A. DATA HASIL PENGAMATAN rheologi1. Penentuan kerapatan/bobot jenis zat cairNOURAIANKetkel 1Ketkel 3Ketkel 6Ketkel 8Ketkel 9

1.Bobot piknometer kosongBobot piknometer+airBobot airVolume air10,9020,609,79,72ml

2.Bobot piknometer kosongBobot piknometer+alkoholBobot alkoholBj alkohol10,9019,508,60,88mg/ml

3.Bobot piknometer kosongBobot piknometer+lar gula 20%Bobot lar gula 20%Bj lar gula 20%9,8717,127,391,083mg/ml

4.Bobot piknometer kosongBobot piknometer+lar gula 40%Bobot lar gula 40%Bj lar gula 40%

10,3718,097,221,15mg/ml

5.Bobot piknometer kosongBobot piknometer+lar gula 60%Bobot lar gula 60%Bj lar gula 60%10,9022,7811,881,22mg/ml

6.Bobot piknometer kosongBobot piknometer+CMCBobot CMCBj CMC14,0426,8412,81,012mg/ml

7.Bobot piknometer kosongBobot piknometer+suspensiBobot suspensiBj lar suspense11.5921,409,810,985mg/ml

2. Penentuan viskositas dengan viscometer BrookfieldSampelRpm 10Rpm 20Rpm 30Rpm 50Rpm 60Rpm 100

Air kel 60004,86,679,2

Lar gula 20%1. 02. 02,002,005,335,338,808,8010,010,014,813,6

Lar gula 40%3. 04. 064,08815,215,217,317,322,823,8

Lar gula 60%5. 06. 018,018,020,020,031,231,234,7034,7044,844,8

Alkohol kel 6011,337,2811,6

CMC7. 208. 60406646,769,35677,663,382,072100,4

Suspensi9. 24,010. 24,0 34,032,041,338,754,453,659,358,774,473,6

A. DATA HASIL PENGAMATAN Data pembakuan NaOHN NaOH = 0,1116 NSebelum di oven : X = V NaOH x N NaOH = 18,15 x 0,1116 = 2,025 mmol Data hasil titrasi seletah di oven1 jamVolume asetosalVolume NaOHVolume akhir

10 ml0-21,821,8 ml

10 ml0-43,121,3 ml

X21,55 ml

Asetosal mula-mula (X) = 2,025 mmol Asetosal yang tersisa setelah 1 jam:(x-y) + y + y = ml NaOH x N NaOH x + y = mmol NaOHy = mmol NaOH xy = (V NaOH x N NaOH) (V NaOH x N NaOH)y = (21,55 x 0,1116) (2,025)y = 2,4049 2,025y = 0,3799maka asetosal sisa (Ct) = x y = 2,025 - 0,3799 = 1,6451/mmol

Jika dalam mg/mol : mg = mol x BM asetosal = 1,6451 mol x 180,16 = 296,3812 mg/10ml = 29,6381mg/ml2 jamVolume asetosalVolume NaOHVolume akhir

10 ml0 - 24,924,9 ml

10 ml24,9 - 49,924,3 ml

X24,6 ml

Asetosal mula-mula (X) = 2,025 mmol Asetosal yang tersisa setelah 1 jam:(x-y) + y + y = ml NaOH x N NaOH x + y = mmol NaOHy = mmol NaOH xy = (V NaOH x N NaOH) (V NaOH x N NaOH)y = (24,6 x 0,1116) (2,025)y = 2,7454 2,025y = 0,7204maka asetosal sisa (Ct) = x y = 2,025 - 0,7204 = 1,3046 mmolJika dalam mg/mol : mg = mol x BM asetosal = 1,3046 mol x 180,16 = 235,0367 mg/10ml = 23,5037 mg/ml

3jamVolume asetosalVolume NaOHVolume akhir

10 ml0 2424 ml

10 ml0 23,923,9 ml

X23,95 ml

Asetosal mula-mula (X) = 2,025 mmol Asetosal yang tersisa setelah 1 jam:(x-y) + y + y = ml NaOH x N NaOH x + y = mmol NaOHy = mmol NaOH xy = (V NaOH x N NaOH) (V NaOH x N NaOH)y = (23,95 x 0,1116) (2,025)y = 2,6728 2,025y = 0,6478maka asetosal sisa (Ct) = x y = 2,025 - 0,6478 = 1,3772 mmolJika dalam mg/mol : mg = mol x BM asetosal = 1,3772 mol x 180,16 = 248,1164 mg/10ml = 24,8116 mg/ml