line balancing application

LINE BALANCING

DefinisiLine balancing merupakan suatu metode penugasan sejumlah pekerjaan yang saling

berkaitan dalam satu lini produksi sehingga setiap stasiun kerja memiliki waktu yang tidak melebihi waktu siklus

dari stasiun kerja tersebut.Line balancing berusaha menyeimbangkan

seluruh lintasan yang ada dalam lini perakitan sehingga aliran produksi berjalan

lancar.

Operator 1

Operator 2

Operator 3

Operator 4

Operator 5

OperatorStandard Minutes

to Perform Operation

1 0.492 0.313 0.254 0.445 0.54

How to Calculate Line Efficiency ?

OperatorStandard Minutes

to Perform Operation

Wait Time Based on Slowest Operator

Allowed Standard Minutes

1 0.49 0.05 0.542 0.31 0.23 0.543 0.25 0.29 0.544 0.44 0.1 0.545 0.54 0 0.54

2.03 2.7

100.

..

5

1

5

1 XMA

MSE

Line Efficiency ?

0.49

0.31

0.25

0.44

0.54

OperatorStandard Minutes

to Perform Operation

Wait Time Based on Slowest Operator

Allowed Standard Minutes

1 0.49 0.05 0.542 0.31 0.23 0.543 0.25 0.29 0.544 0.44 0.1 0.545 0.54 0 0.54

2.03 2.7

Efficiency 75.19%

Opportunities for Improvements ?

Operation Standard Minutes1 1.52 2.253 1.254 2.55 36 2.757 1.75

Assembly Line

(7 operations)

Desired Rate of Production = 1000/day

Efficiency = 95%

1 day = 10 hours = 600 minutes

Thus R = 1000/600 = 1.67 units/minute

Numbers of Operator Needed in Assembly Line?

E

SMRAMRN

27 operators

Operation Standard Minutes

1 1.52 2.253 1.254 2.55 36 2.757 1.75

minutes/unit 0.6

∑SM 15R 1.67E 0.95

26.36842105

Operation Standard Minutes(standard

minutes)/(minutes/unit)

Operators

1 1.5 2.5 32 2.25 3.75 43 1.25 2.083333333 24 2.5 4.166666667 55 3 5 56 2.75 4.583333333 57 1.75 2.916666667 3

minutes/unit 0.6 27

Output?

Slowest One?

Operation Standard Minutes(standard

minutes)/(minutes/unit)

Operators

1 1.5 2.5 3 0.52 2.25 3.75 4 0.56253 1.25 2.083333333 2 0.6254 2.5 4.166666667 5 0.55 3 5 5 0.66 2.75 4.583333333 5 0.557 1.75 2.916666667 3 0.583333333

dayhouroutput /1000/1003

605

Line Balancing Problem

A

B

C

4.1mins

D

1.7mins

E

2.7 mins

F

3.3 mins

G

2.6 mins

2.2 mins

3.4 mins

• 1. What process is the bottleneck?

• 2. How much is the maximum production per hour?

• 3. How much the efficiency?

• 4. How to minimize work stations?

• 5. How should they be grouped?

• 6. New efficiency?

Question

Calculate efficiency• A. 73.2%• B. 56.7%• C. 69.7%• D. 79.6%• E. 81.2%

A

B

C

4.1mins

D

1.7mins

E

2.7 mins

F

3.3 mins

G

2.6 mins

2.2 mins

3.4 mins

(2.2+3.4+4.1+2.7+1.7+3.3+2.6)4.1x7

2028.7

69.7%

1-69.7%=30.3% Balance Delay

time cycletimes taskN

(bottleneck)

204.1 = 4.88 work stations

Number of Workstation

Line Balancing Solution

A

B

C

4.1

D

1.7

E

2.7

F

3.3

G

2.6

Station 1

Station 2

Station 3

Station 4

2.2

3.4

All under 6 minutes?

(6.0)

(5.6)

(5.8)

4 Stations 20/24=83.3%

Max prod./hour60/6

10 units/hour

Line Balancing Problem

A

B

C

4.1mins

D

1.7mins

E

2.7 mins

F

3.3 mins

G

2.6 mins

2.2 mins

3.4 mins5.6

5.0

20/5.6x5 = 20/28 = 71.4%

5 Stations

Max Prod./hour60/5.6

10.7 units/hour

40 secs

59 secs

84 secs34 secs

56 secs 45 secs

What is the minimum # of work stations?Round down.

• 3• 2• 4• 5• 6

timecycle

task timesN

40+59+84+56+34+45 = 318

318/84 = 3.78 or 3 work stations

What is the efficiency with 6 operators?

100

timecyclestations ofnumber

task times%Efficency

318/6 x 84=318/504 =

63%

100

timecyclestations ofnumber

task times%Efficency

40 secs

59 secs

84 secs34 secs

56 secs 45 secs

99 secs

118 secs

3 Stations ?

318/3x118

318/354 = 89.8%101 secs

40 secs

59 secs

84 secs34 secs

56 secs 45 secs

4 Stations?99 secs

84 secs

56 secs

79 secs

318/4 x 99 =318/396 =

80.3%