abutment jembatan
TRANSCRIPT
ANALISIS STRUKTUR JEMBATAN
PERENCANAAN ABUTMENT
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BAB IV
PERENCANAAN ABUTMENT (PANGKAL JEMBATAN)
4.1 Data Beban (dari hitungan terdahulu)
Beban Mati
QD = 5,6273 + 13,8590 = 19,4863 ton
Beban Hidup
QH = 12.9500 + 11.0989 = 24,0489 ton
4.2 Data Lokasi dan Rencana Abutment
Data lokasi dapat dilihat pada gambar 4.1. Ketentuan abutment sebagai berikut :
a. Tipe Abutmen = Cantilever Retaining Wall (CRW) tanpa angkur dan counterfort.
b. Tinggi Abutment = 7 m
c. Pondasi = sumuran
d. f’c = 25 MPa
e. fy = 390 MPa
f. γ beton = 2,4 t/m3
g. kedalaman muka air tanah = -3,0 m
Gambar 4.1 Topografi dan Rencana Abutment
ANALISIS STRUKTUR JEMBATAN
PERENCANAAN ABUTMENT
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4.3 Analisi Data Tanah
Koefisien tanah aktif (tekanan tanah pasif diabaikan)
Ka = tan2 (45o – ϕ/2)
= tan2 (45o – 30o/2) = 1/3
Data karakteristik tanah
a. γ tanah = 1,90 ton/m3
b. Sudut gesek tanah = 30o
c. Kadar air ( w ) = 0,25
d. Angka pori ( n ) = 0,43
Berat Jenis tanah adalah sbb :
γk = γs (1 - n)
= 1,90 (1 - 0,43) = 1,0830 t/m3
γb = γk (1 + w)
= 1,0830 (1 + 0,25) = 1,3538 t/m3
γsat = γk + n
= 1,0830 + 0,43 = 1,5130 t/m3
γ’ = γsat - 1
= 1,5130 - 1 = 0,5130 t/m3
4.4 Analisa Mekanika
Gambar 4.2 Diagram tekanan tanah aktif dan pembebanan abutment
ANALISIS STRUKTUR JEMBATAN
PERENCANAAN ABUTMENT
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h = 7 m P = 4,36364 t γk = 1,0830 t/m3 h1 = 3 m Q = 0,8000 t/m2 γb = 1,3538 t/m3 h2 = 4 m γsat = 1,5130 t/m3 γ’ = 0,5130 t/m3
h’ = l tan (45o +ϕ/2) – l tan ϕ
= 2,5 tan (45 o +30 o/2) – 2,5 tan 30 o
= 4,33 – 1,44 = 2,89
Tekanan tanah aktif
Ea1 = h q Ka Ea4 = ½ h22 γw
Ea2 = ½ h12 γb Ka Ea5 = ½ h2
2 γ’ Ka
Ea3 = h1 h2 γb Ka Ea6 = ½ P aK h’
Tabel 4.1 Perhitungan Gaya Horisontal (Ea) dan Momen (t-m), ditinjau untuk tiap 1 m
h b Ka H (ton) ke A (m) Momen (t-m) Akibat beban merata
1 7 0,8000 1/3 b h Ka 1,8667 3,5000 6,5334 2 3 4,0614 1/3 ½ b h Ka 2,0307 5,0000 10,1535 3 4 4,0614 1/3 b h Ka 5,4152 2,0000 10,8304 4 4 4,0000 - ½ b h 8,0000 1,3333 10,6664 5 4 2,0520 1/3 ½ b h Ka 1,3680 1,3333 1,8240
Akibat baban titik 6 2,89 2,5193 ½ b h 3,6404 4,5967 16,7338
22,3210 56,7415
Tabel 4.2 Perhitungan Gaya vertikal dan Momen (t-m) Abutment
h b A (m2) 1 0,3 0,5 0,15 2 1,1 0,8 0,88 3 1,6 0,8 0,64 4 4,8 0,8 3,84 5 0,8 6,0 4,80
Σ A = 10,31 Titik berat abutment, x = 2,881 m
y = 2,317 m
Berat abutment = 10,31 × 1,0 × 2,4 = 24,7440 ton
