pengumpulan data sebagai berikut

7/25/2019 Pengumpulan Data Sebagai Berikut

1/31

Pengumpulan data sebagai berikut :

a. Data bahan

- Mutu beton ( fc' ) = 27,5 MPa

- Mutu baja ( fy ) = 240 Mpa

- E baja = 210.000 Mpa

- E beton = 4700 fc = 24647 Mpa

b. Data beban

a. Beban mati ( WD )

- eban !en"#$# beton be$tu%an& = 2400 &2

- Ete$n#t "an pen&&antun& 0,07 * 0,11 = 1+ &2

- pe!# t#ap 1 c = 21 &2

- -e$a# t#ap 1 c = 24 &2

- D#n"#n& bata t#ap 1 ete$ = 250 &

- Penutup atap &enten& = 50 &2

b. Beban hidup ( WL )

- Muatan h#"up tepat u$!u! = 250 &2

c. Dimensi

/ eba% p%at %anta# = 12 c

/ eba% p%at tan&&a= 15 c

Menentukan beban yang bekerja pada pelat lantai

Beban mati ( WD )

- eban !en"#$# pe%at = 0,12 24 = 2,++0 2

- P%afon "an pen&&antun& = 0,07 * 0,11 = 0,1+0 2

- pe!# 2 c = 0,02 0,21 = 0,004 2

- -e$a# = 0,5 0,24 = 0,12 2

3,1+4 2

Beban hidup ( WL )

- Muatan h#"up = 250 &2 = 2,500 2

Mencari Q ekuivalen

D# t#njau t#ap %anta#

eu#a%en !e t#&a = 23 . h


2/31

eu#a%en t$ape!#u = ( 1 13 (lx

ly)2. h )

ype = ( 1 13 (lx

ly)2. h )

= ( 1 13 (1

4 )2. 0.5 )

= 1,667

ype = 23 . h

= 23 . 0.5

= 0,333

ype 8 = ( 1 13 (lx

ly)2. h )

= ( 1 13 ( 5,34 )2. 1,75 )

= 0,23+

ype D = 23 . h

= 23 . 1,75= 1,167

ype E = 23 . h

= 23 . 2

= 1,333

ype 9 = ( 1 13 ( lxly

)2

. h )

= ( 1 13 ( 45 )2. 2 )

= 0,042

Pendimensian Balok

a%o #n"u


3/31

h = :15

1!" :

10

1 = 00+

15

1 !" +00

10

1 = 53,33 !" +0

c

"#ab#% h = 60 c

b = h3

2!("h

2

1= 06

3

2!("60

2

1= 30 !" 40 c

"#ab#% b = 30 c

;a"# "#en!# ba%o "#$encanaan 30 60 c

a%o ana

h = :15

1!" :

10

1 = 005

15

1!" 500

10

1= 33,33 !" 50 c

"#ab#% h = 40 c

b = h3

2!("h

2

1= 40

3

2!("40

2

1= 20 !" 26,66 c

"#ab#% b = 20 c

;a"# "#en!# ba%o "#$encanaan 40 65 c

1) Perhitungan Tangga

a. ata Tangga an Bordes#n& %anta# = 350 c


4/31

;a$a $on&&a anta$ tan&&a = 20 c

12 #n& %anta# = 200 c

:eba$ tan&&a =2

20350= 165 c

:eba$ ant$e"e (#njaan) = 30 c

;u%ah ant$e"e (#njaan) =30

270 = < buah

;u%ah opt$e"e (!an"un&an) = < * 1 = 10 buah

#n& opt$e"e (!an"un&an) =10

175 = 17,5 c

Panjan& tan&&a = 270 c

Panjan& bo$"e! = 130 c

-ont$o% te$ha"ap !ya$at ana tan&&a

Den&an

(ant$e"e) = 30 c

> (opt$e"e) = 20 c

2. (>) * = 75 c

2. (20) * 30 = 70 c ????.. >- @

#n& %anta# tan&&a 1 = 175 c

#n& %anta# tan&&a 2 = 350 175 12 = 163 c

0


5/31

ABAC

BC

tey

b. !nalisa Tebal Plat

1. P%at tan&&a

88 = c)12,51

035,1730A17,5

8.8t

t

22=

+==

eyt = c)0+,0115,123

2.t3

2 ==

eba% p%at eB#a%en = 12 * tey= 12 * 10,0+ = 22,0+ c = 0,220+

2. P%at o$"e!

eba% p%at bo$"e! "#ab#% 12 c.

