Perencanaan rumah tinggal 2 lantai

Perencanaan rumah tinggal 2 lantai2015

BAB I DATA PERENCANAAN

1.1 Data Perencanaana) Fungsi Bangunan: Rumah Tinggal b) Lokasi: Ambonc) Jenis struktur: SRPMMd) Jarak antar portal: 5 me) Jumlah Trave (medan) : 3 travef) Penampang Kolom : Bujur sangkarg) Kuat Tekan Beton ( fc ) : 35 Mpah) Tegangan Leleh Tulangan ( fy ) : 240 Mpa(tul.pelat, balok anak, sloof dan tul.geser)i) Tegangan Leleh Tulangan ( fy ) : 390 Mpa(tul.memanjang balok induk, kolom, tul.tangga dan pondasi)j) Tegangan Ijin Tanah () : 0,22 Mpa

Gambar 1.1 Data PerencanaanBeban pada plat lantai

a.Beban hidup

Beban hidup lantai 1 sesuai PPI'87 tabel 3.1=200kg/m2=2kN/m2

Beban hidup lantai 2=200kg/m2=2kN/m2

Beban hidup Atap=100kg/m2=1kN/m3

b.

Beban mati

beban mati lantai bangunan :

beton=2400kg/m2=24kN/m2

keramik per m2=25kg/m2=0.25kN/m2

spesi per cm tebal=21kg/m2=0.21kN/m2

langit-langit=11kg/m2=0.11kN/m2

dinding 1/2 batu per m2=250kg/m2=2.5kN/m2

penggantung=7kg/m2=0.07kN/m2

pasir=1600kg/m3=16kN/m2

1.2 Dimensi BalokPerkiraan dimensi balok dalam SNI 03-2847-2002 dinyatakan dengan rumus :

h =L (untuk balok diatas dua tumpuan)

h =L (untuk balok kantilever)

b =h

1.3 Dimensi Kolom1. Kolom Praktis ukuran Kolom Praktis = 15/15 cm

2. Kolom Struktur ukuran Kolom Struktur = 20/25 cm

3. Kolom Exterior ukuran Kolom Exteriot = 20/20 cm

BAB III PEMBEBANAN PORTAL

3.1Perataan Beban Plat Lt. 1 = Lt. Atapa. Perataan Beban Tipe A ( khusus jemuran )

h =1.125mh =2/3x1.13=0.75m

2.25m

b. Perataan Beban Tipe B = I ( atap )

h =1.00mh =2/3x1.00=0.67m

2.00m

C. Perataan Beban Tipe C = B ( atap )

h =1.5mh =2/3x1.50=1.00m

3.00m

D. Perataan Beban Tipe D = A ( atap )

h =1.50mh =2/3x1.50=1.00m

3.00m

E. Perataan Beban Tipe E = D ( atap )

h =0.75mh =2/3x0.75=0.50m

3.75m

F. Perataan Beban Tipe F = G ( Atap )

h =0.75mh =2/3x0.75=0.50m

2.25m

G. Perataan Beban Tipe G = F ( Atap )

h =1.38mh =2/3x1.38=0.92m

2.75m

H. Perataan Beban Tipe H = G ( Atap )

h =1.00mh =2/3x1.00=0.67m

2.75m

I. Perataan Beban Tipe I = E ( Atap )

h =1.00mh =2/3x1.00=0.67m

2.75m

J. Perataan Beban Tipe J = H ( Atap )

h =0.75mh =2/3x0.75=0.50m

2.75m

G. Perataan Beban Tipe C ( Atap )

h =1.00mh =2/3x1.00=0.67m

3.50m

a.Perataan Beban Tipe aTI = 0,5 x 1,125 x 1,125 = 0.63 mTII = (b/2) x 1,125 = 0,14 mRa = Rb = T1 + T2 = 0.63 + 0,14 = 0,77 m T1 T2Mmax I = Ra x 1/2.L T1 x (1/3 x ( a +) (T2 x b/4) = 0.77 x 1/2 x 2.5 0.63 x (1/3 x 1.125+0.25/2) (0,14 x 0.25/4 ) = 0.642Mmax II = 1/8 x h x L2 = 0,125 x h x 2,502 = 0.78 hMmax I = Mmax II 0.642 = 0.78 h h = 0.82 m < 1,125 m b.Perataan Beban Tipe B dan I ( atap )TI = 0,5 x 1 x 1 = 0.5 mTII =( b/2 ) x 1 = 0,5 mRa = Rb = T1 + T2 = 0.5 + 0,5 = 1 m T1 T2Mmax I = Ra x 1/2.L T1 x (1/3 x ( a +) (T2 x b/4) = 1 x 1/2 x 3 0.5 x (1/3 x 1+1/2) (0,5 x 1/4 ) = 0.958Mmax II = 1/8 x h x L2 = 0,125 x h x 32 = 1.125 hMmax I = Mmax II 0.958 = 1.125 h h = 0.85 m < 1 m

c.Perataan Beban Tipe C dan B ( atap )T1 = 0,50 x 1,5 x 1,5 = 1,125 mRA = RB = T1 = 1,125 mMmaxI = RA x 1,5 T1 x (1/3 . 1,5) = 1,125 x 1,5 1,125 x (1/3 . 1,5) = 1,125 Mmax II= 1/8 . h . L2= 1/8 . h . 32 = 1,125 h Mmax I = Mmax II 1,125 = 1,125 h h = 1 m < 1,5 m atau h = 2/3 x 1,5 = 1 m

