soal tugas1 dimstrukNoangka belakang nimG (N)L (m)b (m)h (m)volume (m)Massa balokmassamesinmassa totalditanya?112000040.30.60.72176.32653061222040.81632653062217.1428571429bj Beton =2400kg/m3a.Hitunglah K(kekakuan balok), w (angular velocity), f(natural frekuensi)223000040.350.70.982403061.22448979593301.2244897959ne=43.3333333333putaran/ detikb.jika pada beban mesin mempunyai rpm seperti di soal, hitung respons dinamik dari struktur pada gambar334000030.40.80.96235.10204081634081.63265306124316.7346938776fc' =25mpa (Nmm)c.hitung pembesaran dinamik445000030.30.60.54132.24489795925102.04081632655234.2857142857E= 4700* fc'0,523500552500020.350.70.491202551.02040816332671.0204081633663500020.40.80.64156.73469387763571.42857142863728.1632653061massa bangunan=1077450002.50.30.60.45110.20408163274591.83673469394702.0408163265=3.1488150002.50.350.70.61251501530.6122448981680.612244898gravitasi=9.899100003.50.40.81.12274.28571428571020.40816326531294.693877551100170003.50.30.60.63154.28571428571734.6938775511888.9795918367w mesin=16328rad/ det=2ne272.1333333333

a.Menghitung KekakuanMenghitung w (angular velocity)menghitung T (periode)menghitung F (frekuensi)karena perletakan adalah jepit bebas maka kekakuannya adalah K=(3 EI/L3)N/mw= (k/m)^0,5sT=2/wf=1/T1. hitung Inersia dari balok2. menghitung Khitung wT=121.2425412918f=0.0082479301I=(bh3/12)K=3EI/L3w=0.0517970007108.69314176330.0092002125I =0.0054K=5.94843750.057777334461.80879731150.01617892670.010004166711.02021484380.1016036596120.99816941180.00826458780.017066666744.5629629630.051901611734.56672405660.02892955660.005414.10.181677615431.26678210250.03198282440.010004166788.161718750.200852136987.24115681970.01146247980.0170666667150.40.071984373338.31937357230.026096460.005424.36480.163885768942.65562854160.0234435650.010004166745.13880.147225588291.59755996670.01091732140.017066666728.06297376090.06856077830.00548.8793002915

b.berat mesinD=0.1x=[(Po x 1- 2)sint/(K x( (1-2)^2+4D^2^2))costPo/k=3362.2274757026sin=0cos=1t=0=/w5253.843455981-^2=-27602870.05994394D22=1104114.842397762722.26997616240.45730489130.88930997770.14710.0361430775-22184439.4690963887377.618763852x=-0.00012180720.0000000046897.60638297870.81337160530.58174447280.22678.3812168329-7173724.94268345286949.037707338-0.00012271080.00000000523546.09929078010.98937407710.14539235060.35243.2540078458-27491711.59079141099668.50363166-0.00012512420.0000000093283.56978918360.9463488715-0.32314673660.41497.8913757863-2243677.5736548989747.1429461957-0.00012898790.0000000049232.71276595740.6938209106-0.72014758490.51354.8938911104-1835736.4561682873429.4982467313-0.00012638620.00000001691846.9267139480.2876948455-0.95772212870.63780.4501288534-14291802.1767475571672.127069899-0.00012676810.0000000187332.3083466995-0.1821211174-0.9832761050.71660.5061881319-2757279.80082423110291.232032969-0.00012922980.0000000068356.3414228723-0.6116190991-0.79115237320.81848.4105701348-3416620.63578605136664.865431442-0.00012052040.00000001451914.5652744944-0.9057168174-0.42388329380.93969.2275985579-15754766.7291539630190.709166156-0.00010429650.0000000113-0.99930690620.03722508821-0.00012152290.0000000061-0.87167038760.49009257841.1(Po x 1- 2)sint4D^2^2))cost00.00000001870.0000000187-0.00005797170.0000000166-0.000057955-0.00010310950.0000000109-0.00010309873783.0319888734-0.0001254210.0000000027-0.0001254183-0.0001199668-0.000000006-0.0001199729-0.0000879543-0.0000000135-0.0000879678-0.0000364705-0.0000000179-0.00003648840.0000230871-0.00000001840.00002306870.0000775338-0.00000001480.0000775190.000114816-0.00000000790.0001148080.00012668020.00000000070.00012668090.00011050.00000000920.0001105091RESPONS STRUKTUR

c.