Momen terhadap pusat dasar abutment = 24,7440 × ( 3,0 – 2,881 ) = 2,9445 t-m
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PERENCANAAN ABUTMENT
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Tanah pengisi
Berat (ton) Lengan (m) Momen (t-m) a 1,8 × 0,3 × 1,0 × 1,90 = 1,0260 2,10 2,1546 b 0,3 × 0,3 × 1,0 × 1,90 = 0,1710 1,05 0,1796 c 1,8 × 1,1 × 1,0 × 1,90 = 3,7620 2,10 7,9002 d 1,8 × 1,6 × 1,0 × 1,90 = 5,7420 2,10 11,4912 e ½ 0,8 × 1,6 × 1,0 × 1,90 = 1,2160 0,93 1,1309 f 2,6 × 3,2 × 1,0 × 0,5130 = 4,2682 1,70 7,2559
= 16,1852 30,1121
A. Kontrol Tegangan tanah
Kontrol tegangan tanah di dasar abutment sebelum jembatan dipasang
V = 24,7440 + 16,1852 = 40,9292 ton
M = - 2,9445 - 30,1121 + 56,7415 = 23,6849 t-m
A = 6 × 1 = 6 m2
W = 1/6 × 1,0 × 62 = 6 m3
WM
AV±=σ
7690,106
23,68496
40,9292=+=maksσ t/m2
8741,26
23,68496
40,9292min =−=σ t/m2
Kontrol tegangan-tegangan tanah di dasar abutment setelah jembatan dipasang
Kombinasi 1 (100% qa)
Jarak titik berat beban mati dan beban hidup terhadap titik berat tumpuan = 3,0-2,881 = 0,119 m
Beban V (ton) M (t-m) Mati 19,4863 2,3187Hidup 24,0489 2,8618 Abutment 24,7440 - 2,9445Tanah pengisi 16,1852 - 30,1121Tekanan tanah aktif 56,7415 84,4644 28,1909
7759,1861909,28
64644,84
=+=maksσ t/m2
ANALISIS STRUKTUR JEMBATAN
PERENCANAAN ABUTMENT
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3789,961909,28
64644,84
min =−=σ t/m2
di dasar sumuran, Berat jenis beton siklop = 2,2 t/m3
( ) ( )( )6
2,266,06,5166
5130,066,06,564644,84 ×××−×
+×××
+=maksσ
6091,218080,57237,10774,14 =++=maksσ t/m2 < qa = 2,25 kg/cm2 (22,5 t/m2)
Kombinasi 2 (125% qa)
Jarak titik berat beban mati dan beban hidup terhadap titik berat tumpuan = 3,0-2,881 = 0,119 m
gaya memanjang karena gesekan tumpuan = 0,25 × M = 0,25 × 19,4863 = 4,8716 ton
Momen = 4,8716 × 0,119 = 0,5797 tm
Beban V (ton) M (t-m) Mati 19,4863 2,3187 Abutment 24,7440 - 2,9445Tanah pengisi 16,1852 - 30,1121Tekanan tanah aktif 56,7415F 0,5797 60,4155 26,5833
4998,1465833,26
64155,60
=+=maksσ t/m2
6387,565833,26
64155,60
min =−=σ t/m2
didasar sumuran, Berat jenis siklop = 2,2 t/m3
( ) ( )( )6
2,266,06,5166
5130,066,06,564155,60 ×××−×
+×××
+=maksσ
6010,178080,57237,10693,10 =++=maksσ t/m2 < 1,25 qa = 2,8125 kg/cm2 (28,125 t/m2)
B. Kontrol Stabilitas terhadap Penggulingan
Momen yang menggulingkan = 56,7415 + 0,5797 = 57,3212 tm
Momen yang menahan guling (titik penggulingan pada tepi luar)
a. Abutment = 24,7440 × (6 – 2,881) = 77,1765 tm b. Tanah pengisi = 30,1121 tm c. Mati = 19,4863 × 3 = 58,4589 tm d. Hidup = 24,0489 × 3 = 72,1467 tm = 237,8942 tm
