soal fisika dan jawaban kelas ii
TRANSCRIPT
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8/9/2019 soal fisika dan jawaban kelas II
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No
.
Standart
Kompetensi
Kompeten
si Dasar
Materi Indikator
Soal
Soal Jawaban Panjang
1.
8. Momentum
Sudut dan
Keseimbanga
n Benda Tegar
8.7
Dinamika
Gerak
Rotasi
Kecepatan
gerak
menggelind
ing benda
pada bidang
miring
Siswa dapat
menentukan
kecepatan
gerak
menggelindi
ng benda
pada bidang
miring jika
diketaui !
" solid c#linder rolls $rom rest down te incline
is %& meters ig. Determine te speed o$ te
c#linder wen it arri'ed at te $oot o$ te
incline(.a. )8*)+ m,s)
b. )7*)8 m,s)
c. )+*)8 m,s)
d. )7*)+ m,s)
e. )%*)7 m,s)
Data - ! %& m g !& m,s)/ ),0 mR)
1roblem - 2b 3"nswer -4p" 5 4ktrans " 5 4krot " 4pB5 4ktrans B 5 4krot B
m g"51
2 m '")5
1
2 /
") m g B 5
1
2 m 'B)5
1
2 /
B)
m g"5 & 5 & & 51
2 m 'B)5
1
2 /
B
)
g" 5+210 'B
)
'B
60010
7
'B )+*)8 m,s)
6adi jawabann#a 9 'B )+*)8 m,s)
)+*)8 m,s)
'B )
2. 10. Fluida
Dinamis
10.9
Penerapa
n hukum
Bernoulli
Kecepata
n pada
tabung
venturi
Sisa
dapat
menentuk
an
kecepatan
pada
salah satu
pipa
tabung
venture.
Tis is in addition to te 'enture meter is
used to determine te $luid $low 'elocit#. /$
:& cm and a densit# o$ !&&& kg,m :
$luid* cross sectional areas "! 0 cm) and
") : cm). ;at is te 'elocit# o$ $luid
$low in cross section "(a. !*8: m,sb. ) m,s
Data - :& "! 0 cm) ") : cm).
1roblem - 2! 3
"nswer -
2! ") 2gh
A1A2
2
3
!*8
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!ika
diketahui
luas area
"1# "2
dan
c. )*:< m,sd. :*!< m,se. 0*% m,s
: = !&>< 2103010
2
(5104)2(3104)2
: = !&>< 23
251089108
2!9)+ = !&>8=6
16108
2! 3,375 !*8: m,s
6adi jawabann#a "9 2! 3,375 !*8: m,s
$.11. %eori
Kinetik &as
11.'(nergi
Dalam
dan
Dera)at
Kebebasa
n
*ata+rataenerg,
kinetic
pada
benda
,ang
memiliki
$ gerak.
Sisa
dapat
menentukan rata+
rata
energ,
kinetic
pada
benda
,ang
memiliki $
gerak.
(ach molecule o- a particular
pol,atomic gas at 1#200 K has three
translational# three rotational# andvibrational degrees o- -reedom is -our
contributes to mechanical energ,. %he
average kinetic energ, per molecule
is.
a. /#/ 10+2$!b. /#9 10+20!c. /#$ 10+20!d. /#0 10+2
!e. /# 10+2$!
Data - T !)&& k K1,3810
23J
K $ !&
1roblem - 4K 3
"nswer -
Ek=f(12 k T)Ek=10( 12 )(1,381023
J
K) (1.200K)=8,3
6adi jawabann#a 9Ek 8,310
20J
Ek
8,3
. 11. %eori
Kinetik &as
11.
