lap.akhir wheatstone(c-2) yulia

8/9/2019 Lap.akhir Wheatstone(C-2) Yulia

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VI. PERHITUNGAN DAN SESATANNYA

Menghitung Rx

RbL

LRx .

1

2= RxRb

Rb

L

L

L

LRx

+

+

=

1

1

2

2

Tabel 1Rb 500 Ohm Rx 1

= )( 11 LL (57,4 cm)05,0 = )( 22 LL (2,6 cm)05,0

RbL

LRx .

1

2= RxRb

Rb

L

L

L

LRx

+

+

=1

1

2

2

== 6,22500.4,57

6,2

=

++= 7,26,22

500

50

4,57

05,0

6,2

05,0

)7,26,22(

= )( 11 LL (56,2 cm)05,0 = )( 22 LL (3,8 cm)05,0

= )( RxRx (33,83,8)

= )( 11 LL (57,1 cm)05,0 = )( 22 LL (2,9 cm)05,0

= )( RxRx (25,33,0)

= )( 11 LL (57,2 cm)05,0 = )( 22 LL (2,8 cm)05,0

= )( RxRx (24,43,0)

= )( 11 LL (57,6 cm)05,0 = )( 22 LL (2,4 cm)05,0

= )( RxRx (20,82,5)

= )( 11 LL (57,0 cm)05,0 = )( 22 LL (3,0 cm)05,0

= )( RxRx (26,33,1)


= )( 11 LL (55,5 cm)05,0 = )( 22 LL (4,5 cm)05,0

= )( RxRx (40,54,5)

= )( 11 LL (55,4 cm)05,0 = )( 22 LL (4,6 cm)05,0

= )( RxRx (41,54,6)

= )( 11 LL (55,3 cm)05,0 = )( 22 LL (4,7 cm)05,0

= )( RxRx (42,44,7)

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= )( 11 LL (55,0 cm)05,0 = )( 22 LL (5,0 cm)05,0

= )( RxRx (45,45,03)

= )( 11 LL (55,5 cm)05,0 = )( 22 LL (4,5 cm)05,0

= )( RxRx (40,54,5)


= )( 11 LL (54,6 cm)05,0 = )( 22 LL (5.4 cm)05,0

= )( RxRx (49,45,4)

= )( 11 LL (54,6 cm)05,0 = )( 22 LL (5.4 cm)05,0

= )( RxRx (49,45,4) = )( 11 LL (55,2 cm)05,0 = )( 22 LL (4,8 cm)05,0

= )( RxRx (43,44,8)

= )( 11 LL (54,8 cm)05,0 = )( 22 LL (5,2 cm)05,0

= )( RxRx (47,45,2)

= )( 11 LL (55,3 cm)05,0 = )( 22 LL (4,7 cm)05,0

= )( RxRx (42,44,7)

Tabel 2 Rb 400 Ohm Rx 1

cmLL )05,06,51()( 11 =

cmLL )05,04,8()( 22 =

RbL

LRx .

1

2= RxRb

Rb

L

L

L

LRx

+

+

=1

1

2

2

== 1,65400.6,51

4,8 1,65

400

50

6,51

05,0

4,8

05,0

++= =8.6

)6,81,65(

= )( 11 LL (50 cm)05,0

= )( 22 LL (10 cm)05,0

= )( RxRx (65,18,6)

= )( 11 LL (50,3 cm)05,0

= )( 22 LL (9,7 cm)05,0

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3/8

= )( RxRx (77,110,1)

= )( 11 LL (51,7 cm)05,0

= )(22 LL (8,3 cm)05,0

= )( RxRx (64,28,5)

= )( 11 LL (51,4 cm)05,0

= )( 22 LL (8,6 cm)05,0

= )( RxRx (66,98,8)

= )( 11 LL (51,2 cm)05,0

= )( 22 LL (8,8 cm)05,0

= )( RxRx (68,759,05)

Tabel 2 Rx 2

= )( 11 LL (54,3 cm)05,0 = )( 22 LL (5,7 cm)05,0

= )( RxRx (41,95.6)

= )( 11 LL (54 cm)05,0 = )( 22 LL (6.00 cm)05,0

= )( RxRx (44,45,96)

= )( 11 LL (54,5 cm)05,0 = )( 22 LL (5,5 cm)05,0

= )( RxRx (40,35,4)

= )( 11 LL (53,9 cm)05,0 = )( 22 LL (6,1 cm)05,0

= )( RxRx (45,26,1)

= )( 11 LL (53,8 cm)05,0 = )( 22 LL (6,2 cm)05,0

= )( RxRx (46,096,17)

= )( 11 LL (54,1 cm)05,0 = )( 22 LL (5,9 cm)05,0

= )( RxRx (43,65,9)