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Angka keamanan terhadap penggulingan, n = 15,43212,578942,237
= > 1,5 O K
C. Kontrol Stabilitas terhadap Penggeseran
Gaya geser = 22,3210 ton
Gaya geser penahan = Σ V tan ϕ (diasumsikan ϕ = 30o)
= (24,7440 + 16,1852 ) tan 30o
= 23,6305 ton
Angka keamanan terhadap penggeseran, n = 06,13210,226305,23
=
4.5 Penulangan Abutment A. Penulangan Titik I
Tabel 4.3 Perhitungan Gaya Horisontal (Ea) dan Momen (t-m), ditinjau untuk tiap 1 m thd ttk I
h b Ka H (ton) ke I (m) Momen (t-m) Akibat beban merata
1 6,2 0,8000 1/3 b h Ka 1,6533 3,1000 5,1252 2 3 4,0614 1/3 ½ b h Ka 2,0307 4,2000 8,5289 3 3,2 4,0614 1/3 b h Ka 4,3322 1,6000 6,9315 4 3,2 4,0000 - ½ b h 6,4000 1,0667 6,8269 5 3,2 2,0520 1/3 ½ b h Ka 1,0944 1,0667 1,1674
Akibat baban titik 6 2,89 2,5193 ½ b h 3,6404 3,7967 13,8215
42,4014
Perhitungan baja tulangan
M = 424,0140 KNm h = 800 mm ρperlu = 2,5410 × 10-3 d = 740 mm Asperlu = 2656,3780 mm2 k = 0,9679 MPa Tulangan pokok = ∅16-75 ρb = 0,028069 Asterpakai = 2800,8253 ρmaks = 0,02105175 Tulangan bagi = ∅16-250 ρmin = 3,5897 × 10-3
ANALISIS STRUKTUR JEMBATAN
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B. Penulangan Titik J
Tabel 4.4 Perhitungan Gaya Horisontal (Ea) dan Momen (t-m), ditinjau untuk tiap 1 m thd ttk J
h b Ka H ke J (m) Momen (tm)Akibat beban merata
1 3,0 0,8000 1/3 b h Ka 0,8 1,5000 1,2000 2 3,0 4,0614 1/3 ½ b h Ka 2,0307 1,0000 2,0307
Akibat baban titik 6a 1,56 1,3599 ½ b h 1,0607 1,04 1,1031 6b 1,56 1,1594 b h 1,8087 0,78 1,4108
5,7446
Perhitungan baja tulangan
M = 57,4460 KNm h = 800 mm ρperlu = 3,3720 × 10-3 d = 740 mm Asperlu = 2656,3780 mm2 k = 0,1311 MPa Tulangan pokok = ∅16-75 ρb = 0,028069 Asterpakai = 2800,8253 ρmaks = 0,02105175 Tulangan bagi = ∅16-250 ρmin = 3,5897 × 10-3
C. Penulangan Titik K
Tabel 4.5 Perhitungan Gaya Horisontal (Ea) dan Momen (t-m), ditinjau untuk tiap 1 m thd ttk K
h b Ka H ke J (m) Momen (tm)Akibat beban merata
1 1,4 0,8000 1/3 b h Ka 0,3733 0,7000 0,2613 2 1,4 4,0614 1/3 ½ b h Ka 0,9477 0,4667 0,4423
0,7036
Perhitungan baja tulangan
M = 7,0360 KNm h = 500 mm ρperlu = 1,1653 × 10-4 d = 440 mm Asperlu = 1579,4680 mm2 k = 0,0454 MPa Tulangan pokok = ∅16-125 ρb = 0,028069 Asterpakai = 1680,4952 ρmaks = 0,02105175 Tulangan bagi = ∅16-250 ρmin = 3,5897 × 10-3
ANALISIS STRUKTUR JEMBATAN
PERENCANAAN ABUTMENT
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D. Penulangan Dasar Abutment
