perhitungan kuda kuda
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PERHITUNGAN GORDING
1 DATA PERENCANAAN
Jarak Gording = 1.22 m
Jarak kuda - kuda = 4 m
Jarak batang tarik (trekstang) = 1.3333333m
Jenis penutup atap = Genteng
Sudut kuda - kuda = 35
2 DAA !"#$%& ' 15.5.2.4*5
+ = 11 kg,m A& AJA
A = 13./ 0m2
= 5.2 0m3
= 1/. 0m3
% = 4/
% = //.2 0m4
3 DATA PEMBEBANAN
eban genteng = 5
(termasuk usuk dan reng)
eban gording = 11 kg,m
Dipakai ' 15.5.2.4*5
4 BEBAN MATI
eban genteng = 1 kg,m
(6arak gording .genteng)
eban Gording = 11 kg,m2kg,m
!enambung (17) = .2 kg,m
/.2 kg,m
5 BEBAN HIDUP
eban peker6a dan a8at (!) = 15 kg
6 BEBAN ANGIN
= 25
9oe:sien angin tekan == .3
9oe:sien angin ;isap = -.4
< tekan = koe tek. angin 6.gordin
= .3
= /.15 kg,m
< ;isap = koe tek. angin 6.gordin
= -.4
o
0m4
kg,m2
>D&
ekanan angin , m2 kg,m2
.2 ? - .4
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= -12.2 kg,m
7 REAKSI PEMBEBANAN ARAH X
a. Akibat Beba Mati
"@ =
= .5 /.2
= 12/.5 kg
ma =
= .125 /.2
= /.5 kg m
b. Akibat Beba Hi!"#
"@ =
= .5 15
= 245.5 kg
ma =
= .25 15
= .4 kg m
0. Akibat Beba A$i
"@ =
= .5 /.15
= 1.3 kg
ma =
= .125 /.15
= 1.3 kg m
% REAKSI PEMBEBANAN ARAH &
a. Akibat Beba Mati
"@ =
= .5 /.2
= 3.2 kg
ma =
= .125 /.2
= 1./ kg m
b. Akibat Beba Hi!"#
"@ =
= .5 15 = 5.3 kg
ma =
= .25 15
= 2. kg m
' KOMBINASI PEMBEBANAN
= 1.2 >D& B 1.
1,2 >D&
'os ? &
1, >D&
Sin ? &2
1,2 >&&
'os ? &
1,4 >&&
Sin ? &
1,2 < tekan &
1, < tekan &2
1,2 >D&
Sin ? &,3
1, >D&
Sin ? &,32
1,2 >&&
Sin ? &,3
1,4 >&&
Sin ? &,3
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= 1/.3 B 13.
= 21.323 kg m
= 21323.54 C mm
= 1.2 >D& B 1.
= 12.11 B 45.
= 5. kg m
= 5.4/2 C mm
1( KONTRO) TEGANGAN
PPBBi 1'%4
= 2132.354
5.2
= 4.
= /3.3
= /3.3 E i6in
11 KONTRO) )ENDUTAN
Be*!a+a*ka PPBBi 1'%4, Ha- 1(6 Pa+a- 15.1 A/at 1
% = 21 pa
1,25.& = 1. 0m
+ =
= 4./ kg,m
= .4/ kg,0m
+ =
= 45.4 kg,m= .454 kg,0m
! =
= 122./ kg
= 1.22/ kg,0m
! =
= . kg= . kg,0m
Me$0it"$ -e!"ta $*!i$
= 5 B 134 % . % 4 % . %
= 5 .4/ 25B
34 21 4/
=.13
14152.32B
12/
kg,0m2
ma(i6in) =
>D&
'os ?
>D&
Sin ?
>&&
'os ?
>&&
Sin ?
+ . &FPx . L
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= .13 1.1 B
= .211 B .1
= .21 0m
= 5 B 134 % . % 4 % . %
= 5 .454 533333333.33333B
34 21 //.2
=.13
345/.434/1B
232
= .13 1.1 B
= .242 B .1
= .24 0m
+e0i$$a 2
= .45 B .
= .15
= .32 0m
aka 2
= .32 0m E :6in = 1.
+ . &,3F ! . &,3
= HI B I
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PPIUG 1'%3
TABE) BAA
B
B PPBBi 1'%4
PPIUG 1'%3
)RD 0a- 4
25 1.22
25 1.22
x
y
px
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Akibat Beba Mati
.1/ 4
.54 1
.1/ 4
.54 4
4
1
Akibat Beba Mati
.54 1.3333333
.54 1.
.54 1.3333333
.54 1.3333333
>&& B . > 1 U =
qy
4.5 mM
D
Dx ma
41,57
2 Mx m
15,59
22.25
qx
4.5 mM
D
Dx
14
2 M
2
22.25
p
yx
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B 14.4 2 U =
3 U =
U =
>&& 4 U =
5 U =
U =
B 5.4/
1/.
B 2/2./3
= 1 HARUS DI CEK OK
1 1.22/ 4
4 21 4/
.235/.251432
12/
kg,0m2
kg,0m215.00
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.2 .