d.Perataan Beban Tipe D dan A ( atap )TI = 0,5 x 1.5 x 1.5 = 1.125 mTII = (b/2) x 1.5 = 0,375 mRa = Rb = T1 + T2 = 1.125 + 0,375 = 1.5 m T1 T2Mmax I = Ra x 1/2.L T1 x (1/3 x ( a +) (T2 x b/4) = 1.5 x 1/2 x 3.5 1.125 x (1/3 x 1.5+0.5/2) (0,375 x 0.5/4 ) = 1.734Mmax II = 1/8 x h x L2 = 0,125 x h x 3.52 = 1.53 hMmax I = Mmax II 1.734 = 1.53 h h = 1.133 m < 1.5 m

e.Perataan Beban Tipe E dan D ( atap )TI = 0,5 x 0.75 x 0.75 = 0.281 mTII = (b/2) x 0.75 = 0,844 mRa = Rb = T1 + T2 = 0.281 + 0,844 = 1.13 m T1 T2Mmax I = Ra x 1/2.L T1 x (1/3 x ( a +) (T2 x b/4) = 1.13 x 1/2 x 3.75 0.281 x (1/3 x 0.75+2.25/2) (0.844 x 0.5/4 ) = 1.248Mmax II = 1/8 x h x L2 = 0,125 x h x 3.752 = 1.76 hMmax I = Mmax II 1.248 = 1.76 h h = 0.71 m < 0.75 mf.Perataan Beban Tipe F TI = 0,5 x 0.75 x 0.75 = 0.281 mTII = (b/2) x 0.75 = 0,281 mRa = Rb = T1 + T2 = 0.281 + 0,281 = 0.562 m T1 T2Mmax I = Ra x 1/2.L T1 x (1/3 x ( a +) (T2 x b/4) = 0.562 x 1/2 x 2.25 0.281 x (1/3 x 0.75+0.75/2) (0,281 x 0.75/4 ) = 0.404Mmax II = 1/8 x h x L2 = 0,125 x h x 2.252 = 0.63 hMmax I = Mmax II 0.404 = 0.63 h h = 0.64 m < 0.75 m

G.Perataan Beban Tipe G Dan F ( Atap )TI = 0,5 x 1.375 x 1.375 = 0.95 mTII = (b/2) x 1.375 = 0,17 mRa = Rb = T1 + T2 = 0.95 + 0,17 = 1.12 m T1 T2Mmax I = Ra x 1/2.L T1 x (1/3 x ( a +) (T2 x b/4) = 1.12 x 1/2 x 3 0.95 x (1/3 x 1.375+0.25/2) (0,17 x 0.25/4 ) = 1.114Mmax II = 1/8 x h x L2 = 0,125 x h x 32 = 1.125 hMmax I = Mmax II 1.114 = 1.125 h h = 1 m < 1.375 mH.Perataan Beban Tipe H Dan G ( Atap )TI = 0,5 x 1 x 1 = 0.5 mTII = (b/2) x 1 = 0,38 mRa = Rb = T1 + T2 = 0.5 + 0,38 = 0.88 m T1 T2Mmax I = Ra x 1/2.L T1 x (1/3 x ( a +) (T2 x b/4) = 0.88 x 1/2 x 2.75 0.5 x (1/3 x 1+0.75/2) (0,38 x 0.75/4 ) = 0.779Mmax II = 1/8 x h x L2 = 0,125 x h x 2.752 = 0.945 hMmax I = Mmax II 0.779 = 0.945 h h = 0.82 m < 1 m

I.Perataan Beban Tipe I Dan E ( Atap/kantilever )TI = 0,5 x 0.75 x 0.75 = 0.28 mTII = (b/2) x 0.75 = 0,38 mRa = Rb = T1 + T2 = 0.28 + 0,38 = 0.66 m T1 T2Mmax I = Ra x 1/2.L T1 x (1/3 x ( a +) (T2 x b/4) = 0.66 x 1/2 x 2.5 0.28 x (1/3 x 0.75+1/2) (0,38 x 1/4 ) = 0.516Mmax II = 1/8 x h x L2 = 0,125 x h x 2.52 = 0.78 hMmax I = Mmax II 0.516 = 0.78 h h = 0.66 m < 0.75 mJ.Perataan Beban Tipe J Dan H ( Atap/balkon )TI = 0,5 x 0.75 x 0.75 = 0.28 mTII = (b/2) x 0.75 = 0,47 mRa = Rb = T1 + T2 = 0.28 + 0,47 = 0.75 m T1 T2Mmax I = Ra x 1/2.L T1 x (1/3 x ( a +) (T2 x b/4) = 0.75 x 1/2 x 2.75 0.28 x (1/3 x 0.75+1.25/2) (0,47 x 1.25/4 ) = 0.639Mmax II = 1/8 x h x L2 = 0,125 x h x 2.752 = 0.95 hMmax I = Mmax II 0.639 = 0.95 h h = 0.68 m < 0.75 mK.Perataan Beban Tipe C ( Atap/void )TI = 0,5 x 1 x 1 = 0.5 mTII = (b/2) x 1 = 0,75 mRa = Rb = T1 + T2 = 0.5 + 0,75 = 1.25 m T1 T2Mmax I = Ra x 1/2.L T1 x (1/3 x ( a +) (T2 x b/4) = 1.25 x 1/2 x 3.5 0.5 x (1/3 x 2+1.5/2) (0,75 x 1.5/4 ) = 1.365Mmax II = 1/8 x h x L2 = 0,125 x h x 3.52 = 1.53 hMmax I = Mmax II 1.365 = 1.531 h h = 0.89 m < 1 mToto Prasetiyo ( 12.21.036 )