7039,143970,964,33789,91 =+=y t/m2
4509,133970,966,23789,92 =+=y t/m2
bagian depan dinding
( ) ⎟⎠⎞
⎜⎝⎛ ×
×××−×+⎟⎠⎞
⎜⎝⎛ ×××=
36,226,20,17039,147759,18
21
26,26,20,17039,14maksM
= 49,6992 + 9,1756 = 58,8748 tm
Perhitungan baja tulangan
M = 588,7480 KNm h = 800 mm ρperlu = 3,5623 × 10-3 d = 740 mm Asperlu = 2656,3780 mm2 k = 1,3439 MPa Tulangan pokok = ∅16-75 ρb = 0,028069 Asterpakai = 2800,8253 ρmaks = 0,02105175 Tulangan bagi = ∅16-250 ρmin = 3,5897 × 10-3
bagian belakang dinding
1.momen akibat tanah pengisi
Berat (ton) Lengan (m) Momen (t-m) a 1,8 × 0,3 × 1,0 × 1,90 = 1,0260 1,70 1,7442 b 0,3 × 0,3 × 1,0 × 1,90 = 0,1710 0,65 0,1112 c 1,8 × 1,1 × 1,0 × 1,90 = 3,7620 1,70 6,3954 d 1,8 × 1,6 × 1,0 × 1,90 = 5,7420 1,70 9,7614 e ½ 0,8 × 1,6 × 1,0 × 1,90 = 1,2160 0,5333 0,6485 f 2,6 × 3,2 × 1,0 × 0,5130 = 4,2682 1,30 5,5487
= 16,1852 24,2094
2. momen akibat berat abutment
= 24,7440 × ( 2,881 – 2,6 ) = 6,9531 t-m
18,7759
9,3789
y2 y1
0,8 m 2,6 m 2,6 m
ANALISIS STRUKTUR JEMBATAN
PERENCANAAN ABUTMENT
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3. momen akibat tekanan tanah
h b Ka H (ton) ke I (m) Momen (t-m) Akibat beban merata
1 6,2 0,8000 1/3 b h Ka 1,6533 3,1000 5,1252 2 3 4,0614 1/3 ½ b h Ka 2,0307 4,2000 8,5289 3 3,2 4,0614 1/3 b h Ka 4,3322 1,6000 6,9315 4 3,2 4,0000 - ½ b h 6,4000 1,0667 6,8269 5 3,2 2,0520 1/3 ½ b h Ka 1,0944 1,0667 1,1674
Akibat baban titik 6 2,89 2,5193 ½ b h 3,6404 3,7967 13,8215
42,4014
Momen total = 42,4014 – (24,2094 + 6,9531) = 11,2389 tm
Perhitungan baja tulangan
M = 112,3890 KNm h = 800 mm ρperlu = 6,6171 × 10-4 d = 740 mm Asperlu = 2656,3780 mm2 k = 0,2565 MPa Tulangan pokok = ∅16-75 ρb = 0,028069 Asterpakai = 2800,8253 ρmaks = 0,02105175 Tulangan bagi = ∅16-250 ρmin = 3,5897 × 10-3
E. Penulangan Sayap
Bentuk garis leleh disederhanakan sebagai berikut :
2,6 m
6,2 m
b
im
im
m
A B
C D
E
ANALISIS STRUKTUR JEMBATAN
PERENCANAAN ABUTMENT
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Perhitungan Gaya Horisontal (Ea) dan Momen (t-m), ditinjau untuk tiap 1 m
h b Ka H (ton) ke I (m) Momen (t-m) Akibat beban merata
1 6,2 0,8000 1/3 b h Ka 1,6533 3,1000 5,1252 2 3 4,0614 1/3 ½ b h Ka 2,0307 4,2000 8,5289 3 3,2 4,0614 1/3 b h Ka 4,3322 1,6000 6,9315 4 3,2 4,0000 - ½ b h 6,4000 1,0667 6,8269 5 3,2 2,0520 1/3 ½ b h Ka 1,0944 1,0667 1,1674
Akibat baban titik 6 2,89 2,5193 ½ b h 3,6404 3,7967 13,8215
42,4014
im = m
3min 105897,3
3904,14,1 −×===
yfρ
As = ρ x b x d = 3,5897 x10-3 x 1000 x 140 = 502,558 mm2