c. Pembebanan

Tangga

a. eban Mat#

e$at !en"#$# p%at = 1 0,220+ 24 3 = 5,2


6/31

b. eban C#"up

B:1 = 1 3 2= 3 ( 3 o$an& be$"ap#n&an )

c.eban e$fato$

u1 = 1,2. BD1 * 1,6. B:1

= 1,2. 5,+4< * 1,6. 3 = 11,+1<

Bordes

a. eban Mat#

e$at !en"#$# p%at = 1 0,12 24 3 = 2,++0

e$at e$a# (0,5 c) = 1 0,24 2 0,5 = 0,120

e$at !pe!# (2 c) = 1 0,21 2 2 = 0,420

BD2 = 3,420 b. eban C#"up

B:2 = 1 3 2= 3

c.eban e$fato$

u2 = 1,2. BD2 * 1,6. B:2

= 1,2. 3,420 * 1,6. 3

= +,


7/31

a). Moen pe%at tan&&a

Mtup1 = 12,


8/31

=

27,5

2401,1+

232,227,5

2402,36240240

2

22

= 0,00


9/31

Fat =

'

c

2

'

c

2

2

yy

f

f.1+,1

.f

f.36,2ff

y

y

=

27,5

2401,1+

20+,127,5

2402,36240240

2

22

= 0,0052

"#paa# F#n= 0,005+

:ua! tu%an&an ! = F#n.b."

= 0,005+ 1000 +5

= 4


10/31

PEKE8 P:

Ly = 500

Lx=400

1) Pe$encanaan pe%at %anta# uu$an 500 400 c

:y = 500 c

: = 400 c

Mu%t Moen-

( Mpa )F#n F

!

( 2)

u%an&an

e$pa!an&

! te$pa!an&

( 2)

Mtp1 12,


11/31

225,1400

500

:

:y>== ( "#h#tun& !eba&a# pe%at "ua a$ah )

2) Menentuan teba% pe%at (Dua a$ah ene$u!)

h = 700

fy

0,42+

:

+

h =700

2400,4

2+

5000+ = 72,014

eba% pe%at "#ab#% = 120

3) Pebebanan

Beban mati ( WD )

- eban !en"#$# pe%at = 0,12 24 = 2,++0 2

-

P%afon "an pen&&antun& = 0,07 * 0,11 = 0,1+0 2

- pe!# 2 c = 0,02 0,21 = 0,004 2

- -e$a# = 0,5 0,24 = 0,12 2

3,1+4 2

Beban hidup ( WL )

- Muatan h#"up = 250 &2 = 2,500 2

= 1,2 D* 1,6 :

= 1,2 3,1+4 * 1,6 2,50 = 7,+21 2

4) Men&h#tun& oen yan& bee$ja "en&an eto"a

pen"eatan oen

Ly=500

Mt = 116 . . :2

= 116 . 7,+21. 5002

= 12,220

Mt = 1< . . :2

= 1< . 7,+21. 5002


12/31

= 21,725

M%ap = 114 . . :2

= 114 . 7,+21. 5002

= 13,


13/31

entuan ( ) yan& "#pe$%uan

= 2"b

Mu

= 6


14/31

= 0,0025.1000.120 = 300 2

atau

!!u! = 20Q . ! poo

= 20Q . 551 = 110,2 2

D#paa# tu%an&an L 10 250 J ! = 314 2

b). upuan

teba% !e%#ut beton = 20

$encana tu%an&an utaa = 10

" efet#f = teba% pe%at teba% !e%#ut beton L tu%an&an utaa

= 120 20 (12 .10)

=


15/31

D#paa# tu%an&an L 10 100 J ! = 7+5,4 2

;a$a a!#u tu%an&an = 3.h atau 500

a= 3.120

= 360 O 100 J >-

Menentuan tu%an&an !uhu "an !u!ut

- /15/1


16/31

=

27,5

2401,1+


17/31

Lx=400

Ly=100

6) Pe$encanaan pe%at %anta# uu$an 100 400 c

:y = 100 c

: = 400 c

24100

400

:

:y>== ( "#h#tun& !eba&a# pe%at !atu a$ah )

7) Menentuan teba% pe%at (atu a$ah ene$u!)

h =700fy0,4

2+: +

h =700

2400,4

2+

1000+ = 14,+71

eba% pe%at "#ab#% = 120

+) Pebebanan

Beban mati ( WD )

