Download - fadri
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Labu ukur 100 ml kemudian tambahkan air sampai tanda batas
1,9023 gr KCl/100 Ml larutan, artinya 1,9023 gr kcl dilarutkan pada labu ukur bervolume 100mL, kemudian tambahkan air sampai tanda batas
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gr K2SO4 = n x mr
=0,0128 x 174,2 = 2,23 gr untuk 100 mL Mol K+ = 0,0255
Mol K3Fe(CN)6 = 1/3 x 0,0255 = 8,52 x 10 -3 mol
gr K3Fe(CN)6 = 8,52 x 10 -3 mol x 329,15 = 2,806 gr
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