1 . 21333333.3333333
4 21 //.2
.21354445./32335
232
.2 .1
HARUS DI CEK OK0m
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Akibat Beba Hi!"#
Akibat Beba Hi!"# Akibat Be
Kombinasi beban Arah x Arah y
1.4 D = 127.196311 14.13
=
g
x =
kgm
4.5
py
M
D
0.17
0.34
0.68 p
Mpx max =
17,02 kgm
Dpx max =
34,05 kg
max =
,31 kg
max =
4,78 kgm
4.5
px
M
D
0.51
2.05
4,10 p
Mpx max =
51,07 kgm
Dpx max =
200,48 kg
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1.2 D + 0.5 L = 152.043642 26.4533452
1.2 D + 1.6 L = 246.683754 58.0000492
1.2 D + 1.6 L + 0.8 = 261.323754 58.0000492
1.2 D + 1.3 + 0.5 L = 175.833642 26.4533452
0.9 D + 1.3 = 193.616462 46.3679191
0.9 D - 1.3 = -30.0783483 -28.1970176
tegangan tekan max =-637,38 kg/cm2
7.50 tegangan tarik max =
+637,38 kg/cm2
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a A$i
qangin tiup
4.5 mM
D
Dx tiup max
= 34,05 kg
2 Mx tiup max =
17,02 kgm
22,42
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PERHITUNGAN BATANG TARIK TREKSTANG8
1 REAKSI PEMBEBANAN KE ARAH SUMBU X
"@ beban mati = 12/.5 kg
"@ beban ;idup = 245.5 kg
"@ beban angin = 1.3 kg B
"@t = 35.5 kg
9 KOMBINASI PEMBEBANAN
" = 1.2 >D& B 1. >&& B . >
= 155. B 3/3.1/ B 14.4
= 53.54 kg
3 DIMENSI TREKSTANG
= "
A
A = "
= 35.5
14
= .2
d = 4 A
= 4 .23.14
= .5 0m bu8atkan
K . 0m = mm
0m2
A = 1,4 d2
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1 Pebebaa t*ek+ta$
!ma = + .& B ! n =
n
dengan
+ = beban merata ara; & = 6arak antar kuda - kuda
n = 6um8a; pembagian trekstang
! = beban ;idup
maka
!ma = + .& B !
n
= 25/.51 B .4
3
= .524 B .4
= 12.54 kg
2 Dimensi trekstang
,
= 1.22 , 3
= .4
= ar0an .41
= 33.2
= .55 = .31
aka " = n . !ma
= 3 12.54
.55
= /2/./5 kg
&uas dimensi trekstang
= 14
A = "
= /2/.//
14
= .4
d = 4 A
= ./ dibu8atkan
tan ? =
?o
sin ? 0os ?
sin ?
= " , A
?
A = 1,4 d2
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= 1.( : ; 1(
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3 b;
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PERHITUNGAN KUDA < KUDA
1 DATA PEMBEBANAN
entang kuda2 = 1.5 m
Jarak kuda2 (&k) = 4 m
Jarak gording = 2 m
Sudut kemiringan atap = 35
!enutup atap = Genteng
erat penutup atap = 5 PPIUG 1'%3
eban gording = 11 kg,m TABE) BAA
B37
$ = 24 pa SNI 9((9
$u = 3 pa
= 21
9 MENGHITUNG BEBAN
BEBAN MATI
erat atap = 4 kg
(+ &k & gording)
erat gording = 44 kg
(+ &k) B
444 kg
!enambung (17) = 44.4 kg B SNI 9((9
+t 4.4 kg
. ati ara; = 4. kg
. ati ara; = 2.13 kg
BEBAN HIDUP
eban peker6a L a8at = 1 kg
. Midup ara; = 1./2 kg
. Midup ara; = 5.3 kg
BEBAN ANGIN
= 25 )RD 0a- 4
9oe:sien angin tekan =
= .3
9oe:sien angin ;isap = -.4
< tekan = koe tek. angin &k &.gording
= .3 25
o
kg,m2
kg,0m2
ekanan angin , m2 kg,m2
.2 ? - .4
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= kg
< ;isap = koe tek. angin &k &.gording
= -.4 25
= - kg
. Angin ara; = 4/.15 kg
. Angin ara; = 34.41 kg
AC A"AM N A"AM O Kbia+i #ebebaa
. A% 4. 2.13 Ara; = 5.4 =
. M%DP! 1./2 5.3 Ara; = 455.4 =
. ACG%C 4/.15 34.41
Pe*0it"$a #a=a$ beta$ k"!a < k"!a
Gambar Auto0ad
Tabe- #a=a$ bata$ k"!a < k"!a
N. A 8 H 8 > 8 D 8
1 1. 1.5 .5 2.12
2 1. 1.5 1.5 2.
3 1. 1.5 2.25 2.
4 1. 1.5 1.5 2.12
5 1. 1.5 .5
1. 1.5
Co atang arik atang ekan
A1
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A2
A3
A4
A5
A
M1
M2M3
M4
M5
M
Q1
Q2
Q3
Q4
Q5
D1D2
D3
D4
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4 2
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4 2
kg
4 kg
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Be*at +e!i*i k"!a < k"!a !itak+i* ) ? 5 8
6arak kuda2 ma = 2 kg
= 54.25 kg
= 2.13 kg
Be*at +e!i*i #e"t"# ata# $ete$8
simpu8 tenga; menerima beban
= 4 kg
simpu8 pun0ak menerima beban
= 4/ kg
simpu8 tepi menerima beban
= 2 kg
Beba akibat $*!i$
tiap simpu8 menerima beban= 44
tiap simpu8 menerima beban
=
Beba be*$"a
tiap simpu8 menerima beban
= 1 kg
Beba tia# +i#"- akibat beba ati !a be*$"a
!2 = !3 = !5 = !
5/.25 kg = kg
!1 = !
415.13 kg = 45 kg
!4
.25 kg = kg
tiap simpu8 tenga;menerima beban
tiap simpu8 tepimenerima beban
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