perhitungan alt jpt

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    CARA PERHITUNGAN ALT

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    10 -1

    10 0

    10 -2

    10 -3

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    1. a. Σ KOLONI : 30-300b. HANYA DATA 1 PENGENCERAN : 30-300

    ALT : Σ KOLONI × FAKTORPENGENCERAN

    Contoh :10 -2 : >30010 -3 : 175

    10-

    : 1!ALT " 175#10 3

    " 1$0#10 3 " 1%$#10 5 CFU

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    2. ADA 2 PENGENCERAN DENGANΣ KOLONI : 30-300

    2 :

    ≤ 2 & RATA-RATA>2 & GUNAKAN 'ATA PENGENCERAN (G

    PERTA)AContoh :*+, 10 -2 : >300

    10 -3 : 22

    10-

    : 30

    SEBELUMNYA NPENGENCERAFAKTOR KOLONITINGGILEBIH NPENGENCERAFAKTOR KOLONI

    ×Σ

    ×Σ

    34,1210.224

    10.303

    4

    =

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    ALT " .*22 #10 3 , / *30#10 ," 2!2000 " 2%!#10 5 CFU

    * , 10 -2 : >30010 -3 : 2 010 - : 50

    ALT " +t+ 4n 4n64 +n 4 t+8+" 2 0#10 3 " 2% #10 5 CFU

    083,22

    10.240

    10.503

    4

    =≥

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    3. SEMUA DATA PETRIDISH

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    &. SPREADER

    • Ko;on< =4 4 t< +nt+< =+;

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    Contoh :10 -2 : >300

    10-3

    : 2 510 - : 1 PREA'ERALT " 2 5#10 3

    " 2%5#105

    CFU

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    '. SEMUA PETRI( KOLONI : 0ALT: 1 × FAKTOR PENGENCERAN*TEREN'AH,9

    Contoh :10 -2 : 0

    10-3

    : 010 - : 0ALT " 1#10 2 9 CFU

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    CONTOH OAL ALT

    I II III I10 -2 : 5 7 230 1 1 2 2

    10-3

    : 173 3 52 101 13710 - : 1! 0 1 2 2!K : 0 0 1 0 0

    H

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    I, ALT " 1%7 #10 5 CFU

    II, ALT "

    " .*230#10 2 ,/*3 #10 3 , " 2$500" 2% # 10 CFU

    III, 10 -2 : 1 1 -1 " 1 010 -3 : 52 -1 " 51

    10 - : 1 -1 " 0

    ALT " 1 0 #10 2 " 1% # 10 CFU

    043,1210.230

    10.342

    3

    =<

    6842,2210.190

    10.512

    3

    =>

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    I ,

    ALT " 2 # 10 2 " 2% # 10 CFU

    ,

    ALT " 2 # 10 2 " 2%5 # 10 CFU

    139,4210.244

    10.1012

    3

    =>

    5020,5210.249

    10.132

    3

    =>

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    1# '+ < 4n+n+8+n 0%1 8; =+8 4; +<< 4 o;4h +t+ o;on< =4 + +<4 < ?t :

    10 -1 : 20/2 = 4+ 4 51310 -2 : 105 35110 -3 : 37 !710 - : 12 2 /1 = 4+ 410 -5 : 3 K : 2H

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    2# P+ + 4n+n+8+n 0%5 8; =+8 4;%< 4 o;4h +t+ =4 + +< 4 < ?t :

    10 0 : 50 30010 -1 : 101 $010 -2 : 3110 -3 : 5 2 K : 2

    H

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    + + +n

    1# ? ;# 1 ? ;#2 +t+2 *- K,

    10 -1 : 22 513 !7%5 M 3 " ! %510 -2 : 105 351 22$ M 3 " 22510 -3 : 37 !7 52 M 3 "

    10 - : 12 30 21 M 3 " 1$10 -5 : 3 3%5 M 3" 0%5

    ALT " 225 # 10 2 " 2%3 # 10 B 0%1 8;" 2%3 # 10 5 CFUB 8;

    1 8,2210.225

    10.49 2

    3

    =>

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    2# ? ;# 1 ? ;#2 +t+2 *- K,10 0 : 50 300 375 M 3 " 37210 -1 : 101 $0 0%5 M 3 " $7%510 -2 : 31 17%5 M 3 " 1 %5

    10 -3 : 5 2 3%5 M 3 " 0%5

    ALT " $7%5 # 10 1 " $%$ # 10 2 B 0%5 8;" 17%! # 10 2 CFUB 8;

    " 1%$ # 103

    CFUB 8;

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    CARA PERHITUNGAN PT

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    1# L

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    2#

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    "

    " 1!%! PTB100 8;*PE) ULATAN 1 ANGKA ELAKANG

    KO)A,Contoh 10 1 0%1 8;P4n4 +=+n 0B1 1B3 1B3

    PTB100 8; "

    " " 15%7

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    3# 4 < 4n 4n64 +n 4=

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    # 3 =4 < 4n 4n64 +n 4=

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    Contoh

    1 0%1 0%01 0%001 0%0001 +83B3 2B3 0B3 0B3 0B33+3 2+3 0+3

    PT " %3B +8 *t+ 4; 3,

    1 0%1 0%01 0%001 0%0001 +8

    3B3 3B3 2B3 1B3 1B33+3 2+3 2+3

    PT " *t+ 4; 2,

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    Contoh1 0%1 0%01 0%001 0%0001 +83B3 2B3 0B3 1B3 0B33+3 2+3 1+3

    PT " 15B +8 *t+ 4; 3,

    1 0%1 0%01 0%001 8;

    0B3 1B3 0B3 0B30+3 1+3 0+3

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    Contoh o+;

    10 1 0%1 8; T# P4 < ++n 3B3 3B3 3B3

    T# P4n4 +=+n 3B3 3B3 2B3 T# P4;4n + 3B3 3B3 2B3H

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    1 0%1 0%01 0%001 +80B3 1B3 0B3 0B3H

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    • Ko8

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    5 0%5 0%05 0%005 0%0005 +8B5 5B5 0B5 1B5 0B5

    H