grafik tugas

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Hukum Gas IdealMemahami penggunaan prinsip PV =

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  nRT

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Hubungan antara tekanan (P) dengan volume (V)

 T (K) = 222

V (mL) V/1 (L) P (a!m)

" #" 2#$%

& #& 1#$%

' #' 1#'

1 #1 #'&

12 #12 #2

1& #1& #&

1 #1 #$2

2 #2 #"'

22 #22 #"$

2$ #2$ #"1

2 40.00

0.50

1.00

1.50

2.00

2.50

3.00

f(x)R² =

Tekaa !)

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n= #$1

6 8 10 12 14 16 18 20 22

 = - 0.1022969561x + 2.1145872441  0.754666748

Volume mL)

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Hubungan antara volume (V) dan suhu (T) dalam Celcius

P (a!m) =

 T (*) V (L) V+1 (mL),12" #2& 2#&2

,11" #2' 2#%

,1" #2% 2#

,%" #" "#"

," #"2 "#2

,'" #"$ "#"'

," #"& "#&"

,&" #"' "#'

,$" #"% "#'

,"" #$ $#$,2" #$2 $#21

-140

Suhu (C)

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2# n = #$1

2

-120 -100 -80 -60 -40 -20

f(x) = 0.0168304814x + 4.5947249905R² = 0.9999999999

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00.000.50

1.00

1.50

2.00

2.50

3.00

3.50

4.00

4.50Volume (mL)

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Hubungan antara volume (V) dan suhu (T) dalam Kelvin

P (atm) =

T (K) V (L) V*1000 (mL)

150 0.0505 50.49

160 0.0539 53.86

170 0.0572 57.22

180 0.0606 60.59

190 0.0640 63.96

200 0.0673 67.32

210 0.0707 70.69

220 0.0741 74.05

230 0.0774 77.42240 0.0808 80.79

250 0.0842 84.15

Volume (

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0.1 n = 0.00041

1

140 160 180 200 220 2400.00

10.0020.00

30.00

40.00

50.00

60.00

70.00

80.00

90.00

f(x) = 0.3366099776x + 0.00000492

R² = 1

Suhu (K)

  mL)

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260

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Hubungan antara volume (V) dan mol

P (atm) =

n (mol) V (L) V*1000 (mL)

0.0001 0.0021 2.05

0.0002 0.0041 4.11

0.0003 0.0062 6.16

0.0004 0.0082 8.21

0.0005 0.0103 10.26

0.0006 0.0123 12.32

0.0007 0.0144 14.37

0.0008 0.0164 16.42

0.0009 0.0185 18.470.0010 0.0205 20.53

0.000

0.0002

0.0004

0.0006

0.0008

0.001

0.0012

mol

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0.6 T (K) = 150

1&

5.00 10.00 15.00 20.00

f(x) = 4.8721071863581E-005x + 6.85709661831387E-020

R² = 1

Volume (mL)

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25.00