perhitungan obj 7

IV. PEMBAHASAN 4.1 Data PercobaanTabel 4.1 Data PercobaanNoKI (mL)Persulfat (mL)tiosulfat (mL)Air (mL)t (30oC)t (35oC)t (40oC)

120201001006750

220161041239255

3201210815414192

42081012200185172

52041016480420384

4.2 PerhitunganA. Pembuatan Larutana. KI 0,5 NM = b. Na2S2O3 0,01 NM = c. K2S2O8 0,02 NM =

B. Menentukan Konsentrasi Tiosulfat dalam Campuran V1 x N1 = V2 x N210 mL x 0,01 N = 50 mL x N2N2 = 0,002 NC. Menentukan Konsentrasi Persulfat dalam CampuranV1 x N1 = V2 x N2a. Volume 20 mL20 mL x 0,02 N = 50 mL x N2N2 = 0,008 Nb. Volume 12 mL12 mL x 0,02 N = 50 mL x N2N2 = 0,0064 Nc. Volume 8 mL8,0 mL x 0,02 N = 50 mL x N2N2 = 0,0032 Nd. Volume 4 mL4,0 mL x 0,02 N = 50 mL x N2N2 = 0,0016 ND. Menentukan Nilai ff = = x 0,002 N = 0,001 NE. Menentukan Nilai yY = ln L = a. L = 0,08 NY = ln b. L = 0,0064 NY = ln c. L = 0,0048 NY = ln d. L = 0,0032 NY = ln e. L = 0,0016 NY = ln E. Menenttukan Persamaan Regresia. Pada T = 30o C = 303 Kx = ty = yXYXyX2

1000,133513,350010000

1230,169920,897715129

1540,233635,974423716

2000,374774,940040000

4800,9808470,7840230400

= 21,14= 0,3785

Nilai BB = = = 2,2535 x 10-3 Nilai = A + B0,3785 = A + (2,2535 x 10-3 ) (21,14)A = -0,0979 Persamaan RegresiY = A + BXY = 2,2535 x 10-3x 0,0979b. Pada T 35oC = 308 KXYxyX2

670,13358,94454489

920,169914,63088646

1410,233632,937619881

1850,374769,319534225

4200,9808411,936176400

= 181= 0,3785

Nilai B B = = = 2,4635 X 10-3 Nilai = A + B0,3785 = A + (2,4635 X 10-3) (181)A = -0,0674 Persamaan RegresiY = A + BXY = 2,4635 x 10-3x 0,0674c. Pada T 40oC = 313 KXYXyX2

500,13356,6752500

550,16999,34453025

920,233621,49128464

1720,374764,448429584

3840,9808376,6272147456

= 150,6= 0,3785

Nilai B B = = = 2,4936 X 10-3 Nilai = A + B0,3785 = A + (2,4936 x 10-3) (150,6)A = 2,9549 x 10-3

Persamaan RegresiY = A + BXY = 2,4936 x 10-3x + 2,9549 x 10-3G. Persamaan Regresi CampuranX = 1/T Y = ln k = ln BXYXyX2

0,00330-6,0953-0,02011,0890 x 10-5

0,00325-6,0062-0,01951,0562 x 10-5

0,00319-5,9940-0,01911,0176 x 10-5

= 3,147 x 10-3= -6,031

Nilai B B = = = - 897,25 Nilai A = A + B-6,031= A + ( - 897,25) (3,147 x 10-3)A = - 3,1187 Persamaan RegresiY = A + BXY = - 897,25x - 3,1187H. Menentukan Energi AktivasiB = Ea = -B x R = - (-897,25) x 8,314 J/molK = 7457,6 Joule = 7,4576 kJI. Menentukan nilai k dan orde reaksiMol tiosulfat = N2 tiosulfat x V x 1 = 0,002 N x 0,05 L x 1 = 0,0001 molLog v = log k + n log [persulfat]V = a. Pada t 30oC = 303 K T = 100 sV = = 5 x 10-7 T = 123 sV = = 4,06 x 10-7 T = 154 sV = = 3,24 x 10-7 T = 200 sV = = 2,5 x 10-7 T = 480 sV = = 1,04 x 10-7J. Menentukan Persamaan RegresiX = log [persulfat]Y = log vXYXyX2

-2,0970-6,30108,39834,397

-2,1938-6,39158,58534,812

-2,3188-6,48948,80825,376

-2,4948-6,602016,4706,224

-2,7959-6,983019,5237,817

= 2,380= 6,153

Nilai B B = = = 0,951 k Nilai A = A + B6,153= A + (0,951) (2,380)A = - 4,2898 Persamaan RegresiY = A + BXY = - 4,2898 + 0,951x Penentuan orde reaksiB = 0,951 = 1 Menentukan nilai kA = log kK = 10- 4,2898 = 5,13097 x 10-5 s

4.3 Grafik1. Perbandingan waktu Vs ln pada T = 303 K

2. Perbandingan waktu Vs ln pada T = 308 K

3. Perbandingan waktu Vs ln pada T = 313 K

4. Grafik regresi campuran

5. Grafik log [persulfat] Vs log v