- eban !en"#$# pe%at = 0,12 24 = 2,++0 2

- P%afon "an pen&&antun& = 0,07 * 0,11 = 0,1+0 2

- pe!# 2 c = 0,02 0,21 = 0,004 2

- -e$a# = 0,5 0,24 = 0,12 2

3,1+4 2

Beban hidup ( WL )

- Muatan h#"up = 250 &2 = 2,500 2

= 1,2 D* 1,6 :

= 1,2 3,1+4 * 1,6 2,50 = 7,+21 2


18/31

Lx=400

Mt = 116 . . :2

= 116 . 7,+21. 4002

= 7,+21

Mt = 1< . . :2

= 1< . 7,+21. 4002

= 13,


19/31

=

27,5

2401,1+

0+3,127,5

2402,36240240

2

22

= 0,0046

F#n =fy

1,4

=240

1,4= 0,005+

Fa =

+

fy600

600

fy

fc'0,+50,75

=

+

240600

600

240

+5,05,270,+50,75 = 0,044

J "#paa# F#n

! = F#n. b . "

= 0,005+ . 1000 . -Menentuan tu%an&an !uhu "an !u!ut

- /15/1


20/31

entuan ( ) yan& "#pe$%uan

= 2"b

Mu

=


21/31

= 20Q . 551 = 110,2 2

D#paa# tu%an&an L 10 250 J ! = 314 2

f). :apan&an /

teba% !e%#ut beton = 20

$encana tu%an&an utaa = 10

" efet#f = teba% pe%at teba% !e%#ut beton L tu%an&an utaa

= 120 20 (12 .10)

=


22/31

= 360 O 100 J >-

Menentuan tu%an&an !uhu "an !u!ut

- /15/1


23/31

A eban h#"up = 250 . ( 0,042*0,042 ) = 21 & J :: = 0,21 -

! 3/ 4

A eban at#

/ e$at !en"#$# = b . ( h / t ) . 2400

= 20 . ( 40 0,12 ) . 2400

= 1


24/31

A eban at#

/ e$at !en"#$# = b . ( h / t ) . 2400

= 30 . ( 60 0,12 ) . 2400

= 431,1 &

/ P%at %anta# = 1,333 . 31+,4

= 424,43 &

/ e$at "#n"#n& = 3,00 . 250

= 750 &

/ eban at# = 431,1 * 424,43 * 750

= 1605,53 & J D: = 16,05 -

A eban h#"up = 250 . 1,333 = 333,25 & J :: = 3,33 -

1) Penu%an&an ba%o ana

Pa"a tupuan, ba%o "#$encanaan tupuan pe$!e


25/31

b

h

As

D#$encanaan "#en!# ba%o = 200 400

e%#ut beton = 40

u%an&an utaa = 1<

tu%an&an !en&an& = +

" efet#f = h p / tu%.!en&an& tu%.utaa

= 400 40 +


26/31

D#paa# tu%an&an 3 D 1< = +50,5 2

u%an&an %apan&an ba%o ana

b

h

As


e%#ut beton = 40

u%an&an utaa = 1<



= 400 40 +


27/31

= 0,00


28/31

2) Penu%an&an ba%o #n"u

Pa"a tupuan, ba%o "#$encanaan tupuan pe$!e

b

h

As


e%#ut beton = 40

u%an&an utaa = 25



= 600 40 + 12,5

= 542,00

F#n =fy

1,4

= 240

1,4

= 0,005+

Fa =

+

fy600

600

fy

fc'0,+50,75

=

+

240600

600

240

+5,05,270,+50,75 = 0,044

Menca$# $a!#o tu%an&an

Mu = 22+,+6

= 246,320,+.300.54

.1022+,+6

I.b."

Mu2

6

2 ==

akt =

fc'

fy1,1+

fc'

fy2,36fyfy

2

22

=

27,5

240

1,1+

246,327,5

2402,36240240

2

22

= 0,015


29/31

U#n N Fat N Fa! = 0,005+ N 0,015N 0,044 "#paa# F#n= 0,0015


= 0,015 300 542

= 243


30/31

=

27,5

2401,1+

246,327,5

2402,36240240

2

22

= 0,010

U#n N Fat N Fa! = 0,005+ N 0,010N 0,044 "#paa# F#n= 0,010


= 0,010 300 542

= 1626,00 2

D#paa# tu%an&an 4 D 25 = 1


31/31

D#&unaan !pa!# !en&an& 150 (10 150 ) ya#tu !ejauh y "a$#

tupuan

y =( ) ( )

+0,14+

5+4,+5+0,14++00.5,0..5,0 =

maks

maks

Vu

VcVuL

= 16

pengumpulan data sebagai berikut

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