Kecepata
n e-ekti-
gas
Kecepata
n e-ekti-
gas
Sisa
dapat
menentuk
an
kecepatan
3alculate the e4ective speed o-
o,gen gas 56 7 $2 kg 8 kmol
situated in the container temperature
2: ; 3. 5K 7 1.$/ < 10+2$ ! 8 K
a. // m8s
Data = 6 7 $2 kg8kmol %7 2:o3 K7!.:8 ? !&>):
6 , K
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e-ekti- gas)ika
diketahui
6 dan %.
b. /' m8sc. / m8sd. /$# m8se. /#9 m8s
1roblem -vRMS
"nswer -
m0=M
NA=
32 kg
kmol
6,021026molekul
kmol
5,311026
kg /molekul
vRMS=3kTm0 =
3(1,381023 JK)(300K)
(5,311026 kgmolekul )483,6m /s
Jadi jawabannya (D) 483,6m /s
'.11. %eori
Kinetik &as
11.1
%ingkat
Keadaan
gas
%ekanan
akhir gas
Sisa
dapat
mentukan
tekanan
akhir gas
)ika
diketahui
%1# P1# >
dan %2.
%he to liters o- gas at a temperature
o- 2: ; 3 and a pressure o- 1 atm is
compressed up to 1 liter at
atmospheric and heated up to the
temperature to 12: ; 3. %he ?nal
pressure o- the gas is
a. 2#/: atmb. 1 atmc. #2 atmd. $ atm
e. 2#: atm
Data - T! )7o 1 ! atm 2 )l T) !)7o
1roblem - 1) 3
"nswer -
P1
.V1
T1=
P2
.V2
T2
P2=
P1
V1
T2
V2 T1=
(1atm ) (2L) (400K)(1L) (300K)
=2,67 atm
Jadi jawabannya (E)
2,67atm
2,
11. %eori
Kinetik &as
11.'
(nergi
dalam
dan
Dera)at
(nergi
Kinetik
*ata+rata
Sisa
dapat
menentuk
an (nergi
kinetic
Determine te a'erage kinetic energ# and
energ# in 0 mol ideal gas at a temperature o$
!)7o i$ te gas is-a.gas monatomic@ b.gas diatomic k !.:8 =!& >
): 6 , K@NA %.&) =!&)%molecules , mol 9.
Data - n 0 mol@ T !)7o k !.:8 =!& >): 6 , K@NA %.&)
=!&)%molecules , mol
1roblem - a9 4K gas monoatomik
b9 4K gas diatomic
"nswer -
d9 ).olume
akhir gas
Sisa
dapatmenentuk
an volume
akhir gas
)ika
diketahui
,gen gas at a temperature o- 2: ; 3
has a volume o- 0 dm$ and apressure o- 1.01 < 10' @8m2. Ehat is
its volume hen the pressure is 1 raksa !:.%&& kg,m:
>raksa 7% cm &*7% m
1 E . g . !:.%&& ? +*8 ? &*7% !&!.)+)*8 C,m)
v=3P
v=3(101.292,8 Nm2 )
1,251kg
m3
v=492,8m /s
92#/
10 11. %eori
Kinetik &as
11.2
Persama
an
Gmum
%ekanan
gas
Sisa
dapat
menentuk
an
o man, moles o- gas pressure o-
10 ho are in a tank that has a
volume o- 100 liters# i- the
temperature is /: ; 3 and g 7 9./
Data-n !& mol2 !&& Fiter &*! m:
T 87A :%& K
2,96
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%ingkat
Keadaan
&as
tekanan
gas )ika
diketahui
n# > dan %
m8s2Ca. )*7 atmb. )*+% atmc. ) atmd. !*%7 atm
e. :*: atm
1roblem - 1 . . . 3
"nswer -
PV= R T ! P= R T
V
P=(10) (8.314)(360)
0,1
P=299,304 C,m)
P= 299,304
13.600 (9,8) (0,76)
P=2,96atm
No. Standart
Kompetensi
Materi Indikator
Soal
Soal Jawaban Panjang Jawaban
Pendek
Aspek
Intelektual!. 8.7 Dinamika
Gerak Rotasi
Kecepatan
gerakmenggelind
ing benda
pada bidang
miring
Siswa dapat
menentukankecepatan
gerak
menggelindi
ng benda
pada bidang
miring
" solid c#linder rolls $rom restdown te incline is %& meters ig.
Determine te speed o$ te c#linder
wen it arri'ed at te $oot o$ te
incline(.
