pelat 2 arah
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PelatTRANSCRIPT
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Fakultas Teknik Sipil dan PerencanaanJurusan Teknik Sipil
Universitas Kristen Petra
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MOMEN-MOMEN YANG BEKERJADAPAT “DIPEROLEH” :
Dengan bantuan Tabel 4.2.b CUR 4atau Tabel 13.3..1 & 13.3.2 PBI-1971
Dengan bantuan Tabel 4.3.b CUR 4
Dengan perhitungan mekanika teknik& “yield-line analysis”.
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CONTOH SOAL :Diketahui :- Pelat t = 120 mm- Beban hidup = 250 kg/m2
- Beban mati selain beratsendiri = 200 kg/m2
- fc’ = 15 MPa- fy = 240 MPaDitanya :
Tentukan tulangan lentur yang dibutuhkan.
lx = 4.00
l y =
6.0
0
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Penyelesaian :
1. Beban-beban yang bekerja :* Beban mati (wD) - berat sendiri pelat : 0.12 x 2400 = 288 kg/m2
- b. mati lain (penutup lantai, ducting ac, pipa-pipa dll) = 200 kg/m2
= 488 kg/m2
* Beban hidup (wL) = 250 kg/m2
* Kombinasi beban :wU = 1.2 wD + 1.6 wL
= 1.2 . 488 + 1.6 . 250= 985.6 kg/m2
2. Perbandingan ly dan lx :
ly 6.00
lx 4.00
= = 1.50
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3. Perhitungan Momen :dengan bantuan Tabel 4.2.b CUR-4
Mlx = 0.001 x wU x lx2 x 45.5
= 0.001 x 985.6 x 4.02 x 45.5= 717.52 kgm = 7.18 kNm
Mly = 0.001 x 985.6 x 4.02 x 16.5= 260.2 kgm = 2.60 kNm
Mtx = - 0.001 x 985.6 x 4.02 x 75= - 1182.72 kgm = - 11.83 kNm
Mty = - 0.001 x 985.6 x 4.02 x 54.5= - 859.44 kgm = - 8.59 kNm
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4. Kebutuhan Tulangan Lentur :dengan bantuan Gambar 5.4.a CUR-4atau Tabel 5.1.a CUR-4Tulangan Lapangan
Arah x : dx = 120 - 20 - ½ . 10 = 95 mm
Mlx = 7.18 kNmdigunakan = 0.0043As = 0.0043 . b . dx
= 408.5 mm2 (10 - 175)
Dengan cara yang sama diperoleh :
dy dx t = 120 mm
Arah Momen As Terhitung TerpasangLap. x 7.18 408.5 (10 - 192) (10 - 175)
y 2.60 170* (10 - 462) (10 - 250)Tump. x - 11.83 693.5 (10 - 113) (10 - 110)
y - 8.59 569.5 (10 - 138) (10 - 130)* Tul. Minimum
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5. Sketsa Pemasangan Tulangan
lx
15
lx
15
10 - 350
10 - 350
lx
14
10
- 5
00
10
- 5
00
8 - 250 8 - 250
8 -
25
0
8 -
25
0
10 - 17510 - 175
10
- 2
50
10
- 2
50
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lx
15
lx
15
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10 - 350
10 - 350
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10
- 5
00
10
- 5
00
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8 - 250 8 - 250
8 -
25
0
8 -
25
0
8 - 250 8 - 250
8 -
25
0
8 -
25
0