perhitungan sag kabel
TRANSCRIPT
BARE CONDUCTOR ACSR SPLN 435/55 (PT KABELINDO MURNI)Tegangan maksimum konduktor yang diizinkan (Kg) : 3,400.00 Diameter konduktor (mm) : 28.80 Berat Konduktor (kg/m) : 1.67 Luas penampang Alumunium (mm^2) : 434.30 Luas penampang kawat baja (mm^2) : 56.30
: 7,000.00 : 1.93E-05
Solusi :1 kg = 1 kgf = 9.81 Ndc = overall diamter of conductor (mm) = 28.80 mm²Leq = Ekuivalen Span atau Rulling Span = 152.000 meterA = Conductor Area (mm2) ( Al Area + St Area ) = 490.600 mm²t0 = Basic temperature = 20.00 °Cw0 = Basic weight per length of conductor at basic temperature (t1) = 1.67 kg/mt1 = Initial condition temperature = 10.00 °Ct2 = Final condition temperature = 80.00 °Cε = Linear coeffecient of expansion = 0.000019 1/°CE = Modulus elasticity of conductor (N/mm²) = 68,670.00 N/mm²P = Wind pressure (kg/m²) = 40.00 kg/m²
wp = wind load = P . (dc / 1000) = 1.15 kg/mwe = Effective weight of conductor per unit length = √ (wp² + wo²) = 2.0271 kg/m
= Basic weight per length of conductor at initial temperature (t1) = 2.0275 kg/m = we / lt 1 (at initial temperature)
lt 1 = lo (1 + ε (t1-to)) = 1 x (1 + 0.0000193 ( 10 - 20 )) = 1 x 0.999807
lt 1 = 0.999807 m = Basic weight per length of conductor at final temperature (t2) = 2.0252 kg/m = w1 / lt 2 (at final temperature)
lt 2 = lo (1 + ε (t1-to)) = 1 x (1 + 0.000019 ( 80 - 20 )) = 1 x 1.001158
lt 2 = 1.001158 m = Initial condition weight of conductor per unit volume = 0.04054 N/mm².m = (lt 1 x g)/ A = Final condition weight of conductor per unit volume = 0.04050 N/mm².m = (lt 2 x g)/ A
σ1 = Initial condition tension of conductor (Max. Working Tension) = 67.986 N/mm²= (max tension x gravity) / total area = 3,400.00 x 9.81 / 490.60 = 67.986 N/mm²
σ2 = Final condition tension of conductor (Max. Working Tension) = 38.416 N/mm²Stress = (Final tension x Total Conductor Sectional Area) / Gravity
= 38.42 x 490.60 / 9.81 = 1,921.183 N/mm²
σ2 value obtain form equationwhere:
Modulus elastisitas konduktor (kg/mm2) Koefesien muai panjang (1/derajat Celsius)
w1
w2
y1
y2
A = 5.32 B = 943.66
Y(σ2) ==> σ2^3 + 5.32 σ2^2 - 943.7 = 0 Y'(σ2) ==> 3σ2^2 + 10.64 σ2 = 0
Newton - Rhapson Iteration (trial error method)langkah σ2 Y'(σ2) Y (σ2) σ2+1
1 39 4,978.136 66,470.490 25.648 2 38.5 4,856.564 64,011.878 25.320 3 38.42 4,837.251 63,624.126 25.267 4 38.416 4,836.287 63,604.779 25.264 5 38.4159 4,836.262 63,604.295 25.264 6 38.41582 4,836.243 63,603.908 25.264 7 38.415819 4,836.243 63,603.903 25.264 8 38.4158196 4,836.243 63,603.906 25.264 9 38.41581965 4,836.243 63,603.906 25.264
S max =
= 3.0460 meter
Andongan min = 1.7222 Tegangan tarik kabel t0 = 3,403.49 Tegangan tarik kabel t max 1,920.16
N/mm².m
N/mm².m
350 280
48 43
48.35 43.348.353 43.3248.3531 43.32748.35312 43.327648.35315 43.32766
48.353157 43.32766848.3531574 43.3276684
48.35315745 43.32766843