Tabel 2 Rx 3

= )( 11 LL (52,7 cm)05,0 = )( 22 LL (7,3 cm)05,0

= )( RxRx (55,47,3)

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= )( 11 LL (52,8 cm)05,0 = )( 22 LL (7,2 cm)05,0

= )( RxRx (54,57,2)

= )(11 LL (53,1 cm)05,0

= )(

22 LL (6,9 cm)05,0

= )( RxRx (51,96,9)

= )( 11 LL (53 cm)05,0 = )( 22 LL (7,0 cm)05,0

= )( RxRx (52,87,02)

= )( 11 LL (52,9 cm)05,0 = )( 22 LL (8,1 cm)05,0

= )( RxRx (61,28,1)

= )( 11 LL (53,2 cm)05,0 = )( 22 LL (6,8 cm)05,0

= )( RxRx (51,16,8)

Menghitung Rx rata-rata

a)N

RxRx

=

1

)( 22

=

N

RxNRxRx


N

RxRx

=1

)( 22

=

N

RxNRxRx

=25,53 =4.52

(25,53 )52,4


(42,121,72)


(45,93,2)


(69,347,63)


(42,582,19)


(54,483,72)

b) =+= 43,472

).400()500( 111

RxRxRx

9


5/8

=2Rx 42,35

3Rx 50,19

= 66,46Rx

1

)( 22

=

N

RxNRxRx =14,55

(46,66 )55,14

Menghitung 1L dan 2L untuk setiap Rx

o Untuk Rx 1

N

LL

= 111

)(2

1

2

1

1

=

N

LNLL

=12

7,648=

11

3468,111

=54,06 cm = 3,18

(54,063,18) cm

N

LL

=

2

2

1

)(2

2

2

2

2

=

N

LNLL

= 12

3,71

= 11

7468,113

= 5,94 cm = 3,21

(5,943.21) cm

o Untuk Rx 2

=1L (54,720,25) cm

=2L (5,280,71) cm

o Untuk Rx 3

=1L (53,941,15) cm

Membuat GRAFIK

RbL

LRx .

1

2= RbLRx

L ..1

21 =

xaty .=

10


6/8

btxaty += .

%100graf

hitgraf

Rx

RxRKSR

=

Tabel 1 Rx 1

%100graf

hitgraf

Rx

RxRKSR

=

= %10053,25

66,4653,25 = 82,76%

Tabel 1 Rx 2

%88,10%10012,42

66,4612,42=

=KSR

Tabel 1 Rx 3

%65,1%1009,45

66,469,45=

=KSR

Tabel 2 Rx 1

%7,32%10034,69

66,4634,69=

=KSR

Tabel 2 Rx 2

%58,9%10058,42

66,4658,42=

=

KSR

Tabel 2 Rx 3

%35,14%10048,54

66,4648,54=

=KSR

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7/8

VII. ANALISA

Dari data hasil percobaan dapat dilihat seberapa besar perbedaan nilai yang

dihasilkan dari data hasil percobaan jembatan wheatstone dengan mengunakan

Rb 50 ohm dengan Rb 40 ohm. Adapun perbandingan nilai-nilai hasil percobaan

tersebut dapat dibandingkan dengan melihat beberapa data di bawah ini :

Perbandingan nilai Rx pada tabel 1 Rb 50 ohm dengan Rx pada tabel 1 Rb 40

ohm.

Rb 50 ohm Rb 40 ohm

Rx = 41,74 Rx = 42,76

Rx =43,17 Rx = 42,19

Rx = 42,31 Rx = 42,76

Rx = 42,31 Rx = 42,47

Rx = 42,02 Rx = 42,76

Rx = 42,59 Rx = 42,47


ohm.

Rb = 55,26 Rb = 54,12

Rb = 54,17 Rb = 54,49

Rb = 54,53 Rb = 54,86

Rb = 54,89 Rb = 54,49

Rb = 55,26 Rb = 54,49

Rb = 55,26 Rb = 54,49

Rb = 54,17 Rb = 54,49


ohm.

Rb = 46,77 Rb = 47,27

Rb = 46,77 Rb = 47,59

Rb = 46,15 Rb = 47,59

Rb = 47,40 Rb = 47,96

Rb = 47,72 Rb = 47,91

Rb = 46,77 Rb = 48,89

Hasil yang didapatkan dari percobaan dengan menggunakan Rb yang berbedaternyata setelah dianalisis hasilnya tidak jauh bebeda.

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VIII. KESIMPULAN

Kesalahan hasil akhir dapat disebabkan oleh kalibrasiataupun kualitas alat yang kurang baik

Ketelitian dari praktikan juga sangat menentukan

keberhasilan percoban terutama saat menghitung jarak (L)

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lap.akhir wheatstone(c-2) yulia

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