$. )8*)+ m,s)
g. )7*)8 m,s)
. )+*)8 m,s)
i. )7*)+ m,s)
j. )%*)7 m,s)
4p" 5 4ktrans " 5 4krot " 4pB5 4ktrans B 5 4krot B
m g"51
2 m '")5
1
2 /
") m g B
51
2 m 'B)5
1
2 /
B)
m g"5 & 5 & & 51
2 m 'B) 5
1
2 /
B)
g" 5+2
10 'B)
'B )+*)8 m,s)
9
:
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'B 60010
7
'B )+*)8 m,s)
6adi jawabann#a 9 'B )+*)8 m,s)
)+*)8 m,s)
).
!&.+
1enerapan
ukum
Bernoulli
Kecepatan
pada tabung
'enturi
Siswa dapat
menentukan
kecepatan
pada sala
satu pipa
tabung'enture.
Tis is in addition to te 'enture
meter is used to determine te $luid
$low 'elocit#. /$ :& cm
and a densit# o$ !&&& kg,m: $luid*
cross sectional areas "! 0 cm)and
") : cm). ;at is te 'elocit# o$
$luid $low in cross section "(
$. !*8: m,sg. ) m,s. )*:< m,si. :*!< m,sj. 0*% m,s
2! ") 2gh
A1A2
: = !&>< 2103010
2
(5104)2(3104)2
: = !&>< 23
251089108
2!9)+ = !&>8=
6
16108
2! 3,375 !*8: m,s
6adi jawabann#a "9 2! 3,375 !*8: m,s
2!
3,375
!*8: m,s
"9
:
:. !!.0 4nergi
Dalam dan
Derajat
Kebebasan
Rata>rata
energ#
kinetic pada
benda #ang
memiliki :gerak.
Siswa dapat
menentukan
rata>rata
energ#
kinetic padabenda #ang
memiliki :
gerak.
4ac molecule o$ a particular
pol#atomic gas at !*)&& K as tree
translational* tree rotational* and
'ibrational degrees o$ $reedom is
$our contributes to mecanicalenerg#. Te a'erage kinetic energ#
per molecule is(.
$. 8*8 = !&>):6g. 8*+ = !&>)&6. 8*: = !&>)& 6i. 8*& = !&>)
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j. 8*% = !&>):6
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)& = !&>:I 2 !"#$2 N.m
7.Rotation
D#namics
Total
energ#
kinetic in
rolling
To anal#He
te total
energ#
kinetic o$
rolling object
" solid c#linder is rolling on a $lat
$loor wit 'elocit# !& m,s. Mass o$
te solid c#linder is < kg and te
diameter is 8& cm. Determine te
total kinetic energ# o$ te solid
c#linder -
". :&& 6B. :& 6. :&&& 6D. ::&& 64. : 6
Data - Solid c#linder
' !& m,s
m < kg
/ 1
2 mr)
d 8& cm r
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B.R
#
.6R
#
D.#R
3
4.