2,910002585,0390502,558
85,0 ' =×××
=××
×=
bffA
ac
ys mm
( )2a
ysu dfAm −××=φ
( ) 2305,2110140390558,5028,0 622,9 =×−×××= − KNm
Bagian CDE
( ) ( ) 321 6,26,2 b
u bqmim ×××=×+
2766,254
bqu = 1)
Bagian ABCE
( ) ( ) ( )( ) 26,2
36,2
21 6,22,66,22,6 ××−+×××=×+ bqbqmim uu
bqu 52,13736,125
5492,1579−
= 2)
1) = 2)
bb 52,13736,1255492,1579766,254
2 −=
02578,320334363,34445492,1579 2 =−+ bb
b = 3,5431 m
ANALISIS STRUKTUR JEMBATAN
PERENCANAAN ABUTMENT
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2943,205431,3
766,2542 ==uq KN/m
Arah CD
( ) 3985,1105431,36,22943,20 35431,3
21 =××××=m KNm (untuk lebar plat 2,6 m)
M = 110,3985 KNm
h = 200 mm d = 200 - 60 = 140 mm
7080,214026008,010 110,3985
2
6
2 =×××
=××
=db
Mkφ
MPa
028069,0
200000390003,0
003,0390
85,02585,0003,0
003,085,0 1'
=+
××
=+
××
=
s
yy
cb
Eff
f βρ
ρmaks = 0,75 ρb = 0,75 x 0,028069 = 0,02105175
3'
'
104534,72585,0
7080,22113902585,0
85,021185,0 −×=⎟⎟
⎠
⎞⎜⎜⎝
⎛×
×−−=⎟⎟
⎠
⎞⎜⎜⎝
⎛−−=
cy
cperlu f
kff
ρ
3min 105897,3
3904,14,1 −×===
yfρ
As = ρ x b x d = 7,4534 x10-3 x 2600 x 140 = 2713,0376 mm2
Dipakai tulangan ∅16 (As = 210,0619 mm2), dengan jarak antar tulangan
3098,2012713,0376
2600210,0619=
×=perlus mm
dipakai tulangan ∅16-200 mm
8047,2730200
2600210,0619=
×=sA mm2
tulangan bagi = 20 % × 2730,8407 = 546,1609 mm2
dipakai tulangan ∅16-250 mm
Arah AC
( ) ( )( ) 2617,2636,22,66,2 26,2
36,2
21 =××−+×××= bqbqm uu KNm (untuk lebar plat 6,2 m)
M = 263,2617 KNm
h = 200 mm d = 200 - 60 = 140 mm
7080,214062008,010 263,2617
2
6
2 =×××
=××
=db
Mkφ
MPa
ANALISIS STRUKTUR JEMBATAN
PERENCANAAN ABUTMENT
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028069,0
200000390003,0
003,0390
85,02585,0003,0
003,085,0 1'
=+
××
=+
××
=
s
yy
cb
Eff
f βρ
ρmaks = 0,75 ρb = 0,75 x 0,028069 = 0,02105175
3'
'
104534,72585,0
7080,22113902585,0
85,021185,0 −×=⎟⎟
⎠
⎞⎜⎜⎝
⎛×
×−−=⎟⎟
⎠
⎞⎜⎜⎝
⎛−−=
cy
cperlu f
kff
ρ
3min 105897,3
3904,14,1 −×===
yfρ
As = ρ x b x d = 7,4534 x10-3 x 6200 x 140 = 6469,5512 mm2
Dipakai tulangan ∅16 (As = 210,0619 mm2), dengan jarak antar tulangan
3098,2016469,5512
6200210,0619=
×=perlus mm
dipakai tulangan ∅16-200 mm
9189,6511200
6200210,0619=
×=sA mm2
tulangan bagi = 20 % × 6511,9189 = 1302,3838 mm2
dipakai tulangan ∅16-250 mm
Tabel 4.6. Penulangan Abutment
Tulangan No. Elemen struktur pokok bagi 1 Dinding (titik I) ∅16-75 ∅16-250 2 (titik J) ∅16-75 ∅16-250 3 Parapet (titik K) ∅16-125 ∅16-250 4 Dasar abutment Bagian depan dinding ∅16-75 ∅16-250 Bagian belakang dinding ∅16-75 ∅16-250 5 Sayap ∅16-200 ∅16-250