11 5
8 1 2 2 2 9
9 18 0 13 4 1
10 0 8 2 1 4
60 44 67 59 55
6 4.4 6.7 5.9 5.5
S2 76.22222 29.6 91.56667 55.65556 33.61111
m 17.7037 10.12727 19.36667 14.33315 10.61111
4.28557
- 9.99937
m (Iwao) 14.42838
m = 423.465 ; = 28.5 ; m =72.1419 ; 2 = 165.31 ; ( )2 = 812.25
=14.42838 ; = 5.7
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PENENTUAN POLA SEBARAN DENGAN METODE IWAO
m = + . Metode Iwao
Jika y = a + bx, maka y = m ; a = ; dan b =
Jika a = - b, maka = -
Jika b =
( )
, maka =
( )
2 = 1
9 [1046 360]
2 = 0.111 [868]
= .
= .
= .
= .
= .
m = + (2
) 1
m = 6 + (2
) 1
m = 6 + (76.2222
6) 1
m = 6 +12.7037 1
m1 = .
m2 = .
m3 = .
m4 = .
m5 = .
=
( )
= .
. .
. .
= .
. .
. .
= . .
. .
= .
. = 4.28557
= -
= 14.42838 (4.28557)(5.7)
= 14.42838 24.42775
= - 9.99937
m = + Metode Iwao
m = (-9.99937) + (4.28557)(5.7)
m = 14.42838
2 = 1
1 [ 2
( )2
]
2 = 1
10 1 [1046
3600
10]
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SI2 = ( + 1) + ( 1) 2
SI2 = (-9.99937 + 1) 6 + (4.28557 1) 62
SI2 = (-8.99937) 6 + (3.28557) 36
SI2 = 64.28 Petak 1
SI2 = (-8.99937) 4.4 + (3.28557) 19.36
SI2 = 24.01 Petak 2
SI2 = (-8.99937) 6.7 + (3.28557) 44.89
SI2 = 87.19 Petak 3
SI2 = (-8.99937) 5.9 + (3.28557) 34.81
SI2 = 61.27 Petak 4
SI2 = (-8.99937) 5.5 + (3.28557) 30.25
SI2 = 49.89 Petak 5
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PENENTUAN POLA SEBARAN DENGAN METODE TAYLOR
S2 = a b . Metode Iwao log S2 = log a + b log
Jika y = a + bx, maka y = log S2 ; a = log a ; dan = rata2 log
Jika a = - b, maka log a = rata2 log S2 - b (rata-rata log )
Jika b =
( )
, maka =
( )
NO PETAK KE -
1 2 3 4 5
1 9 0 27 23 18
2 1 11 0 2 12
3 25 2 1 1 2
4 1 3 2 2 3
5 0 1 19 0 0
6 2 16 1 13 1
7 3 1 0 11 5
8 1 2 2 2 9
9 18 0 13 4 1
10 0 8 2 1 4
60 44 67 59 55
6 4.4 6.7 5.9 5.5
Log 0.778151 0.643453 0.826075 0.770852 0.740363 = 3.758893
Log S2 1.882082 1.471292 1.961737 1.745509 1.526483 = 8.587102
(log S2)2 3.542231 2.164699 3.848414 3.0468 2.33015
(log )2 13.77616 6.516421 15.99832 11.04873 7.856071
(log . log S2) 1.464544 0.946707 1.620542 1.345529 1.130151 = 6.507472
(log 2) 0.605519 0.414031 0.6824 0.594213 0.548137 = 2.8443
(log)2 = 14.12928 ; log.logS = 32.278
Rata2 (logS2) = 1.71742 ; Rata2 (log) = 1.71742
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=
( )
= .
(..)(.
. .
= .
.
. .
= . .
. .
= .
.
= 2.8
log a = rata2 log S2 - b (rata-rata log )
log a = 1.71742 (2.8) (0.751779)
log a = 1.71742 (2.114297)
log a = (0.39) (0.4)
a = 100.4
a =
.
a = 0.4
SII2 = a b
SII2 = 0.4 (6)2.8
SII2 = 0.4 (150.94665)
SII2 = 60.38 Petak 1
SII2 = 0.4 (4.4)2.8
SII2 = 25.34 Petak 2
SII2 = 0.4 (6.7)2.8
SII2 = 82.24 Petak 3
SII2 = 0.4 (5.9)2.8
SII2 = 57.60 Petak 4
SII2 = 0.4 (5.5)2.8
SII2 = 47.32 Petak 5
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Berdasarkan hasil perhitungan dengan Metode Iwao dan Metode Taylor, maka
diperoleh Data Tabel sebagai berikut :
Tabel 2. Hasil Perhitungan Selisih Ragam Sampel dengan masing-masing Ragam Model
RAGAM PETAK
TOTAL 1 2 3 4 5
SI2 64.28 24.01 87.19 61.27 49.89 286.66
SII2 60.38 25.34 82.24 57.60 47.32 272.88
S2 76.22 29.60 91.57 55.66 33.61 286.66
SI2 - S2 -11.94 -5.59 -4.37 5.62 16.28 0.00
SII2 - S2 -15.84 -4.26 -9.33 1.95 13.71 -13.78
(SI2 - S2)2 142.51 31.23 19.12 31.57 265.07 489.51
(SII2 - S2)2 251.02 18.19 87.03 3.79 188.03 548.06