4R
#
R
1
632 # R . R
R2
1
3# R
3R
#
+. Oluid Statics
Fiuid
le'er rise in
capillar#
To anal#He
te distance
o$ te center
o$ gra'it#Mercur# as a densit# o$ !:*%
g,cm:. "t te mercur# placed te
small tube wit diameter 0 mm. /t
turns out tat te mercur# in te
tube ) cm lower tan te mercur#
in te outer tube. /$ te contact
angle is !)7Q
* ow muc doessur$ace tension o$ mercur#3
". 0%*7 C,mB. 0*00% C,m. 0*%7 C,mD. 0*7% C,m4. 0*%& C,m
Data - Em !:*% g,cm: !:%&& kg,m:
d 0 mm 0=!&>:m r )*0=!& >:m ) cm )=!& >)m
!)7Q g !& m,s)
1roblem- 3
"nswer - 2&cos'
g"
)=!&>)
2 . &cos127
13600 .10.2,5x103
)=!&>). !:%&& . !& . )*0=!&>: 2 . &0,6
%*8 >!*) &
& 6,8
1,2
& & $()*+ N,m & ()*+ N,m
&
0*%7 C,m9
!&. Oluid Statics 1ascalUs
Faw
To anal#He
te
application
o$ 1ascalUs
law
" c#lindrical #draulic pump wit
eac diameter 8 cm and )& cm. /$
te small tube pressed wit $orce
0&& C* ten te $orce tat can be
produced b# te big tube is -
". :*!)0 CB. :!)0 C. :)!0 C
Data - d! 8 cm r < cm &*&< m
d) )& cm r !& cm &*! m
O! 0&& C
1roblem - O)3
"nswer -(1
A1 (2
A2
O) :!)0 CB9
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D. :!)*0 C%. :)*!0 C
(1
# "2
(2
# "2
500
#0,042
(2
#0,12
500
0,0016 (2
0,01
&*&&!%O) 0
O)5
0,0016
O) '"2( N
!!.Oluid
D#namics
Te
principle o$
continuit#
To anal#He
te diameter
o$ pipe basic
on principle
o$ continuit#Te 'elocit# o$ water in a pipe wit
diameter % cm is &*)0 m,s. Tat te
water out wit speed < m,s* te pipemust be connected wit anoter
pipe* wic one end is a smaller
diameter. So* te diameter o$ tat
pipe is3
". !0 cmB. !0=!&>0cm. !0=!&>:cmD. !*0 cm4. !0& cm
Data - d! % cm %=!&>)m r :=!&>)m
'! &*)0 m,s ') < m,s
1roblem - d)3
"nswer - "!. '! "). ')
#
r!)
. '!
#
r))
. ')
# :=!&>)9). &*)0
# r) . : m
d & 2 ! +)(!"#$'
& #)#"( m & ")( -m
d !*0 cm
D9
!). Oluid
D#namics
Generator
e$icienc#
To calculate
a'erage
power in
application
o$ $luid
" water$all wit ig )& m is used
$or #dropower 1FT"9. 4'er#
second te water $lowing at !& m :.
/$ te generator e$$icienc# 00V and
acceleration o$ gra'it# g !& m,s)*
Data - )& m
E !&&& kg,m:
g !& m,s W 00V 2 !& m:
1listrik
!!&& k;
B9
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d#namics
so te a'erage power tat can be
produced is - in k;9
". !!&B. !!&&. ))&&D. )0&&4. 00&&
1roblem - 1listrik3
"nswer - X V
t 10
1 !& m:,s
1 W E X g 00V !&&& !& !& )&
&*00 !&&& !& !& )&
!!&&&&& ;
Plistrik& ""## k
!:.Kinetic Gas
Teor#
"'erage o$
kinetic
energ#
To anal#He
te a'erage
o$ kinetic
energ#
/n a bo=* its contents &*0 m:. Tere
are !&0 gas particle. /$ te gas
pressure is ! atm* ow muc te
a'erage kinetic energ#3
". &*70 k6B. 70 6. 70&&& k6
D. 70& 64. &*70 6
Data - 2 &*0 m:
C !&0
1 ! atm !&0Cm)
1roblem - 4kY3
"nswer - 12 1
3 C m ')
&1
3 1
2 m ')C
12 2
3 4kC
4k3PV2N
310
50,5
2105
4k &*70 6
4k &*70 6
49
!
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2x 10
6
33,24x 105
E &*% kg,m:
!0.Kinetic Gas
Teor#
/n energ# o$
ideal gas
To calculate
te in energ#
o$ ideal gasCeon Ce9 is monoatomic gas. ow
muc te in energ# o$ ) gram Ce
gas at temperature 0&Q i$ relati'e
molecular mass Mr !& kg,kmol3". 8&0)*< 6B. 8&*0)< 6. 8*&0)< 6D. 8&0)< 64. 8&0*)< 6
Data - m ) gram )=!&>:kg T 0&Q :):QK
Mr !& kg,kmol3
R 8*:! Z !&:6,kmol K1roblem - P3
"nswer - n
m
M"
2x103
10 )=!&>